To solve the problem of finding the area of each parallelogram, we use the formula for the area of a parallelogram:
\[
\text{Area} = \text{base} \times \text{height}
\]
We will calculate the area for each parallelogram step by step.
---
1)
- Base = 6 ft
- Height = 4 ft
\[
\text{Area} = 6 \, \text{ft} \times 4 \, \text{ft} = 24 \, \text{ft}^2
\]
Answer: \( 24 \, \text{ft}^2 \)
---
2)
- Base = 9 yd
- Height = 5 yd
\[
\text{Area} = 9 \, \text{yd} \times 5 \, \text{yd} = 45 \, \text{yd}^2
\]
Answer: \( 45 \, \text{yd}^2 \)
---
3)
- Base = 7 in
- Height = 3 in
\[
\text{Area} = 7 \, \text{in} \times 3 \, \text{in} = 21 \, \text{in}^2
\]
Answer: \( 21 \, \text{in}^2 \)
---
4)
- Base = 9 in
- Height = 7 in
\[
\text{Area} = 9 \, \text{in} \times 7 \, \text{in} = 63 \, \text{in}^2
\]
Answer: \( 63 \, \text{in}^2 \)
---
5)
- Base = 10 ft
- Height = 2 ft
\[
\text{Area} = 10 \, \text{ft} \times 2 \, \text{ft} = 20 \, \text{ft}^2
\]
Answer: \( 20 \, \text{ft}^2 \)
---
6)
- Base = 6 yd
- Height = 8 yd
\[
\text{Area} = 6 \, \text{yd} \times 8 \, \text{yd} = 48 \, \text{yd}^2
\]
Answer: \( 48 \, \text{yd}^2 \)
---
7)
- Base = 12 yd
- Height = 8 yd
\[
\text{Area} = 12 \, \text{yd} \times 8 \, \text{yd} = 96 \, \text{yd}^2
\]
Answer: \( 96 \, \text{yd}^2 \)
---
8)
- Base = 7 in
- Height = 6 in
\[
\text{Area} = 7 \, \text{in} \times 6 \, \text{in} = 42 \, \text{in}^2
\]
Answer: \( 42 \, \text{in}^2 \)
---
9)
- Base = 4 ft
- Height = 9 ft
\[
\text{Area} = 4 \, \text{ft} \times 9 \, \text{ft} = 36 \, \text{ft}^2
\]
Answer: \( 36 \, \text{ft}^2 \)
---
Final Answers:
1. \( 24 \, \text{ft}^2 \)
2. \( 45 \, \text{yd}^2 \)
3. \( 21 \, \text{in}^2 \)
4. \( 63 \, \text{in}^2 \)
5. \( 20 \, \text{ft}^2 \)
6. \( 48 \, \text{yd}^2 \)
7. \( 96 \, \text{yd}^2 \)
8. \( 42 \, \text{in}^2 \)
9. \( 36 \, \text{ft}^2 \)
\boxed{24, 45, 21, 63, 20, 48, 96, 42, 36}
Parent Tip: Review the logic above to help your child master the concept of area of triangle rectangle parallelogram trapezoid worksheet.
