Math worksheet for calculating the area of rectangles using fractions.

Let’s solve each problem one by one.
To find the area of a rectangle, we multiply its length by its width:
Area = length × width

We’ll do this for all 9 problems. Remember to multiply fractions carefully — multiply numerators together and denominators together. If you have mixed numbers (like 1½), turn them into improper fractions first.

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Problem 1:

Dimensions: 2/5 yd and 10/7 yd
Area = (2/5) × (10/7) = (2×10)/(5×7) = 20/35
Simplify: divide numerator and denominator by 5 → 4/7 yd²

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Problem 2:

Dimensions: 1¾ ft and 3⅓ ft
Convert to improper fractions:
1¾ = 7/4
3⅓ = 10/3
Area = (7/4) × (10/3) = 70/12
Simplify: divide numerator and denominator by 2 → 35/6
Convert to mixed number: 35 ÷ 6 = 5 with remainder 5 → 5⅚ ft²

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Problem 3:

Dimensions: 9/2 in and 10 in
Note: 10 is same as 10/1
Area = (9/2) × (10/1) = 90/2 = 45 in²

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Problem 4:

Dimensions: 7/8 ft and 2⁴⁄ ft
Convert 2⁴⁄₇ to improper fraction: (2×7 + 4)/7 = 18/7
Area = (7/8) × (18/7)
Notice 7 cancels out: (1/8) × 18 = 18/8 = 9/4
Convert to mixed number: 9 ÷ 4 = 2 with remainder 1 → 2¼ ft²

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Problem 5:

Dimensions: 1¹⁄₉ in and 9/2 in
Convert 1¹⁄₉ to improper: (1×9 + 1)/9 = 10/9
Area = (10/9) × (9/2)
9 cancels out: (10/1) × (1/2) = 10/2 = 5 in²

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Problem 6:

Dimensions: 14/3 yd and 1/7 yd
Area = (14/3) × (1/7) = 14/(3×7) = 14/21
Simplify: divide by 7 → 2/3 yd²

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Problem 7:

Dimensions: 6 in and 5/9 in
Area = 6 × (5/9) = 30/9
Simplify: divide by 3 → 10/3
Convert to mixed number: 10 ÷ 3 = 3 with remainder 1 → 3⅓ in²

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Problem 8:

Dimensions: 5/2 yd and 6/5 yd
Area = (5/2) × (6/5)
5 cancels out: (1/2) × 6 = 6/2 = 3 yd²

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Problem 9:

Dimensions: 2¹⁄₈ ft and 8/7 ft
Convert 2¹⁄₈ to improper: (2×8 + 1)/8 = 17/8
Area = (17/8) × (8/7)
8 cancels out: 17/7
Convert to mixed number: 17 ÷ 7 = 2 with remainder 3 → 2³⁄₇ ft²

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Final Answer:

1) 4/7 yd²
2) 5⅚ ft²
3) 45 in²
4) 2¼ ft²
5) 5 in²
6) 2/3 yd²
7) 3⅓ in²
8) 3 yd²
9) 2³⁄₇ ft²