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Worksheets featuring area and perimeter word problems for students to solve.

Three overlapping worksheets titled "Area and Perimeter Word Problems" with math problems and space for answers, displayed on a light green background.

Three overlapping worksheets titled "Area and Perimeter Word Problems" with math problems and space for answers, displayed on a light green background.

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Show Answer Key & Explanations Step-by-step solution for: Area and Perimeter Word Problems | Teach Starter
It looks like you've uploaded a worksheet titled "Area and Perimeter Word Problems" from *TeachStarter*. However, the image shows only the front of the pages with several word problems listed, but the actual problems are partially obscured or cut off, especially on the right side. This makes it difficult to read all the full questions.

However, I can still help you solve any specific problem from this worksheet if you provide the full text of the question(s) you'd like solved. Alternatively, I can walk through how to solve typical area and perimeter word problems based on the visible ones.

Let me go through a few of the visible problems and solve them step-by-step:

---

🔹 Problem 1:


> Mrs. Brown's classroom is a rectangle. It has a length of 9 m and a width of 7 m. Mr. Block's classroom is a square. It has sides of 8 m. What is the area of each classroom, and whose classroom has the greatest area?

#### Step-by-step Solution:

- Area of a rectangle = length × width
Mrs. Brown’s classroom:
$$
9 \text{ m} \times 7 \text{ m} = 63 \text{ m}^2
$$

- Area of a square = side × side
Mr. Block’s classroom:
$$
8 \text{ m} \times 8 \text{ m} = 64 \text{ m}^2
$$

- Compare:
$63 \text{ m}^2 < 64 \text{ m}^2$

Answer:
- Mrs. Brown’s classroom: 63 m²
- Mr. Block’s classroom: 64 m²
- Mr. Block’s classroom has the greater area.

---

🔹 Problem 2:


> Mila has just bought a rectangular display board for her bedroom. It has a length of 90 cm and a width of 50 cm. Mila would like to put a border of yellow ribbon around the perimeter of her display board. How many centimetres of yellow ribbon will she need to buy?

#### Step-by-step Solution:

- Perimeter of a rectangle = $2 \times (\text{length} + \text{width})$
$$
2 \times (90 + 50) = 2 \times 140 = 280 \text{ cm}
$$

Answer: Mila needs 280 cm of ribbon.

---

🔹 Problem 3:


> David has just bought a new puppy. He needs to build a fence around his backyard so the puppy can't run away and get lost. David's backyard is a rectangle. It has a length of 8 m and a width of 6.5 m. How many metres of fencing does David need to buy?

#### Step-by-step Solution:

- Perimeter = $2 \times (8 + 6.5) = 2 \times 14.5 = 29$ meters

Answer: David needs 29 metres of fencing.

---

🔹 Problem 4:


> Emily does her hair every morning using the square mirror on her bathroom wall. The mirror has sides of 60 cm. What is the perimeter of Emily's mirror? What is the area of Emily's mirror?

#### Step-by-step Solution:

- Perimeter of a square = $4 \times \text{side}$
$$
4 \times 60 = 240 \text{ cm}
$$

- Area of a square = $\text{side}^2$
$$
60 \times 60 = 3600 \text{ cm}^2
$$

Answer:
- Perimeter: 240 cm
- Area: 3600 cm²

---

🔹 Problem 6:


> Amir went to see a circus-themed performance tent with his family. The performance tent was in the shape of a hexagon. Before the show began, Amir and his family walked around the tent. How many metres did they walk, if each side of the hexagon was 22 m in length?

#### Step-by-step Solution:

- A regular hexagon has 6 equal sides.
- Total distance walked = perimeter = $6 \times 22 = 132$ m

Answer: They walked 132 metres.

---

🔹 Problem 10:


> Sasha wants to completely cover her bedroom window with black curtains, so that no light can come through and wake her early in the morning. Her window is 2 m in length and has a width of 1 m. What area of material will she need to buy?

#### Step-by-step Solution:

- Area of rectangle = length × width
$$
2 \times 1 = 2 \text{ m}^2
$$

Answer: She needs 2 m² of material.

---

🔹 Problem 12:


> Meteo and Juan share a bedroom. The length is 12 m and the width is 4 m. One day, Meteo and Juan have an argument, so Juan places a line of tape down the middle of the bedroom. How much area of the bedroom will each child have to play in?

#### Step-by-step Solution:

- Total area = $12 \times 4 = 48 \text{ m}^2$
- Divided equally: $48 \div 2 = 24 \text{ m}^2$

Answer: Each child has 24 m² to play in.

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