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Math worksheet for calculating area and perimeter of geometric shapes.

Worksheet titled "Area and Perimeter" with ten math problems involving calculating area and perimeter of various shapes including squares, rectangles, parallelograms, triangles, and trapezoids, along with missing angle calculations and word problems.

Worksheet titled "Area and Perimeter" with ten math problems involving calculating area and perimeter of various shapes including squares, rectangles, parallelograms, triangles, and trapezoids, along with missing angle calculations and word problems.

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Show Answer Key & Explanations Step-by-step solution for: Area and Perimeter interactive exercise for 7th
Let's solve each problem step by step.

---

1) Calculate the Area and Perimeter


#### Given:
- Square with side length \( 5 \, \text{m} \)

#### Solution:
- Area of a square: \( \text{Area} = \text{side}^2 \)
\[
\text{Area} = 5^2 = 25 \, \text{m}^2
\]

- Perimeter of a square: \( \text{Perimeter} = 4 \times \text{side} \)
\[
\text{Perimeter} = 4 \times 5 = 20 \, \text{m}
\]

#### Final Answer:
\[
\boxed{25 \, \text{m}^2, 20 \, \text{m}}
\]

---

2) Calculate the Area and Perimeter


#### Given:
- Rectangle with length \( 12 \, \text{ft} \) and width \( 7 \, \text{ft} \)

#### Solution:
- Area of a rectangle: \( \text{Area} = \text{length} \times \text{width} \)
\[
\text{Area} = 12 \times 7 = 84 \, \text{ft}^2
\]

- Perimeter of a rectangle: \( \text{Perimeter} = 2 \times (\text{length} + \text{width}) \)
\[
\text{Perimeter} = 2 \times (12 + 7) = 2 \times 19 = 38 \, \text{ft}
\]

#### Final Answer:
\[
\boxed{84 \, \text{ft}^2, 38 \, \text{ft}}
\]

---

3) Calculate the Area


#### Given:
- Parallelogram with base \( 19 \, \text{in} \) and height \( 15 \, \text{in} \)

#### Solution:
- Area of a parallelogram: \( \text{Area} = \text{base} \times \text{height} \)
\[
\text{Area} = 19 \times 15 = 285 \, \text{in}^2
\]

#### Final Answer:
\[
\boxed{285 \, \text{in}^2}
\]

---

4) Calculate the missing angle


#### Given:
- Triangle with angles \( 66^\circ \) and \( 58^\circ \)

#### Solution:
- The sum of the interior angles of a triangle is always \( 180^\circ \).
\[
\text{Missing angle} = 180^\circ - (66^\circ + 58^\circ)
\]
\[
\text{Missing angle} = 180^\circ - 124^\circ = 56^\circ
\]

#### Final Answer:
\[
\boxed{56^\circ}
\]

---

5) Calculate the Area


#### Given:
- Triangle with base \( 16 \, \text{ft} \) and height \( 11 \, \text{ft} \)

#### Solution:
- Area of a triangle: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)
\[
\text{Area} = \frac{1}{2} \times 16 \times 11 = 8 \times 11 = 88 \, \text{ft}^2
\]

#### Final Answer:
\[
\boxed{88 \, \text{ft}^2}
\]

---

6) Calculate the Area


#### Given:
- Trapezoid with bases \( 18 \, \text{in} \) and \( 40 \, \text{in} \), and height \( 11 \, \text{in} \)

#### Solution:
- Area of a trapezoid: \( \text{Area} = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height} \)
\[
\text{Area} = \frac{1}{2} \times (18 + 40) \times 11
\]
\[
\text{Area} = \frac{1}{2} \times 58 \times 11 = 29 \times 11 = 319 \, \text{in}^2
\]

#### Final Answer:
\[
\boxed{319 \, \text{in}^2}
\]

---

7) What is the area of a square whose side is equal to 7 yds?


#### Given:
- Side length of the square: \( 7 \, \text{yds} \)

#### Solution:
- Area of a square: \( \text{Area} = \text{side}^2 \)
\[
\text{Area} = 7^2 = 49 \, \text{yd}^2
\]

#### Final Answer:
\[
\boxed{49 \, \text{yd}^2}
\]

---

8) What is the perimeter of a rectangle with a length of 10.2 m and width of 12.8 m?


#### Given:
- Length: \( 10.2 \, \text{m} \)
- Width: \( 12.8 \, \text{m} \)

#### Solution:
- Perimeter of a rectangle: \( \text{Perimeter} = 2 \times (\text{length} + \text{width}) \)
\[
\text{Perimeter} = 2 \times (10.2 + 12.8) = 2 \times 23 = 46 \, \text{m}
\]

#### Final Answer:
\[
\boxed{46 \, \text{m}}
\]

---

9) What is the area of a parallelogram with a height of 13 in and base of 16 in?


#### Given:
- Base: \( 16 \, \text{in} \)
- Height: \( 13 \, \text{in} \)

#### Solution:
- Area of a parallelogram: \( \text{Area} = \text{base} \times \text{height} \)
\[
\text{Area} = 16 \times 13 = 208 \, \text{in}^2
\]

#### Final Answer:
\[
\boxed{208 \, \text{in}^2}
\]

---

10) What is the area of a triangle with a base of 18 ft and height of 13 ft?


#### Given:
- Base: \( 18 \, \text{ft} \)
- Height: \( 13 \, \text{ft} \)

#### Solution:
- Area of a triangle: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)
\[
\text{Area} = \frac{1}{2} \times 18 \times 13 = 9 \times 13 = 117 \, \text{ft}^2
\]

#### Final Answer:
\[
\boxed{117 \, \text{ft}^2}
\]

---

Final Answers Summary:


1. \( \boxed{25 \, \text{m}^2, 20 \, \text{m}} \)
2. \( \boxed{84 \, \text{ft}^2, 38 \, \text{ft}} \)
3. \( \boxed{285 \, \text{in}^2} \)
4. \( \boxed{56^\circ} \)
5. \( \boxed{88 \, \text{ft}^2} \)
6. \( \boxed{319 \, \text{in}^2} \)
7. \( \boxed{49 \, \text{yd}^2} \)
8. \( \boxed{46 \, \text{m}} \)
9. \( \boxed{208 \, \text{in}^2} \)
10. \( \boxed{117 \, \text{ft}^2} \)
Parent Tip: Review the logic above to help your child master the concept of area and perimeter worksheet grade 7.
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