To solve the problem of finding the perimeter of each parallelogram, we need to use the formula for the perimeter of a parallelogram. The perimeter \( P \) of a parallelogram is given by:
\[
P = 2 \times (\text{Base} + \text{Height})
\]
However, in this context, the "height" mentioned in the image refers to one of the sides of the parallelogram, not the perpendicular height. Therefore, the formula simplifies to:
\[
P = 2 \times (\text{Length of one pair of opposite sides} + \text{Length of the other pair of opposite sides})
\]
Let's solve each problem step by step.
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Problem 61:
- Base (one pair of opposite sides): 7 units
- Height (the other pair of opposite sides): 5 units
Using the formula:
\[
P = 2 \times (7 + 5) = 2 \times 12 = 24
\]
Answer for Problem 61: \(\boxed{24}\)
---
Problem 62:
- Base (one pair of opposite sides): 8 units
- Height (the other pair of opposite sides): 6 units
Using the formula:
\[
P = 2 \times (8 + 6) = 2 \times 14 = 28
\]
Answer for Problem 62: \(\boxed{28}\)
---
Problem 63:
- Base (one pair of opposite sides): 9 units
- Height (the other pair of opposite sides): 7 units
Using the formula:
\[
P = 2 \times (9 + 7) = 2 \times 16 = 32
\]
Answer for Problem 63: \(\boxed{32}\)
---
Problem 64:
- Base (one pair of opposite sides): 10 units
- Height (the other pair of opposite sides): 8 units
Using the formula:
\[
P = 2 \times (10 + 8) = 2 \times 18 = 36
\]
Answer for Problem 64: \(\boxed{36}\)
---
Problem 65:
- Base (one pair of opposite sides): 11 units
- Height (the other pair of opposite sides): 9 units
Using the formula:
\[
P = 2 \times (11 + 9) = 2 \times 20 = 40
\]
Answer for Problem 65: \(\boxed{40}\)
---
Problem 66:
- Base (one pair of opposite sides): 12 units
- Height (the other pair of opposite sides): 10 units
Using the formula:
\[
P = 2 \times (12 + 10) = 2 \times 22 = 44
\]
Answer for Problem 66: \(\boxed{44}\)
---
Problem 67:
- Base (one pair of opposite sides): 13 units
- Height (the other pair of opposite sides): 11 units
Using the formula:
\[
P = 2 \times (13 + 11) = 2 \times 24 = 48
\]
Answer for Problem 67: \(\boxed{48}\)
---
Problem 68:
- Base (one pair of opposite sides): 14 units
- Height (the other pair of opposite sides): 12 units
Using the formula:
\[
P = 2 \times (14 + 12) = 2 \times 26 = 52
\]
Answer for Problem 68: \(\boxed{52}\)
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Final Answers:
\[
\boxed{24, 28, 32, 36, 40, 44, 48, 52}
\]
Parent Tip: Review the logic above to help your child master the concept of area of parallelograms worksheet.
