Quadrilateral Worksheets | Area and perimeter worksheets ... - Free Printable

To solve the problem of finding the perimeter of each quadrilateral, we need to use the formula for the perimeter of a polygon, which is the sum of the lengths of all its sides. Let's go through each quadrilateral step by step.

1)

- Shape: Parallelogram
- Sides: 10 mm, 4 mm, 10 mm, 4 mm
- Perimeter: \( 10 + 4 + 10 + 4 = 28 \) mm

2)

- Shape: Square
- Side length: 5 yd
- Perimeter: \( 5 + 5 + 5 + 5 = 20 \) yd

3)

- Shape: Trapezoid
- Sides: 17 in, 9 in, 8 in, 2 in
- Perimeter: \( 17 + 9 + 8 + 2 = 36 \) in

4)

- Shape: Irregular quadrilateral
- Sides: 4 ft, 7 ft, 7 ft, 4 ft
- Perimeter: \( 4 + 7 + 7 + 4 = 22 \) ft

5)

- Shape: Square
- Side length: 6 cm
- Perimeter: \( 6 + 6 + 6 + 6 = 24 \) cm

6)

- Shape: Rhombus
- Side length: 4 yd
- Perimeter: \( 4 + 4 + 4 + 4 = 16 \) yd

7)

- Shape: Irregular pentagon (but only four sides are given)
- Sides: 5 ft, 7 ft, 3 ft, 4 ft
- Perimeter: \( 5 + 7 + 3 + 4 = 19 \) ft

8)

- Shape: Parallelogram
- Sides: 7 ft, 12 ft, 7 ft, 12 ft
- Perimeter: \( 7 + 12 + 7 + 12 = 38 \) ft

9)

- Shape: Rectangle
- Length: 9 m
- Width: 6 m
- Perimeter: \( 9 + 6 + 9 + 6 = 30 \) m

10)

- Shape: Rhombus
- Side length: 6 cm
- Perimeter: \( 6 + 6 + 6 + 6 = 24 \) cm

11)

- Shape: Rectangle
- Length: 14 yd
- Width: 8 yd
- Perimeter: \( 14 + 8 + 14 + 8 = 44 \) yd

12)

- Shape: Irregular quadrilateral
- Sides: 7 mm, 7 mm, 12 mm, 2.7 mm
- Perimeter: \( 7 + 7 + 12 + 2.7 = 28.7 \) mm

Final Answers:

1. \( \boxed{28} \) mm
2. \( \boxed{20} \) yd
3. \( \boxed{36} \) in
4. \( \boxed{22} \) ft
5. \( \boxed{24} \) cm
6. \( \boxed{16} \) yd
7. \( \boxed{19} \) ft
8. \( \boxed{38} \) ft
9. \( \boxed{30} \) m
10. \( \boxed{24} \) cm
11. \( \boxed{44} \) yd
12. \( \boxed{28.7} \) mm

Each perimeter is calculated by summing the lengths of all the sides of the respective quadrilateral.