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Area and perimeter worksheet with six geometric shapes and space to solve equations.

Worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions and blank lines for calculating area and perimeter.

Worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions and blank lines for calculating area and perimeter.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
To solve the problems involving area and perimeter for the given shapes, we will use the following formulas:

Formulas:


1. Rectangle:
- Area = Length × Width
- Perimeter = 2 × (Length + Width)

2. Triangle:
- Area = 0.5 × Base × Height

---

Step-by-Step Solutions:



#### 1. Rectangle (11m × 12m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 11 \, \text{m} \times 12 \, \text{m} = 132 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (11 \, \text{m} + 12 \, \text{m}) = 2 \times 23 \, \text{m} = 46 \, \text{m}
\]

#### 2. Rectangle (4m × 12m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 4 \, \text{m} \times 12 \, \text{m} = 48 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (4 \, \text{m} + 12 \, \text{m}) = 2 \times 16 \, \text{m} = 32 \, \text{m}
\]

#### 3. Triangle (Base = 3m, Height = 12m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 3 \, \text{m} \times 12 \, \text{m} = 0.5 \times 36 \, \text{m}^2 = 18 \, \text{m}^2
\]

#### 4. Rectangle (7m × 3m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 7 \, \text{m} \times 3 \, \text{m} = 21 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (7 \, \text{m} + 3 \, \text{m}) = 2 \times 10 \, \text{m} = 20 \, \text{m}
\]

#### 5. Triangle (Base = 4m, Height = 11m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 4 \, \text{m} \times 11 \, \text{m} = 0.5 \times 44 \, \text{m}^2 = 22 \, \text{m}^2
\]

#### 6. Square (12m × 12m)
- Area:
\[
\text{Area} = \text{Side} \times \text{Side} = 12 \, \text{m} \times 12 \, \text{m} = 144 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 4 \times \text{Side} = 4 \times 12 \, \text{m} = 48 \, \text{m}
\]

---

Final Answers:



1. Rectangle (11m × 12m):
- Area: \( \boxed{132} \, \text{m}^2 \)
- Perimeter: \( \boxed{46} \, \text{m} \)

2. Rectangle (4m × 12m):
- Area: \( \boxed{48} \, \text{m}^2 \)
- Perimeter: \( \boxed{32} \, \text{m} \)

3. Triangle (Base = 3m, Height = 12m):
- Area: \( \boxed{18} \, \text{m}^2 \)

4. Rectangle (7m × 3m):
- Area: \( \boxed{21} \, \text{m}^2 \)
- Perimeter: \( \boxed{20} \, \text{m} \)

5. Triangle (Base = 4m, Height = 11m):
- Area: \( \boxed{22} \, \text{m}^2 \)

6. Square (12m × 12m):
- Area: \( \boxed{144} \, \text{m}^2 \)
- Perimeter: \( \boxed{48} \, \text{m} \)

---

Boxed Final Answers:


\[
\boxed{
\begin{array}{ll}
1. & \text{Area: } 132 \, \text{m}^2, \text{ Perimeter: } 46 \, \text{m} \\
2. & \text{Area: } 48 \, \text{m}^2, \text{ Perimeter: } 32 \, \text{m} \\
3. & \text{Area: } 18 \, \text{m}^2 \\
4. & \text{Area: } 21 \, \text{m}^2, \text{ Perimeter: } 20 \, \text{m} \\
5. & \text{Area: } 22 \, \text{m}^2 \\
6. & \text{Area: } 144 \, \text{m}^2, \text{ Perimeter: } 48 \, \text{m} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of area and perimeter worksheet 5th grade.
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