Angle Addition Postulate worksheet with problems and color-by-number activity for solving angle measures.
Worksheet titled "Angle Addition Postulate Color by Number" with six problems involving angle measurements and variables, each requiring calculation and coloring according to the answer.
JPG
1700×2200
149.7 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #346355
⭐
Show Answer Key & Explanations
Step-by-step solution for: Angle Addition Postulate Color by Number
▼
Show Answer Key & Explanations
Step-by-step solution for: Angle Addition Postulate Color by Number
Let's solve each problem step by step using the Angle Addition Postulate, which states:
> If point $ I $ lies in the interior of $ \angle FGH $, then
> $$
> m\angle FGH = m\angle FGI + m\angle IGH
> $$
We’ll apply this to each question.
---
Given:
- $ m\angle FGI = 22^\circ $
- $ m\angle IGH = 110^\circ $
Find: $ m\angle FGH $
Using the Angle Addition Postulate:
$$
m\angle FGH = m\angle FGI + m\angle IGH = 22^\circ + 110^\circ = 132^\circ
$$
✔ Answer: $ \boxed{132} $ (maroon)
---
Given:
- $ m\angle LKJ = 160^\circ $
- $ m\angle LKG = 45^\circ $
Find: $ m\angle GKJ $
Note: $ \angle LKJ $ is made up of $ \angle LKG $ and $ \angle GKJ $. So,
$$
m\angle LKJ = m\angle LKG + m\angle GKJ
$$
$$
160^\circ = 45^\circ + m\angle GKJ
$$
$$
m\angle GKJ = 160^\circ - 45^\circ = 115^\circ
$$
✔ Answer: $ \boxed{115} $ (sky blue)
---
Given:
- $ m\angle IJE = x + 40 $
- $ m\angle EJK = x + 100 $
- $ m\angle IJK = 120^\circ $
Note: $ \angle IJK $ is composed of $ \angle IJE $ and $ \angle EJK $, so:
$$
m\angle IJK = m\angle IJE + m\angle EJK
$$
$$
120 = (x + 40) + (x + 100)
$$
$$
120 = 2x + 140
$$
$$
2x = 120 - 140 = -20
$$
$$
x = -10
$$
Wait — a negative angle measure? That seems odd, but let’s check.
But angles can't be negative. Let’s double-check the diagram.
Looking at the figure: Point $ J $ has rays going to $ I $, $ E $, and $ K $. The angle from $ I $ to $ K $ via $ E $ should add up.
But if $ m\angle IJE = x+40 $, $ m\angle EJK = x+100 $, and total $ m\angle IJK = 120^\circ $, then:
$$
(x+40) + (x+100) = 120 \\
2x + 140 = 120 \\
2x = -20 \Rightarrow x = -10
$$
This implies $ m\angle IJE = -10 + 40 = 30^\circ $, and $ m\angle EJK = -10 + 100 = 90^\circ $, sum = 120° — mathematically consistent.
But geometrically, it’s unusual for expressions to give negative values unless the variable represents something else.
But since the math checks out, we accept:
✔ Answer: $ \boxed{-10} $ (black)
However, this might be an error in the problem setup, as angles are typically positive. But based on given info, $ x = -10 $ is correct.
---
Given:
- $ m\angle KGH = x + 100 $
- $ m\angle FGH = 115^\circ $
- $ m\angle FGK = x + 29 $
From the diagram: $ \angle FGH $ is composed of $ \angle FGK $ and $ \angle KGH $
So:
$$
m\angle FGH = m\angle FGK + m\angle KGH
$$
$$
115 = (x + 29) + (x + 100)
$$
$$
115 = 2x + 129
$$
$$
2x = 115 - 129 = -14
$$
$$
x = -7
$$
Again, negative value.
Check:
- $ m\angle FGK = -7 + 29 = 22^\circ $
- $ m\angle KGH = -7 + 100 = 93^\circ $
- Sum: $ 22 + 93 = 115^\circ $ → Correct.
So even though $ x $ is negative, the angles are valid.
✔ Answer: $ \boxed{-7} $ (yellow)
---
Given:
- $ m\angle MLR = 88^\circ $
- $ m\angle RLK = 3x + 6 $
- $ m\angle MLK = 11x + 14 $
From the diagram: $ \angle MLK $ is composed of $ \angle MLR $ and $ \angle RLK $
So:
$$
m\angle MLK = m\angle MLR + m\angle RLK
$$
$$
11x + 14 = 88 + (3x + 6)
$$
$$
11x + 14 = 3x + 94
$$
$$
11x - 3x = 94 - 14
$$
$$
8x = 80 \Rightarrow x = 10
$$
✔ Answer: $ \boxed{10} $ (purple)
---
Given:
- $ m\angle EFG = 113^\circ $
- $ m\angle AFG = 8x - 3 $
- $ m\angle EFA = 8x + 4 $
From the diagram: $ \angle EFG $ is composed of $ \angle EFA $ and $ \angle AFG $
So:
$$
m\angle EFG = m\angle EFA + m\angle AFG
$$
$$
113 = (8x + 4) + (8x - 3)
$$
$$
113 = 16x + 1
$$
$$
16x = 112 \Rightarrow x = 7
$$
✔ Answer: $ \boxed{7} $ (maroon)
---
| Problem | Answer | Color |
|--------|--------|-------------|
| 1 | 132 | maroon |
| 2 | 115 | sky blue |
| 3 | -10 | black |
| 4 | -7 | yellow |
| 5 | 10 | purple |
| 6 | 7 | maroon |
---
Color each section of the picture according to the answer:
- 132 → maroon
- 115 → sky blue
- -10 → black
- -7 → yellow
- 10 → purple
- 7 → maroon
(Note: The "picture" isn’t visible here, but you would color the regions labeled with these answers accordingly.)
---
- Used Angle Addition Postulate: when two adjacent angles form a larger angle, their measures add.
- Solved equations involving variables and angle expressions.
- Accepted negative values for $ x $ only if they result in valid (positive) angle measures — which they did in problems 3 and 4.
Let me know if you'd like a visual explanation or help coloring!
> If point $ I $ lies in the interior of $ \angle FGH $, then
> $$
> m\angle FGH = m\angle FGI + m\angle IGH
> $$
We’ll apply this to each question.
---
1.
Given:
- $ m\angle FGI = 22^\circ $
- $ m\angle IGH = 110^\circ $
Find: $ m\angle FGH $
Using the Angle Addition Postulate:
$$
m\angle FGH = m\angle FGI + m\angle IGH = 22^\circ + 110^\circ = 132^\circ
$$
✔ Answer: $ \boxed{132} $ (maroon)
---
2.
Given:
- $ m\angle LKJ = 160^\circ $
- $ m\angle LKG = 45^\circ $
Find: $ m\angle GKJ $
Note: $ \angle LKJ $ is made up of $ \angle LKG $ and $ \angle GKJ $. So,
$$
m\angle LKJ = m\angle LKG + m\angle GKJ
$$
$$
160^\circ = 45^\circ + m\angle GKJ
$$
$$
m\angle GKJ = 160^\circ - 45^\circ = 115^\circ
$$
✔ Answer: $ \boxed{115} $ (sky blue)
---
3.
Given:
- $ m\angle IJE = x + 40 $
- $ m\angle EJK = x + 100 $
- $ m\angle IJK = 120^\circ $
Note: $ \angle IJK $ is composed of $ \angle IJE $ and $ \angle EJK $, so:
$$
m\angle IJK = m\angle IJE + m\angle EJK
$$
$$
120 = (x + 40) + (x + 100)
$$
$$
120 = 2x + 140
$$
$$
2x = 120 - 140 = -20
$$
$$
x = -10
$$
Wait — a negative angle measure? That seems odd, but let’s check.
But angles can't be negative. Let’s double-check the diagram.
Looking at the figure: Point $ J $ has rays going to $ I $, $ E $, and $ K $. The angle from $ I $ to $ K $ via $ E $ should add up.
But if $ m\angle IJE = x+40 $, $ m\angle EJK = x+100 $, and total $ m\angle IJK = 120^\circ $, then:
$$
(x+40) + (x+100) = 120 \\
2x + 140 = 120 \\
2x = -20 \Rightarrow x = -10
$$
This implies $ m\angle IJE = -10 + 40 = 30^\circ $, and $ m\angle EJK = -10 + 100 = 90^\circ $, sum = 120° — mathematically consistent.
But geometrically, it’s unusual for expressions to give negative values unless the variable represents something else.
But since the math checks out, we accept:
✔ Answer: $ \boxed{-10} $ (black)
However, this might be an error in the problem setup, as angles are typically positive. But based on given info, $ x = -10 $ is correct.
---
4.
Given:
- $ m\angle KGH = x + 100 $
- $ m\angle FGH = 115^\circ $
- $ m\angle FGK = x + 29 $
From the diagram: $ \angle FGH $ is composed of $ \angle FGK $ and $ \angle KGH $
So:
$$
m\angle FGH = m\angle FGK + m\angle KGH
$$
$$
115 = (x + 29) + (x + 100)
$$
$$
115 = 2x + 129
$$
$$
2x = 115 - 129 = -14
$$
$$
x = -7
$$
Again, negative value.
Check:
- $ m\angle FGK = -7 + 29 = 22^\circ $
- $ m\angle KGH = -7 + 100 = 93^\circ $
- Sum: $ 22 + 93 = 115^\circ $ → Correct.
So even though $ x $ is negative, the angles are valid.
✔ Answer: $ \boxed{-7} $ (yellow)
---
5.
Given:
- $ m\angle MLR = 88^\circ $
- $ m\angle RLK = 3x + 6 $
- $ m\angle MLK = 11x + 14 $
From the diagram: $ \angle MLK $ is composed of $ \angle MLR $ and $ \angle RLK $
So:
$$
m\angle MLK = m\angle MLR + m\angle RLK
$$
$$
11x + 14 = 88 + (3x + 6)
$$
$$
11x + 14 = 3x + 94
$$
$$
11x - 3x = 94 - 14
$$
$$
8x = 80 \Rightarrow x = 10
$$
✔ Answer: $ \boxed{10} $ (purple)
---
6.
Given:
- $ m\angle EFG = 113^\circ $
- $ m\angle AFG = 8x - 3 $
- $ m\angle EFA = 8x + 4 $
From the diagram: $ \angle EFG $ is composed of $ \angle EFA $ and $ \angle AFG $
So:
$$
m\angle EFG = m\angle EFA + m\angle AFG
$$
$$
113 = (8x + 4) + (8x - 3)
$$
$$
113 = 16x + 1
$$
$$
16x = 112 \Rightarrow x = 7
$$
✔ Answer: $ \boxed{7} $ (maroon)
---
✔ Final Answers:
| Problem | Answer | Color |
|--------|--------|-------------|
| 1 | 132 | maroon |
| 2 | 115 | sky blue |
| 3 | -10 | black |
| 4 | -7 | yellow |
| 5 | 10 | purple |
| 6 | 7 | maroon |
---
🎨 Coloring Instructions:
Color each section of the picture according to the answer:
- 132 → maroon
- 115 → sky blue
- -10 → black
- -7 → yellow
- 10 → purple
- 7 → maroon
(Note: The "picture" isn’t visible here, but you would color the regions labeled with these answers accordingly.)
---
🔍 Summary of Key Concepts:
- Used Angle Addition Postulate: when two adjacent angles form a larger angle, their measures add.
- Solved equations involving variables and angle expressions.
- Accepted negative values for $ x $ only if they result in valid (positive) angle measures — which they did in problems 3 and 4.
Let me know if you'd like a visual explanation or help coloring!
Parent Tip: Review the logic above to help your child master the concept of angle addition worksheet.