To solve the problem, we need to calculate the areas of various geometric shapes provided in the image. Let's go through each shape step by step.
1. Parallelogram
-
Formula: \( \text{Area} = \text{base} \times \text{height} \)
-
Given: Base = 6 cm, Height = 5 cm
-
Calculation:
\[
\text{Area} = 6 \, \text{cm} \times 5 \, \text{cm} = 30 \, \text{cm}^2
\]
2. Trapezoid
-
Formula: \( \text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{height} \)
-
Given: Base₁ = 5 cm, Base₂ = 6 cm, Height = 2 cm
-
Calculation:
\[
\text{Area} = \frac{1}{2} \times (5 \, \text{cm} + 6 \, \text{cm}) \times 2 \, \text{cm} = \frac{1}{2} \times 11 \, \text{cm} \times 2 \, \text{cm} = 11 \, \text{cm}^2
\]
3. Rectangle
-
Formula: \( \text{Area} = \text{length} \times \text{width} \)
-
Given: Length = 8 cm, Width = 5 cm
-
Calculation:
\[
\text{Area} = 8 \, \text{cm} \times 5 \, \text{cm} = 40 \, \text{cm}^2
\]
4. Triangle
-
Formula: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)
-
Given: Base = 20 m, Height = 5 m
-
Calculation:
\[
\text{Area} = \frac{1}{2} \times 20 \, \text{m} \times 5 \, \text{m} = 50 \, \text{m}^2
\]
5. Parallelogram
-
Formula: \( \text{Area} = \text{base} \times \text{height} \)
-
Given: Base = 8 cm, Height = 4 cm
-
Calculation:
\[
\text{Area} = 8 \, \text{cm} \times 4 \, \text{cm} = 32 \, \text{cm}^2
\]
6. Triangle
-
Formula: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)
-
Given: Base = 8 cm, Height = 4 cm
-
Calculation:
\[
\text{Area} = \frac{1}{2} \times 8 \, \text{cm} \times 4 \, \text{cm} = 16 \, \text{cm}^2
\]
7. Rectangle
-
Formula: \( \text{Area} = \text{length} \times \text{width} \)
-
Given: Length = 10 in, Width = 4 in
-
Calculation:
\[
\text{Area} = 10 \, \text{in} \times 4 \, \text{in} = 40 \, \text{in}^2
\]
8. Triangle
-
Formula: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)
-
Given: Base = 9 cm, Height = 4 cm
-
Calculation:
\[
\text{Area} = \frac{1}{2} \times 9 \, \text{cm} \times 4 \, \text{cm} = 18 \, \text{cm}^2
\]
9. Trapezoid
-
Formula: \( \text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{height} \)
-
Given: Base₁ = 9 m, Base₂ = 7 m, Height = 6 m
-
Calculation:
\[
\text{Area} = \frac{1}{2} \times (9 \, \text{m} + 7 \, \text{m}) \times 6 \, \text{m} = \frac{1}{2} \times 16 \, \text{m} \times 6 \, \text{m} = 48 \, \text{m}^2
\]
Final Answers
\[
\boxed{
\begin{array}{ll}
1. & 30 \, \text{cm}^2 \\
2. & 11 \, \text{cm}^2 \\
3. & 40 \, \text{cm}^2 \\
4. & 50 \, \text{m}^2 \\
5. & 32 \, \text{cm}^2 \\
6. & 16 \, \text{cm}^2 \\
7. & 40 \, \text{in}^2 \\
8. & 18 \, \text{cm}^2 \\
9. & 48 \, \text{m}^2 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of area of triangle rectangle parallelogram trapezoid worksheet.