Find the area of composite figures worksheet for math practice.

To solve the problem of finding the area of the composite figures, we need to break each figure into simpler shapes (usually rectangles) and then calculate the area of each part before summing them up. Let's go through each figure step by step.

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Figure 1:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(5 \, \text{cm} \times 6 \, \text{cm}\).
2. A smaller rectangle with dimensions \(4 \, \text{cm} \times 4 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(5 \times 6 = 30 \, \text{cm}^2\).
- Area of the smaller rectangle: \(4 \times 4 = 16 \, \text{cm}^2\).
- Total area: \(30 + 16 = 46 \, \text{cm}^2\).

Answer for Figure 1: \(46 \, \text{cm}^2\).

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Figure 2:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(11 \, \text{cm} \times 4 \, \text{cm}\).
2. A smaller rectangle with dimensions \(2 \, \text{cm} \times 10 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(11 \times 4 = 44 \, \text{cm}^2\).
- Area of the smaller rectangle: \(2 \times 10 = 20 \, \text{cm}^2\).
- Total area: \(44 + 20 = 64 \, \text{cm}^2\).

Answer for Figure 2: \(64 \, \text{cm}^2\).

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Figure 3:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(8 \, \text{cm} \times 5 \, \text{cm}\).
2. A smaller rectangle with dimensions \(4 \, \text{cm} \times 8 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(8 \times 5 = 40 \, \text{cm}^2\).
- Area of the smaller rectangle: \(4 \times 8 = 32 \, \text{cm}^2\).
- Total area: \(40 + 32 = 72 \, \text{cm}^2\).

Answer for Figure 3: \(72 \, \text{cm}^2\).

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Figure 4:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(10 \, \text{cm} \times 12 \, \text{cm}\).
2. A smaller rectangle with dimensions \(3 \, \text{cm} \times 7 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(10 \times 12 = 120 \, \text{cm}^2\).
- Area of the smaller rectangle: \(3 \times 7 = 21 \, \text{cm}^2\).
- Total area: \(120 + 21 = 141 \, \text{cm}^2\).

Answer for Figure 4: \(141 \, \text{cm}^2\).

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Figure 5:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(17 \, \text{cm} \times 4 \, \text{cm}\).
2. A smaller rectangle with dimensions \(3 \, \text{cm} \times 16 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(17 \times 4 = 68 \, \text{cm}^2\).
- Area of the smaller rectangle: \(3 \times 16 = 48 \, \text{cm}^2\).
- Total area: \(68 + 48 = 116 \, \text{cm}^2\).

Answer for Figure 5: \(116 \, \text{cm}^2\).

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Figure 6:

The figure can be divided into two rectangles:
1. A rectangle with dimensions \(7.5 \, \text{cm} \times 8 \, \text{cm}\).
2. A smaller rectangle with dimensions \(1.5 \, \text{cm} \times 6 \, \text{cm}\).

Area Calculation:
- Area of the larger rectangle: \(7.5 \times 8 = 60 \, \text{cm}^2\).
- Area of the smaller rectangle: \(1.5 \times 6 = 9 \, \text{cm}^2\).
- Total area: \(60 + 9 = 69 \, \text{cm}^2\).

Answer for Figure 6: \(69 \, \text{cm}^2\).

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Final Answers:

1. \(46 \, \text{cm}^2\)
2. \(64 \, \text{cm}^2\)
3. \(72 \, \text{cm}^2\)
4. \(141 \, \text{cm}^2\)
5. \(116 \, \text{cm}^2\)
6. \(69 \, \text{cm}^2\)

Boxed Final Answer:
\[
\boxed{46, 64, 72, 141, 116, 69}
\]