Math worksheet for calculating area and perimeter of rectangles with a baseball-themed joke.

Problem Overview:

The task involves calculating the perimeter and area of six rectangles. The formulas provided are:
- Area (A): \( A = \text{length} \times \text{width} \)
- Perimeter (P): \( P = 2 \times (\text{length} + \text{width}) \)

We will solve each rectangle step by step.

---

Rectangle 1:

#### Dimensions:
- Length = 11 inches
- Width = 8 inches

#### Area:
\[
A = \text{length} \times \text{width} = 11 \times 8 = 88 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (11 + 8) = 2 \times 19 = 38 \, \text{inches}
\]

#### Answer:
- Area: 88 square inches
- Perimeter: 38 inches

---

Rectangle 2:

#### Dimensions:
- Length = 10 inches
- Width = 7 inches

#### Area:
\[
A = \text{length} \times \text{width} = 10 \times 7 = 70 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (10 + 7) = 2 \times 17 = 34 \, \text{inches}
\]

#### Answer:
- Area: 70 square inches
- Perimeter: 34 inches

---

Rectangle 3:

#### Dimensions:
- Length = 10 inches
- Width = 8 inches

#### Area:
\[
A = \text{length} \times \text{width} = 10 \times 8 = 80 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (10 + 8) = 2 \times 18 = 36 \, \text{inches}
\]

#### Answer:
- Area: 80 square inches
- Perimeter: 36 inches

---

Rectangle 4:

#### Dimensions:
- Length = 9 inches
- Width = 6 inches

#### Area:
\[
A = \text{length} \times \text{width} = 9 \times 6 = 54 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (9 + 6) = 2 \times 15 = 30 \, \text{inches}
\]

#### Answer:
- Area: 54 square inches
- Perimeter: 30 inches

---

Rectangle 5:

#### Dimensions:
- Length = 9 inches
- Width = 7 inches

#### Area:
\[
A = \text{length} \times \text{width} = 9 \times 7 = 63 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (9 + 7) = 2 \times 16 = 32 \, \text{inches}
\]

#### Answer:
- Area: 63 square inches
- Perimeter: 32 inches

---

Rectangle 6:

#### Dimensions:
- Length = 10 inches
- Width = 10 inches (This is a square)

#### Area:
\[
A = \text{length} \times \text{width} = 10 \times 10 = 100 \, \text{square inches}
\]

#### Perimeter:
\[
P = 2 \times (\text{length} + \text{width}) = 2 \times (10 + 10) = 2 \times 20 = 40 \, \text{inches}
\]

#### Answer:
- Area: 100 square inches
- Perimeter: 40 inches

---

Final Answers:

1. Area: 88 square inches, Perimeter: 38 inches
2. Area: 70 square inches, Perimeter: 34 inches
3. Area: 80 square inches, Perimeter: 36 inches
4. Area: 54 square inches, Perimeter: 30 inches
5. Area: 63 square inches, Perimeter: 32 inches
6. Area: 100 square inches, Perimeter: 40 inches

Boxed Final Answer:

\[
\boxed{
\begin{array}{ll}
1. & \text{Area: } 88 \, \text{sq in}, \, \text{Perimeter: } 38 \, \text{in} \\
2. & \text{Area: } 70 \, \text{sq in}, \, \text{Perimeter: } 34 \, \text{in} \\
3. & \text{Area: } 80 \, \text{sq in}, \, \text{Perimeter: } 36 \, \text{in} \\
4. & \text{Area: } 54 \, \text{sq in}, \, \text{Perimeter: } 30 \, \text{in} \\
5. & \text{Area: } 63 \, \text{sq in}, \, \text{Perimeter: } 32 \, \text{in} \\
6. & \text{Area: } 100 \, \text{sq in}, \, \text{Perimeter: } 40 \, \text{in} \\
\end{array}
}
\]