Let’s solve each rectangle problem one by one.
We’ll use two simple formulas:
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Area of a rectangle = length × width
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Perimeter of a rectangle = 2 × (length + width)
We’ll calculate both for each shape, making sure to keep the units correct.
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Problem 1:
Length = 9 ft, Width = 6 ft
→ Area = 9 × 6 =
54 sq ft
→ Perimeter = 2 × (9 + 6) = 2 × 15 =
30 ft
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Problem 2:
Length = 11 ft, Width = 3 ft
→ Area = 11 × 3 =
33 sq ft
→ Perimeter = 2 × (11 + 3) = 2 × 14 =
28 ft
*(Note: It doesn’t matter which side you call length or width — multiplication and addition are commutative.)*
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Problem 3:
Sides = 7 cm and 13 cm
→ Area = 7 × 13 =
91 sq cm
→ Perimeter = 2 × (7 + 13) = 2 × 20 =
40 cm
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Problem 4:
Length = 22 in, Width = 19 in
→ Area = 22 × 19 → Let’s compute:
20×19 = 380, 2×19=38 → 380+38 =
418 sq in
→ Perimeter = 2 × (22 + 19) = 2 × 41 =
82 in
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Problem 5:
Sides = 16 m and 25 m
→ Area = 16 × 25 → Think: 16×25 = 4×4×25 = 4×100 =
400 sq m
→ Perimeter = 2 × (16 + 25) = 2 × 41 =
82 m
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Problem 6:
Length = 10 yd, Width = 2 yd
→ Area = 10 × 2 =
20 sq yd
→ Perimeter = 2 × (10 + 2) = 2 × 12 =
24 yd
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Problem 7:
Length = 6 mm, Width = 1 mm
→ Area = 6 × 1 =
6 sq mm
→ Perimeter = 2 × (6 + 1) = 2 × 7 =
14 mm
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Problem 8:
Length = 44 km, Width = 21 km
→ Area = 44 × 21 → Break it down:
40×21 = 840, 4×21=84 → 840+84 =
924 sq km
→ Perimeter = 2 × (44 + 21) = 2 × 65 =
130 km
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✔ All calculations double-checked. Units preserved. Formulas applied correctly.
Final Answer:
1. Area = 54 sq ft, Perimeter = 30 ft
2. Area = 33 sq ft, Perimeter = 28 ft
3. Area = 91 sq cm, Perimeter = 40 cm
4. Area = 418 sq in, Perimeter = 82 in
5. Area = 400 sq m, Perimeter = 82 m
6. Area = 20 sq yd, Perimeter = 24 yd
7. Area = 6 sq mm, Perimeter = 14 mm
8. Area = 924 sq km, Perimeter = 130 km
Parent Tip: Review the logic above to help your child master the concept of area and perimeter worksheets grade 3.
