Free. Exclusive. Just for you.
Four unique services that make learning easier, faster, and smarter - only on our website.

Grade 5 Area and Perimeter Worksheets | Free Math Worksheets - Free Printable

Grade 5 Area and Perimeter Worksheets | Free Math Worksheets

Educational worksheet: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets. Download and print for classroom or home learning activities.

JPG 742×1050 116.4 KB Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #141394
Show Answer Key & Explanations Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
To solve the problems of finding the area and perimeter of irregular polygons, we need to break each shape into simpler geometric shapes (like rectangles) and then calculate the area and perimeter step by step. Let's go through each problem:

---

Problem 1


Shape:
- A rectangle with a smaller rectangle cut out.

Dimensions:
- Outer rectangle: \(18 \, \text{cm} \times 10 \, \text{cm}\)
- Inner rectangle: \(4 \, \text{cm} \times 8 \, \text{cm}\)

#### Area:
1. Area of the outer rectangle:
\[
\text{Area}_{\text{outer}} = 18 \times 10 = 180 \, \text{cm}^2
\]
2. Area of the inner rectangle:
\[
\text{Area}_{\text{inner}} = 4 \times 8 = 32 \, \text{cm}^2
\]
3. Total area:
\[
\text{Area} = \text{Area}_{\text{outer}} - \text{Area}_{\text{inner}} = 180 - 32 = 148 \, \text{cm}^2
\]

#### Perimeter:
1. The perimeter is the sum of all outer edges. Since the inner rectangle does not affect the outer perimeter:
\[
\text{Perimeter} = 2 \times (18 + 10) = 2 \times 28 = 56 \, \text{cm}
\]

Answer:
\[
\boxed{148 \, \text{cm}^2, 56 \, \text{cm}}
\]

---

Problem 2


Shape:
- Two rectangles side by side with a smaller rectangle in the middle.

Dimensions:
- Left rectangle: \(4 \, \text{in} \times 8.5 \, \text{in}\)
- Right rectangle: \(4 \, \text{in} \times 8.5 \, \text{in}\)
- Middle rectangle (cutout): \(2.5 \, \text{in} \times 6 \, \text{in}\)

#### Area:
1. Area of the left rectangle:
\[
\text{Area}_{\text{left}} = 4 \times 8.5 = 34 \, \text{in}^2
\]
2. Area of the right rectangle:
\[
\text{Area}_{\text{right}} = 4 \times 8.5 = 34 \, \text{in}^2
\]
3. Area of the middle rectangle (cutout):
\[
\text{Area}_{\text{middle}} = 2.5 \times 6 = 15 \, \text{in}^2
\]
4. Total area:
\[
\text{Area} = \text{Area}_{\text{left}} + \text{Area}_{\text{right}} - \text{Area}_{\text{middle}} = 34 + 34 - 15 = 53 \, \text{in}^2
\]

#### Perimeter:
1. The perimeter includes all outer edges. The total length of the top and bottom edges is:
\[
4 + 2.5 + 4 = 10.5 \, \text{in}
\]
2. The total length of the left and right edges is:
\[
8.5 + 8.5 = 17 \, \text{in}
\]
3. Total perimeter:
\[
\text{Perimeter} = 2 \times (10.5 + 8.5) = 2 \times 19 = 38 \, \text{in}
\]

Answer:
\[
\boxed{53 \, \text{in}^2, 38 \, \text{in}}
\]

---

Problem 3


Shape:
- An L-shaped polygon.

Dimensions:
- Top part: \(12 \, \text{in} \times 7 \, \text{in}\)
- Bottom part: \(6 \, \text{in} \times 19 \, \text{in}\)

#### Area:
1. Area of the top rectangle:
\[
\text{Area}_{\text{top}} = 12 \times 7 = 84 \, \text{in}^2
\]
2. Area of the bottom rectangle:
\[
\text{Area}_{\text{bottom}} = 6 \times 19 = 114 \, \text{in}^2
\]
3. Total area:
\[
\text{Area} = \text{Area}_{\text{top}} + \text{Area}_{\text{bottom}} = 84 + 114 = 208 \, \text{in}^2
\]

#### Perimeter:
1. The perimeter includes all outer edges. The total length of the top and bottom edges is:
\[
12 + 6 + 19 = 37 \, \text{in}
\]
2. The total length of the left and right edges is:
\[
7 + 19 = 26 \, \text{in}
\]
3. Total perimeter:
\[
\text{Perimeter} = 37 + 26 = 63 \, \text{in}
\]

Answer:
\[
\boxed{208 \, \text{in}^2, 63 \, \text{in}}
\]

---

Problem 4


Shape:
- An irregular polygon with multiple sides.

Dimensions:
- Top: \(16.8 \, \text{ft}\)
- Right: \(13.2 \, \text{ft}\)
- Bottom: \(12.4 \, \text{ft}\)
- Left: \(8.1 \, \text{ft}\)
- Inner dimensions: \(4.4 \, \text{ft}\) and \(5.1 \, \text{ft}\)

#### Area:
1. Break the shape into two rectangles:
- Rectangle 1: \(16.8 \, \text{ft} \times 8.1 \, \text{ft}\)
- Rectangle 2: \(12.4 \, \text{ft} \times 4.4 \, \text{ft}\)
2. Area of Rectangle 1:
\[
\text{Area}_{1} = 16.8 \times 8.1 = 136.08 \, \text{ft}^2
\]
3. Area of Rectangle 2:
\[
\text{Area}_{2} = 12.4 \times 4.4 = 54.56 \, \text{ft}^2
\]
4. Total area:
\[
\text{Area} = \text{Area}_{1} + \text{Area}_{2} = 136.08 + 54.56 = 190.64 \, \text{ft}^2
\]

#### Perimeter:
1. Sum all the outer edges:
\[
\text{Perimeter} = 16.8 + 13.2 + 12.4 + 8.1 + 4.4 + 5.1 = 60 \, \text{ft}
\]

Answer:
\[
\boxed{190.64 \, \text{ft}^2, 60 \, \text{ft}}
\]

---

Problem 5


Shape:
- An irregular polygon with multiple sides.

Dimensions:
- Top: \(17.8 \, \text{in}\)
- Right: \(5.7 \, \text{in}\)
- Bottom: \(15.2 \, \text{in}\)
- Left: \(6.5 \, \text{in}\)
- Inner dimension: \(4.8 \, \text{in}\)

#### Area:
1. Break the shape into two rectangles:
- Rectangle 1: \(17.8 \, \text{in} \times 6.5 \, \text{in}\)
- Rectangle 2: \(15.2 \, \text{in} \times 4.8 \, \text{in}\)
2. Area of Rectangle 1:
\[
\text{Area}_{1} = 17.8 \times 6.5 = 115.7 \, \text{in}^2
\]
3. Area of Rectangle 2:
\[
\text{Area}_{2} = 15.2 \times 4.8 = 72.96 \, \text{in}^2
\]
4. Total area:
\[
\text{Area} = \text{Area}_{1} + \text{Area}_{2} = 115.7 + 72.96 = 188.66 \, \text{in}^2
\]

#### Perimeter:
1. Sum all the outer edges:
\[
\text{Perimeter} = 17.8 + 5.7 + 15.2 + 6.5 + 4.8 = 49 \, \text{in}
\]

Answer:
\[
\boxed{188.66 \, \text{in}^2, 49 \, \text{in}}
\]

---

Problem 6


Shape:
- An irregular polygon with multiple sides.

Dimensions:
- Top: \(18.8 \, \text{ft}\)
- Right: \(25.5 \, \text{ft}\)
- Bottom: \(18.8 \, \text{ft}\)
- Left: \(5.5 \, \text{ft}\)
- Inner dimension: \(4.2 \, \text{ft}\)

#### Area:
1. Break the shape into two rectangles:
- Rectangle 1: \(18.8 \, \text{ft} \times 5.5 \, \text{ft}\)
- Rectangle 2: \(18.8 \, \text{ft} \times 4.2 \, \text{ft}\)
2. Area of Rectangle 1:
\[
\text{Area}_{1} = 18.8 \times 5.5 = 103.4 \, \text{ft}^2
\]
3. Area of Rectangle 2:
\[
\text{Area}_{2} = 18.8 \times 4.2 = 79.36 \, \text{ft}^2
\]
4. Total area:
\[
\text{Area} = \text{Area}_{1} + \text{Area}_{2} = 103.4 + 79.36 = 182.76 \, \text{ft}^2
\]

#### Perimeter:
1. Sum all the outer edges:
\[
\text{Perimeter} = 18.8 + 25.5 + 18.8 + 5.5 + 4.2 + 4.2 = 77 \, \text{ft}
\]

Answer:
\[
\boxed{182.76 \, \text{ft}^2, 77 \, \text{ft}}
\]

---

Problem 7


Shape:
- An irregular polygon with multiple sides.

Dimensions:
- Top: \(9 \, \text{cm}\)
- Right: \(6.8 \, \text{cm}\)
- Bottom: \(16 \, \text{cm}\)
- Left: \(6.8 \, \text{cm}\)
- Inner dimensions: \(5.5 \, \text{cm}\) and \(6.8 \, \text{cm}\)

#### Area:
1. Break the shape into two rectangles:
- Rectangle 1: \(9 \, \text{cm} \times 6.8 \, \text{cm}\)
- Rectangle 2: \(16 \, \text{cm} \times 6.8 \, \text{cm}\)
2. Area of Rectangle 1:
\[
\text{Area}_{1} = 9 \times 6.8 = 61.2 \, \text{cm}^2
\]
3. Area of Rectangle 2:
\[
\text{Area}_{2} = 16 \times 6.8 = 108.8 \, \text{cm}^2
\]
4. Total area:
\[
\text{Area} = \text{Area}_{1} + \text{Area}_{2} = 61.2 + 108.8 = 170 \, \text{cm}^2
\]

#### Perimeter:
1. Sum all the outer edges:
\[
\text{Perimeter} = 9 + 6.8 + 16 + 6.8 + 5.5 + 6.8 = 50.9 \, \text{cm}
\]

Answer:
\[
\boxed{170 \, \text{cm}^2, 50.9 \, \text{cm}}
\]

---

Problem 8


Shape:
- An irregular polygon with multiple sides.

Dimensions:
- Top: \(3.8 \, \text{m}\)
- Right: \(16.8 \, \text{m}\)
- Bottom: \(3.8 \, \text{m}\)
- Left: \(4.4 \, \text{m}\)
- Inner dimensions: \(4.4 \, \text{m}\), \(8.8 \, \text{m}\), and \(4.4 \, \text{m}\)

#### Area:
1. Break the shape into three rectangles:
- Rectangle 1: \(3.8 \, \text{m} \times 4.4 \, \text{m}\)
- Rectangle 2: \(8.8 \, \text{m} \times 4.4 \, \text{m}\)
- Rectangle 3: \(3.8 \, \text{m} \times 4.4 \, \text{m}\)
2. Area of Rectangle 1:
\[
\text{Area}_{1} = 3.8 \times 4.4 = 16.72 \, \text{m}^2
\]
3. Area of Rectangle 2:
\[
\text{Area}_{2} = 8.8 \times 4.4 = 38.72 \, \text{m}^2
\]
4. Area of Rectangle 3:
\[
\text{Area}_{3} = 3.8 \times 4.4 = 16.72 \, \text{m}^2
\]
5. Total area:
\[
\text{Area} = \text{Area}_{1} + \text{Area}_{2} + \text{Area}_{3} = 16.72 + 38.72 + 16.72 = 72.16 \, \text{m}^2
\]

#### Perimeter:
1. Sum all the outer edges:
\[
\text{Perimeter} = 3.8 + 16.8 + 3.8 + 4.4 + 8.8 + 4.4 = 41.6 \, \text{m}
\]

Answer:
\[
\boxed{72.16 \, \text{m}^2, 41.6 \, \text{m}}
\]

---

Final Answers:


1. \(\boxed{148 \, \text{cm}^2, 56 \, \text{cm}}\)
2. \(\boxed{53 \, \text{in}^2, 38 \, \text{in}}\)
3. \(\boxed{208 \, \text{in}^2, 63 \, \text{in}}\)
4. \(\boxed{190.64 \, \text{ft}^2, 60 \, \text{ft}}\)
5. \(\boxed{188.66 \, \text{in}^2, 49 \, \text{in}}\)
6. \(\boxed{182.76 \, \text{ft}^2, 77 \, \text{ft}}\)
7. \(\boxed{170 \, \text{cm}^2, 50.9 \, \text{cm}}\)
8. \(\boxed{72.16 \, \text{m}^2, 41.6 \, \text{m}}\)
Parent Tip: Review the logic above to help your child master the concept of area and perimeter worksheets.
Print Download

How to use

Click Print to open a print-ready version directly in your browser, or use Download to save the file to your device. The ⭐ Answer button generates an AI answer key instantly - useful for teachers who need a quick reference. Need a different version? Our AI Worksheet Generator lets you create a custom worksheet on any topic in seconds.

(view all area and perimeter worksheets)

Area and Perimeter Word Problems Worksheet | All Kids Network
Pin on Recipes
Area and Perimeter of Rectangle
Area & Perimeter of Rectangles (worksheets, printable, online
Pin on Tutoring
Area and perimeter using a grid worksheets | K5 Learning
Worksheet on area and perimeter grade 5 maths
FREE Area And Perimeter Worksheets Grade 4 [PDFs] Brighterly
Grade 5 Area & Perimeter Worksheets | Free Worksheets
Area and Perimeter Worksheets | Grade1to6.com