Find the area of three irregular shapes with labeled side lengths.

To solve the problem of finding the area for each shape, we will break down each figure into simpler geometric shapes (rectangles) and calculate their areas individually. Then, we will sum up the areas to get the total area for each figure.

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Problem 1:

The shape is composed of two rectangles:
- The first rectangle has dimensions \(5 \, \text{m} \times 3 \, \text{m}\).
- The second rectangle has dimensions \(12 \, \text{m} \times 3 \, \text{m}\).

#### Step 1: Calculate the area of the first rectangle.
\[
\text{Area}_1 = \text{length} \times \text{width} = 5 \, \text{m} \times 3 \, \text{m} = 15 \, \text{m}^2
\]

#### Step 2: Calculate the area of the second rectangle.
\[
\text{Area}_2 = \text{length} \times \text{width} = 12 \, \text{m} \times 3 \, \text{m} = 36 \, \text{m}^2
\]

#### Step 3: Sum the areas of both rectangles.
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 15 \, \text{m}^2 + 36 \, \text{m}^2 = 51 \, \text{m}^2
\]

Answer for Problem 1:
\[
\boxed{51}
\]

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Problem 2:

The shape is composed of two rectangles:
- The first rectangle has dimensions \(9 \, \text{m} \times 10 \, \text{m}\).
- The second rectangle has dimensions \(4 \, \text{m} \times 5 \, \text{m}\).

#### Step 1: Calculate the area of the first rectangle.
\[
\text{Area}_1 = \text{length} \times \text{width} = 9 \, \text{m} \times 10 \, \text{m} = 90 \, \text{m}^2
\]

#### Step 2: Calculate the area of the second rectangle.
\[
\text{Area}_2 = \text{length} \times \text{width} = 4 \, \text{m} \times 5 \, \text{m} = 20 \, \text{m}^2
\]

#### Step 3: Sum the areas of both rectangles.
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 90 \, \text{m}^2 + 20 \, \text{m}^2 = 110 \, \text{m}^2
\]

Answer for Problem 2:
\[
\boxed{110}
\]

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Problem 3:

The shape is composed of three rectangles:
- The first rectangle has dimensions \(10 \, \text{m} \times 12 \, \text{m}\).
- The second rectangle has dimensions \(5 \, \text{m} \times 7 \, \text{m}\) (since the total height is \(10 \, \text{m}\) and the smaller rectangle's height is \(6 \, \text{m}\), the remaining height is \(10 - 6 = 4 \, \text{m}\), but the width is \(5 \, \text{m}\)).
- The third rectangle has dimensions \(6 \, \text{m} \times 5 \, \text{m}\).

#### Step 1: Calculate the area of the first rectangle.
\[
\text{Area}_1 = \text{length} \times \text{width} = 10 \, \text{m} \times 12 \, \text{m} = 120 \, \text{m}^2
\]

#### Step 2: Calculate the area of the second rectangle.
\[
\text{Area}_2 = \text{length} \times \text{width} = 5 \, \text{m} \times 7 \, \text{m} = 35 \, \text{m}^2
\]

#### Step 3: Calculate the area of the third rectangle.
\[
\text{Area}_3 = \text{length} \times \text{width} = 6 \, \text{m} \times 5 \, \text{m} = 30 \, \text{m}^2
\]

#### Step 4: Sum the areas of all three rectangles.
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 + \text{Area}_3 = 120 \, \text{m}^2 + 35 \, \text{m}^2 + 30 \, \text{m}^2 = 185 \, \text{m}^2
\]

Answer for Problem 3:
\[
\boxed{185}
\]

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Final Answers:

1. \(\boxed{51}\)
2. \(\boxed{110}\)
3. \(\boxed{185}\)