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Grade 5 Worksheets: Area of triangles, parallelograms, trapezoids ... - Free Printable

Grade 5 Worksheets: Area of triangles, parallelograms, trapezoids ...

Educational worksheet: Grade 5 Worksheets: Area of triangles, parallelograms, trapezoids .... Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 Worksheets: Area of triangles, parallelograms, trapezoids ...
Let's solve each problem on the worksheet step by step. The worksheet asks us to find the area of various shapes: triangles, parallelograms, and trapezoids.

We will use the following formulas:

1. Area of a triangle:
$$
A = \frac{1}{2} \times \text{base} \times \text{height}
$$

2. Area of a parallelogram:
$$
A = \text{base} \times \text{height}
$$

3. Area of a trapezoid:
$$
A = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}
$$

---

Problem 1: Parallelogram


Given:
- Base = 5
- Height = 2 (the perpendicular height is labeled as 2)
- Side lengths: 3.76 and 5 (but we only need base and height)

$$
A = \text{base} \times \text{height} = 5 \times 2 = 10
$$

Answer: 10

---

Problem 2: Trapezoid


Given:
- Bases: 9 (bottom) and 5 (top)
- Height = 2.03 (the perpendicular distance between bases)
- Other side: 2.84 (not needed for area)

$$
A = \frac{1}{2} \times (9 + 5) \times 2.03 = \frac{1}{2} \times 14 \times 2.03 = 7 \times 2.03 = 14.21
$$

Answer: 14.21

---

Problem 3: Trapezoid


Given:
- Bases: 16 (bottom), 7 (top)
- Height = 3.94 (perpendicular height from top to bottom)
- Other sides: 6.35 and 4 (not needed)

$$
A = \frac{1}{2} \times (16 + 7) \times 3.94 = \frac{1}{2} \times 23 \times 3.94 = 11.5 \times 3.94
$$

Now calculate:
$$
11.5 \times 3.94 = (10 + 1.5) \times 3.94 = 39.4 + 5.91 = 45.31
$$

Answer: 45.31

---

Problem 4: Parallelogram


Given:
- Base = 14
- Height = 2 (vertical line labeled 2)
- Sides: 5.27 and 6.32 (not needed)

$$
A = \text{base} \times \text{height} = 14 \times 2 = 28
$$

Answer: 28

---

Problem 5: Triangle


Given:
- Base = 11
- Height = 4.50 (perpendicular from vertex to base)
- Other sides: 6 and 8 (not needed)

$$
A = \frac{1}{2} \times 11 \times 4.50 = 5.5 \times 4.50
$$

Calculate:
$$
5.5 \times 4.5 = (5 + 0.5) \times 4.5 = 22.5 + 2.25 = 24.75
$$

Answer: 24.75

---

Problem 6: Trapezoid


Given:
- Bases: 8 (bottom), 4 (top)
- Height = 2.53 (perpendicular height)
- Other sides: 2.36 and 2.53 (wait — note: the 2.53 is likely the height, not a side)

So:
- Base₁ = 8
- Base₂ = 4
- Height = 2.53

$$
A = \frac{1}{2} \times (8 + 4) \times 2.53 = \frac{1}{2} \times 12 \times 2.53 = 6 \times 2.53 = 15.18
$$

Answer: 15.18

---

Final Answers:


1. 10
2. 14.21
3. 45.31
4. 28
5. 24.75
6. 15.18

---

🔍 Explanation Summary:


- For parallelograms, use base × height.
- For triangles, use ½ × base × height.
- For trapezoids, use ½ × (sum of bases) × height.
- Always identify the height as the perpendicular distance between bases or from vertex to base.

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Parent Tip: Review the logic above to help your child master the concept of area of a triangle worksheet 5th grade.
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