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Balancing Act Practice worksheet featuring seven chemical equations to balance, with a challenging combustion reaction at the end.

Balancing Act Practice worksheet with chemical equations to balance, including a challenge equation.

Balancing Act Practice worksheet with chemical equations to balance, including a challenge equation.

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Show Answer Key & Explanations Step-by-step solution for: Balancing Act worksheet
To balance the chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations along with explanations:

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1. \( \text{Na} + \text{MgF}_2 \rightarrow \text{NaF} + \text{Mg} \)



- Step 1: Count the atoms on both sides.
- Left: 1 Na, 1 Mg, 2 F
- Right: 1 Na, 1 Mg, 1 F

- Step 2: Balance the fluorine (F) atoms.
- There are 2 F atoms on the left and 1 F atom on the right. To balance F, multiply NaF by 2.
- New equation: \( \text{Na} + \text{MgF}_2 \rightarrow 2\text{NaF} + \text{Mg} \)

- Step 3: Check the sodium (Na) atoms.
- Now there are 2 Na atoms on the right but only 1 on the left. Multiply Na by 2 on the left.
- Final balanced equation: \( 2\text{Na} + \text{MgF}_2 \rightarrow 2\text{NaF} + \text{Mg} \)

Balanced Equation:
\[ \boxed{2\text{Na} + \text{MgF}_2 \rightarrow 2\text{NaF} + \text{Mg}} \]

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2. \( \text{Mg} + \text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 \)



- Step 1: Count the atoms on both sides.
- Left: 1 Mg, 1 H, 1 Cl
- Right: 1 Mg, 2 H, 2 Cl

- Step 2: Balance the chlorine (Cl) atoms.
- There are 2 Cl atoms on the right and 1 Cl atom on the left. Multiply HCl by 2.
- New equation: \( \text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 \)

- Step 3: Check the hydrogen (H) atoms.
- Now there are 2 H atoms on the left and 2 H atoms on the right. The equation is balanced.

Balanced Equation:
\[ \boxed{\text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2} \]

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3. \( \text{Cl}_2 + \text{KI} \rightarrow \text{KCl} + \text{I}_2 \)



- Step 1: Count the atoms on both sides.
- Left: 2 Cl, 1 K, 1 I
- Right: 1 K, 1 Cl, 2 I

- Step 2: Balance the chlorine (Cl) atoms.
- There are 2 Cl atoms on the left and 1 Cl atom on the right. Multiply KCl by 2.
- New equation: \( \text{Cl}_2 + 2\text{KI} \rightarrow 2\text{KCl} + \text{I}_2 \)

- Step 3: Check the iodine (I) atoms.
- Now there are 2 I atoms on the left and 2 I atoms on the right. The equation is balanced.

Balanced Equation:
\[ \boxed{\text{Cl}_2 + 2\text{KI} \rightarrow 2\text{KCl} + \text{I}_2} \]

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4. \( \text{NaCl} \rightarrow \text{Na} + \text{Cl}_2 \)



- Step 1: Count the atoms on both sides.
- Left: 1 Na, 1 Cl
- Right: 1 Na, 2 Cl

- Step 2: Balance the chlorine (Cl) atoms.
- There are 2 Cl atoms on the right and 1 Cl atom on the left. Multiply NaCl by 2.
- New equation: \( 2\text{NaCl} \rightarrow 2\text{Na} + \text{Cl}_2 \)

- Step 3: Check the sodium (Na) atoms.
- Now there are 2 Na atoms on the left and 2 Na atoms on the right. The equation is balanced.

Balanced Equation:
\[ \boxed{2\text{NaCl} \rightarrow 2\text{Na} + \text{Cl}_2} \]

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5. \( \text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O} \)



- Step 1: Count the atoms on both sides.
- Left: 1 Na, 2 O
- Right: 2 Na, 1 O

- Step 2: Balance the sodium (Na) atoms.
- There are 2 Na atoms on the right and 1 Na atom on the left. Multiply Na by 2.
- New equation: \( 2\text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O} \)

- Step 3: Balance the oxygen (O) atoms.
- Now there are 2 O atoms on the left and 1 O atom on the right. Multiply Na₂O by 2.
- Final equation: \( 4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O} \)

Balanced Equation:
\[ \boxed{4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O}} \]

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6. \( \text{Na} + \text{HCl} \rightarrow \text{H}_2 + \text{NaCl} \)



- Step 1: Count the atoms on both sides.
- Left: 1 Na, 1 H, 1 Cl
- Right: 2 H, 1 Na, 1 Cl

- Step 2: Balance the hydrogen (H) atoms.
- There are 2 H atoms on the right and 1 H atom on the left. Multiply HCl by 2.
- New equation: \( \text{Na} + 2\text{HCl} \rightarrow \text{H}_2 + \text{NaCl} \)

- Step 3: Balance the sodium (Na) and chlorine (Cl) atoms.
- Now there are 2 Cl atoms on the left and 1 Cl atom on the right. Multiply NaCl by 2.
- Final equation: \( 2\text{Na} + 2\text{HCl} \rightarrow \text{H}_2 + 2\text{NaCl} \)

Balanced Equation:
\[ \boxed{2\text{Na} + 2\text{HCl} \rightarrow \text{H}_2 + 2\text{NaCl}} \]

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7. \( \text{K} + \text{Cl}_2 \rightarrow \text{KCl} \)



- Step 1: Count the atoms on both sides.
- Left: 1 K, 2 Cl
- Right: 1 K, 1 Cl

- Step 2: Balance the chlorine (Cl) atoms.
- There are 2 Cl atoms on the left and 1 Cl atom on the right. Multiply KCl by 2.
- New equation: \( \text{K} + \text{Cl}_2 \rightarrow 2\text{KCl} \)

- Step 3: Balance the potassium (K) atoms.
- Now there are 2 K atoms on the right and 1 K atom on the left. Multiply K by 2.
- Final equation: \( 2\text{K} + \text{Cl}_2 \rightarrow 2\text{KCl} \)

Balanced Equation:
\[ \boxed{2\text{K} + \text{Cl}_2 \rightarrow 2\text{KCl}} \]

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Challenge: \( \text{C}_2\text{H}_6 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)



- Step 1: Count the atoms on both sides.
- Left: 2 C, 6 H, 2 O
- Right: 1 C, 2 H, 3 O

- Step 2: Balance the carbon (C) atoms.
- There are 2 C atoms on the left and 1 C atom on the right. Multiply CO₂ by 2.
- New equation: \( \text{C}_2\text{H}_6 + \text{O}_2 \rightarrow 2\text{CO}_2 + \text{H}_2\text{O} \)

- Step 3: Balance the hydrogen (H) atoms.
- There are 6 H atoms on the left and 2 H atoms on the right. Multiply H₂O by 3.
- New equation: \( \text{C}_2\text{H}_6 + \text{O}_2 \rightarrow 2\text{CO}_2 + 3\text{H}_2\text{O} \)

- Step 4: Balance the oxygen (O) atoms.
- Now there are 2 O atoms on the left and 7 O atoms on the right (2 from CO₂ and 3 from H₂O). Multiply O₂ by 7/2 or 3.5. Since coefficients must be whole numbers, multiply the entire equation by 2.
- Final equation: \( 2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O} \)

Balanced Equation:
\[ \boxed{2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O}} \]

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Final Answers:


1. \( \boxed{2\text{Na} + \text{MgF}_2 \rightarrow 2\text{NaF} + \text{Mg}} \)
2. \( \boxed{\text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2} \)
3. \( \boxed{\text{Cl}_2 + 2\text{KI} \rightarrow 2\text{KCl} + \text{I}_2} \)
4. \( \boxed{2\text{NaCl} \rightarrow 2\text{Na} + \text{Cl}_2} \)
5. \( \boxed{4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O}} \)
6. \( \boxed{2\text{Na} + 2\text{HCl} \rightarrow \text{H}_2 + 2\text{NaCl}} \)
7. \( \boxed{2\text{K} + \text{Cl}_2 \rightarrow 2\text{KCl}} \)
8. \( \boxed{2\text{C}_2\text{H}_6 + 7\text{O}_2 \rightarrow 4\text{CO}_2 + 6\text{H}_2\text{O}} \)
Parent Tip: Review the logic above to help your child master the concept of balancing act worksheet.
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