Perimeter and Area worksheet featuring four shapes with dimensions for calculating area and perimeter.

To solve the problem, we need to calculate the perimeter and area for each shape provided in the image. Let's go through each shape step by step.

---

Shape 1: Rectangle

#### Dimensions:
- Length = 20 inches
- Width = 17 inches

#### Perimeter:
The formula for the perimeter of a rectangle is:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
\]
Substitute the given values:
\[
\text{Perimeter} = 2 \times (20 + 17) = 2 \times 37 = 74 \text{ inches}
\]

#### Area:
The formula for the area of a rectangle is:
\[
\text{Area} = \text{Length} \times \text{Width}
\]
Substitute the given values:
\[
\text{Area} = 20 \times 17 = 340 \text{ square inches}
\]

#### Answers:
- Perimeter: 74 inches
- Area: 340 square inches

---

Shape 2: Triangle

#### Dimensions:
- Base = 25 cm
- Height = 15 cm (one of the sides perpendicular to the base)
- Other sides = 30 cm (hypotenuse)

#### Perimeter:
The perimeter of a triangle is the sum of the lengths of its three sides:
\[
\text{Perimeter} = \text{Side 1} + \text{Side 2} + \text{Side 3}
\]
Substitute the given values:
\[
\text{Perimeter} = 25 + 15 + 30 = 70 \text{ cm}
\]

#### Area:
The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height}
\]
Substitute the given values:
\[
\text{Area} = \frac{1}{2} \times 25 \times 15 = \frac{1}{2} \times 375 = 187.5 \text{ square cm}
\]

#### Answers:
- Perimeter: 70 cm
- Area: 187.5 square cm

---

Shape 3: Irregular Shape (L-shaped figure)

#### Dimensions:
- The shape can be divided into two rectangles:
- Rectangle 1: 10 ft × 18 ft
- Rectangle 2: 8 ft × 10 ft

#### Perimeter:
To find the perimeter, count all the outer edges:
- Top edge: 18 ft
- Right edge: 10 ft
- Bottom edge: 10 ft + 8 ft = 18 ft
- Left edge: 10 ft + 10 ft = 20 ft

Add all the edges:
\[
\text{Perimeter} = 18 + 10 + 18 + 20 = 66 \text{ feet}
\]

#### Area:
Calculate the area of each rectangle and add them together:
- Area of Rectangle 1: \( 10 \times 18 = 180 \text{ square feet} \)
- Area of Rectangle 2: \( 8 \times 10 = 80 \text{ square feet} \)

Total area:
\[
\text{Area} = 180 + 80 = 260 \text{ square feet}
\]

#### Answers:
- Perimeter: 66 feet
- Area: 260 square feet

---

Shape 4: Irregular Shape (T-shaped figure)

#### Dimensions:
- The shape can be divided into two rectangles:
- Rectangle 1: 70 m × 15 m
- Rectangle 2: 40 m × 70 m

#### Perimeter:
To find the perimeter, count all the outer edges:
- Top edge: 70 m
- Right edge: 70 m
- Bottom edge: 70 m
- Left edge: 15 m + 40 m + 15 m = 70 m

Add all the edges:
\[
\text{Perimeter} = 70 + 70 + 70 + 70 = 280 \text{ meters}
\]

#### Area:
Calculate the area of each rectangle and add them together:
- Area of Rectangle 1: \( 70 \times 15 = 1050 \text{ square meters} \)
- Area of Rectangle 2: \( 40 \times 70 = 2800 \text{ square meters} \)

Total area:
\[
\text{Area} = 1050 + 2800 = 3850 \text{ square meters}
\]

#### Answers:
- Perimeter: 280 meters
- Area: 3850 square meters

---

Final Answers:

1. Rectangle:
- Perimeter: \( \boxed{74 \text{ inches}} \)
- Area: \( \boxed{340 \text{ square inches}} \)

2. Triangle:
- Perimeter: \( \boxed{70 \text{ cm}} \)
- Area: \( \boxed{187.5 \text{ square cm}} \)

3. Irregular Shape (L-shaped):
- Perimeter: \( \boxed{66 \text{ feet}} \)
- Area: \( \boxed{260 \text{ square feet}} \)

4. Irregular Shape (T-shaped):
- Perimeter: \( \boxed{280 \text{ meters}} \)
- Area: \( \boxed{3850 \text{ square meters}} \)