Let’s solve each problem one by one. We’ll use the correct area formulas for triangles, parallelograms, and trapezoids.
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Problem 1: Triangle
We are given a triangle with base = 14 and height = 5.25 (the perpendicular height from the base to the opposite vertex).
Area of triangle = (base × height) ÷ 2
= (14 × 5.25) ÷ 2
First, 14 × 5.25:
14 × 5 = 70
14 × 0.25 = 3.5
So 70 + 3.5 = 73.5
Now divide by 2: 73.5 ÷ 2 =
36.75
✔ Area = 36.75
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Problem 2: Parallelogram
Base = 6, height = 3 (perpendicular distance between bases)
Area of parallelogram = base × height
= 6 × 3 =
18
✔ Area = 18
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Problem 3: Parallelogram
Base = 5, height = 2 (note: the side labeled 3.01 is slanted — not the height! The height is the perpendicular line inside, which is 2.)
Area = base × height = 5 × 2 =
10
✔ Area = 10
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Problem 4: Parallelogram
Base = 5, height = 2 (again, 4.65 is the slanted side — ignore it for area)
Area = 5 × 2 =
10
✔ Area = 10
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Problem 5: Trapezoid
Top base = 6, bottom base = 13, height = 2 (the perpendicular distance between the two parallel sides)
Area of trapezoid = [(top + bottom) × height] ÷ 2
= [(6 + 13) × 2] ÷ 2
= [19 × 2] ÷ 2
= 38 ÷ 2 =
19
✔ Area = 19
*(Note: The numbers 3.30 and 4.36 are the non-parallel sides — we don’t need them for area.)*
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Problem 6: Parallelogram
Base = 11, height = 4 (again, 5.27 is the slanted side — not used for area)
Area = 11 × 4 =
44
✔ Area = 44
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Final Answer:
1. 36.75
2. 18
3. 10
4. 10
5. 19
6. 44
Parent Tip: Review the logic above to help your child master the concept of area of triangles and trapezoids worksheet.
