To solve the problems involving area and perimeter for the given shapes, we will use the following formulas:
Formulas:
1.
Rectangle:
-
Area = Length × Width
-
Perimeter = 2 × (Length + Width)
2.
Triangle:
-
Area = 0.5 × Base × Height
---
Step-by-Step Solutions:
####
1. Rectangle (11m × 12m)
-
Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 11 \, \text{m} \times 12 \, \text{m} = 132 \, \text{m}^2
\]
-
Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (11 \, \text{m} + 12 \, \text{m}) = 2 \times 23 \, \text{m} = 46 \, \text{m}
\]
####
2. Rectangle (4m × 12m)
-
Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 4 \, \text{m} \times 12 \, \text{m} = 48 \, \text{m}^2
\]
-
Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (4 \, \text{m} + 12 \, \text{m}) = 2 \times 16 \, \text{m} = 32 \, \text{m}
\]
####
3. Triangle (Base = 3m, Height = 12m)
-
Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 3 \, \text{m} \times 12 \, \text{m} = 0.5 \times 36 \, \text{m}^2 = 18 \, \text{m}^2
\]
####
4. Rectangle (7m × 3m)
-
Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 7 \, \text{m} \times 3 \, \text{m} = 21 \, \text{m}^2
\]
-
Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (7 \, \text{m} + 3 \, \text{m}) = 2 \times 10 \, \text{m} = 20 \, \text{m}
\]
####
5. Triangle (Base = 4m, Height = 11m)
-
Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 4 \, \text{m} \times 11 \, \text{m} = 0.5 \times 44 \, \text{m}^2 = 22 \, \text{m}^2
\]
####
6. Square (12m × 12m)
-
Area:
\[
\text{Area} = \text{Side} \times \text{Side} = 12 \, \text{m} \times 12 \, \text{m} = 144 \, \text{m}^2
\]
-
Perimeter:
\[
\text{Perimeter} = 4 \times \text{Side} = 4 \times 12 \, \text{m} = 48 \, \text{m}
\]
---
Final Answers:
1.
Rectangle (11m × 12m):
- Area: \( \boxed{132} \, \text{m}^2 \)
- Perimeter: \( \boxed{46} \, \text{m} \)
2.
Rectangle (4m × 12m):
- Area: \( \boxed{48} \, \text{m}^2 \)
- Perimeter: \( \boxed{32} \, \text{m} \)
3.
Triangle (Base = 3m, Height = 12m):
- Area: \( \boxed{18} \, \text{m}^2 \)
4.
Rectangle (7m × 3m):
- Area: \( \boxed{21} \, \text{m}^2 \)
- Perimeter: \( \boxed{20} \, \text{m} \)
5.
Triangle (Base = 4m, Height = 11m):
- Area: \( \boxed{22} \, \text{m}^2 \)
6.
Square (12m × 12m):
- Area: \( \boxed{144} \, \text{m}^2 \)
- Perimeter: \( \boxed{48} \, \text{m} \)
---
Boxed Final Answers:
\[
\boxed{
\begin{array}{ll}
1. & \text{Area: } 132 \, \text{m}^2, \text{ Perimeter: } 46 \, \text{m} \\
2. & \text{Area: } 48 \, \text{m}^2, \text{ Perimeter: } 32 \, \text{m} \\
3. & \text{Area: } 18 \, \text{m}^2 \\
4. & \text{Area: } 21 \, \text{m}^2, \text{ Perimeter: } 20 \, \text{m} \\
5. & \text{Area: } 22 \, \text{m}^2 \\
6. & \text{Area: } 144 \, \text{m}^2, \text{ Perimeter: } 48 \, \text{m} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of area and perimeter worksheet 5th grade.