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Geometry Worksheets | Volume Worksheets - Free Printable

Geometry Worksheets | Volume Worksheets

Educational worksheet: Geometry Worksheets | Volume Worksheets. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Geometry Worksheets | Volume Worksheets
Let’s solve each problem step by step. We’ll use the correct formulas for surface area of cylinders and cones.

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Formulas to remember:

Cylinder Surface Area (including top and bottom):
SA = 2πr² + 2πrh
= 2πr(r + h)

🔹 Cone Surface Area (including base):
SA = πr² + πrl
= πr(r + l)
where *l* is the slant height (the side length, not the vertical height).

️ Note: In some problems, they give you the slant height directly (like in #2, #4, #5, #8, #9). In others, if only radius and vertical height are given, we’d need to use Pythagoras to find slant height — but looking at the diagrams, all cone problems here already give the slant height (the diagonal side), so we can use it directly.

Also, round answers to nearest hundredth (two decimal places) when needed.

We’ll use π ≈ 3.1416 for calculations.

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Problem 1: Cylinder


Radius r = 8 ft, Height h = 12 ft

SA = 2πr(r + h)
= 2 × π × 8 × (8 + 12)
= 2 × π × 8 × 20
= 320π
≈ 320 × 3.1416 = 1005.31 ft²

Final Answer for #1: 1005.31

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Problem 2: Cone


Radius r = 4 in, Slant height l = 6 in

SA = πr(r + l)
= π × 4 × (4 + 6)
= π × 4 × 10
= 40π
≈ 40 × 3.1416 = 125.66 in²

Final Answer for #2: 125.66

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Problem 3: Cylinder


Radius r = 6 yd, Height h = 8 yd

SA = 2πr(r + h)
= 2 × π × 6 × (6 + 8)
= 2 × π × 6 × 14
= 168π
≈ 168 × 3.1416 = 527.79 yd²

Final Answer for #3: 527.79

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Problem 4: Cone


Radius r = 5 mm, Slant height l = 13 mm

SA = πr(r + l)
= π × 5 × (5 + 13)
= π × 5 × 18
= 90π
≈ 90 × 3.1416 = 282.74 mm²

Final Answer for #4: 282.74

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Problem 5: Cone


Radius r = 6 mm, Slant height l = 14 mm

SA = πr(r + l)
= π × 6 × (6 + 14)
= π × 6 × 20
= 120π
≈ 120 × 3.1416 = 376.99 mm²

Final Answer for #5: 376.99

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Problem 6: Cylinder


Radius r = 6 cm, Height h = 8 cm

SA = 2πr(r + h)
= 2 × π × 6 × (6 + 8)
= 2 × π × 6 × 14
= 168π
≈ 168 × 3.1416 = 527.79 cm²

Final Answer for #6: 527.79

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Problem 7: Cylinder


Radius r = 7 yd, Height h = 10 yd

SA = 2πr(r + h)
= 2 × π × 7 × (7 + 10)
= 2 × π × 7 × 17
= 238π
≈ 238 × 3.1416 = 747.70 yd²

Final Answer for #7: 747.70

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Problem 8: Cone


Radius r = 7 ft, Slant height l = 10 ft

SA = πr(r + l)
= π × 7 × (7 + 10)
= π × 7 × 17
= 119π
≈ 119 × 3.1416 = 373.85 ft²

Final Answer for #8: 373.85

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Problem 9: Cone


Radius r = 4 cm, Slant height l = 6 cm

SA = πr(r + l)
= π × 4 × (4 + 6)
= π × 4 × 10
= 40π
≈ 40 × 3.1416 = 125.66 cm²

Final Answer for #9: 125.66

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Final Answer:
1) 1005.31
2) 125.66
3) 527.79
4) 282.74
5) 376.99
6) 527.79
7) 747.70
8) 373.85
9) 125.66
Parent Tip: Review the logic above to help your child master the concept of area and volume practice.
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