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Math worksheet for calculating the area of regular polygons and composite figures.

Worksheet titled "Areas of Regular Polygons and Composite Figures" with eight numbered problems showing various geometric shapes including rectangles, triangles, pentagons, hexagons, and composite figures, each with dimensions and a blank space for calculating the area.

Worksheet titled "Areas of Regular Polygons and Composite Figures" with eight numbered problems showing various geometric shapes including rectangles, triangles, pentagons, hexagons, and composite figures, each with dimensions and a blank space for calculating the area.

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Show Answer Key & Explanations Step-by-step solution for: Area of Composite Figures Worksheets - Math Monks
Here are the step-by-step solutions for each problem on the worksheet.

1. Rectangle
* Formula: Area = base $\times$ height
* Calculation: $10.9 \text{ m} \times 7.5 \text{ m}$
* Result: $81.75 \text{ m}^2$

2. Regular Pentagon
* Formula: Area = $\frac{1}{2} \times \text{Perimeter} \times \text{Apothem}$
* Step 1 (Perimeter): A pentagon has 5 sides. $5 \times 13.2 \text{ yd} = 66 \text{ yd}$.
* Step 2 (Area): $\frac{1}{2} \times 66 \times 3.5$
* Calculation: $33 \times 3.5 = 115.5$
* Result: $115.5 \text{ yd}^2$

3. Regular Hexagon
* Formula: Area = $\frac{1}{2} \times \text{Perimeter} \times \text{Apothem}$
* Step 1 (Perimeter): A hexagon has 6 sides. $6 \times 12 \text{ cm} = 72 \text{ cm}$.
* Step 2 (Area): $\frac{1}{2} \times 72 \times 5\sqrt{3}$
* Calculation: $36 \times 5\sqrt{3} = 180\sqrt{3}$
* Decimal Approximation: $180 \times 1.732 \approx 311.77$
* Result: $180\sqrt{3} \text{ cm}^2$ (or approx. $311.8 \text{ cm}^2$)

4. Triangle
* Formula: Area = $\frac{1}{2} \times \text{base} \times \text{height}$
* Calculation: $\frac{1}{2} \times 22 \text{ in} \times 16 \text{ in}$
* Simplify: $11 \times 16$
* Result: $176 \text{ in}^2$

5. Composite Figure (Rectangle + Semicircle)
* Part 1: Rectangle
* Area = $32 \text{ ft} \times 18 \text{ ft} = 576 \text{ ft}^2$
* Part 2: Semicircle
* Diameter = $18 \text{ ft}$, so Radius ($r$) = $9 \text{ ft}$.
* Area of full circle = $\pi \times 9^2 = 81\pi$.
* Area of semicircle = $\frac{81\pi}{2} = 40.5\pi \approx 127.23 \text{ ft}^2$.
* Total Area: $576 + 127.23$
* Result: $703.23 \text{ ft}^2$

6. Composite Figure (Triangle + Semicircle)
* Part 1: Triangle
* Base = $9 \text{ mm}$.
* Height = Total height ($12$) minus radius. Radius is half of $9$ ($4.5$). So, Height = $12 - 4.5 = 7.5 \text{ mm}$.
* Area = $\frac{1}{2} \times 9 \times 7.5 = 33.75 \text{ mm}^2$.
* Part 2: Semicircle
* Radius = $4.5 \text{ mm}$.
* Area = $\frac{\pi \times 4.5^2}{2} = \frac{20.25\pi}{2} \approx 31.81 \text{ mm}^2$.
* Total Area: $33.75 + 31.81$
* Result: $65.56 \text{ mm}^2$

7. Composite Figure (Rectangle + Triangle)
* Part 1: Rectangle
* Area = $10 \text{ km} \times 6 \text{ km} = 60 \text{ km}^2$.
* Part 2: Triangle
* Base = $6 \text{ km}$ (matches the rectangle side).
* Height = $4.8 \text{ km}$.
* Area = $\frac{1}{2} \times 6 \times 4.8 = 14.4 \text{ km}^2$.
* Total Area: $60 + 14.4$
* Result: $74.4 \text{ km}^2$

8. Composite Figure (Square + Triangle)
* Part 1: Square
* Area = $16 \text{ cm} \times 16 \text{ cm} = 256 \text{ cm}^2$.
* Part 2: Triangle
* Base = $16 \text{ cm}$ (matches the square side).
* Height = $8.5 \text{ cm}$.
* Area = $\frac{1}{2} \times 16 \times 8.5 = 8 \times 8.5 = 68 \text{ cm}^2$.
* Total Area: $256 + 68$
* Result: $324 \text{ cm}^2$

Final Answer:
1. 81.75 m²
2. 115.5 yd²
3. 180√3 cm² (approx. 311.8 cm²)
4. 176 in²
5. 703.23 ft²
6. 65.56 mm²
7. 74.4 km²
8. 324 cm²
Parent Tip: Review the logic above to help your child master the concept of area of composite figures worksheet 7th grade answers.
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