Grade 5 Area and Perimeter Worksheets | Free Math Worksheets - Free Printable
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Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
To solve the problems related to area and perimeter for each shape, we will use the following formulas:
1. Rectangle:
- Area = Length × Width
- Perimeter = 2 × (Length + Width)
2. Triangle:
- Area = 0.5 × Base × Height
3. Square:
- Area = Side × Side
- Perimeter = 4 × Side
---
#### 1. Rectangle (10m × 4m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 10 \, \text{m} \times 4 \, \text{m} = 40 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (10 \, \text{m} + 4 \, \text{m}) = 2 \times 14 \, \text{m} = 28 \, \text{m}
\]
#### 2. Triangle (Base = 9m, Height = 6m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 9 \, \text{m} \times 6 \, \text{m} = 0.5 \times 54 \, \text{m}^2 = 27 \, \text{m}^2
\]
#### 3. Square (Side = 7m)
- Area:
\[
\text{Area} = \text{Side} \times \text{Side} = 7 \, \text{m} \times 7 \, \text{m} = 49 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 4 \times \text{Side} = 4 \times 7 \, \text{m} = 28 \, \text{m}
\]
#### 4. Triangle (Base = 8m, Height = 12m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 8 \, \text{m} \times 12 \, \text{m} = 0.5 \times 96 \, \text{m}^2 = 48 \, \text{m}^2
\]
#### 5. Rectangle (20m × 7m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 20 \, \text{m} \times 7 \, \text{m} = 140 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (20 \, \text{m} + 7 \, \text{m}) = 2 \times 27 \, \text{m} = 54 \, \text{m}
\]
#### 6. Rectangle (11m × 8m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 11 \, \text{m} \times 8 \, \text{m} = 88 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (11 \, \text{m} + 8 \, \text{m}) = 2 \times 19 \, \text{m} = 38 \, \text{m}
\]
---
1. Rectangle (10m × 4m):
- Area: \( \boxed{40 \, \text{m}^2} \)
- Perimeter: \( \boxed{28 \, \text{m}} \)
2. Triangle (Base = 9m, Height = 6m):
- Area: \( \boxed{27 \, \text{m}^2} \)
3. Square (Side = 7m):
- Area: \( \boxed{49 \, \text{m}^2} \)
- Perimeter: \( \boxed{28 \, \text{m}} \)
4. Triangle (Base = 8m, Height = 12m):
- Area: \( \boxed{48 \, \text{m}^2} \)
5. Rectangle (20m × 7m):
- Area: \( \boxed{140 \, \text{m}^2} \)
- Perimeter: \( \boxed{54 \, \text{m}} \)
6. Rectangle (11m × 8m):
- Area: \( \boxed{88 \, \text{m}^2} \)
- Perimeter: \( \boxed{38 \, \text{m}} \)
---
\[
\boxed{
\begin{array}{ll}
1. & \text{Area: } 40 \, \text{m}^2, \text{ Perimeter: } 28 \, \text{m} \\
2. & \text{Area: } 27 \, \text{m}^2 \\
3. & \text{Area: } 49 \, \text{m}^2, \text{ Perimeter: } 28 \, \text{m} \\
4. & \text{Area: } 48 \, \text{m}^2 \\
5. & \text{Area: } 140 \, \text{m}^2, \text{ Perimeter: } 54 \, \text{m} \\
6. & \text{Area: } 88 \, \text{m}^2, \text{ Perimeter: } 38 \, \text{m} \\
\end{array}
}
\]
Formulas:
1. Rectangle:
- Area = Length × Width
- Perimeter = 2 × (Length + Width)
2. Triangle:
- Area = 0.5 × Base × Height
3. Square:
- Area = Side × Side
- Perimeter = 4 × Side
---
Solutions:
#### 1. Rectangle (10m × 4m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 10 \, \text{m} \times 4 \, \text{m} = 40 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (10 \, \text{m} + 4 \, \text{m}) = 2 \times 14 \, \text{m} = 28 \, \text{m}
\]
#### 2. Triangle (Base = 9m, Height = 6m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 9 \, \text{m} \times 6 \, \text{m} = 0.5 \times 54 \, \text{m}^2 = 27 \, \text{m}^2
\]
#### 3. Square (Side = 7m)
- Area:
\[
\text{Area} = \text{Side} \times \text{Side} = 7 \, \text{m} \times 7 \, \text{m} = 49 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 4 \times \text{Side} = 4 \times 7 \, \text{m} = 28 \, \text{m}
\]
#### 4. Triangle (Base = 8m, Height = 12m)
- Area:
\[
\text{Area} = 0.5 \times \text{Base} \times \text{Height} = 0.5 \times 8 \, \text{m} \times 12 \, \text{m} = 0.5 \times 96 \, \text{m}^2 = 48 \, \text{m}^2
\]
#### 5. Rectangle (20m × 7m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 20 \, \text{m} \times 7 \, \text{m} = 140 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (20 \, \text{m} + 7 \, \text{m}) = 2 \times 27 \, \text{m} = 54 \, \text{m}
\]
#### 6. Rectangle (11m × 8m)
- Area:
\[
\text{Area} = \text{Length} \times \text{Width} = 11 \, \text{m} \times 8 \, \text{m} = 88 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (11 \, \text{m} + 8 \, \text{m}) = 2 \times 19 \, \text{m} = 38 \, \text{m}
\]
---
Final Answers:
1. Rectangle (10m × 4m):
- Area: \( \boxed{40 \, \text{m}^2} \)
- Perimeter: \( \boxed{28 \, \text{m}} \)
2. Triangle (Base = 9m, Height = 6m):
- Area: \( \boxed{27 \, \text{m}^2} \)
3. Square (Side = 7m):
- Area: \( \boxed{49 \, \text{m}^2} \)
- Perimeter: \( \boxed{28 \, \text{m}} \)
4. Triangle (Base = 8m, Height = 12m):
- Area: \( \boxed{48 \, \text{m}^2} \)
5. Rectangle (20m × 7m):
- Area: \( \boxed{140 \, \text{m}^2} \)
- Perimeter: \( \boxed{54 \, \text{m}} \)
6. Rectangle (11m × 8m):
- Area: \( \boxed{88 \, \text{m}^2} \)
- Perimeter: \( \boxed{38 \, \text{m}} \)
---
Boxed Final Answers:
\[
\boxed{
\begin{array}{ll}
1. & \text{Area: } 40 \, \text{m}^2, \text{ Perimeter: } 28 \, \text{m} \\
2. & \text{Area: } 27 \, \text{m}^2 \\
3. & \text{Area: } 49 \, \text{m}^2, \text{ Perimeter: } 28 \, \text{m} \\
4. & \text{Area: } 48 \, \text{m}^2 \\
5. & \text{Area: } 140 \, \text{m}^2, \text{ Perimeter: } 54 \, \text{m} \\
6. & \text{Area: } 88 \, \text{m}^2, \text{ Perimeter: } 38 \, \text{m} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of area perimeter worksheet.