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Series of letter pairs with blanks for completion.

A sequence of letter pairs arranged in rows, each followed by two blank spaces, presented in a handwritten style on a white background.

A sequence of letter pairs arranged in rows, each followed by two blank spaces, presented in a handwritten style on a white background.

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Show Answer Key & Explanations Step-by-step solution for: 11 Plus: Key Stage 2: 11 Plus Verbal Reasoning, Type L - Alphabet ...

Problem Analysis


The task involves identifying patterns in sequences of two-letter pairs and determining the missing entries. Each row appears to follow a specific rule or pattern. Let's analyze each row step by step.

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Row 1: \( FA, GB, HC, ID, JE, \_\_ \)


- Observation: The first letters are consecutive letters in the alphabet: \( F, G, H, I, J \).
- Second Letters: The second letters are also consecutive letters in the alphabet: \( A, B, C, D, E \).
- Pattern: Both the first and second letters increase by one position in the alphabet.
- Missing Entry: The next pair should be \( KF \) (since \( K \) follows \( J \) and \( F \) follows \( E \)).

Answer for Row 1: \( KF \)

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Row 2: \( WH, TJ, QL, NN, KP, \_\_ \)


- Observation: The pairs seem to involve a decreasing pattern in the first letter and an increasing pattern in the second letter.
- First Letters: \( W, T, Q, N, K \). These letters decrease by 3 positions in the alphabet: \( W \to T \), \( T \to Q \), \( Q \to N \), \( N \to K \).
- Second Letters: \( H, J, L, N, P \). These letters increase by 2 positions in the alphabet: \( H \to J \), \( J \to L \), \( L \to N \), \( N \to P \).
- Missing Entry:
- Next first letter: \( K - 3 = H \).
- Next second letter: \( P + 2 = R \).
- Therefore, the missing pair is \( HR \).

Answer for Row 2: \( HR \)

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Row 3: \( FL, GK, IJ, LI, PH, \_\_ \)


- Observation: The pairs appear to involve a mix of increasing and decreasing patterns.
- First Letters: \( F, G, I, L, P \). These letters increase by varying amounts: \( F \to G (+1) \), \( G \to I (+2) \), \( I \to L (+3) \), \( L \to P (+4) \).
- Second Letters: \( L, K, J, I, H \). These letters decrease by 1 position each time: \( L \to K (-1) \), \( K \to J (-1) \), \( J \to I (-1) \), \( I \to H (-1) \).
- Missing Entry:
- Next first letter: \( P + 5 = U \) (since the increment increases by 1 each time).
- Next second letter: \( H - 1 = G \).
- Therefore, the missing pair is \( UG \).

Answer for Row 3: \( UG \)

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Row 4: \( WX, SA, OD, KG, GJ, \_\_ \)


- Observation: The pairs seem to involve a complex pattern involving both increasing and decreasing positions.
- First Letters: \( W, S, O, K, G \). These letters decrease by varying amounts: \( W \to S (-4) \), \( S \to O (-2) \), \( O \to K (-2) \), \( K \to G (-2) \).
- Second Letters: \( X, A, D, G, J \). These letters increase by varying amounts: \( X \to A (-21, wrapping around the alphabet) \), \( A \to D (+3) \), \( D \to G (+3) \), \( G \to J (+3) \).
- Missing Entry:
- Next first letter: \( G - 2 = E \).
- Next second letter: \( J + 3 = M \).
- Therefore, the missing pair is \( EM \).

Answer for Row 4: \( EM \)

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Row 5: \( WD, VB, TZ, QX, MV, \_\_ \)


- Observation: The pairs involve a mix of decreasing and increasing patterns.
- First Letters: \( W, V, T, Q, M \). These letters decrease by varying amounts: \( W \to V (-1) \), \( V \to T (-2) \), \( T \to Q (-1) \), \( Q \to M (-2) \).
- Second Letters: \( D, B, Z, X, V \). These letters decrease by varying amounts: \( D \to B (-2) \), \( B \to Z (-2) \), \( Z \to X (-2) \), \( X \to V (-2) \).
- Missing Entry:
- Next first letter: \( M - 1 = L \).
- Next second letter: \( V - 2 = T \).
- Therefore, the missing pair is \( LT \).

Answer for Row 5: \( LT \)

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Row 6: \( MB, NG, LL, OQ, KV, \_\_ \)


- Observation: The pairs involve a complex pattern that alternates between increasing and decreasing.
- First Letters: \( M, N, L, O, K \). These letters alternate between increasing and decreasing: \( M \to N (+1) \), \( N \to L (-2) \), \( L \to O (+3) \), \( O \to K (-2) \).
- Second Letters: \( B, G, L, Q, V \). These letters increase by 5 positions each time: \( B \to G (+5) \), \( G \to L (+5) \), \( L \to Q (+5) \), \( Q \to V (+5) \).
- Missing Entry:
- Next first letter: \( K + 5 = P \) (wrapping around the alphabet if necessary).
- Next second letter: \( V + 5 = A \).
- Therefore, the missing pair is \( PA \).

Answer for Row 6: \( PA \)

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Row 7: \( AZ, TI, BY, RK, CX, PM, \_\_, \_\_ \)


- Observation: This row involves two missing entries, suggesting a more complex pattern.
- First Letters: \( A, T, B, R, C, P, \_\_, \_\_ \). These letters alternate between increasing and decreasing in a specific pattern.
- Second Letters: \( Z, I, Y, K, X, M, \_\_, \_\_ \). These letters also follow a specific alternating pattern.
- Pattern Analysis:
- First Letters: \( A \to T (+19) \), \( T \to B (-18) \), \( B \to R (+16) \), \( R \to C (-15) \), \( C \to P (+13) \). The differences alternate and decrease by 1 each time.
- Second Letters: \( Z \to I (-19) \), \( I \to Y (+18) \), \( Y \to K (-16) \), \( K \to X (+15) \), \( X \to M (-13) \). The differences alternate and decrease by 1 each time.
- Missing Entries:
- Next first letter: \( P - 12 = N \).
- Next second letter: \( M + 12 = O \).
- Following first letter: \( N + 11 = W \).
- Following second letter: \( O - 11 = N \).
- Therefore, the missing pairs are \( NO \) and \( WN \).

Answer for Row 7: \( NO, WN \)

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Final Answer


\[
\boxed{KF, HR, UG, EM, LT, PA, NO, WN}
\]
Parent Tip: Review the logic above to help your child master the concept of alphabet sequence worksheet.
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