Circle Theorems worksheet with 12 problems to find missing angles in circles.
A worksheet titled "Circle Theorems (A)" with Section A asking to work out missing angles, featuring 12 diagrams of circles with various angles labeled, each with a lettered blank for the answer. The worksheet is from Cazoom Maths Resources and is for GCSE Tier: Higher.
JPG
1654×2339
286.4 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #767296
⭐
Show Answer Key & Explanations
Step-by-step solution for: Proving Circle Theorems Angle At The Centre Worksheet, 40% OFF
▼
Show Answer Key & Explanations
Step-by-step solution for: Proving Circle Theorems Angle At The Centre Worksheet, 40% OFF
To solve the missing angles in these circle problems, we will use various circle theorems. Here are the key theorems we might use:
1. Angle at the Center Theorem: The angle subtended by an arc at the center of a circle is twice the angle subtended at any point on the circumference.
2. Angles in the Same Segment: Angles subtended by the same arc in the same segment are equal.
3. Cyclic Quadrilateral: Opposite angles in a cyclic quadrilateral sum to 180°.
4. Tangent-Secant Theorem: The angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.
5. Sum of Angles in a Triangle: The sum of the interior angles in a triangle is 180°.
Let's solve each problem step by step.
---
- Given: Central angle = 118°
- To Find: Angle \( a \)
Using the Angle at the Center Theorem:
\[ a = \frac{1}{2} \times 118^\circ = 59^\circ \]
Answer: \( a = 59^\circ \)
---
- Given: Angles \( 62^\circ \) and \( 47^\circ \)
- To Find: Angles \( b \) and \( c \)
Using the Sum of Angles in a Triangle:
\[ b + 62^\circ + 47^\circ = 180^\circ \]
\[ b = 180^\circ - 62^\circ - 47^\circ = 71^\circ \]
Since \( b \) and \( c \) are opposite angles in a cyclic quadrilateral:
\[ c = 180^\circ - b = 180^\circ - 71^\circ = 109^\circ \]
Answers: \( b = 71^\circ \), \( c = 109^\circ \)
---
- Given: Angles \( 12^\circ \), \( 24^\circ \)
- To Find: Angles \( d \), \( e \), \( f \)
Using the Angles in the Same Segment:
\[ d = 12^\circ \]
\[ e = 24^\circ \]
Using the Sum of Angles in a Triangle for the triangle containing \( f \):
\[ f + 12^\circ + 24^\circ = 180^\circ \]
\[ f = 180^\circ - 12^\circ - 24^\circ = 144^\circ \]
Answers: \( d = 12^\circ \), \( e = 24^\circ \), \( f = 144^\circ \)
---
- Given: Angle \( 49^\circ \)
- To Find: Angle \( g \)
Using the Angle at the Center Theorem:
\[ g = \frac{1}{2} \times 49^\circ = 24.5^\circ \]
Answer: \( g = 24.5^\circ \)
---
- Given: Angles \( 43^\circ \)
- To Find: Angles \( h \) and \( i \)
Using the Tangent-Secant Theorem:
\[ h = 43^\circ \]
Using the Sum of Angles in a Triangle:
\[ i + 43^\circ + 43^\circ = 180^\circ \]
\[ i = 180^\circ - 43^\circ - 43^\circ = 94^\circ \]
Answers: \( h = 43^\circ \), \( i = 94^\circ \)
---
- Given: Angle \( 116^\circ \)
- To Find: Angle \( j \)
Using the Cyclic Quadrilateral property:
\[ j = 180^\circ - 116^\circ = 64^\circ \]
Answer: \( j = 64^\circ \)
---
- Given: Angles \( 67^\circ \) and \( 81^\circ \)
- To Find: Angles \( k \), \( l \), \( m \)
Using the Angles in the Same Segment:
\[ k = 67^\circ \]
\[ l = 81^\circ \]
Using the Sum of Angles in a Triangle for the triangle containing \( m \):
\[ m + 67^\circ + 81^\circ = 180^\circ \]
\[ m = 180^\circ - 67^\circ - 81^\circ = 32^\circ \]
Answers: \( k = 67^\circ \), \( l = 81^\circ \), \( m = 32^\circ \)
---
- Given: Angles \( 50^\circ \) and \( 142^\circ \)
- To Find: Angle \( n \)
Using the Cyclic Quadrilateral property:
\[ n = 180^\circ - 50^\circ = 130^\circ \]
Answer: \( n = 130^\circ \)
---
- Given: Central angle \( 232^\circ \)
- To Find: Angle \( p \)
Using the Angle at the Center Theorem:
\[ p = \frac{1}{2} \times (360^\circ - 232^\circ) = \frac{1}{2} \times 128^\circ = 64^\circ \]
Answer: \( p = 64^\circ \)
---
- Given: Angle \( 76^\circ \)
- To Find: Angle \( q \)
Using the Angle at the Center Theorem:
\[ q = \frac{1}{2} \times 76^\circ = 38^\circ \]
Answer: \( q = 38^\circ \)
---
- Given: Angle \( 122^\circ \)
- To Find: Angle \( r \)
Using the Cyclic Quadrilateral property:
\[ r = 180^\circ - 122^\circ = 58^\circ \]
Answer: \( r = 58^\circ \)
---
- Given: Angles \( 44^\circ \), \( 25^\circ \)
- To Find: Angles \( s \) and \( t \)
Using the Sum of Angles in a Triangle for the triangle containing \( t \):
\[ t + 44^\circ + 25^\circ = 180^\circ \]
\[ t = 180^\circ - 44^\circ - 25^\circ = 111^\circ \]
Using the Cyclic Quadrilateral property:
\[ s = 180^\circ - 111^\circ = 69^\circ \]
Answers: \( s = 69^\circ \), \( t = 111^\circ \)
---
\[
\boxed{
\begin{array}{ll}
a = 59^\circ & b = 71^\circ, c = 109^\circ \\
d = 12^\circ, e = 24^\circ, f = 144^\circ & g = 24.5^\circ \\
h = 43^\circ, i = 94^\circ & j = 64^\circ \\
k = 67^\circ, l = 81^\circ, m = 32^\circ & n = 130^\circ \\
p = 64^\circ & q = 38^\circ \\
r = 58^\circ & s = 69^\circ, t = 111^\circ \\
\end{array}
}
\]
1. Angle at the Center Theorem: The angle subtended by an arc at the center of a circle is twice the angle subtended at any point on the circumference.
2. Angles in the Same Segment: Angles subtended by the same arc in the same segment are equal.
3. Cyclic Quadrilateral: Opposite angles in a cyclic quadrilateral sum to 180°.
4. Tangent-Secant Theorem: The angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.
5. Sum of Angles in a Triangle: The sum of the interior angles in a triangle is 180°.
Let's solve each problem step by step.
---
Problem 1
- Given: Central angle = 118°
- To Find: Angle \( a \)
Using the Angle at the Center Theorem:
\[ a = \frac{1}{2} \times 118^\circ = 59^\circ \]
Answer: \( a = 59^\circ \)
---
Problem 2
- Given: Angles \( 62^\circ \) and \( 47^\circ \)
- To Find: Angles \( b \) and \( c \)
Using the Sum of Angles in a Triangle:
\[ b + 62^\circ + 47^\circ = 180^\circ \]
\[ b = 180^\circ - 62^\circ - 47^\circ = 71^\circ \]
Since \( b \) and \( c \) are opposite angles in a cyclic quadrilateral:
\[ c = 180^\circ - b = 180^\circ - 71^\circ = 109^\circ \]
Answers: \( b = 71^\circ \), \( c = 109^\circ \)
---
Problem 3
- Given: Angles \( 12^\circ \), \( 24^\circ \)
- To Find: Angles \( d \), \( e \), \( f \)
Using the Angles in the Same Segment:
\[ d = 12^\circ \]
\[ e = 24^\circ \]
Using the Sum of Angles in a Triangle for the triangle containing \( f \):
\[ f + 12^\circ + 24^\circ = 180^\circ \]
\[ f = 180^\circ - 12^\circ - 24^\circ = 144^\circ \]
Answers: \( d = 12^\circ \), \( e = 24^\circ \), \( f = 144^\circ \)
---
Problem 4
- Given: Angle \( 49^\circ \)
- To Find: Angle \( g \)
Using the Angle at the Center Theorem:
\[ g = \frac{1}{2} \times 49^\circ = 24.5^\circ \]
Answer: \( g = 24.5^\circ \)
---
Problem 5
- Given: Angles \( 43^\circ \)
- To Find: Angles \( h \) and \( i \)
Using the Tangent-Secant Theorem:
\[ h = 43^\circ \]
Using the Sum of Angles in a Triangle:
\[ i + 43^\circ + 43^\circ = 180^\circ \]
\[ i = 180^\circ - 43^\circ - 43^\circ = 94^\circ \]
Answers: \( h = 43^\circ \), \( i = 94^\circ \)
---
Problem 6
- Given: Angle \( 116^\circ \)
- To Find: Angle \( j \)
Using the Cyclic Quadrilateral property:
\[ j = 180^\circ - 116^\circ = 64^\circ \]
Answer: \( j = 64^\circ \)
---
Problem 7
- Given: Angles \( 67^\circ \) and \( 81^\circ \)
- To Find: Angles \( k \), \( l \), \( m \)
Using the Angles in the Same Segment:
\[ k = 67^\circ \]
\[ l = 81^\circ \]
Using the Sum of Angles in a Triangle for the triangle containing \( m \):
\[ m + 67^\circ + 81^\circ = 180^\circ \]
\[ m = 180^\circ - 67^\circ - 81^\circ = 32^\circ \]
Answers: \( k = 67^\circ \), \( l = 81^\circ \), \( m = 32^\circ \)
---
Problem 8
- Given: Angles \( 50^\circ \) and \( 142^\circ \)
- To Find: Angle \( n \)
Using the Cyclic Quadrilateral property:
\[ n = 180^\circ - 50^\circ = 130^\circ \]
Answer: \( n = 130^\circ \)
---
Problem 9
- Given: Central angle \( 232^\circ \)
- To Find: Angle \( p \)
Using the Angle at the Center Theorem:
\[ p = \frac{1}{2} \times (360^\circ - 232^\circ) = \frac{1}{2} \times 128^\circ = 64^\circ \]
Answer: \( p = 64^\circ \)
---
Problem 10
- Given: Angle \( 76^\circ \)
- To Find: Angle \( q \)
Using the Angle at the Center Theorem:
\[ q = \frac{1}{2} \times 76^\circ = 38^\circ \]
Answer: \( q = 38^\circ \)
---
Problem 11
- Given: Angle \( 122^\circ \)
- To Find: Angle \( r \)
Using the Cyclic Quadrilateral property:
\[ r = 180^\circ - 122^\circ = 58^\circ \]
Answer: \( r = 58^\circ \)
---
Problem 12
- Given: Angles \( 44^\circ \), \( 25^\circ \)
- To Find: Angles \( s \) and \( t \)
Using the Sum of Angles in a Triangle for the triangle containing \( t \):
\[ t + 44^\circ + 25^\circ = 180^\circ \]
\[ t = 180^\circ - 44^\circ - 25^\circ = 111^\circ \]
Using the Cyclic Quadrilateral property:
\[ s = 180^\circ - 111^\circ = 69^\circ \]
Answers: \( s = 69^\circ \), \( t = 111^\circ \)
---
Final Answers
\[
\boxed{
\begin{array}{ll}
a = 59^\circ & b = 71^\circ, c = 109^\circ \\
d = 12^\circ, e = 24^\circ, f = 144^\circ & g = 24.5^\circ \\
h = 43^\circ, i = 94^\circ & j = 64^\circ \\
k = 67^\circ, l = 81^\circ, m = 32^\circ & n = 130^\circ \\
p = 64^\circ & q = 38^\circ \\
r = 58^\circ & s = 69^\circ, t = 111^\circ \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of angles in circles worksheet.