Probability Worksheets | Dynamically Created Probability Worksheets - Free Printable
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Step-by-step solution for: Probability Worksheets | Dynamically Created Probability Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Probability Worksheets | Dynamically Created Probability Worksheets
Let's solve each question step by step using the two spinners provided in the image.
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This spinner is divided into 8 equal sections:
- Numbers on the spinner:
- 1 → appears 1 time
- 2 → appears 2 times
- 3 → appears 2 times
- 4 → appears 3 times
So, total sections = 8
We will use this to calculate probabilities.
---
#### 1) What is the probability of the spinner landing on 1 or 3?
- Number of favorable outcomes:
- 1 appears once → 1 section
- 3 appears twice → 2 sections
→ Total = 1 + 2 = 3
- Total possible outcomes = 8
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
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#### 2) What is the probability of the spinner not landing on 3?
- Number of sections with 3 = 2
- So, number of sections not 3 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $
✔ Answer: $ \frac{3}{4} $
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#### 3) What is the probability of the spinner not landing on 2?
- Sections with 2 = 2
- Not 2 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $
✔ Answer: $ \frac{3}{4} $
---
#### 4) What is the probability of the spinner landing on 1?
- Only 1 section has 1
- Probability = $ \frac{1}{8} $
✔ Answer: $ \frac{1}{8} $
---
#### 5) What is the probability of the spinner landing on 3?
- 3 appears in 2 sections
- Probability = $ \frac{2}{8} = \frac{1}{4} $
✔ Answer: $ \frac{1}{4} $
---
#### 6) What is the probability of the spinner landing on 4?
- 4 appears in 3 sections
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
---
#### 7) What is the probability of the spinner not landing on 3 or 4?
- Sections with 3 or 4:
- 3 → 2 sections
- 4 → 3 sections
→ Total = 2 + 3 = 5
- So, not landing on 3 or 4 = 8 - 5 = 3
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
---
This spinner is divided into 6 equal sections:
- Labeling:
- A → 1 section
- B → 1 section
- C → 2 sections
- E → 2 sections
Total = 6 sections
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#### 8) Do you have an equal chance of landing on either B or C?
- B: 1 section
- C: 2 sections
- So, no — probability of B is $ \frac{1}{6} $, C is $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 9) What is the probability of the spinner not landing on B or E?
- B: 1 section
- E: 2 sections
- B or E = 1 + 2 = 3 sections
- Not B or E = 6 - 3 = 3 sections
- These are A and C (A: 1, C: 2)
- Probability = $ \frac{3}{6} = \frac{1}{2} $
✔ Answer: $ \frac{1}{2} $
---
#### 10) Do you have an equal chance of landing on either A or C?
- A: 1 section → $ \frac{1}{6} $
- C: 2 sections → $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 11) What is the probability of the spinner landing on A or B?
- A: 1 section
- B: 1 section
- Total = 2
- Probability = $ \frac{2}{6} = \frac{1}{3} $
✔ Answer: $ \frac{1}{3} $
---
#### 12) What is the probability of the spinner not landing on B or C?
- B: 1 section
- C: 2 sections
- B or C = 3 sections
- Not B or C = 6 - 3 = 3 sections → A and E
- A: 1, E: 2 → total 3
- Probability = $ \frac{3}{6} = \frac{1}{2} $
✔ Answer: $ \frac{1}{2} $
---
#### 13) Do you have an equal chance of landing on either A or E?
- A: 1 section → $ \frac{1}{6} $
- E: 2 sections → $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 14) What is the probability of the spinner not landing on E?
- E: 2 sections
- Not E = 6 - 2 = 4 sections
- Probability = $ \frac{4}{6} = \frac{2}{3} $
✔ Answer: $ \frac{2}{3} $
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| Question | Answer |
|--------|--------|
| 1 | $ \frac{3}{8} $ |
| 2 | $ \frac{3}{4} $ |
| 3 | $ \frac{3}{4} $ |
| 4 | $ \frac{1}{8} $ |
| 5 | $ \frac{1}{4} $ |
| 6 | $ \frac{3}{8} $ |
| 7 | $ \frac{3}{8} $ |
| 8 | No |
| 9 | $ \frac{1}{2} $ |
| 10 | No |
| 11 | $ \frac{1}{3} $ |
| 12 | $ \frac{1}{2} $ |
| 13 | No |
| 14 | $ \frac{2}{3} $ |
---
Let me know if you'd like these answers formatted for printing or need explanations in simpler terms!
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First Spinner (Numbers: 1, 2, 3, 4)
This spinner is divided into 8 equal sections:
- Numbers on the spinner:
- 1 → appears 1 time
- 2 → appears 2 times
- 3 → appears 2 times
- 4 → appears 3 times
So, total sections = 8
We will use this to calculate probabilities.
---
#### 1) What is the probability of the spinner landing on 1 or 3?
- Number of favorable outcomes:
- 1 appears once → 1 section
- 3 appears twice → 2 sections
→ Total = 1 + 2 = 3
- Total possible outcomes = 8
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
---
#### 2) What is the probability of the spinner not landing on 3?
- Number of sections with 3 = 2
- So, number of sections not 3 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $
✔ Answer: $ \frac{3}{4} $
---
#### 3) What is the probability of the spinner not landing on 2?
- Sections with 2 = 2
- Not 2 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $
✔ Answer: $ \frac{3}{4} $
---
#### 4) What is the probability of the spinner landing on 1?
- Only 1 section has 1
- Probability = $ \frac{1}{8} $
✔ Answer: $ \frac{1}{8} $
---
#### 5) What is the probability of the spinner landing on 3?
- 3 appears in 2 sections
- Probability = $ \frac{2}{8} = \frac{1}{4} $
✔ Answer: $ \frac{1}{4} $
---
#### 6) What is the probability of the spinner landing on 4?
- 4 appears in 3 sections
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
---
#### 7) What is the probability of the spinner not landing on 3 or 4?
- Sections with 3 or 4:
- 3 → 2 sections
- 4 → 3 sections
→ Total = 2 + 3 = 5
- So, not landing on 3 or 4 = 8 - 5 = 3
- Probability = $ \frac{3}{8} $
✔ Answer: $ \frac{3}{8} $
---
Second Spinner (Letters: A, B, C, E)
This spinner is divided into 6 equal sections:
- Labeling:
- A → 1 section
- B → 1 section
- C → 2 sections
- E → 2 sections
Total = 6 sections
---
#### 8) Do you have an equal chance of landing on either B or C?
- B: 1 section
- C: 2 sections
- So, no — probability of B is $ \frac{1}{6} $, C is $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 9) What is the probability of the spinner not landing on B or E?
- B: 1 section
- E: 2 sections
- B or E = 1 + 2 = 3 sections
- Not B or E = 6 - 3 = 3 sections
- These are A and C (A: 1, C: 2)
- Probability = $ \frac{3}{6} = \frac{1}{2} $
✔ Answer: $ \frac{1}{2} $
---
#### 10) Do you have an equal chance of landing on either A or C?
- A: 1 section → $ \frac{1}{6} $
- C: 2 sections → $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 11) What is the probability of the spinner landing on A or B?
- A: 1 section
- B: 1 section
- Total = 2
- Probability = $ \frac{2}{6} = \frac{1}{3} $
✔ Answer: $ \frac{1}{3} $
---
#### 12) What is the probability of the spinner not landing on B or C?
- B: 1 section
- C: 2 sections
- B or C = 3 sections
- Not B or C = 6 - 3 = 3 sections → A and E
- A: 1, E: 2 → total 3
- Probability = $ \frac{3}{6} = \frac{1}{2} $
✔ Answer: $ \frac{1}{2} $
---
#### 13) Do you have an equal chance of landing on either A or E?
- A: 1 section → $ \frac{1}{6} $
- E: 2 sections → $ \frac{2}{6} $
- Not equal
✔ Answer: No
---
#### 14) What is the probability of the spinner not landing on E?
- E: 2 sections
- Not E = 6 - 2 = 4 sections
- Probability = $ \frac{4}{6} = \frac{2}{3} $
✔ Answer: $ \frac{2}{3} $
---
✔ Final Answers:
| Question | Answer |
|--------|--------|
| 1 | $ \frac{3}{8} $ |
| 2 | $ \frac{3}{4} $ |
| 3 | $ \frac{3}{4} $ |
| 4 | $ \frac{1}{8} $ |
| 5 | $ \frac{1}{4} $ |
| 6 | $ \frac{3}{8} $ |
| 7 | $ \frac{3}{8} $ |
| 8 | No |
| 9 | $ \frac{1}{2} $ |
| 10 | No |
| 11 | $ \frac{1}{3} $ |
| 12 | $ \frac{1}{2} $ |
| 13 | No |
| 14 | $ \frac{2}{3} $ |
---
Let me know if you'd like these answers formatted for printing or need explanations in simpler terms!
Parent Tip: Review the logic above to help your child master the concept of and or probability worksheet.