Let's solve each triangle's area using the formula:
$$
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
$$
We’ll go through each triangle one by one.
---
Problem 1
- Base = 18 cm
- Height = 12 cm
$$
\text{Area} = \frac{1}{2} \times 18 \times 12 = 9 \times 12 = 108\ \text{cm}^2
$$
✔ Answer: 108 cm²
---
Problem 2
- Base = 33 in
- Height = 22 in
$$
\text{Area} = \frac{1}{2} \times 33 \times 22 = \frac{726}{2} = 363\ \text{in}^2
$$
✔ Answer: 363 in²
---
Problem 3
- Base = 6 m
- Height = 9 m
$$
\text{Area} = \frac{1}{2} \times 6 \times 9 = 3 \times 9 = 27\ \text{m}^2
$$
✔ Answer: 27 m²
---
Problem 4
- Base = 11 cm
- Height = 13 cm
Note: The height is drawn from the top vertex to the base, so it's perpendicular. Even though the triangle is upside down, the formula still applies.
$$
\text{Area} = \frac{1}{2} \times 11 \times 13 = \frac{143}{2} = 71.5\ \text{cm}^2
$$
✔ Answer: 71.5 cm²
---
Problem 5
- Base = 7 yd
- Height = 5 yd
This is a right triangle, and the two legs are the base and height.
$$
\text{Area} = \frac{1}{2} \times 7 \times 5 = \frac{35}{2} = 17.5\ \text{yd}^2
$$
✔ Answer: 17.5 yd²
---
Problem 6
- Base = 9 mm
- Height = 4 mm
Right triangle with legs 9 mm and 4 mm.
$$
\text{Area} = \frac{1}{2} \times 9 \times 4 = \frac{36}{2} = 18\ \text{mm}^2
$$
✔ Answer: 18 mm²
---
Problem 7
- Base = 44 mm
- Height = 28 mm
$$
\text{Area} = \frac{1}{2} \times 44 \times 28 = 22 \times 28 = 616\ \text{mm}^2
$$
✔ Answer: 616 mm²
---
Problem 8
- Base = 15 in
- Height = 8 in
$$
\text{Area} = \frac{1}{2} \times 15 \times 8 = \frac{120}{2} = 60\ \text{in}^2
$$
✔ Answer: 60 in²
---
✔ Final Answers:
1.
108 cm²
2.
363 in²
3.
27 m²
4.
71.5 cm²
5.
17.5 yd²
6.
18 mm²
7.
616 mm²
8.
60 in²
Let me know if you'd like this formatted as a completed worksheet!
Parent Tip: Review the logic above to help your child master the concept of area of triangle and parallelogram worksheet.
