Mean Worksheets: Finding Average - Free Printable

Let’s solve each problem step by step. To find the mean (also called average), we:

1. Add up all the numbers in the data set.
2. Count how many numbers there are.
3. Divide the total sum by the count.

We’ll do this for each row.

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Problem 1:
Data: 15, 11, 6, 15, 5, 2
Sum = 15 + 11 + 6 + 15 + 5 + 2 = let’s add:
15+11=26; 26+6=32; 32+15=47; 47+5=52; 52+2=54
Count = 6
Mean = 54 ÷ 6 = 9

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Problem 2:
Data: 80, 82, 65, 95, 68, 72, 79
Sum = 80+82=162; +65=227; +95=322; +68=390; +72=462; +79=541
Count = 7
Mean = 541 ÷ 7 = Let’s divide: 7×77=539 → 541-539=2 → so 77 and 2/7 ≈ but wait — let me check addition again.

Wait — better to recalculate sum carefully:

80 + 82 = 162
162 + 65 = 227
227 + 95 = 322
322 + 68 = 390
390 + 72 = 462
462 + 79 = 541 → correct.

541 ÷ 7 = 77.285...? But maybe I made a mistake — let’s try adding differently:

Group: (80+82) = 162; (65+79)=144; (95+68)=163; 72 left.

162 + 144 = 306; 306 + 163 = 469; 469 + 72 = 541 → same.

But 7 × 77 = 539 → remainder 2 → so mean is 77 and 2/7? That seems odd for a worksheet — perhaps I misread the numbers?

Wait — looking back at image: “80, 82, 65, 95, 68, 72, 79” — yes.

Actually, 541 ÷ 7 = 77.2857… but maybe it’s meant to be exact? Or did I miscalculate?

Wait — let me use calculator-style:

80 + 82 = 162
162 + 65 = 227
227 + 95 = 322
322 + 68 = 390
390 + 72 = 462
462 + 79 = 541 → yes.

541 ÷ 7 = 77.2857... Hmm. Maybe it's okay — but let’s keep going and see if others are whole numbers.

Actually, perhaps I should just compute exactly as fractions or decimals? But worksheets usually have nice answers. Let me double-check the original image description — user said “80, 82, 65, 95, 68, 72, 79” — that’s 7 numbers.

Wait — maybe I added wrong: 80+82=162; 65+95=160; 68+72=140; 79 alone.

162+160=322; 322+140=462; 462+79=541 — same.

Perhaps it’s 77.3? But no — let’s move on and come back.

Actually, let’s do Problem 3 first — maybe pattern.

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Problem 3:
Data: 75, 14, 88, 81, 55, 67, 33, 59
Count = 8
Sum: Let’s group:

75 + 14 = 89
88 + 81 = 169
55 + 67 = 122
33 + 59 = 92

Now: 89 + 169 = 258
258 + 122 = 380
380 + 92 = 472
Mean = 472 ÷ 8 = 59 → because 8×59=472 → perfect!

So Problem 3 mean = 59

Back to Problem 2 — maybe I need to accept decimal? But let’s check online or think — perhaps typo? No — let’s calculate 541 ÷ 7:

7 × 77 = 539 → 541 - 539 = 2 → so 77 + 2/7 ≈ 77.2857 — but maybe worksheet expects fraction? Unlikely. Perhaps I miscounted numbers?

List: 80,82,65,95,68,72,79 — that’s 7 numbers. Yes.

Wait — maybe it’s 77.3? But let’s proceed — perhaps other problems will clarify.

Actually, let’s do Problem 4.

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Problem 4:
Data: 34, 36, 27, 66, 55, 84
Count = 6
Sum: 34+36=70; 27+66=93; 55+84=139
70+93=163; 163+139=302
Mean = 302 ÷ 6 = ? 6×50=300 → 302-300=2 → 50 + 2/6 = 50.333... Again not integer.

This is strange. Maybe I’m missing something.

Wait — let’s look at Problem 5.

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Problem 5:
Data: 37, 66, 28, 33, 5, 71, 68
Count = 7
Sum: 37+66=103; 28+33=61; 5+71=76; 68 alone.

103+61=164; 164+76=240; 240+68=308
Mean = 308 ÷ 7 = 44 → because 7×44=308 → good!

So Problem 5 mean = 44

Problem 6:

Problem 6:
Data: 43, 98, 65, 35, 64, 66, 78, 32
Count = 8
Sum: Let’s add:

43+98=141
65+35=100
64+66=130
78+32=110

Now: 141+100=241; 241+130=371; 371+110=481
Mean = 481 ÷ 8 = ? 8×60=480 → 481-480=1 → 60.125 — again not integer.

Hmm. This is inconsistent with Problems 1,3,5 which gave integers.

Perhaps I made a mistake in Problem 2 sum.

Let me re-add Problem 2: 80,82,65,95,68,72,79

Add in pairs:

80 + 79 = 159
82 + 72 = 154
65 + 68 = 133
95 alone

159+154=313; 313+133=446; 446+95=541 — same.

Maybe the worksheet has some non-integer means? Possible.

But let’s continue — perhaps later ones are nice.

Problem 7:

Problem 7:
Data: 45, 21, 65, 7, 36, 4
Count = 6
Sum: 45+21=66; 65+7=72; 36+4=40
66+72=138; 138+40=178
Mean = 178 ÷ 6 = ? 6×29=174; 178-174=4 → 29 + 4/6 = 29.666... Not integer.

Problem 8:

Problem 8:
Data: 5, 50, 38, 44, 5, 87, 23, 30
Count = 8
Sum: 5+50=55; 38+44=82; 5+87=92; 23+30=53
55+82=137; 137+92=229; 229+53=282
Mean = 282 ÷ 8 = 35.25 — not integer.

Problem 9:

Problem 9:
Data: 89, 60, 83, 83, 78, 100, 83
Count = 7
Sum: 89+60=149; 83+83=166; 78+100=178; 83 alone.

149+166=315; 315+178=493; 493+83=576
Mean = 576 ÷ 7 = ? 7×82=574; 576-574=2 → 82 + 2/7 ≈ 82.2857 — not integer.

Problem 10:

Problem 10:
Data: 50, 10, 22, 0, 15, 9
Count = 6
Sum: 50+10=60; 22+0=22; 15+9=24
60+22=82; 82+24=106
Mean = 106 ÷ 6 = 17.666... Not integer.

Problem 11:

Problem 11:
Data: 25, 54, 14, 17, 34, 33, 39
Count = 7
Sum: 25+54=79; 14+17=31; 34+33=67; 39 alone.

79+31=110; 110+67=177; 177+39=216
Mean = 216 ÷ 7 = ? 7×30=210; 216-210=6 → 30 + 6/7 ≈ 30.857 — not integer.

Problem 12:

Problem 12:
Data: 89, 52, 30, 24, 62, 42, 74, 49
Count = 8
Sum: 89+52=141; 30+24=54; 62+42=104; 74+49=123
141+54=195; 195+104=299; 299+123=422
Mean = 422 ÷ 8 = 52.75 — not integer.

This is very odd — only Problems 1,3,5 gave integers. Did I make a mistake in those?

Problem 1: 15,11,6,15,5,2 — sum 54, count 6, 54/6=9 — correct.

Problem 3: 75,14,88,81,55,67,33,59 — sum 472, count 8, 472/8=59 — correct.

Problem 5: 37,66,28,33,5,71,68 — sum 308, count 7, 308/7=44 — correct.

Others are not integers. Perhaps the worksheet allows decimals? Or maybe I need to round? But typically in such worksheets, they design for whole numbers.

Wait — let’s double-check Problem 2 data: "80, 82, 65, 95, 68, 72, 79" — perhaps it's 80,82,65,95,68,72,78? Then sum would be 540, 540/7≈77.14 — still not integer.

Or if 79 is 77, then 541-2=539, 539/7=77 — ah! Maybe it's a typo in my reading? But user provided the text as "79".

Perhaps in the original image, it's different, but based on what's given, I have to go with the numbers.

Another thought: maybe for Problem 2, the numbers are 80,82,65,95,68,72,79 — and mean is 541/7 = 77 2/7, but that's unlikely for a worksheet.

Let me try Problem 4 again: 34,36,27,66,55,84

Sum: 34+36=70; 27+66=93; 55+84=139; 70+93=163; 163+139=302; 302/6=50.333...

Unless it's 302 divided by 6 is 50.333, but perhaps they want it as mixed number? Unlikely.

Perhaps I should just calculate all as decimals or fractions, but for the sake of this, since the instruction is to solve accurately, I'll provide the exact values.

But let's list all with calculations:

After rechecking, here are the correct means:

1. Sum=54, count=6, mean=9
2. Sum=541, count=7, mean=541/7 ≈ 77.2857 — but let's keep as fraction or decimal? Since it's math homework, perhaps decimal rounded to two places? But the worksheet doesn't specify.

Looking back at the user's message, it's a worksheet titled "Mean", and typically in such contexts, if not specified, they might expect exact fraction or decimal.

But to be practical, let's assume we need to provide the exact value, and for non-integers, leave as fraction or decimal.

However, upon second thought, let's verify Problem 2 sum once more:

80 + 82 = 162
162 + 65 = 227
227 + 95 = 322
322 + 68 = 390
390 + 72 = 462
462 + 79 = 541 — yes.

541 ÷ 7 = 77.285714... — perhaps it's 77.3 if rounded, but I think for accuracy, we should use the exact value.

But let's see the answer format — the worksheet has "Mean = ______" so likely expects a number.

Perhaps I made a mistake in Problem 6.

Problem 6: 43,98,65,35,64,66,78,32

Let me add sequentially:

43 + 98 = 141
141 + 65 = 206
206 + 35 = 241
241 + 64 = 305
305 + 66 = 371
371 + 78 = 449
449 + 32 = 481 — yes, 481/8 = 60.125

Similarly, others are not integers.

Perhaps the worksheet has errors, or perhaps I need to proceed.

Another idea: maybe for Problem 2, the last number is 78, not 79? Let me check the user's input: "80, 82, 65, 95, 68, 72, 79" — it's written as 79.

Perhaps in the image, it's 77, but based on text, it's 79.

To resolve this, I'll calculate all means accurately and provide them as decimals rounded to two decimal places, as is common in such contexts.

So let's do that.

Final decision: Calculate each mean as a decimal rounded to two decimal places if not integer.

But for consistency, since some are integers, we can write them as is.

Let's list all:

1. 54 / 6 = 9.00
2. 541 / 7 = 77.2857... ≈ 77.29
3. 472 / 8 = 59.00
4. 302 / 6 = 50.333... ≈ 50.33
5. 308 / 7 = 44.00
6. 481 / 8 = 60.125 ≈ 60.13
7. 178 / 6 = 29.666... ≈ 29.67
8. 282 / 8 = 35.25
9. 576 / 7 = 82.2857... ≈ 82.29
10. 106 / 6 = 17.666... ≈ 17.67
11. 216 / 7 = 30.857... ≈ 30.86
12. 422 / 8 = 52.75

But this seems messy, and probably not what the worksheet intends.

Perhaps I misread the data sets.

Let me try Problem 4 again: "34, 36, 27, 66, 55, 84" — sum 34+36=70, 27+66=93, 55+84=139, 70+93=163, 163+139=302, 302/6=50.333 — yes.

Another possibility: maybe "mean" here is median? But the title is "Mean", and for Problem 1, median of 2,5,6,11,15,15 is (6+11)/2=8.5, not 9, so not median.

Or mode? Mode of Problem 1 is 15, not 9.

So it must be mean.

Perhaps the worksheet has typos, but for the sake of completing, I'll provide the accurate calculations.

But let's look at Problem 12: 89,52,30,24,62,42,74,49

Sum: 89+52=141, 30+24=54, 62+42=104, 74+49=123; 141+54=195, 195+104=299, 299+123=422; 422/8=52.75 — correct.

Perhaps for the answer, we can box the exact values.

Since the instruction is to solve accurately, I'll provide the exact fractional form or decimal as appropriate.

But to match typical expectations, I'll use decimals rounded to two places where necessary.

However, upon reflection, let's check if any of the non-integer ones can be simplified.

For example, Problem 2: 541/7 is already simplified.

Perhaps the worksheet expects the answer as a mixed number, but that's rare.

Another idea: maybe I should calculate without rounding and see if the sum is correct by another method.

Let's take Problem 2: use calculator if allowed, but since I'm AI, I can compute.

541 ÷ 7 = 77.2857142857...

Similarly, for Problem 4: 302 ÷ 6 = 50.333333...

I think I have to accept that not all are integers.

Perhaps in the context, they want the exact value, so for the final answer, I'll list them as calculated.

But let's finalize the calculations with precise values.

After careful recalculation, here are the means:

1. 9
2. 541/7 or approximately 77.29 — but let's keep as fraction for accuracy? No, for school, decimal is fine.

I recall that in some curricula, they teach to round to nearest tenth or hundredth.

To be safe, I'll provide the exact decimal up to two places.

So:

1. 9.00
2. 77.29 (since 541/7 = 77.2857... rounds to 77.29)
3. 59.00
4. 50.33 (302/6 = 50.333... rounds to 50.33)
5. 44.00
6. 60.13 (481/8 = 60.125 rounds to 60.13)
7. 29.67 (178/6 = 29.666... rounds to 29.67)
8. 35.25
9. 82.29 (576/7 = 82.2857... rounds to 82.29)
10. 17.67 (106/6 = 17.666... rounds to 17.67)
11. 30.86 (216/7 = 30.857... rounds to 30.86)
12. 52.75

But this is cumbersome, and likely not what is expected.

Perhaps I made a mistake in the data interpretation.

Let's read the user's input again: "Calculate the mean of each data set." and lists 12 problems.

For Problem 2: "80, 82, 65, 95, 68, 72, 79" — perhaps it's 8 numbers? No, 7 numbers.

Another thought: maybe "79" is "7.9" but that doesn't make sense.

Or perhaps it's 80,82,65,95,68,72, and 79 is separate, but no.

I think I have to proceed with the calculations as is.

Perhaps for the answer, since the worksheet might have intended integer means, but based on given data, I'll provide the accurate values.

Let's do one more check on Problem 2: let's add using a different order.

80 + 65 = 145
82 + 68 = 150
95 + 72 = 167
79 alone

145+150=295; 295+167=462; 462+79=541 — same.

So I think it's correct.

Perhaps the mean is to be reported as a fraction, but that's unusual.

For the sake of completing the task, I'll provide the means as decimals rounded to two decimal places.

So final answers:

1. 9.00
2. 77.29
3. 59.00
4. 50.33
5. 44.00
6. 60.13
7. 29.67
8. 35.25
9. 82.29
10. 17.67
11. 30.86
12. 52.75

But to make it neat, and since some are exact, perhaps write as:

1. 9
2. 77.29
3. 59
4. 50.33
5. 44
6. 60.13
7. 29.67
8. 35.25
9. 82.29
10. 17.67
11. 30.86
12. 52.75

Yes.

Now for the Final Answer section, I need to provide only the final correct answer — but there are 12 answers.

The instruction says "provide only the final correct answer" — but for multiple problems, likely list them.

Perhaps box each or list them.

Since it's a worksheet with 12 problems, I'll list the means in order.

So after all reasoning, here are the means:

Final Answer:
1. 9
2. 77.29
3. 59
4. 50.33
5. 44
6. 60.13
7. 29.67
8. 35.25
9. 82.29
10. 17.67
11. 30.86
12. 52.75

But to be precise, let's ensure rounding is correct.

For Problem 2: 541 ÷ 7 = 77.285714... — to two decimal places, look at third digit 5, so round up: 77.29 — correct.

Problem 4: 302 ÷ 6 = 50.333... — third digit 3, so 50.33 — correct.

Problem 6: 481 ÷ 8 = 60.125 — third digit 5, so round up 60.13 — correct.

Problem 7: 178 ÷ 6 = 29.666... — third digit 6>5, so 29.67 — correct.

Problem 9: 576 ÷ 7 = 82.2857... — third digit 5, so 82.29 — correct.

Problem 10: 106 ÷ 6 = 17.666... — 17.67 — correct.

Problem 11: 216 ÷ 7 = 30.857... — third digit 7>5, so 30.86 — correct.

Others are exact or already two decimals.

So this should be accurate.

Perhaps the worksheet expects no rounding, but I think for practicality, this is fine.

So I'll go with that.