Balancing Chemical Equation | PDF | Hydroxide | Sodium Hydroxide - Free Printable

Let's solve the Balancing Chemical Equations Worksheet step by step and then classify each reaction type.

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🔧 Step 1: Balancing Each Equation

We'll balance each chemical equation by ensuring the number of atoms of each element is equal on both sides.

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#### 1. Zn (s) + AgNO₃ (aq) → Zn(NO₃)₂ (aq) + Ag (s)

- Zn: 1 on left, 1 on right ✔
- Ag: 1 on left, 1 on right → but Ag is produced as solid, and Zn(NO₃)₂ has two NO₃⁻ groups.
- So need 2 AgNO₃ to provide two NO₃⁻ for Zn²⁺.

✔ Balanced:
Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag

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#### 2. N₂ (g) + H₂ (g) → NH₃ (g)

- N: 2 on left, 1 in NH₃ → need 2NH₃
- H: 6H on right → need 3H₂

✔ Balanced:
N₂ + 3H₂ → 2NH₃

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#### 3. NaCl (aq) + AgC₂H₃O₂ (aq) → NaC₂H₃O₂ (aq) + AgCl (s)

- All ions exchange → double displacement
- Already balanced as written (1:1:1:1)

✔ Balanced:
NaCl + AgC₂H₃O₂ → NaC₂H₃O₂ + AgCl

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#### 4. Mg(OH)₂ (aq) + H₃PO₄ (aq) → H₂O (l) + Mg₃(PO₄)₂ (aq)

- Mg: 2 on left → need 3Mg(OH)₂ → so use 3Mg(OH)₂
- PO₄: 2 on right → need 2H₃PO₄
- Now H from acid and base:
- 2H₃PO₄ → 6H⁺
- 3Mg(OH)₂ → 6OH⁻ → forms 6H₂O

✔ Balanced:
3Mg(OH)₂ + 2H₃PO₄ → 6H₂O + Mg₃(PO₄)₂

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#### 5. HNO₃ (aq) + Ni (s) → Ni(NO₃)₂ (aq) + H₂ (g)

- Ni: 1 on both sides ✔
- NO₃: 2 in Ni(NO₃)₂ → need 2HNO₃
- H: 2H on left → H₂ on right → 1H₂

✔ Balanced:
2HNO₃ + Ni → Ni(NO₃)₂ + H₂

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#### 6. Ba(HCO₃)₂ (s) → BaCO₃ (s) + H₂O (g) + CO₂ (g)

- Decomposition of bicarbonate
- HCO₃⁻ decomposes to CO₃²⁻, H₂O, and CO₂
- One Ba(HCO₃)₂ gives:
- BaCO₃
- H₂O
- CO₂

But we have two HCO₃⁻, so:

- 2HCO₃⁻ → CO₃²⁻ + H₂O + CO₂

So:
Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂

✔ Already balanced!

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#### 7. BaCl₂ (aq) + Na₂SO₄ (aq) → NaCl (aq) + BaSO₄ (s)

- Ba: 1 on both sides ✔
- SO₄: 1 on both ✔
- Na: 2 on left → need 2NaCl
- Cl: 2 on left → 2NaCl has 2Cl ✔

✔ Balanced:
BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄

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#### 8. Al₂(CO₃)₃ (s) → Al₂O₃ (s) + CO₂ (g)

- Decomposition of carbonate
- Al₂(CO₃)₃ → Al₂O₃ + 3CO₂

✔ Balanced:
Al₂(CO₃)₃ → Al₂O₃ + 3CO₂

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#### 9. Ca (s) + H₂O (l) → Ca(OH)₂ (aq) + H₂ (g)

- Ca: 1 on both ✔
- O: 1 on left → 1 in Ca(OH)₂ ✔
- H: 2 on left → 2H in Ca(OH)₂ and 2H in H₂ → total 4H → need 2H₂O

Try:
Ca + 2H₂O → Ca(OH)₂ + H₂

Now check:
- Ca: 1 ✔
- O: 2 on left, 2 in Ca(OH)₂ ✔
- H: 4 on left → 2 in Ca(OH)₂ + 2 in H₂ → 4 ✔

✔ Balanced:
Ca + 2H₂O → Ca(OH)₂ + H₂

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#### 10. LiHCO₃ (s) → Li₂CO₃ (s) + H₂O (g) + CO₂ (g)

- Li: 2 on right → need 2LiHCO₃
- HCO₃: 2 → decomposition: 2HCO₃⁻ → CO₃²⁻ + H₂O + CO₂

So:
2LiHCO₃ → Li₂CO₃ + H₂O + CO₂

✔ Balanced:
2LiHCO₃ → Li₂CO₃ + H₂O + CO₂

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#### 11. N₂ (g) + O₂ (g) → N₂O₅ (g)

- N: 2 on both ✔
- O: 5 on right → need 5/2 O₂ → multiply all by 2

→ 2N₂ + 5O₂ → 2N₂O₅

✔ Balanced:
2N₂ + 5O₂ → 2N₂O₅

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#### 12. MgBr₂ (aq) + KOH (aq) → KBr (aq) + Mg(OH)₂ (s)

- Mg: 1 ✔
- Br: 2 → need 2KBr
- K: 2 → need 2KOH
- OH: 2 → Mg(OH)₂ needs 2OH → 2KOH provides 2OH ✔

✔ Balanced:
MgBr₂ + 2KOH → 2KBr + Mg(OH)₂

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#### 13. Mn (s) + CuCl₂ (aq) → Cu (s) + MnCl₂ (s)

- Single replacement
- Mn replaces Cu
- Already balanced: 1:1:1:1

✔ Balanced:
Mn + CuCl₂ → Cu + MnCl₂

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#### 14. Zn (s) + S₈ (s) → ZnS (s)

- S₈ has 8 sulfur atoms → need 8ZnS
- So 8Zn + S₈ → 8ZnS

✔ Balanced:
8Zn + S₈ → 8ZnS

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#### 15. NaOH (aq) + H₂SO₄ (aq) → H₂O (l) + Na₂SO₄ (aq)

- Acid-base neutralization
- H₂SO₄ has 2H⁺ → needs 2NaOH
- Na: 2 → Na₂SO₄
- H: 2H from acid + 2H from base → 2H₂O

So:
2NaOH + H₂SO₄ → 2H₂O + Na₂SO₄

✔ Balanced:
2NaOH + H₂SO₄ → 2H₂O + Na₂SO₄

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#### 16. K (s) + H₂O (l) → KOH (aq) + H₂ (g)

- K: 1 on both ✔
- O: 1 ✔
- H: 2 on left → 1 in KOH + 1 in H₂ → need 2KOH and 1H₂?

Wait:
K + H₂O → KOH + ½H₂ → multiply by 2:

2K + 2H₂O → 2KOH + H₂

Check:
- K: 2 ✔
- H: 4 on left → 2 in 2KOH + 2 in H₂ → 4 ✔
- O: 2 on left → 2 in 2KOH ✔

✔ Balanced:
2K + 2H₂O → 2KOH + H₂

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#### 17. C₆H₁₂ (l) + O₂ (g) → H₂O (g) + CO₂ (g)

- Combustion of hydrocarbon
- C₆H₁₂ → 6CO₂ + 6H₂O
- H: 12 → 6H₂O → 6H₂O has 12H ✔
- O: 6CO₂ = 12O, 6H₂O = 6O → total 18O → need 9O₂

So:
C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

✔ Balanced:
C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

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#### 18. KOH (aq) + H₂CO₃ (aq) → H₂O (l) + K₂CO₃ (aq)

- Acid-base
- H₂CO₃ has 2H⁺ → needs 2KOH
- K: 2 → K₂CO₃
- H: 2 from acid + 2 from base → 2H₂O

So:
2KOH + H₂CO₃ → 2H₂O + K₂CO₃

✔ Balanced:
2KOH + H₂CO₃ → 2H₂O + K₂CO₃

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#### 19. C₆H₁₂O₆ (l) + O₂ (g) → H₂O (g) + CO₂ (g)

- Glucose combustion
- C₆H₁₂O₆ → 6CO₂ + 6H₂O
- O: Left: 6 in glucose + ? from O₂
- Right: 6×2 = 12O in CO₂ + 6O in H₂O → 18O
- Glucose has 6O → need 12 more → 6O₂

So:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

✔ Balanced:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

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#### 20. Al (s) + S₈ (s) → Al₂S₃ (s)

- Al₂S₃ requires 2Al and 3S
- S₈ has 8S → need multiple
- Find LCM of 3 and 8 → 24S
- So: 8Al₂S₃ → 16Al and 24S
- S₈ → 3S₈ gives 24S
- Al: 16Al

So:
16Al + 3S₈ → 8Al₂S₃

✔ Balanced:
16Al + 3S₈ → 8Al₂S₃

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✔ Balanced Equations Summary

| # | Balanced Equation |
|---|------------------|
| 1 | Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag |
| 2 | N₂ + 3H₂ → 2NH₃ |
| 3 | NaCl + AgC₂H₃O₂ → NaC₂H₃O₂ + AgCl |
| 4 | 3Mg(OH)₂ + 2H₃PO₄ → 6H₂O + Mg₃(PO₄)₂ |
| 5 | 2HNO₃ + Ni → Ni(NO₃)₂ + H₂ |
| 6 | Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂ |
| 7 | BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄ |
| 8 | Al₂(CO₃)₃ → Al₂O₃ + 3CO₂ |
| 9 | Ca + 2H₂O → Ca(OH)₂ + H₂ |
|10 | 2LiHCO₃ → Li₂CO₃ + H₂O + CO₂ |
|11 | 2N₂ + 5O₂ → 2N₂O₅ |
|12 | MgBr₂ + 2KOH → 2KBr + Mg(OH)₂ |
|13 | Mn + CuCl₂ → Cu + MnCl₂ |
|14 | 8Zn + S₈ → 8ZnS |
|15 | 2NaOH + H₂SO₄ → 2H₂O + Na₂SO₄ |
|16 | 2K + 2H₂O → 2KOH + H₂ |
|17 | C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O |
|18 | 2KOH + H₂CO₃ → 2H₂O + K₂CO₃ |
|19 | C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O |
|20 | 16Al + 3S₈ → 8Al₂S₃ |

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🧪 TYPES OF REACTION

The five main types of chemical reactions are:

1. Synthesis (Combination)
A + B → AB
Example: 2H₂ + O₂ → 2H₂O

2. Decomposition
AB → A + B
Example: 2H₂O → 2H₂ + O₂

3. Single Replacement (Displacement)
A + BC → AC + B
Example: Zn + 2HCl → ZnCl₂ + H₂

4. Double Replacement (Metathesis)
AB + CD → AD + CB
Example: AgNO₃ + NaCl → AgCl + NaNO₃

5. Combustion
Fuel + O₂ → CO₂ + H₂O
Example: CH₄ + 2O₂ → CO₂ + 2H₂O

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🔍 Classify Each Reaction

| # | Type |
|---|------|
| 1 | Single Replacement |
| 2 | Synthesis |
| 3 | Double Replacement |
| 4 | Double Replacement |
| 5 | Single Replacement |
| 6 | Decomposition |
| 7 | Double Replacement |
| 8 | Decomposition |
| 9 | Single Replacement |
|10 | Decomposition |
|11 | Synthesis |
|12 | Double Replacement |
|13 | Single Replacement |
|14 | Synthesis |
|15 | Double Replacement |
|16 | Single Replacement |
|17 | Combustion |
|18 | Double Replacement |
|19 | Combustion |
|20 | Synthesis |

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✔ Final Answer:

#### Balanced Equations:

1. Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag
2. N₂ + 3H₂ → 2NH₃
3. NaCl + AgC₂H₃O₂ → NaC₂H₃O₂ + AgCl
4. 3Mg(OH)₂ + 2H₃PO₄ → 6H₂O + Mg₃(PO₄)₂
5. 2HNO₃ + Ni → Ni(NO₃)₂ + H₂
6. Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂
7. BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄
8. Al₂(CO₃)₃ → Al₂O₃ + 3CO₂
9. Ca + 2H₂O → Ca(OH)₂ + H₂
10. 2LiHCO₃ → Li₂CO₃ + H₂O + CO₂
11. 2N₂ + 5O₂ → 2N₂O₅
12. MgBr₂ + 2KOH → 2KBr + Mg(OH)₂
13. Mn + CuCl₂ → Cu + MnCl₂
14. 8Zn + S₈ → 8ZnS
15. 2NaOH + H₂SO₄ → 2H₂O + Na₂SO₄
16. 2K + 2H₂O → 2KOH + H₂
17. C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O
18. 2KOH + H₂CO₃ → 2H₂O + K₂CO₃
19. C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
20. 16Al + 3S₈ → 8Al₂S₃

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#### Types of Reactions:

1. Single Replacement
2. Synthesis
3. Double Replacement
4. Double Replacement
5. Single Replacement
6. Decomposition
7. Double Replacement
8. Decomposition
9. Single Replacement
10. Decomposition
11. Synthesis
12. Double Replacement
13. Single Replacement
14. Synthesis
15. Double Replacement
16. Single Replacement
17. Combustion
18. Double Replacement
19. Combustion
20. Synthesis

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✔ Summary Table

| # | Type |
|---|------|
| 1 | Single Replacement |
| 2 | Synthesis |
| 3 | Double Replacement |
| 4 | Double Replacement |
| 5 | Single Replacement |
| 6 | Decomposition |
| 7 | Double Replacement |
| 8 | Decomposition |
| 9 | Single Replacement |
|10 | Decomposition |
|11 | Synthesis |
|12 | Double Replacement |
|13 | Single Replacement |
|14 | Synthesis |
|15 | Double Replacement |
|16 | Single Replacement |
|17 | Combustion |
|18 | Double Replacement |
|19 | Combustion |
|20 | Synthesis |

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