Sample page from a physics unit covering pressure, featuring questions on atmospheric pressure and force calculations.
Physics pressure worksheet with multiple choice questions on force and atmospheric pressure.
JPG
768×1024
189.1 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #328513
⭐
Show Answer Key & Explanations
Step-by-step solution for: Baro Mano Worksheet | PDF | Pressure | Atmosphere Of Earth
▼
Show Answer Key & Explanations
Step-by-step solution for: Baro Mano Worksheet | PDF | Pressure | Atmosphere Of Earth
Let's solve the problems step by step and explain the reasoning for each answer.
---
- Question: Stiletto heels can exert great pressure mainly due to
- a. the large force acting on it
- b. the small force acting on it
- c. its large surface area
- d. its small surface area
Explanation:
Pressure is defined as the force applied per unit area:
\[
P = \frac{F}{A}
\]
where \( P \) is pressure, \( F \) is force, and \( A \) is the area over which the force is applied.
Stiletto heels have a very small surface area in contact with the ground. Since the force (body weight) remains constant but the area is very small, the pressure becomes very high.
Answer: d. its small surface area
---
- Question: Which of the following places has the highest atmospheric pressure?
- a. on the top of a hill
- b. in a car
- c. on the roof top of a tall building
- d. at the bottom of the sea
Explanation:
Atmospheric pressure decreases with altitude because the air becomes less dense as you go higher. Therefore, the place with the lowest altitude will have the highest atmospheric pressure.
- On the top of a hill or on the roof of a tall building: Lower atmospheric pressure due to higher altitude.
- In a car: Atmospheric pressure is similar to that at ground level.
- At the bottom of the sea: The water exerts additional pressure on top of the atmospheric pressure, making it the highest overall pressure.
Answer: d. at the bottom of the sea
---
- Question: Wind blows
- a. from areas of high atmospheric pressure to low pressure areas
- b. from areas of low atmospheric pressure to high pressure areas
- c. only at areas above normal atmospheric pressure
- d. only at areas below normal atmospheric pressure
Explanation:
Wind is caused by differences in atmospheric pressure. Air naturally moves from areas of high pressure to areas of low pressure to equalize the pressure difference.
Answer: a. from areas of high atmospheric pressure to low pressure areas
---
- Question: The pressure in a liquid decreases with
- a. increase in surface area
- b. decrease in surface area
- c. increase in depth
- d. decrease in depth
Explanation:
The pressure in a liquid increases with depth due to the weight of the liquid above a given point. This relationship is described by the formula:
\[
P = \rho g h
\]
where \( P \) is pressure, \( \rho \) is the density of the liquid, \( g \) is the acceleration due to gravity, and \( h \) is the depth.
Thus, pressure decreases as the depth decreases.
Answer: d. decrease in depth
---
- Question: A block of wood measuring 6m by 3m by 0.5m is placed on a table. If the mass of the block of wood is 4500kg, what is the pressure on the table due to the block? Take \( g = 10 \, \text{N/kg} \)
- a. 2500Pa
- b. 5000Pa
- c. 9000Pa
- d. 22500Pa
Explanation:
1. Calculate the force (weight) of the block:
\[
F = m \cdot g = 4500 \, \text{kg} \cdot 10 \, \text{N/kg} = 45000 \, \text{N}
\]
2. Calculate the area of the block in contact with the table:
The block is placed on the table, so the area in contact is the base area:
\[
A = \text{length} \times \text{width} = 6 \, \text{m} \times 3 \, \text{m} = 18 \, \text{m}^2
\]
3. Calculate the pressure:
\[
P = \frac{F}{A} = \frac{45000 \, \text{N}}{18 \, \text{m}^2} = 2500 \, \text{Pa}
\]
Answer: a. 2500Pa
---
- Question: A man stands on snow wearing a pair of skis. The total mass of the man is 60kg and each of the skis has an area of 0.2m² in contact with the snow. A 1kg mass has a gravitational force of 10N acting on it. What pressure does the man exert on the snow?
- a. 15N/m²
- b. 30N/m²
- c. 1500N/m²
- d. 3000N/m²
Explanation:
1. Calculate the total force (weight) of the man:
\[
F = m \cdot g = 60 \, \text{kg} \cdot 10 \, \text{N/kg} = 600 \, \text{N}
\]
2. Calculate the total area of contact with the snow:
Each ski has an area of 0.2 m², and there are two skis:
\[
A = 2 \times 0.2 \, \text{m}^2 = 0.4 \, \text{m}^2
\]
3. Calculate the pressure:
\[
P = \frac{F}{A} = \frac{600 \, \text{N}}{0.4 \, \text{m}^2} = 1500 \, \text{N/m}^2
\]
Answer: c. 1500N/m²
---
- Question: Which of the following does not cause the height of the mercury column of a simple mercury barometer to vary?
- a. changes in atmospheric pressure
- b. changes in the value of \( g \)
- c. evaporation of mercury from the barometer reservoir
- d. leakage of air into the tube
Explanation:
The height of the mercury column in a barometer is determined by the balance between atmospheric pressure and the weight of the mercury column. Factors that affect this balance include:
- Changes in atmospheric pressure: Directly affects the height of the mercury column.
- Changes in \( g \): The acceleration due to gravity affects the weight of the mercury column.
- Evaporation of mercury: Reduces the amount of mercury available, affecting the height.
- Leakage of air into the tube: Introduces air pressure inside the tube, affecting the vacuum and thus the height.
However, the height of the mercury column is not affected by the evaporation of mercury from the reservoir because the reservoir ensures that the mercury level is maintained.
Answer: c. evaporation of mercury from the barometer reservoir
---
- Question: In which of the following examples is the greatest pressure exerted?
- a. a barefoot person standing on the beach
- b. a brick resting on the ground
- c. an elephant standing on the ground
- d. a knife cutting a piece of meat
Explanation:
Pressure is given by:
\[
P = \frac{F}{A}
\]
The greater the force or the smaller the area, the higher the pressure.
- Barefoot person: Moderate force, large area (footprint).
- Brick: Small force, large area (brick base).
- Elephant: Large force, large area (four legs).
- Knife: Moderate force, very small area (knife blade).
The knife has the smallest area, resulting in the highest pressure.
Answer: d. a knife cutting a piece of meat
---
1. d. its small surface area
2. d. at the bottom of the sea
3. a. from areas of high atmospheric pressure to low pressure areas
4. d. decrease in depth
5. a. 2500Pa
6. c. 1500N/m²
7. c. evaporation of mercury from the barometer reservoir
9. d. a knife cutting a piece of meat
\boxed{d, d, a, d, a, c, c, d}
---
Problem 1: Stiletto heels can exert great pressure mainly due to
- Question: Stiletto heels can exert great pressure mainly due to
- a. the large force acting on it
- b. the small force acting on it
- c. its large surface area
- d. its small surface area
Explanation:
Pressure is defined as the force applied per unit area:
\[
P = \frac{F}{A}
\]
where \( P \) is pressure, \( F \) is force, and \( A \) is the area over which the force is applied.
Stiletto heels have a very small surface area in contact with the ground. Since the force (body weight) remains constant but the area is very small, the pressure becomes very high.
Answer: d. its small surface area
---
Problem 2: Which of the following places has the highest atmospheric pressure?
- Question: Which of the following places has the highest atmospheric pressure?
- a. on the top of a hill
- b. in a car
- c. on the roof top of a tall building
- d. at the bottom of the sea
Explanation:
Atmospheric pressure decreases with altitude because the air becomes less dense as you go higher. Therefore, the place with the lowest altitude will have the highest atmospheric pressure.
- On the top of a hill or on the roof of a tall building: Lower atmospheric pressure due to higher altitude.
- In a car: Atmospheric pressure is similar to that at ground level.
- At the bottom of the sea: The water exerts additional pressure on top of the atmospheric pressure, making it the highest overall pressure.
Answer: d. at the bottom of the sea
---
Problem 3: Wind blows
- Question: Wind blows
- a. from areas of high atmospheric pressure to low pressure areas
- b. from areas of low atmospheric pressure to high pressure areas
- c. only at areas above normal atmospheric pressure
- d. only at areas below normal atmospheric pressure
Explanation:
Wind is caused by differences in atmospheric pressure. Air naturally moves from areas of high pressure to areas of low pressure to equalize the pressure difference.
Answer: a. from areas of high atmospheric pressure to low pressure areas
---
Problem 4: The pressure in a liquid decreases with
- Question: The pressure in a liquid decreases with
- a. increase in surface area
- b. decrease in surface area
- c. increase in depth
- d. decrease in depth
Explanation:
The pressure in a liquid increases with depth due to the weight of the liquid above a given point. This relationship is described by the formula:
\[
P = \rho g h
\]
where \( P \) is pressure, \( \rho \) is the density of the liquid, \( g \) is the acceleration due to gravity, and \( h \) is the depth.
Thus, pressure decreases as the depth decreases.
Answer: d. decrease in depth
---
Problem 5: Pressure on the table due to the block of wood
- Question: A block of wood measuring 6m by 3m by 0.5m is placed on a table. If the mass of the block of wood is 4500kg, what is the pressure on the table due to the block? Take \( g = 10 \, \text{N/kg} \)
- a. 2500Pa
- b. 5000Pa
- c. 9000Pa
- d. 22500Pa
Explanation:
1. Calculate the force (weight) of the block:
\[
F = m \cdot g = 4500 \, \text{kg} \cdot 10 \, \text{N/kg} = 45000 \, \text{N}
\]
2. Calculate the area of the block in contact with the table:
The block is placed on the table, so the area in contact is the base area:
\[
A = \text{length} \times \text{width} = 6 \, \text{m} \times 3 \, \text{m} = 18 \, \text{m}^2
\]
3. Calculate the pressure:
\[
P = \frac{F}{A} = \frac{45000 \, \text{N}}{18 \, \text{m}^2} = 2500 \, \text{Pa}
\]
Answer: a. 2500Pa
---
Problem 6: Pressure exerted by the man on the snow
- Question: A man stands on snow wearing a pair of skis. The total mass of the man is 60kg and each of the skis has an area of 0.2m² in contact with the snow. A 1kg mass has a gravitational force of 10N acting on it. What pressure does the man exert on the snow?
- a. 15N/m²
- b. 30N/m²
- c. 1500N/m²
- d. 3000N/m²
Explanation:
1. Calculate the total force (weight) of the man:
\[
F = m \cdot g = 60 \, \text{kg} \cdot 10 \, \text{N/kg} = 600 \, \text{N}
\]
2. Calculate the total area of contact with the snow:
Each ski has an area of 0.2 m², and there are two skis:
\[
A = 2 \times 0.2 \, \text{m}^2 = 0.4 \, \text{m}^2
\]
3. Calculate the pressure:
\[
P = \frac{F}{A} = \frac{600 \, \text{N}}{0.4 \, \text{m}^2} = 1500 \, \text{N/m}^2
\]
Answer: c. 1500N/m²
---
Problem 7: Which does not cause the height of the mercury column in a simple mercury barometer to vary?
- Question: Which of the following does not cause the height of the mercury column of a simple mercury barometer to vary?
- a. changes in atmospheric pressure
- b. changes in the value of \( g \)
- c. evaporation of mercury from the barometer reservoir
- d. leakage of air into the tube
Explanation:
The height of the mercury column in a barometer is determined by the balance between atmospheric pressure and the weight of the mercury column. Factors that affect this balance include:
- Changes in atmospheric pressure: Directly affects the height of the mercury column.
- Changes in \( g \): The acceleration due to gravity affects the weight of the mercury column.
- Evaporation of mercury: Reduces the amount of mercury available, affecting the height.
- Leakage of air into the tube: Introduces air pressure inside the tube, affecting the vacuum and thus the height.
However, the height of the mercury column is not affected by the evaporation of mercury from the reservoir because the reservoir ensures that the mercury level is maintained.
Answer: c. evaporation of mercury from the barometer reservoir
---
Problem 9: Greatest pressure exerted
- Question: In which of the following examples is the greatest pressure exerted?
- a. a barefoot person standing on the beach
- b. a brick resting on the ground
- c. an elephant standing on the ground
- d. a knife cutting a piece of meat
Explanation:
Pressure is given by:
\[
P = \frac{F}{A}
\]
The greater the force or the smaller the area, the higher the pressure.
- Barefoot person: Moderate force, large area (footprint).
- Brick: Small force, large area (brick base).
- Elephant: Large force, large area (four legs).
- Knife: Moderate force, very small area (knife blade).
The knife has the smallest area, resulting in the highest pressure.
Answer: d. a knife cutting a piece of meat
---
Final Answers
1. d. its small surface area
2. d. at the bottom of the sea
3. a. from areas of high atmospheric pressure to low pressure areas
4. d. decrease in depth
5. a. 2500Pa
6. c. 1500N/m²
7. c. evaporation of mercury from the barometer reservoir
9. d. a knife cutting a piece of meat
\boxed{d, d, a, d, a, c, c, d}
Parent Tip: Review the logic above to help your child master the concept of atmospheric pressure worksheet.
