2nd Grade Math - Patterns Worksheets using Numbers and Letters ... - Free Printable
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Step-by-step solution for: 2nd Grade Math - Patterns Worksheets using Numbers and Letters ...
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Show Answer Key & Explanations
Step-by-step solution for: 2nd Grade Math - Patterns Worksheets using Numbers and Letters ...
Explanation:
We need to find the missing letters or numbers in each pattern. Let’s go row by row and look for the rule.
1. Row 1: abc abc pqr xyz abc abc
This looks like repeating groups of 3 letters.
- abc → abc (repeated)
- Then pqr (next 3 letters after o? Wait — let’s list alphabet positions:
a=1, b=2, c=3
p=16, q=17, r=18
x=24, y=25, z=26
So: abc (1–3), abc (1–3), pqr (16–18), xyz (24–26), then abc, abc again.
No missing items here — all filled. So nothing to fill.
2. Row 2: AB BC CD DE _____ _____ _____
Each pair moves forward by 1 letter:
AB → B is next after A
BC → C is next after B
CD → D after C
DE → E after D
So next should be: EF, FG, GH
✔ Missing: EF, FG, GH
3. Row 3: aa BB cc DD _____ _____ _____
Pattern: lowercase double, uppercase double, alternating.
aa (lower), BB (upper), cc (lower), DD (upper) → next should be ee (lower), FF (upper), gg (lower)
But note: case alternates, and letters go a, b, c, d, e, f, g…
So: aa → a, BB → B, cc → c, DD → D
Next: ee, FF, gg
4. Row 4: a b B a b _____ a
Let’s write positions:
1: a
2: b
3: B (uppercase b)
4: a
5: b
6: ?
7: a
Looks like a repeating cycle: a, b, B, then again a, b, ?, a
Maybe it's “a, b, B” repeated?
First 3: a, b, B
Next 3: a, b, ? → should be B
Then last is a — but that would make 7 items: [a,b,B,a,b,B,a] — yes! That fits.
So position 6 = B
5. Row 5: zy x wv u ts _____ _____ _____
Look at pairs and singles:
zy = z,y (reverse of yz)
x = single
wv = w,v
u = single
ts = t,s
So pattern: reverse pair, single, reverse pair, single, reverse pair, …
After ts, should be single → r
Then next reverse pair: qp
Then single: o
Let’s verify letter order backward:
zy (26,25), x (24), wv (23,22), u (21), ts (20,19), ?
So next single = 18 → r
Then pair = 17,16 → qp
Then single = 15 → o
✔ Missing: r, qp, o
6. Row 6: Zz _____ Xx Ww Vv Uu
Zz (Z and z), then missing, then Xx, Ww, Vv, Uu
Letters: Z (26), ?, X (24), W (23), V (22), U (21)
So missing should be Yy (25)
✔ Missing: Yy
7. Row 7: AAB BBC CCD DDE _____ _____ _____
Each group: first two letters same, third is next letter.
AAB: A,A,B
BBC: B,B,C
CCD: C,C,D
DDE: D,D,E
So next: EEF, FFG, GGH
(E,E,F), (F,F,G), (G,G,H)
Given last is GGH — matches third missing.
So missing: EEF, FFG, GGH
But wait — the row shows: AAB BBC CCD DDE ______ ______ GGH
So only two blanks before GGH → positions 5 and 6 are blank, 7 is GGH.
So:
5: EEF
6: FFG
7: GGH (given)
✔ Missing: EEF, FFG
8. Row 8: 90A 80C _____ 60G _____ 40K _____
Look at numbers: 90, 80, ?, 60, ?, 40, ?
Decreasing by 10 each time: 90, 80, 70, 60, 50, 40, 30
Now letters: A, C, ?, G, ?, K, ?
A=1, C=3, ? , G=7, ? , K=11, ?
Differences:
A(1) → C(3): +2
C(3) → ? → should be +2 → E(5)
E(5) → G(7): +2
G(7) → ? → +2 = I(9)
I(9) → K(11): +2
K(11) → ? → +2 = M(13)
So:
3rd term: 70E
5th term: 50I
7th term: 30M
✔ Missing: 70E, 50I, 30M
9. Row 9: AZ BY CX DW _____ _____ _____
A→Z (1,26), B→Y (2,25), C→X (3,24), D→W (4,23)
First letter increases by 1, second decreases by 1.
So next:
E (5) and V (22) → EV
F (6) and U (21) → FU
G (7) and T (20) → GT
✔ Missing: EV, FU, GT
10. Row 10: A 1 B 11 C 111 _____ _____ _____
Pattern: Letter, then number made of 1s.
A → 1 (one "1")
B → 11 (two "1"s)
C → 111 (three "1"s)
So next: D → 1111 (four 1s)
E → 11111 (five 1s)
F → 111111 (six 1s)
✔ Missing: D, 1111, E, 11111, F, 111111? Wait — row shows only 3 blanks at end:
Given: A 1 B 11 C 111 _____ _____ _____
That’s 9 slots. First 6 are filled. So slots 7,8,9 are missing.
So:
7: D
8: 1111
9: E? No — wait, pattern is alternating: letter, number, letter, number...
Positions:
1: A
2: 1
3: B
4: 11
5: C
6: 111
7: D
8: 1111
9: E ← but that breaks the alternation? Actually, it should continue: letter, number, letter… so after 111 (number), next is letter D, then number 1111, then letter E. But there are only 3 blanks — so likely they want: D, 1111, E
However, the pattern may intend to list 3 more items: D, 1111, E — but E is a letter, and next number would be 11111, but no space. Since only 3 blanks, and pattern is letter-number-letter, we fill:
7: D
8: 1111
9: E
But let’s double-check common versions of this pattern — often it's just D, 1111, E — yes, acceptable for grade 2.
Now compile all missing entries per row (only where blanks exist):
Row 2: EF, FG, GH
Row 3: ee, FF, gg
Row 4: B
Row 5: r, qp, o
Row 6: Yy
Row 7: EEF, FFG
Row 8: 70E, 50I, 30M
Row 9: EV, FU, GT
Row 10: D, 1111, E
But the worksheet shows dotted lines under each blank — count how many blanks per row:
Let me reconstruct based on original layout (as text):
Row 1: abc abc pqr xyz abc abc → no blanks
Row 2: AB BC CD DE ______ ______ ______ → 3 blanks → EF, FG, GH
Row 3: aa BB cc DD ______ ______ ______ → 3 → ee, FF, gg
Row 4: a b B a b ______ a → 1 blank → B
Row 5: zy x wv u ts ______ ______ ______ → 3 → r, qp, o
Row 6: Zz ______ Xx Ww Vv Uu → 1 blank → Yy
Row 7: AAB BBC CCD DDE ______ ______ GGH → 2 blanks → EEF, FFG
Row 8: 90A 80C ______ 60G ______ 40K ______ → 3 blanks → 70E, 50I, 30M
Row 9: AZ BY CX DW ______ ______ ______ → 3 → EV, FU, GT
Row 10: A 1 B 11 C 111 ______ ______ ______ → 3 → D, 1111, E
All consistent.
Final Answer:
Row 2: EF, FG, GH
Row 3: ee, FF, gg
Row 4: B
Row 5: r, qp, o
Row 6: Yy
Row 7: EEF, FFG
Row 8: 70E, 50I, 30M
Row 9: EV, FU, GT
Row 10: D, 1111, E
We need to find the missing letters or numbers in each pattern. Let’s go row by row and look for the rule.
1. Row 1: abc abc pqr xyz abc abc
This looks like repeating groups of 3 letters.
- abc → abc (repeated)
- Then pqr (next 3 letters after o? Wait — let’s list alphabet positions:
a=1, b=2, c=3
p=16, q=17, r=18
x=24, y=25, z=26
So: abc (1–3), abc (1–3), pqr (16–18), xyz (24–26), then abc, abc again.
No missing items here — all filled. So nothing to fill.
2. Row 2: AB BC CD DE _____ _____ _____
Each pair moves forward by 1 letter:
AB → B is next after A
BC → C is next after B
CD → D after C
DE → E after D
So next should be: EF, FG, GH
✔ Missing: EF, FG, GH
3. Row 3: aa BB cc DD _____ _____ _____
Pattern: lowercase double, uppercase double, alternating.
aa (lower), BB (upper), cc (lower), DD (upper) → next should be ee (lower), FF (upper), gg (lower)
But note: case alternates, and letters go a, b, c, d, e, f, g…
So: aa → a, BB → B, cc → c, DD → D
Next: ee, FF, gg
4. Row 4: a b B a b _____ a
Let’s write positions:
1: a
2: b
3: B (uppercase b)
4: a
5: b
6: ?
7: a
Looks like a repeating cycle: a, b, B, then again a, b, ?, a
Maybe it's “a, b, B” repeated?
First 3: a, b, B
Next 3: a, b, ? → should be B
Then last is a — but that would make 7 items: [a,b,B,a,b,B,a] — yes! That fits.
So position 6 = B
5. Row 5: zy x wv u ts _____ _____ _____
Look at pairs and singles:
zy = z,y (reverse of yz)
x = single
wv = w,v
u = single
ts = t,s
So pattern: reverse pair, single, reverse pair, single, reverse pair, …
After ts, should be single → r
Then next reverse pair: qp
Then single: o
Let’s verify letter order backward:
zy (26,25), x (24), wv (23,22), u (21), ts (20,19), ?
So next single = 18 → r
Then pair = 17,16 → qp
Then single = 15 → o
✔ Missing: r, qp, o
6. Row 6: Zz _____ Xx Ww Vv Uu
Zz (Z and z), then missing, then Xx, Ww, Vv, Uu
Letters: Z (26), ?, X (24), W (23), V (22), U (21)
So missing should be Yy (25)
✔ Missing: Yy
7. Row 7: AAB BBC CCD DDE _____ _____ _____
Each group: first two letters same, third is next letter.
AAB: A,A,B
BBC: B,B,C
CCD: C,C,D
DDE: D,D,E
So next: EEF, FFG, GGH
(E,E,F), (F,F,G), (G,G,H)
Given last is GGH — matches third missing.
So missing: EEF, FFG, GGH
But wait — the row shows: AAB BBC CCD DDE ______ ______ GGH
So only two blanks before GGH → positions 5 and 6 are blank, 7 is GGH.
So:
5: EEF
6: FFG
7: GGH (given)
✔ Missing: EEF, FFG
8. Row 8: 90A 80C _____ 60G _____ 40K _____
Look at numbers: 90, 80, ?, 60, ?, 40, ?
Decreasing by 10 each time: 90, 80, 70, 60, 50, 40, 30
Now letters: A, C, ?, G, ?, K, ?
A=1, C=3, ? , G=7, ? , K=11, ?
Differences:
A(1) → C(3): +2
C(3) → ? → should be +2 → E(5)
E(5) → G(7): +2
G(7) → ? → +2 = I(9)
I(9) → K(11): +2
K(11) → ? → +2 = M(13)
So:
3rd term: 70E
5th term: 50I
7th term: 30M
✔ Missing: 70E, 50I, 30M
9. Row 9: AZ BY CX DW _____ _____ _____
A→Z (1,26), B→Y (2,25), C→X (3,24), D→W (4,23)
First letter increases by 1, second decreases by 1.
So next:
E (5) and V (22) → EV
F (6) and U (21) → FU
G (7) and T (20) → GT
✔ Missing: EV, FU, GT
10. Row 10: A 1 B 11 C 111 _____ _____ _____
Pattern: Letter, then number made of 1s.
A → 1 (one "1")
B → 11 (two "1"s)
C → 111 (three "1"s)
So next: D → 1111 (four 1s)
E → 11111 (five 1s)
F → 111111 (six 1s)
✔ Missing: D, 1111, E, 11111, F, 111111? Wait — row shows only 3 blanks at end:
Given: A 1 B 11 C 111 _____ _____ _____
That’s 9 slots. First 6 are filled. So slots 7,8,9 are missing.
So:
7: D
8: 1111
9: E? No — wait, pattern is alternating: letter, number, letter, number...
Positions:
1: A
2: 1
3: B
4: 11
5: C
6: 111
7: D
8: 1111
9: E ← but that breaks the alternation? Actually, it should continue: letter, number, letter… so after 111 (number), next is letter D, then number 1111, then letter E. But there are only 3 blanks — so likely they want: D, 1111, E
However, the pattern may intend to list 3 more items: D, 1111, E — but E is a letter, and next number would be 11111, but no space. Since only 3 blanks, and pattern is letter-number-letter, we fill:
7: D
8: 1111
9: E
But let’s double-check common versions of this pattern — often it's just D, 1111, E — yes, acceptable for grade 2.
Now compile all missing entries per row (only where blanks exist):
Row 2: EF, FG, GH
Row 3: ee, FF, gg
Row 4: B
Row 5: r, qp, o
Row 6: Yy
Row 7: EEF, FFG
Row 8: 70E, 50I, 30M
Row 9: EV, FU, GT
Row 10: D, 1111, E
But the worksheet shows dotted lines under each blank — count how many blanks per row:
Let me reconstruct based on original layout (as text):
Row 1: abc abc pqr xyz abc abc → no blanks
Row 2: AB BC CD DE ______ ______ ______ → 3 blanks → EF, FG, GH
Row 3: aa BB cc DD ______ ______ ______ → 3 → ee, FF, gg
Row 4: a b B a b ______ a → 1 blank → B
Row 5: zy x wv u ts ______ ______ ______ → 3 → r, qp, o
Row 6: Zz ______ Xx Ww Vv Uu → 1 blank → Yy
Row 7: AAB BBC CCD DDE ______ ______ GGH → 2 blanks → EEF, FFG
Row 8: 90A 80C ______ 60G ______ 40K ______ → 3 blanks → 70E, 50I, 30M
Row 9: AZ BY CX DW ______ ______ ______ → 3 → EV, FU, GT
Row 10: A 1 B 11 C 111 ______ ______ ______ → 3 → D, 1111, E
All consistent.
Final Answer:
Row 2: EF, FG, GH
Row 3: ee, FF, gg
Row 4: B
Row 5: r, qp, o
Row 6: Yy
Row 7: EEF, FFG
Row 8: 70E, 50I, 30M
Row 9: EV, FU, GT
Row 10: D, 1111, E
Parent Tip: Review the logic above to help your child master the concept of alphabet worksheets year 2.