Find the missing angles in the parallel lines and transversal diagram.

Let’s solve this step by step.

We have two horizontal lines cut by a diagonal line (called a transversal). The angles formed follow rules based on their positions.

First, look at the top intersection:

- One angle is given as 70°.
- Angle b is next to it — they form a straight line → so they add up to 180°.
→ So, ∠b = 180° - 70° = 110°

Now, angle c is directly across from the 70° angle → these are vertical angles → equal!
→ So, ∠c = 70°

Angle d is across from angle b → also vertical angles → equal!
→ So, ∠d = 110°

Now move to the bottom intersection. Since the two horizontal lines are parallel (they’re drawn that way and we assume they are unless told otherwise), the angles will match the top ones in specific ways.

Angle e is in the same position as the 70° angle → corresponding angles → equal!
→ So, ∠e = 70°

Angle f is next to e → forms a straight line with e → adds to 180°
→ So, ∠f = 180° - 70° = 110°

Angle g is across from f → vertical angles → equal!
→ So, ∠g = 110°

Angle h is across from e → vertical angles → equal!
→ So, ∠h = 70°

Let’s double-check:

Top: 70°, 110°, 70°, 110° → makes sense around a point and along lines.

Bottom: 70°, 110°, 110°, 70° → matches because of parallel lines and transversal.

All angles make sense.

Final Answer:
∠b = 110°
∠c = 70°
∠d = 110°
∠e = 70°
∠f = 110°
∠g = 110°
∠h = 70°