Identify the element based on the atomic structure in this educational worksheet.

Let's solve this step-by-step by analyzing each atom diagram and identifying the element based on its number of protons (atomic number) and electron configuration.

Each diagram shows:
- A central nucleus with protons (black dots in the center)
- Electrons (small black dots) arranged in energy levels (shells)

We'll count:
1. The number of protons (in the nucleus).
2. The number of electrons (around the nucleus).
3. Since atoms are neutral, protons = electrons.
4. Use the atomic number (number of protons) to identify the element using the periodic table.

---

A

- Protons: 6
- Electrons: 2 (first shell) + 4 (second shell) = 6
- Atomic number = 6 → Carbon (C)

✔ Answer: Carbon

---

B

- Protons: 8
- Electrons: 2 + 6 = 8
- Atomic number = 8 → Oxygen (O)

✔ Answer: Oxygen

---

C

- Protons: 5
- Electrons: 2 + 3 = 5
- Atomic number = 5 → Boron (B)

✔ Answer: Boron

---

D

- Protons: 7
- Electrons: 2 + 5 = 7
- Atomic number = 7 → Nitrogen (N)

✔ Answer: Nitrogen

---

E

- Protons: 2
- Electrons: 2
- Atomic number = 2 → Helium (He)

✔ Answer: Helium

---

F

- Protons: 1
- Electrons: 1
- Atomic number = 1 → Hydrogen (H)

✔ Answer: Hydrogen

---

G

- Protons: 3
- Electrons: 2 + 1 = 3
- Atomic number = 3 → Lithium (Li)

✔ Answer: Lithium

---

H

- Protons: 4
- Electrons: 2 + 2 = 4
- Atomic number = 4 → Beryllium (Be)

✔ Answer: Beryllium

---

I

- Protons: 6
- Electrons: 2 + 4 = 6
- Wait — this looks like carbon again, but let’s check carefully.

Wait! Let's look at I:

- Nucleus has 6 protons (same as A)
- Electrons: 2 (inner shell) + 4 (outer shell) = 6
- So it's also Carbon (C)?

But wait — A and I look identical.

But let’s double-check if there's a difference.

Looking closely:
- A: Two shells, 2+4 = 6 electrons, 6 protons → Carbon
- I: Same — 2+4 = 6 electrons, 6 protons → Also Carbon

But that can’t be — unless they’re meant to be the same element.

Wait — is there a mistake? Or maybe I miscounted.

Wait — actually, I has 6 protons and 6 electrons, so yes — Carbon.

But let's recheck all diagrams carefully.

Wait — perhaps I is not carbon? Let's see:

Wait — no, both A and I have:
- 6 protons
- 2 electrons in first shell
- 4 electrons in second shell

So both are Carbon.

But that seems odd for a worksheet — usually each one is different.

Wait — let’s go back to C:

C has:
- 5 protons
- 2 + 3 = 5 electrons → Boron

D has 7 protons → Nitrogen

E = 2 protons → Helium

F = 1 proton → Hydrogen

G = 3 protons → Lithium

H = 4 protons → Beryllium

Now I:

- Protons: 6
- Electrons: 2 + 4 = 6 → Carbon

But A is also carbon.

Wait — maybe I made an error.

Wait — let's recount A:

A: nucleus has 6 dots → 6 protons
Electrons: 2 on inner ring, 4 on outer → total 6 → Carbon

I: nucleus has 6 dots → 6 protons
Electrons: 2 on inner, 4 on outer → Carbon

So both A and I are Carbon?

That seems like a duplication.

But perhaps the diagram is intended to show different isotopes or just repeated examples?

Alternatively, maybe I'm misreading.

Wait — look at I again:

Is the nucleus really 6 protons? Yes.

But let's check H:

H: nucleus has 4 protons → Beryllium

Yes.

Wait — what about G?

G: nucleus has 3 protons → Lithium

Yes.

Now, is there any diagram missing?

Let’s list all:

- A: 6 protons → Carbon
- B: 8 protons → Oxygen
- C: 5 protons → Boron
- D: 7 protons → Nitrogen
- E: 2 protons → Helium
- F: 1 proton → Hydrogen
- G: 3 protons → Lithium
- H: 4 protons → Beryllium
- I: 6 protons → Carbon

Ah — so A and I are both Carbon.

But that’s okay — maybe it's intentional to reinforce the idea.

But let’s double-check I — could it be something else?

Wait — I has:
- 2 electrons in first shell
- 4 electrons in second shell
- 6 protons

Yes — that’s Carbon.

But perhaps the nucleus in I has fewer protons?

Wait — no — the nucleus has 6 small dots — same as A.

So both A and I are Carbon.

But maybe the question allows duplicates?

Alternatively, maybe I miscounted A.

Wait — let's recheck A:

- Nucleus: cluster of 6 dots → 6 protons
- First shell: 2 electrons
- Second shell: 4 electrons → total 6 electrons → Carbon

Same for I.

So likely, both A and I are Carbon.

But let's check C again:

C: nucleus has 5 dots → 5 protons
- Electrons: 2 + 3 = 5 → Boron → correct

D: 7 protons → Nitrogen → correct

E: 2 protons → Helium → correct

F: 1 proton → Hydrogen → correct

G: 3 protons → Lithium → correct

H: 4 protons → Beryllium → correct

So only A and I are both Carbon.

But perhaps I is meant to be Oxygen? No — oxygen has 8 protons.

Wait — no.

Unless the nucleus has 8 dots?

No — I has 6 dots in the nucleus.

Wait — maybe I’m wrong about I.

Let me describe I:

- One circle (shell)
- Inner shell: 2 electrons
- Outer shell: 4 electrons
- Nucleus: 6 protons

Yes — Carbon

So unless the image is flawed, both A and I are Carbon.

But let's consider: maybe I is Silicon? No — Silicon has 14 protons.

No — clearly not.

Wait — perhaps I has only 4 electrons?

No — it has 2 in first shell, 4 in second → 6.

Wait — maybe I has 6 protons and 6 electrons, but is drawn differently?

No — same as A.

So conclusion: A and I are both Carbon.

But let's see if any other diagram might be misread.

Wait — H:

- Nucleus: 4 protons
- Electrons: 2 + 2 = 4 → Beryllium → correct

G: 3 protons → Lithium → correct

F: 1 proton → Hydrogen → correct

E: 2 protons → Helium → correct

D: 7 protons → Nitrogen → correct

C: 5 protons → Boron → correct

B: 8 protons → Oxygen → correct

So the only duplicate is Carbon appearing twice.

But that's acceptable.

Alternatively, perhaps I is Carbon, and A is something else?

Wait — no — both have same structure.

Wait — perhaps A has more than 6 protons?

Let me recount A's nucleus:

It's a cluster — hard to count, but it's 6 dots.

Similarly for I.

So yes — both are Carbon.

Therefore, final answers:

---

Final Answers:

| Letter | Element |
|--------|--------------|
| A | Carbon |
| B | Oxygen |
| C | Boron |
| D | Nitrogen |
| E | Helium |
| F | Hydrogen |
| G | Lithium |
| H | Beryllium |
| I | Carbon |

---

✔ Explanation: Each atom is identified by counting the number of protons in the nucleus (which gives the atomic number). Using the periodic table, we match that number to the element name. Electrons are arranged in shells, and for neutral atoms, the number of electrons equals the number of protons.

Note: A and I are both carbon, which may be intentional for reinforcement.

Let me know if you'd like a labeled version or help with the periodic table lookup.