Area Word Problems online exercise for - Free Printable

Let's solve each of these area word problems step by step, with clear explanations.

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1. Table Area

Given:
- Length = 110 cm
- Width = 55 cm

a) Area in square centimetres:
Area = length × width
= 110 cm × 55 cm
= 6,050 cm²

Convert to square metres:
We know:
1 m = 100 cm → 1 m² = 10,000 cm²
So:
6,050 cm² ÷ 10,000 = 0.605 m²

✔ Answer:
- Area per table = 6,050 cm² or 0.605 m²

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a) Total area for 16 tables:
Total area = 16 × 0.605 m² = 9.68 m²

✔ Answer:
- Total area = 9.68 m²

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2. Artificial Football Pitch

Given:
- Pitch dimensions: 92 m long, 41 m wide
- Grass border: 2 m wide all around

This means the entire artificial surface includes:
- The pitch + a 2 m border on all sides

So, total length = 92 + 2 + 2 = 96 m
Total width = 41 + 2 + 2 = 45 m

Area of whole artificial surface:
= 96 m × 45 m = 4,320 m²

✔ Answer:
- Area = 4,320 m²

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a) Cost at £38 per m²:
Cost = 4,320 × £38 = £164,160

✔ Answer:
- Cost = £164,160

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3. Bedroom Wall Area

Given:
- Length = 3.5 m
- Width = 2.4 m
- Height = 2.1 m
- Ignore door and window

We need the total wall area (not floor or ceiling).
A room has 4 walls:

- Two walls: 3.5 m × 2.1 m (length × height)
- Two walls: 2.4 m × 2.1 m (width × height)

Area of two longer walls:
2 × (3.5 × 2.1) = 2 × 7.35 = 14.7 m²

Area of two shorter walls:
2 × (2.4 × 2.1) = 2 × 5.04 = 10.08 m²

Total wall area = 14.7 + 10.08 = 24.78 m²

✔ Answer:
- Total wall area = 24.78 m²

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a) Paint needed (2 coats, 1 tin covers 20 m²):

Total area to paint = 24.78 m² × 2 = 49.56 m²

Tins needed = 49.56 ÷ 20 = 2.478 tins

Since you can't buy part of a tin, round up to next whole number:
→ 3 tins

✔ Answer:
- 3 tins are needed

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4. Window Area

Given:
- Width = 1.7 m
- Height = 85 cm = 0.85 m (convert to metres)

Area = 1.7 × 0.85 = 1.445 m²

✔ Answer:
- Area of window = 1.445 m²

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a) Curtains need 3 times the area:
3 × 1.445 = 4.335 m²

✔ Answer:
- Material needed = 4.335 m²

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5. Car Park Space

Given:
- Each car needs 8 m²
- 62 cars

Total area needed = 62 × 8 = 496 m²

Now, we need dimensions for the car park (possible rectangle).

There are many possible dimensions, but common ones could be:

- 16 m × 31 m = 496 m²
- 8 m × 62 m = 496 m²
- 32 m × 15.5 m = 496 m²

But typically, parking spaces are arranged in rows. A reasonable layout might be:

- 8 m wide × 62 m long (if one row)
- Or 2 rows of 31 cars: 16 m wide × 31 m long

✔ Answer:
- Possible dimensions: e.g., 16 m × 31 m (or any pair that multiplies to 496 m²)

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a) What else needs to be taken into account?

Other factors include:
- Access roads between rows
- Turning space for vehicles
- Pedestrian walkways
- Drainage and lighting
- Safety margins
- Entrance/exit points
- Disabled parking spots
- Space for signage

✔ Answer:
- Access lanes, turning space, entrances/exits, pedestrian paths, and safety zones must also be considered.

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✔ Final Answers Summary:

#### 1.
- Area per table: 6,050 cm² or 0.605 m²
- Total for 16 tables: 9.68 m²

#### 2.
- Total artificial surface: 4,320 m²
- Cost: £164,160

#### 3.
- Wall area: 24.78 m²
- Tins of paint: 3 tins

#### 4.
- Window area: 1.445 m²
- Curtain material: 4.335 m²

#### 5.
- Area needed: 496 m², e.g., 16 m × 31 m
- Other considerations: Access roads, turning space, entrances, pedestrian areas, etc.

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