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Surface area calculation worksheet for mixed geometric shapes.

Worksheet titled "Surface Area of Mixed Shapes" with nine problems featuring various 3D geometric figures including a sphere, pyramid, rectangular prism, cone, cube, cylinder, and hemisphere, each with labeled dimensions and instructions to calculate surface area using π = 3.14.

Worksheet titled "Surface Area of Mixed Shapes" with nine problems featuring various 3D geometric figures including a sphere, pyramid, rectangular prism, cone, cube, cylinder, and hemisphere, each with labeled dimensions and instructions to calculate surface area using π = 3.14.

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Show Answer Key & Explanations Step-by-step solution for: Name De 1 Surface Area of Mixed Shapes Find the | Chegg.com
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Let's solve each of these surface area problems step by step. We'll use the formulas for the surface areas of common 3D shapes and round answers to two decimal places using π ≈ 3.14.

---

1) Sphere


- Diameter = 20.5 cm → Radius $ r = \frac{20.5}{2} = 10.25 $ cm
- Surface Area of a sphere:
$$
SA = 4\pi r^2 = 4 \times 3.14 \times (10.25)^2
$$
$$
= 4 \times 3.14 \times 105.0625 = 1319.47 \text{ cm}^2
$$

✔ Surface Area = 1319.47 cm²

---

2) Triangular Prism


This is a triangular prism with:
- Base triangle: base = 10.8 yd, height = 12.4 yd
- Length of prism = 14.6 yd

We need:
- Area of two triangular bases
- Area of three rectangular sides

#### Step 1: Area of one triangle
$$
A_{\text{triangle}} = \frac{1}{2} \times b \times h = \frac{1}{2} \times 10.8 \times 12.4 = 66.96 \text{ yd}^2
$$
Two triangles: $ 2 \times 66.96 = 133.92 $

#### Step 2: Areas of rectangular faces
The three rectangles have widths equal to the sides of the triangle and length = 14.6 yd.

We know:
- One side = 10.8 yd
- One side = 12.4 yd
- The third side (hypotenuse) can be found using Pythagoras:

$$
\text{Hypotenuse} = \sqrt{10.8^2 + 12.4^2} = \sqrt{116.64 + 153.76} = \sqrt{270.4} ≈ 16.44 \text{ yd}
$$

Now compute rectangle areas:
- $ 10.8 \times 14.6 = 157.68 $
- $ 12.4 \times 14.6 = 180.24 $
- $ 16.44 \times 14.6 ≈ 239.02 $

Total rectangle area = $ 157.68 + 180.24 + 239.02 = 576.94 $

#### Total Surface Area:
$$
SA = 133.92 + 576.94 = 710.86 \text{ yd}^2
$$

✔ Surface Area = 710.86 yd²

---

3) Cube


- Side length = 5.4 ft
- Surface area of cube: $ 6s^2 $
$$
SA = 6 \times (5.4)^2 = 6 \times 29.16 = 174.96 \text{ ft}^2
$$

✔ Surface Area = 174.96 ft²

---

4) Cone


- Radius $ r = 2.5 $ m
- Slant height $ l = 12.4 $ m
- Surface Area of cone:
$$
SA = \pi r^2 + \pi r l = \pi r(r + l)
$$
$$
= 3.14 \times 2.5 \times (2.5 + 12.4) = 3.14 \times 2.5 \times 14.9
$$
$$
= 3.14 \times 37.25 = 116.87 \text{ m}^2
$$

✔ Surface Area = 116.87 m²

---

5) Rectangular Prism (Cuboid)


- Dimensions: 5.5 in × 5.5 in × 5.5 in? Wait — looks like it’s 5.5 in × 5.5 in × 5.5 in, but that would be a cube. But wait — the drawing shows different dimensions?

Wait — looking at image: It's labeled as 5.5 in on two sides and 13.5 in on the other? Let me recheck.

Actually, from the diagram:
- Height = 13.5 in
- Width = 5.5 in
- Depth = 5.5 in

So it’s a rectangular prism with:
- Two faces: $ 5.5 \times 5.5 $
- Two faces: $ 5.5 \times 13.5 $
- Two faces: $ 5.5 \times 13.5 $

Wait — actually:
- Front/back: $ 5.5 \times 13.5 $
- Left/right: $ 5.5 \times 13.5 $? No — depth is 5.5, so left/right are $ 5.5 \times 5.5 $? Let's clarify.

Standard labeling:
- Length = 13.5 in
- Width = 5.5 in
- Height = 5.5 in

Then:
- Top/Bottom: $ 13.5 \times 5.5 = 74.25 $ → two faces: $ 2 \times 74.25 = 148.5 $
- Front/Back: $ 13.5 \times 5.5 = 74.25 $ → same as above → $ 148.5 $
- Sides: $ 5.5 \times 5.5 = 30.25 $ → two sides → $ 60.5 $

Wait — no! The vertical dimension is 13.5 in, and horizontal is 5.5 in, and depth is 5.5 in.

So:
- Top/Bottom: $ 13.5 \times 5.5 = 74.25 $ → 2 × 74.25 = 148.5
- Front/Back: $ 13.5 \times 5.5 = 74.25 $ → same → 148.5
- Left/Right: $ 5.5 \times 5.5 = 30.25 $ → 2 × 30.25 = 60.5

But that can’t be — if both width and depth are 5.5, then yes.

Wait — perhaps it's a rectangular prism with:
- L = 13.5 in
- W = 5.5 in
- H = 5.5 in

Then:
- SA = 2(LW + LH + WH)
$$
= 2(13.5 \times 5.5 + 13.5 \times 5.5 + 5.5 \times 5.5)
= 2(74.25 + 74.25 + 30.25)
= 2(178.75) = 357.50 \text{ in}^2
$$

✔ Surface Area = 357.50 in²

---

6) Cylinder


- Diameter = 11.4 cm → radius $ r = 5.7 $ cm
- Height = 12.4 cm

Surface Area:
$$
SA = 2\pi r^2 + 2\pi r h = 2\pi r(r + h)
$$
$$
= 2 \times 3.14 \times 5.7 \times (5.7 + 12.4) = 2 \times 3.14 \times 5.7 \times 18.1
$$
First: $ 2 \times 3.14 = 6.28 $
$ 6.28 \times 5.7 = 35.80 $
$ 35.80 \times 18.1 ≈ 647.18 $

Let’s compute step-by-step:
- $ r^2 = 5.7^2 = 32.49 $
- $ 2\pi r^2 = 2 \times 3.14 \times 32.49 = 6.28 \times 32.49 ≈ 204.18 $
- $ 2\pi r h = 2 \times 3.14 \times 5.7 \times 12.4 = 6.28 \times 5.7 \times 12.4 $
- $ 6.28 \times 5.7 = 35.80 $
- $ 35.80 \times 12.4 ≈ 444.32 $
- Total: $ 204.18 + 444.32 = 648.50 \text{ cm}^2 $

✔ Surface Area = 648.50 cm²

---

7) Rectangular Prism


- Dimensions: 17.9 in × 7 in × 3.5 in

Use formula:
$$
SA = 2(lw + lh + wh)
$$
$$
= 2(17.9 \times 7 + 17.9 \times 3.5 + 7 \times 3.5)
= 2(125.3 + 62.65 + 24.5)
= 2(212.45) = 424.90 \text{ in}^2
$$

✔ Surface Area = 424.90 in²

---

8) Hemisphere


- Radius = 5.8 in
- Surface Area of a hemisphere includes:
- Curved surface: $ 2\pi r^2 $
- Flat circular base: $ \pi r^2 $
- So total: $ 3\pi r^2 $

$$
SA = 3 \times 3.14 \times (5.8)^2 = 3 \times 3.14 \times 33.64 = 9.42 \times 33.64
$$
$$
= 317.23 \text{ in}^2
$$

✔ Surface Area = 317.23 in²

---

9) Square Pyramid


- Base: square with side = 5.4 yd
- Slant height = 11.4 yd (from apex to midpoint of base edge)

Surface Area = Base area + 4 × (area of triangular face)

- Base area = $ 5.4 \times 5.4 = 29.16 $
- Each triangle: $ \frac{1}{2} \times \text{base} \times \text{slant height} = \frac{1}{2} \times 5.4 \times 11.4 = 30.78 $
- Four triangles: $ 4 \times 30.78 = 123.12 $
- Total SA = $ 29.16 + 123.12 = 152.28 \text{ yd}^2 $

✔ Surface Area = 152.28 yd²

---

✔ Final Answers:



| Problem | Surface Area |
|--------|--------------|
| 1) Sphere | 1319.47 cm² |
| 2) Triangular Prism | 710.86 yd² |
| 3) Cube | 174.96 ft² |
| 4) Cone | 116.87 m² |
| 5) Rectangular Prism | 357.50 in² |
| 6) Cylinder | 648.50 cm² |
| 7) Rectangular Prism | 424.90 in² |
| 8) Hemisphere | 317.23 in² |
| 9) Square Pyramid | 152.28 yd² |

---

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