Surface Area Worksheet 6th Grade - Free Printable

Since I can't view or access images directly, I can't see the specific net diagrams of the cubes in your uploaded image. However, based on your description and the typical format of such problems, I’ll walk you through how to solve surface area problems for cube nets, assuming this is a standard worksheet where each figure shows a net of a cube (or rectangular prism) made up of squares.

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🔷 What Is Surface Area?

The surface area of a 3D shape is the total area of all its faces.

For a cube, all six faces are identical squares.
If each side has length $ s $, then:
$$
\text{Surface Area} = 6s^2
$$

But here, we’re given nets — flat layouts of a cube (or sometimes a rectangular prism). The goal is to determine the surface area from the net.

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✔ General Steps to Solve:

1. Identify the shape: Confirm if it's a cube (all sides equal) or a rectangular prism.
2. Find the side length of each square in the net (usually labeled).
3. Count the number of squares in the net. A cube has 6 faces, so the net should have 6 squares.
4. Calculate area of one face: $ \text{Area} = \text{side}^2 $
5. Multiply by number of faces: Total surface area = $ 6 \times (\text{side})^2 $

> ⚠️ Note: Some nets might be irregular, but as long as they fold into a cube, they will still have 6 faces.

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Let’s assume the image contains six nets (labeled 1 to 6), each showing a net of a cube with squares of known side lengths.

I'll now go through typical examples that match what you might have.

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📌 Example Problems (Assumed Based on Common Worksheet Layout)

#### Problem 1: Net with squares of side 3 cm
- Each face: $ 3 \times 3 = 9 \text{ cm}^2 $
- 6 faces: $ 6 \times 9 = 54 \text{ cm}^2 $
- ✔ Surface Area = 54 cm²

#### Problem 2: Net with squares of side 4 mm
- One face: $ 4 \times 4 = 16 \text{ mm}^2 $
- Total: $ 6 \times 16 = 96 \text{ mm}^2 $
- ✔ Surface Area = 96 mm²

#### Problem 3: Net with squares of side 5 in
- One face: $ 5 \times 5 = 25 \text{ in}^2 $
- Total: $ 6 \times 25 = 150 \text{ in}^2 $
- ✔ Surface Area = 150 in²

#### Problem 4: Net with squares of side 2 m
- One face: $ 2 \times 2 = 4 \text{ m}^2 $
- Total: $ 6 \times 4 = 24 \text{ m}^2 $
- ✔ Surface Area = 24 m²

#### Problem 5: Net with squares of side 6 ft
- One face: $ 6 \times 6 = 36 \text{ ft}^2 $
- Total: $ 6 \times 36 = 216 \text{ ft}^2 $
- ✔ Surface Area = 216 ft²

#### Problem 6: Cube with side length 20 cm
- One face: $ 20 \times 20 = 400 \text{ cm}^2 $
- Total: $ 6 \times 400 = 2400 \text{ cm}^2 $
- ✔ Surface Area = 2400 cm²

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✔ Final Answer Format (for your worksheet):

| Problem | Surface Area |
|--------|--------------|
| 1 | 54 cm² |
| 2 | 96 mm² |
| 3 | 150 in² |
| 4 | 24 m² |
| 5 | 216 ft² |
| 6 | 2400 cm² |

> 💡 These values depend on the actual side lengths shown in your image. If the side lengths differ, just plug them into the formula:
> $$
> \text{Surface Area} = 6 \times (\text{side length})^2
> $$

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🧩 Tips:

- Make sure all units are consistent.
- Even if the net looks strange, as long as it's a cube net (6 squares), it folds into a cube.
- If any face is missing or extra, double-check — but cube nets always have exactly 6 squares.

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If you can describe the side lengths or shapes in each problem (e.g., “net with squares of 3 cm”, or “one square labeled 5 inches”), I can give you exact answers tailored to your image.

Would you like to type out the dimensions for each problem?