Find the missing alternate angles in each diagram.
Worksheet with six problems showing parallel lines and transversals, each with some angles labeled and others to be found using alternate angle properties.
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Step-by-step solution for: Find Alternate Angles Worksheets | Estrategias de matemáticas ...
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Show Answer Key & Explanations
Step-by-step solution for: Find Alternate Angles Worksheets | Estrategias de matemáticas ...
To find the missing angles, we need to use two main rules about parallel lines cut by a transversal (the line crossing them):
1. Alternate Interior Angles are Equal: These are the angles on opposite sides of the crossing line and *between* the parallel lines. In these diagrams, $\angle 2$ and $\angle 4$ are alternate interior angles. So, $\angle 2 = \angle 4$.
2. Supplementary Angles add up to $180^\circ$: Angles that form a straight line add up to $180^\circ$. For example, $\angle 1 + \angle 2 = 180^\circ$ and $\angle 3 + \angle 4 = 180^\circ$. Also, vertical angles (angles opposite each other at an intersection) are equal, so $\angle 1 = \angle 3$ and $\angle 2 = \angle 4$.
Let's solve each problem step-by-step:
Problem 1)
* Given: $\angle 2 = 123.8^\circ$, $\angle 3 = 56.2^\circ$
* Find $\angle 4$: Since $\angle 3$ and $\angle 4$ are on a straight line, they add to $180^\circ$.
$\angle 4 = 180^\circ - 56.2^\circ = 123.8^\circ$.
*(Check: $\angle 4$ should equal $\angle 2$ because they are alternate interior angles. $123.8^\circ = 123.8^\circ$. Correct.)*
* Find $\angle 1$: $\angle 1$ and $\angle 2$ are on a straight line.
$\angle 1 = 180^\circ - 123.8^\circ = 56.2^\circ$.
*(Check: $\angle 1$ should equal $\angle 3$ because they are alternate exterior angles or corresponding logic. $56.2^\circ = 56.2^\circ$. Correct.)*
* Answer: $\angle 1 = 56.2^\circ$, $\angle 4 = 123.8^\circ$
Problem 2)
* Given: $\angle 3 = 123.9^\circ$, $\angle 4 = 56.1^\circ$
* Find $\angle 1$: $\angle 1$ and $\angle 4$ are not directly related by a simple name, but $\angle 1$ and $\angle 3$ are alternate exterior angles? No, let's look closer. $\angle 1$ and $\angle 4$ are consecutive interior? No.
Let's use vertical angles and linear pairs.
$\angle 1$ is vertically opposite to the angle adjacent to $\angle 4$? No, simpler: $\angle 1$ and $\angle 2$ are supplementary. $\angle 3$ and $\angle 4$ are supplementary ($123.9 + 56.1 = 180$).
$\angle 1$ corresponds to the angle vertically opposite $\angle 3$? No.
Let's use Alternate Exterior Angles: $\angle 1$ and $\angle 3$ are NOT alternate exterior. $\angle 1$ is bottom-right interior? No, looking at the arrows:
Line 1 (top) has angles 3 (left) and 4 (right).
Line 2 (bottom) has angles 2 (left) and 1 (right).
Actually, usually standard numbering is counter-clockwise or specific positions. Let's look at the positions in the diagram.
Diagram 2:
Top intersection: Left is $\angle 3$, Right is $\angle 4$.
Bottom intersection: Left is $\angle 2$, Right is $\angle 1$.
Therefore:
$\angle 3$ and $\angle 1$ are Alternate Exterior Angles? No, $\angle 3$ is top-left, $\angle 1$ is bottom-right. They are Alternate Exterior if they are outside the parallel lines. Here, $\angle 3$ is "inside" the left side? No, the parallel lines are horizontal. The transversal cuts them.
Let's assume standard positions relative to the parallel lines:
Top Line: $\angle 3$ is Top-Left? Or Interior Left? The arc for $\angle 3$ is between the transversal and the parallel line on the left. It looks like an interior angle. Wait, looking at Problem 1, $\angle 2$ and $\angle 4$ are clearly the "Z" shape angles (Alternate Interior).
So, $\angle 2$ (Bottom Left) and $\angle 4$ (Top Right) are Alternate Interior Angles. Thus $\angle 2 = \angle 4$.
And $\angle 3$ (Top Left) and $\angle 1$ (Bottom Right) are Alternate Interior? No.
Let's re-evaluate based on the "Z" shape.
In all diagrams:
$\angle 4$ is Top-Right (Interior).
$\angle 2$ is Bottom-Left (Interior).
So $\angle 2$ and $\angle 4$ are Alternate Interior Angles. $\angle 2 = \angle 4$.
$\angle 3$ is Top-Left (Interior? Or Exterior?). Looking at the arc in #1, $\angle 3$ is adjacent to $\angle 4$ on the straight line. So $\angle 3 + \angle 4 = 180^\circ$.
$\angle 1$ is Bottom-Right (Interior? Or Exterior?). Looking at the arc in #1, $\angle 1$ is adjacent to $\angle 2$ on the straight line. So $\angle 1 + \angle 2 = 180^\circ$.
Let's re-read the diagram carefully.
Usually, 1,2,3,4 are quadrants.
But here, the labels are specific.
Top Intersection: $\angle 3$ is Left, $\angle 4$ is Right. They form a linear pair on the parallel line? No, they are on opposite sides of the transversal. They are adjacent angles on the straight parallel line. So $\angle 3 + \angle 4 = 180^\circ$.
Bottom Intersection: $\angle 2$ is Left, $\angle 1$ is Right. They form a linear pair on the parallel line. So $\angle 2 + \angle 1 = 180^\circ$.
Relationship between Top and Bottom:
$\angle 4$ (Top Right) and $\angle 1$ (Bottom Right) are Corresponding Angles. So $\angle 4 = \angle 1$.
$\angle 3$ (Top Left) and $\angle 2$ (Bottom Left) are Corresponding Angles. So $\angle 3 = \angle 2$.
Let's test this hypothesis on Problem 1:
Given $\angle 2 = 123.8$, $\angle 3 = 56.2$.
If $\angle 3 = \angle 2$, then $56.2$ should equal $123.8$. It does not.
So my assumption about which angle is which position is wrong.
Let's look at the "Z" again.
In Problem 1: $\angle 2 = 123.8^\circ$. $\angle 4$ is blank.
Visually, $\angle 2$ is obtuse. $\angle 4$ is obtuse.
$\angle 3 = 56.2^\circ$ (acute). $\angle 1$ is blank.
Visually, $\angle 1$ is acute.
Standard Alternate Interior Angles theorem: The angles inside the parallel lines on opposite sides of the transversal are equal.
In the diagram, the angles "inside" the parallel lines are $\angle 4$ (top, right of transversal) and $\angle 2$ (bottom, left of transversal)?
Or is it $\angle 3$ and $\angle 1$?
Let's look at the arcs.
In #1: Arc for $\angle 4$ is inside the parallel lines. Arc for $\angle 2$ is inside the parallel lines.
So $\angle 2$ and $\angle 4$ are Alternate Interior Angles.
Therefore, $\angle 2 = \angle 4$.
Consequently:
$\angle 3$ and $\angle 4$ are supplementary (linear pair on the top line). $\angle 3 + \angle 4 = 180^\circ$.
$\angle 1$ and $\angle 2$ are supplementary (linear pair on the bottom line). $\angle 1 + \angle 2 = 180^\circ$.
Also, $\angle 1$ and $\angle 3$ are Alternate Exterior Angles? No, $\angle 1$ is inside?
Let's look at $\angle 1$'s position. It is on the bottom line, right side of transversal. Is it inside or outside?
The arc for $\angle 1$ is between the parallel line and the transversal, on the "inside" region?
Actually, looking at #1, $\angle 1$ and $\angle 2$ are adjacent on the bottom line.
$\angle 3$ and $\angle 4$ are adjacent on the top line.
If $\angle 2$ and $\angle 4$ are Alternate Interior, they are equal.
Then $\angle 1$ (supplement of $\angle 2$) must equal $\angle 3$ (supplement of $\angle 4$).
Let's check #1:
$\angle 2 = 123.8$. So $\angle 4 = 123.8$.
$\angle 3 = 56.2$.
Check sum: $123.8 + 56.2 = 180$. This works perfectly.
So, $\angle 1$ is supplement of $\angle 2$. $\angle 1 = 180 - 123.8 = 56.2$.
Rule Established:
1. $\angle 2 = \angle 4$ (Alternate Interior Angles)
2. $\angle 1 = \angle 3$ (Alternate Interior/Exterior depending on definition, but effectively they are equal because they are supplements of equal angles).
3. $\angle 1 + \angle 2 = 180^\circ$
4. $\angle 3 + \angle 4 = 180^\circ$
Let's apply this to all problems.
Problem 1)
Given: $\angle 2 = 123.8^\circ$, $\angle 3 = 56.2^\circ$
$\angle 4 = \angle 2 = \mathbf{123.8^\circ}$
$\angle 1 = \angle 3 = \mathbf{56.2^\circ}$ (or $180 - 123.8$)
Problem 2)
Given: $\angle 3 = 123.9^\circ$, $\angle 4 = 56.1^\circ$
Check sum: $123.9 + 56.1 = 180$. Good.
$\angle 1 = \angle 3 = \mathbf{123.9^\circ}$
$\angle 2 = \angle 4 = \mathbf{56.1^\circ}$
Problem 3)
Given: $\angle 1 = 122.3^\circ$, $\angle 2 = 56.7^\circ$
Check sum: $122.3 + 56.7 = 179.0$? Wait.
$122.3 + 56.7 = 179.0$. This is not 180. There might be a typo in the problem or my reading.
Let me re-read the numbers in image 3.
$\angle 1 = 122.3^\circ$? Or $123.3$? It looks like $122.3$.
$\angle 2 = 56.7^\circ$?
$122.3 + 56.7 = 179$.
Let's look at $\angle 1$ and $\angle 2$. They are a linear pair. They MUST add to 180.
Maybe $\angle 1$ is $123.3$? $123.3 + 56.7 = 180$. That makes sense.
Or maybe $\angle 2$ is $57.7$? $122.3 + 57.7 = 180$.
Looking closely at crop 3... The number for L1 is `122.3`. The number for L2 is `56.7`.
This is a contradiction in the problem statement itself ($122.3+56.7 \neq 180$).
However, often in these worksheets, you just follow the equality rules.
Rule: $\angle 3 = \angle 1$ and $\angle 4 = \angle 2$.
So $\angle 3 = 122.3^\circ$ and $\angle 4 = 56.7^\circ$.
Let's check if $\angle 3 + \angle 4 = 180$. $122.3 + 56.7 = 179$.
I will provide the answers based on the direct equality properties ($\angle 1=\angle 3, \angle 2=\angle 4$), noting the slight arithmetic error in the question's source data if necessary, but for a student, just applying the rule is best.
$\angle 3 = \angle 1 = \mathbf{122.3^\circ}$
$\angle 4 = \angle 2 = \mathbf{56.7^\circ}$
Problem 4)
Given: $\angle 2 = 75.7^\circ$, $\angle 3 = 104.3^\circ$
Check sum for top line: We don't have $\angle 4$ yet.
We know $\angle 2 = \angle 4$. So $\angle 4 = \mathbf{75.7^\circ}$.
We know $\angle 1 = \angle 3$. So $\angle 1 = \mathbf{104.3^\circ}$.
Check consistency: Does $\angle 3 + \angle 4 = 180$?
$104.3 + 75.7 = 180.0$. Yes.
Does $\angle 1 + \angle 2 = 180$?
$104.3 + 75.7 = 180.0$. Yes.
Answers: $\angle 1 = 104.3^\circ$, $\angle 4 = 75.7^\circ$.
Problem 5)
Given: $\angle 1 = 74.6^\circ$, $\angle 4 = 105.4^\circ$
We know $\angle 3 = \angle 1$. So $\angle 3 = \mathbf{74.6^\circ}$.
We know $\angle 2 = \angle 4$. So $\angle 2 = \mathbf{105.4^\circ}$.
Check consistency:
$\angle 1 + \angle 2 = 74.6 + 105.4 = 180.0$. Yes.
$\angle 3 + \angle 4 = 74.6 + 105.4 = 180.0$. Yes.
Answers: $\angle 2 = 105.4^\circ$, $\angle 3 = 74.6^\circ$.
Problem 6)
Given: $\angle 1 = 45.2^\circ$, $\angle 2 = 134.8^\circ$
We know $\angle 3 = \angle 1$. So $\angle 3 = \mathbf{45.2^\circ}$.
We know $\angle 4 = \angle 2$. So $\angle 4 = \mathbf{134.8^\circ}$.
Check consistency:
$\angle 1 + \angle 2 = 45.2 + 134.8 = 180.0$. Yes.
Answers: $\angle 3 = 45.2^\circ$, $\angle 4 = 134.8^\circ$.
Final Answer:
1)
$\angle 1 = 56.2^\circ$
$\angle 4 = 123.8^\circ$
2)
$\angle 1 = 123.9^\circ$
$\angle 2 = 56.1^\circ$
3)
$\angle 3 = 122.3^\circ$
$\angle 4 = 56.7^\circ$
*(Note: The given angles $122.3^\circ$ and $56.7^\circ$ add up to $179^\circ$ instead of $180^\circ$, but using the angle correspondence rules gives these values.)*
4)
$\angle 1 = 104.3^\circ$
$\angle 4 = 75.7^\circ$
5)
$\angle 2 = 105.4^\circ$
$\angle 3 = 74.6^\circ$
6)
$\angle 3 = 45.2^\circ$
$\angle 4 = 134.8^\circ$
1. Alternate Interior Angles are Equal: These are the angles on opposite sides of the crossing line and *between* the parallel lines. In these diagrams, $\angle 2$ and $\angle 4$ are alternate interior angles. So, $\angle 2 = \angle 4$.
2. Supplementary Angles add up to $180^\circ$: Angles that form a straight line add up to $180^\circ$. For example, $\angle 1 + \angle 2 = 180^\circ$ and $\angle 3 + \angle 4 = 180^\circ$. Also, vertical angles (angles opposite each other at an intersection) are equal, so $\angle 1 = \angle 3$ and $\angle 2 = \angle 4$.
Let's solve each problem step-by-step:
Problem 1)
* Given: $\angle 2 = 123.8^\circ$, $\angle 3 = 56.2^\circ$
* Find $\angle 4$: Since $\angle 3$ and $\angle 4$ are on a straight line, they add to $180^\circ$.
$\angle 4 = 180^\circ - 56.2^\circ = 123.8^\circ$.
*(Check: $\angle 4$ should equal $\angle 2$ because they are alternate interior angles. $123.8^\circ = 123.8^\circ$. Correct.)*
* Find $\angle 1$: $\angle 1$ and $\angle 2$ are on a straight line.
$\angle 1 = 180^\circ - 123.8^\circ = 56.2^\circ$.
*(Check: $\angle 1$ should equal $\angle 3$ because they are alternate exterior angles or corresponding logic. $56.2^\circ = 56.2^\circ$. Correct.)*
* Answer: $\angle 1 = 56.2^\circ$, $\angle 4 = 123.8^\circ$
Problem 2)
* Given: $\angle 3 = 123.9^\circ$, $\angle 4 = 56.1^\circ$
* Find $\angle 1$: $\angle 1$ and $\angle 4$ are not directly related by a simple name, but $\angle 1$ and $\angle 3$ are alternate exterior angles? No, let's look closer. $\angle 1$ and $\angle 4$ are consecutive interior? No.
Let's use vertical angles and linear pairs.
$\angle 1$ is vertically opposite to the angle adjacent to $\angle 4$? No, simpler: $\angle 1$ and $\angle 2$ are supplementary. $\angle 3$ and $\angle 4$ are supplementary ($123.9 + 56.1 = 180$).
$\angle 1$ corresponds to the angle vertically opposite $\angle 3$? No.
Let's use Alternate Exterior Angles: $\angle 1$ and $\angle 3$ are NOT alternate exterior. $\angle 1$ is bottom-right interior? No, looking at the arrows:
Line 1 (top) has angles 3 (left) and 4 (right).
Line 2 (bottom) has angles 2 (left) and 1 (right).
Actually, usually standard numbering is counter-clockwise or specific positions. Let's look at the positions in the diagram.
Diagram 2:
Top intersection: Left is $\angle 3$, Right is $\angle 4$.
Bottom intersection: Left is $\angle 2$, Right is $\angle 1$.
Therefore:
$\angle 3$ and $\angle 1$ are Alternate Exterior Angles? No, $\angle 3$ is top-left, $\angle 1$ is bottom-right. They are Alternate Exterior if they are outside the parallel lines. Here, $\angle 3$ is "inside" the left side? No, the parallel lines are horizontal. The transversal cuts them.
Let's assume standard positions relative to the parallel lines:
Top Line: $\angle 3$ is Top-Left? Or Interior Left? The arc for $\angle 3$ is between the transversal and the parallel line on the left. It looks like an interior angle. Wait, looking at Problem 1, $\angle 2$ and $\angle 4$ are clearly the "Z" shape angles (Alternate Interior).
So, $\angle 2$ (Bottom Left) and $\angle 4$ (Top Right) are Alternate Interior Angles. Thus $\angle 2 = \angle 4$.
And $\angle 3$ (Top Left) and $\angle 1$ (Bottom Right) are Alternate Interior? No.
Let's re-evaluate based on the "Z" shape.
In all diagrams:
$\angle 4$ is Top-Right (Interior).
$\angle 2$ is Bottom-Left (Interior).
So $\angle 2$ and $\angle 4$ are Alternate Interior Angles. $\angle 2 = \angle 4$.
$\angle 3$ is Top-Left (Interior? Or Exterior?). Looking at the arc in #1, $\angle 3$ is adjacent to $\angle 4$ on the straight line. So $\angle 3 + \angle 4 = 180^\circ$.
$\angle 1$ is Bottom-Right (Interior? Or Exterior?). Looking at the arc in #1, $\angle 1$ is adjacent to $\angle 2$ on the straight line. So $\angle 1 + \angle 2 = 180^\circ$.
Let's re-read the diagram carefully.
Usually, 1,2,3,4 are quadrants.
But here, the labels are specific.
Top Intersection: $\angle 3$ is Left, $\angle 4$ is Right. They form a linear pair on the parallel line? No, they are on opposite sides of the transversal. They are adjacent angles on the straight parallel line. So $\angle 3 + \angle 4 = 180^\circ$.
Bottom Intersection: $\angle 2$ is Left, $\angle 1$ is Right. They form a linear pair on the parallel line. So $\angle 2 + \angle 1 = 180^\circ$.
Relationship between Top and Bottom:
$\angle 4$ (Top Right) and $\angle 1$ (Bottom Right) are Corresponding Angles. So $\angle 4 = \angle 1$.
$\angle 3$ (Top Left) and $\angle 2$ (Bottom Left) are Corresponding Angles. So $\angle 3 = \angle 2$.
Let's test this hypothesis on Problem 1:
Given $\angle 2 = 123.8$, $\angle 3 = 56.2$.
If $\angle 3 = \angle 2$, then $56.2$ should equal $123.8$. It does not.
So my assumption about which angle is which position is wrong.
Let's look at the "Z" again.
In Problem 1: $\angle 2 = 123.8^\circ$. $\angle 4$ is blank.
Visually, $\angle 2$ is obtuse. $\angle 4$ is obtuse.
$\angle 3 = 56.2^\circ$ (acute). $\angle 1$ is blank.
Visually, $\angle 1$ is acute.
Standard Alternate Interior Angles theorem: The angles inside the parallel lines on opposite sides of the transversal are equal.
In the diagram, the angles "inside" the parallel lines are $\angle 4$ (top, right of transversal) and $\angle 2$ (bottom, left of transversal)?
Or is it $\angle 3$ and $\angle 1$?
Let's look at the arcs.
In #1: Arc for $\angle 4$ is inside the parallel lines. Arc for $\angle 2$ is inside the parallel lines.
So $\angle 2$ and $\angle 4$ are Alternate Interior Angles.
Therefore, $\angle 2 = \angle 4$.
Consequently:
$\angle 3$ and $\angle 4$ are supplementary (linear pair on the top line). $\angle 3 + \angle 4 = 180^\circ$.
$\angle 1$ and $\angle 2$ are supplementary (linear pair on the bottom line). $\angle 1 + \angle 2 = 180^\circ$.
Also, $\angle 1$ and $\angle 3$ are Alternate Exterior Angles? No, $\angle 1$ is inside?
Let's look at $\angle 1$'s position. It is on the bottom line, right side of transversal. Is it inside or outside?
The arc for $\angle 1$ is between the parallel line and the transversal, on the "inside" region?
Actually, looking at #1, $\angle 1$ and $\angle 2$ are adjacent on the bottom line.
$\angle 3$ and $\angle 4$ are adjacent on the top line.
If $\angle 2$ and $\angle 4$ are Alternate Interior, they are equal.
Then $\angle 1$ (supplement of $\angle 2$) must equal $\angle 3$ (supplement of $\angle 4$).
Let's check #1:
$\angle 2 = 123.8$. So $\angle 4 = 123.8$.
$\angle 3 = 56.2$.
Check sum: $123.8 + 56.2 = 180$. This works perfectly.
So, $\angle 1$ is supplement of $\angle 2$. $\angle 1 = 180 - 123.8 = 56.2$.
Rule Established:
1. $\angle 2 = \angle 4$ (Alternate Interior Angles)
2. $\angle 1 = \angle 3$ (Alternate Interior/Exterior depending on definition, but effectively they are equal because they are supplements of equal angles).
3. $\angle 1 + \angle 2 = 180^\circ$
4. $\angle 3 + \angle 4 = 180^\circ$
Let's apply this to all problems.
Problem 1)
Given: $\angle 2 = 123.8^\circ$, $\angle 3 = 56.2^\circ$
$\angle 4 = \angle 2 = \mathbf{123.8^\circ}$
$\angle 1 = \angle 3 = \mathbf{56.2^\circ}$ (or $180 - 123.8$)
Problem 2)
Given: $\angle 3 = 123.9^\circ$, $\angle 4 = 56.1^\circ$
Check sum: $123.9 + 56.1 = 180$. Good.
$\angle 1 = \angle 3 = \mathbf{123.9^\circ}$
$\angle 2 = \angle 4 = \mathbf{56.1^\circ}$
Problem 3)
Given: $\angle 1 = 122.3^\circ$, $\angle 2 = 56.7^\circ$
Check sum: $122.3 + 56.7 = 179.0$? Wait.
$122.3 + 56.7 = 179.0$. This is not 180. There might be a typo in the problem or my reading.
Let me re-read the numbers in image 3.
$\angle 1 = 122.3^\circ$? Or $123.3$? It looks like $122.3$.
$\angle 2 = 56.7^\circ$?
$122.3 + 56.7 = 179$.
Let's look at $\angle 1$ and $\angle 2$. They are a linear pair. They MUST add to 180.
Maybe $\angle 1$ is $123.3$? $123.3 + 56.7 = 180$. That makes sense.
Or maybe $\angle 2$ is $57.7$? $122.3 + 57.7 = 180$.
Looking closely at crop 3... The number for L1 is `122.3`. The number for L2 is `56.7`.
This is a contradiction in the problem statement itself ($122.3+56.7 \neq 180$).
However, often in these worksheets, you just follow the equality rules.
Rule: $\angle 3 = \angle 1$ and $\angle 4 = \angle 2$.
So $\angle 3 = 122.3^\circ$ and $\angle 4 = 56.7^\circ$.
Let's check if $\angle 3 + \angle 4 = 180$. $122.3 + 56.7 = 179$.
I will provide the answers based on the direct equality properties ($\angle 1=\angle 3, \angle 2=\angle 4$), noting the slight arithmetic error in the question's source data if necessary, but for a student, just applying the rule is best.
$\angle 3 = \angle 1 = \mathbf{122.3^\circ}$
$\angle 4 = \angle 2 = \mathbf{56.7^\circ}$
Problem 4)
Given: $\angle 2 = 75.7^\circ$, $\angle 3 = 104.3^\circ$
Check sum for top line: We don't have $\angle 4$ yet.
We know $\angle 2 = \angle 4$. So $\angle 4 = \mathbf{75.7^\circ}$.
We know $\angle 1 = \angle 3$. So $\angle 1 = \mathbf{104.3^\circ}$.
Check consistency: Does $\angle 3 + \angle 4 = 180$?
$104.3 + 75.7 = 180.0$. Yes.
Does $\angle 1 + \angle 2 = 180$?
$104.3 + 75.7 = 180.0$. Yes.
Answers: $\angle 1 = 104.3^\circ$, $\angle 4 = 75.7^\circ$.
Problem 5)
Given: $\angle 1 = 74.6^\circ$, $\angle 4 = 105.4^\circ$
We know $\angle 3 = \angle 1$. So $\angle 3 = \mathbf{74.6^\circ}$.
We know $\angle 2 = \angle 4$. So $\angle 2 = \mathbf{105.4^\circ}$.
Check consistency:
$\angle 1 + \angle 2 = 74.6 + 105.4 = 180.0$. Yes.
$\angle 3 + \angle 4 = 74.6 + 105.4 = 180.0$. Yes.
Answers: $\angle 2 = 105.4^\circ$, $\angle 3 = 74.6^\circ$.
Problem 6)
Given: $\angle 1 = 45.2^\circ$, $\angle 2 = 134.8^\circ$
We know $\angle 3 = \angle 1$. So $\angle 3 = \mathbf{45.2^\circ}$.
We know $\angle 4 = \angle 2$. So $\angle 4 = \mathbf{134.8^\circ}$.
Check consistency:
$\angle 1 + \angle 2 = 45.2 + 134.8 = 180.0$. Yes.
Answers: $\angle 3 = 45.2^\circ$, $\angle 4 = 134.8^\circ$.
Final Answer:
1)
$\angle 1 = 56.2^\circ$
$\angle 4 = 123.8^\circ$
2)
$\angle 1 = 123.9^\circ$
$\angle 2 = 56.1^\circ$
3)
$\angle 3 = 122.3^\circ$
$\angle 4 = 56.7^\circ$
*(Note: The given angles $122.3^\circ$ and $56.7^\circ$ add up to $179^\circ$ instead of $180^\circ$, but using the angle correspondence rules gives these values.)*
4)
$\angle 1 = 104.3^\circ$
$\angle 4 = 75.7^\circ$
5)
$\angle 2 = 105.4^\circ$
$\angle 3 = 74.6^\circ$
6)
$\angle 3 = 45.2^\circ$
$\angle 4 = 134.8^\circ$
Parent Tip: Review the logic above to help your child master the concept of alternate angles worksheet.