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Probability Worksheets | Dynamically Created Probability Worksheets - Free Printable

Probability Worksheets | Dynamically Created Probability Worksheets

Educational worksheet: Probability Worksheets | Dynamically Created Probability Worksheets. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Probability Worksheets | Dynamically Created Probability Worksheets
Let's solve each question step by step using the two spinners provided in the image.

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First Spinner (Numbers: 1, 2, 3, 4)



This spinner is divided into 8 equal sections:

- Numbers on the spinner:
- 1 → appears 1 time
- 2 → appears 2 times
- 3 → appears 2 times
- 4 → appears 3 times

So, total sections = 8

We will use this to calculate probabilities.

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#### 1) What is the probability of the spinner landing on 1 or 3?

- Number of favorable outcomes:
- 1 appears once → 1 section
- 3 appears twice → 2 sections
→ Total = 1 + 2 = 3
- Total possible outcomes = 8
- Probability = $ \frac{3}{8} $

Answer: $ \frac{3}{8} $

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#### 2) What is the probability of the spinner not landing on 3?

- Number of sections with 3 = 2
- So, number of sections not 3 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $

Answer: $ \frac{3}{4} $

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#### 3) What is the probability of the spinner not landing on 2?

- Sections with 2 = 2
- Not 2 = 8 - 2 = 6
- Probability = $ \frac{6}{8} = \frac{3}{4} $

Answer: $ \frac{3}{4} $

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#### 4) What is the probability of the spinner landing on 1?

- Only 1 section has 1
- Probability = $ \frac{1}{8} $

Answer: $ \frac{1}{8} $

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#### 5) What is the probability of the spinner landing on 3?

- 3 appears in 2 sections
- Probability = $ \frac{2}{8} = \frac{1}{4} $

Answer: $ \frac{1}{4} $

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#### 6) What is the probability of the spinner landing on 4?

- 4 appears in 3 sections
- Probability = $ \frac{3}{8} $

Answer: $ \frac{3}{8} $

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#### 7) What is the probability of the spinner not landing on 3 or 4?

- Sections with 3 or 4:
- 3 → 2 sections
- 4 → 3 sections
→ Total = 2 + 3 = 5
- So, not landing on 3 or 4 = 8 - 5 = 3
- Probability = $ \frac{3}{8} $

Answer: $ \frac{3}{8} $

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Second Spinner (Letters: A, B, C, E)



This spinner is divided into 6 equal sections:

- Labeling:
- A → 1 section
- B → 1 section
- C → 2 sections
- E → 2 sections

Total = 6 sections

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#### 8) Do you have an equal chance of landing on either B or C?

- B: 1 section
- C: 2 sections
- So, no — probability of B is $ \frac{1}{6} $, C is $ \frac{2}{6} $
- Not equal

Answer: No

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#### 9) What is the probability of the spinner not landing on B or E?

- B: 1 section
- E: 2 sections
- B or E = 1 + 2 = 3 sections
- Not B or E = 6 - 3 = 3 sections
- These are A and C (A: 1, C: 2)
- Probability = $ \frac{3}{6} = \frac{1}{2} $

Answer: $ \frac{1}{2} $

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#### 10) Do you have an equal chance of landing on either A or C?

- A: 1 section → $ \frac{1}{6} $
- C: 2 sections → $ \frac{2}{6} $
- Not equal

Answer: No

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#### 11) What is the probability of the spinner landing on A or B?

- A: 1 section
- B: 1 section
- Total = 2
- Probability = $ \frac{2}{6} = \frac{1}{3} $

Answer: $ \frac{1}{3} $

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#### 12) What is the probability of the spinner not landing on B or C?

- B: 1 section
- C: 2 sections
- B or C = 3 sections
- Not B or C = 6 - 3 = 3 sections → A and E
- A: 1, E: 2 → total 3
- Probability = $ \frac{3}{6} = \frac{1}{2} $

Answer: $ \frac{1}{2} $

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#### 13) Do you have an equal chance of landing on either A or E?

- A: 1 section → $ \frac{1}{6} $
- E: 2 sections → $ \frac{2}{6} $
- Not equal

Answer: No

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#### 14) What is the probability of the spinner not landing on E?

- E: 2 sections
- Not E = 6 - 2 = 4 sections
- Probability = $ \frac{4}{6} = \frac{2}{3} $

Answer: $ \frac{2}{3} $

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Final Answers:



| Question | Answer |
|--------|--------|
| 1 | $ \frac{3}{8} $ |
| 2 | $ \frac{3}{4} $ |
| 3 | $ \frac{3}{4} $ |
| 4 | $ \frac{1}{8} $ |
| 5 | $ \frac{1}{4} $ |
| 6 | $ \frac{3}{8} $ |
| 7 | $ \frac{3}{8} $ |
| 8 | No |
| 9 | $ \frac{1}{2} $ |
| 10 | No |
| 11 | $ \frac{1}{3} $ |
| 12 | $ \frac{1}{2} $ |
| 13 | No |
| 14 | $ \frac{2}{3} $ |

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