Area and Perimeter Worksheet for Grade 4 Students - Practice Calculating Area and Perimeter of Rectangles and Squares.

Problem Overview:

The task is to calculate the area and perimeter of each given rectangle or square. The formulas provided are:

- Area: \( \text{Area} = \text{length} \times \text{breadth} \)
- Perimeter: \( \text{Perimeter} = 2 \times (\text{length} + \text{breadth}) \)

We will solve for each figure step by step.

---

Figure 1:

- Dimensions: Length = 6 cm, Breadth = 4 cm
- Area:
\[
\text{Area} = \text{length} \times \text{breadth} = 6 \, \text{cm} \times 4 \, \text{cm} = 24 \, \text{sq.cm}
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{breadth}) = 2 \times (6 \, \text{cm} + 4 \, \text{cm}) = 2 \times 10 \, \text{cm} = 20 \, \text{cm}
\]

Answers for Figure 1:
\[
\text{A} = 24 \, \text{sq.cm}, \quad \text{P} = 20 \, \text{cm}
\]

---

Figure 2:

- Dimensions: Side = 3 cm (since it is a square)
- Area:
\[
\text{Area} = \text{side} \times \text{side} = 3 \, \text{cm} \times 3 \, \text{cm} = 9 \, \text{sq.cm}
\]
- Perimeter:
\[
\text{Perimeter} = 4 \times \text{side} = 4 \times 3 \, \text{cm} = 12 \, \text{cm}
\]

Answers for Figure 2:
\[
\text{A} = 9 \, \text{sq.cm}, \quad \text{P} = 12 \, \text{cm}
\]

---

Figure 3:

- Dimensions: Length = 8 cm, Breadth = 3 cm
- Area:
\[
\text{Area} = \text{length} \times \text{breadth} = 8 \, \text{cm} \times 3 \, \text{cm} = 24 \, \text{sq.cm}
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{breadth}) = 2 \times (8 \, \text{cm} + 3 \, \text{cm}) = 2 \times 11 \, \text{cm} = 22 \, \text{cm}
\]

Answers for Figure 3:
\[
\text{A} = 24 \, \text{sq.cm}, \quad \text{P} = 22 \, \text{cm}
\]

---

Figure 4:

- Dimensions: Side = 4 cm (since it is a square)
- Area:
\[
\text{Area} = \text{side} \times \text{side} = 4 \, \text{cm} \times 4 \, \text{cm} = 16 \, \text{sq.cm}
\]
- Perimeter:
\[
\text{Perimeter} = 4 \times \text{side} = 4 \times 4 \, \text{cm} = 16 \, \text{cm}
\]

Answers for Figure 4:
\[
\text{A} = 16 \, \text{sq.cm}, \quad \text{P} = 16 \, \text{cm}
\]

---

Figure 5:

- Dimensions: Length = 5 cm, Breadth = 3 cm
- Area:
\[
\text{Area} = \text{length} \times \text{breadth} = 5 \, \text{cm} \times 3 \, \text{cm} = 15 \, \text{sq.cm}
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{breadth}) = 2 \times (5 \, \text{cm} + 3 \, \text{cm}) = 2 \times 8 \, \text{cm} = 16 \, \text{cm}
\]

Answers for Figure 5:
\[
\text{A} = 15 \, \text{sq.cm}, \quad \text{P} = 16 \, \text{cm}
\]

---

Final Answers:

1. \( \text{A} = 24 \, \text{sq.cm}, \, \text{P} = 20 \, \text{cm} \)
2. \( \text{A} = 9 \, \text{sq.cm}, \, \text{P} = 12 \, \text{cm} \)
3. \( \text{A} = 24 \, \text{sq.cm}, \, \text{P} = 22 \, \text{cm} \)
4. \( \text{A} = 16 \, \text{sq.cm}, \, \text{P} = 16 \, \text{cm} \)
5. \( \text{A} = 15 \, \text{sq.cm}, \, \text{P} = 16 \, \text{cm} \)

\boxed{
\begin{array}{ll}
1) & \text{A} = 24 \, \text{sq.cm}, \, \text{P} = 20 \, \text{cm} \\
2) & \text{A} = 9 \, \text{sq.cm}, \, \text{P} = 12 \, \text{cm} \\
3) & \text{A} = 24 \, \text{sq.cm}, \, \text{P} = 22 \, \text{cm} \\
4) & \text{A} = 16 \, \text{sq.cm}, \, \text{P} = 16 \, \text{cm} \\
5) & \text{A} = 15 \, \text{sq.cm}, \, \text{P} = 16 \, \text{cm} \\
\end{array}
}