Let’s solve each rectangle problem one by one. For every rectangle, we need to find:
-
Area = length × width
-
Perimeter = 2 × (length + width)
We’ll go in order from top left to bottom right.
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Problem 1:
Dimensions: 5 ft (height), 3 ft (width)
→ Area = 5 × 3 =
15 sq ft
→ Perimeter = 2 × (5 + 3) = 2 × 8 =
16 ft
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Problem 2:
Dimensions: 7 m (length), 4 m (width)
→ Area = 7 × 4 =
28 sq m
→ Perimeter = 2 × (7 + 4) = 2 × 11 =
22 m
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Problem 3:
Dimensions: 9 cm (height), 2 cm (width)
→ Area = 9 × 2 =
18 sq cm
→ Perimeter = 2 × (9 + 2) = 2 × 11 =
22 cm
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Problem 4:
Dimensions: 6 in (length), 3 in (width)
→ Area = 6 × 3 =
18 sq in
→ Perimeter = 2 × (6 + 3) = 2 × 9 =
18 in
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Problem 5:
Dimensions: 8 mm (height), 3 mm (width)
→ Area = 8 × 3 =
24 sq mm
→ Perimeter = 2 × (8 + 3) = 2 × 11 =
22 mm
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Problem 6:
Dimensions: 5 yd (side — it’s a square!)
→ Area = 5 × 5 =
25 sq yd
→ Perimeter = 2 × (5 + 5) = 2 × 10 =
20 yd
*(Or since it’s a square: 4 × 5 = 20 yd)*
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Problem 7:
Dimensions: 4 m (length), 2 m (width)
→ Area = 4 × 2 =
8 sq m
→ Perimeter = 2 × (4 + 2) = 2 × 6 =
12 m
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Problem 8:
Dimensions: 7 ft (height), 3 ft (width)
→ Area = 7 × 3 =
21 sq ft
→ Perimeter = 2 × (7 + 3) = 2 × 10 =
20 ft
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Problem 9:
Dimensions: 6 in (height), 2 in (width)
→ Area = 6 × 2 =
12 sq in
→ Perimeter = 2 × (6 + 2) = 2 × 8 =
16 in
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Final Answer:
1. Area: 15 sq ft, Perimeter: 16 ft
2. Area: 28 sq m, Perimeter: 22 m
3. Area: 18 sq cm, Perimeter: 22 cm
4. Area: 18 sq in, Perimeter: 18 in
5. Area: 24 sq mm, Perimeter: 22 mm
6. Area: 25 sq yd, Perimeter: 20 yd
7. Area: 8 sq m, Perimeter: 12 m
8. Area: 21 sq ft, Perimeter: 20 ft
9. Area: 12 sq in, Perimeter: 16 in
Parent Tip: Review the logic above to help your child master the concept of area worksheet with fractions.
