Balancing Act worksheet for practicing balancing chemical equations with provided number tiles.

Explanation:
We need to balance each chemical equation by making sure the number of atoms of each element is the same on both sides.

Let’s go one by one:

1. Zn + O₂ → ZnO
Left: Zn = 1, O = 2
Right: Zn = 1, O = 1
To get 2 O on right, put 2 in front of ZnO → ZnO × 2 = 2 Zn, 2 O
Now Zn is 2 on right, so need 2 Zn on left.
→ 2 Zn + 1 O₂ → 2 ZnO

2. N₂ + H₂ → NH₃
Left: N = 2, H = 2
Right: N = 1, H = 3
To balance N: need 2 NH₃ → gives 2 N and 6 H
So need 3 H₂ on left (3 × 2 = 6 H)
→ 1 N₂ + 3 H₂ → 2 NH₃

3. B + F₂ → BF₃
Right: B = 1, F = 3
Left: B = 1, F = 2 per F₂
To get 3 F, need 3/2 F₂ — but we want whole numbers. Multiply all by 2:
2 B + 3 F₂ → 2 BF₃
Check: B = 2, F = 6 on both sides
→ 2 B + 3 F₂ → 2 BF₃

4. H₂ + O₂ → H₂O
Right: H = 2, O = 1
Left: H = 2, O = 2
To get 2 O on right, need 2 H₂O → gives 4 H and 2 O
So need 2 H₂ on left (2 × 2 = 4 H)
→ 2 H₂ + 1 O₂ → 2 H₂O

5. Fe + H₂O → Fe₃O₄ + H₂
Right: Fe = 3, O = 4, H = 2
Left: Fe = 1, H = 2, O = 1
To get 3 Fe, need 3 Fe on left.
To get 4 O, need 4 H₂O on left (4 O, 8 H)
Then right: Fe₃O₄ has 3 Fe, 4 O; H₂ must have 8 H → 4 H₂
So: 3 Fe + 4 H₂O → Fe₃O₄ + 4 H₂

6. HgO + Cl₂ → HgCl + O₂
Wait — HgCl is not standard; usually it's HgCl₂. But as written, assume HgCl.
Let’s check atoms:
Left: Hg = 1, O = 1, Cl = 2
Right: Hg = 1, Cl = 1, O = 2
Not balanced. Try 2 HgO + Cl₂ → 2 HgCl + O₂
Left: Hg = 2, O = 2, Cl = 2
Right: Hg = 2, Cl = 2, O = 2 ✔
→ 2 HgO + 1 Cl₂ → 2 HgCl + 1 O₂

7. KClO₃ → KCl + O₂
Left: K = 1, Cl = 1, O = 3
Right: K = 1, Cl = 1, O = 2
Need O = 3 on right → not possible with O₂ alone unless we use fractions.
Use 2 KClO₃ → 2 KCl + 3 O₂
Left: K=2, Cl=2, O=6
Right: K=2, Cl=2, O=6 ✔
→ 2 KClO₃ → 2 KCl + 3 O₂

8. Cl₂ + NaBr → NaCl + Br₂
Left: Cl = 2, Na = 1, Br = 1
Right: Na = 1, Cl = 1, Br = 2
To balance Br: need 2 NaBr → gives 2 Na, 2 Br
Then need 2 NaCl on right → 2 Na, 2 Cl
So need 1 Cl₂ on left (2 Cl)
→ 1 Cl₂ + 2 NaBr → 2 NaCl + 1 Br₂

9. Na₂O + CO₂ → Na₂CO₃
Left: Na = 2, O = 1+2 = 3, C = 1
Right: Na = 2, C = 1, O = 3
Already balanced!
→ 1 Na₂O + 1 CO₂ → 1 Na₂CO₃

10. Al₂O₃ → Al + O₂
Left: Al = 2, O = 3
Right: Al = 1, O = 2
To get even O, multiply left by 2: 2 Al₂O₃ → 4 Al + 3 O₂
Check: Left: Al = 4, O = 6
Right: Al = 4, O = 6 ✔
→ 2 Al₂O₃ → 4 Al + 3 O₂

Now match with the squares at bottom. The squares show numbers that likely correspond to coefficients in order (probably top row = eq 1–10 first coefficient, second row = second coefficient, third row = third coefficient, etc.). But the instruction says: *“Cut out the squares… pasting the small squares as needed into the spaces.”* And “Some spaces will not require a number” — meaning if coefficient is 1, maybe leave blank.

Let’s list all equations with coefficients (1 omitted if not needed):

1. 2 Zn + 1 O₂ → 2 ZnO → coefficients: 2, 1, 2
2. 1 N₂ + 3 H₂ → 2 NH₃ → 1, 3, 2
3. 2 B + 3 F₂ → 2 BF₃ → 2, 3, 2
4. 2 H₂ + 1 O₂ → 2 H₂O → 2, 1, 2
5. 3 Fe + 4 H₂O → 1 Fe₃O₄ + 4 H₂ → 3, 4, 1, 4
6. 2 HgO + 1 Cl₂ → 2 HgCl + 1 O₂ → 2, 1, 2, 1
7. 2 KClO₃ → 2 KCl + 3 O₂ → 2, 2, 3
8. 1 Cl₂ + 2 NaBr → 2 NaCl + 1 Br₂ → 1, 2, 2, 1
9. 1 Na₂O + 1 CO₂ → 1 Na₂CO₃ → 1, 1, 1
10. 2 Al₂O₃ → 4 Al + 3 O₂ → 2, 4, 3

But the worksheet only has 3 blanks per equation (except #5, #6, #8, #10 have 4 terms). Looking at the format:

1. __ Zn + __ O₂ → __ ZnO → 3 blanks
2. __ N₂ + __ H₂ → __ NH₃ → 3
3. __ B + __ F₂ → __ BF₃ → 3
4. __ H₂ + __ O₂ → __ H₂O → 3
5. __ Fe + __ H₂O → __ Fe₃O₄ + __ H₂ → 4 blanks
6. __ HgO + __ Cl₂ → __ HgCl + __ O₂ → 4
7. __ KClO₃ → __ KCl + __ O₂ → 3
8. __ Cl₂ + __ NaBr → __ NaCl + __ Br₂ → 4
9. __ Na₂O + __ CO₂ → __ Na₂CO₃ → 3
10. __ Al₂O₃ → __ Al + __ O₂ → 3

So for equations with 3 blanks, we give 3 numbers; for 4 blanks, 4 numbers.

Now, the squares at bottom are arranged in rows:
Row 1: 2 3 2 4 2 3 2 2 2 2
Row 2: 2 2 3 4 2 2 3 2 2 4
Row 3: 3 2

That’s 10 + 10 + 2 = 22 numbers — but we need:
Eq1:3, Eq2:3, Eq3:3, Eq4:3, Eq5:4, Eq6:4, Eq7:3, Eq8:4, Eq9:3, Eq10:3 → total = 3×7 + 4×3 = 21 + 12 = 33 blanks? Wait no:

Let’s count blanks:
1:3
2:3 → 6
3:3 → 9
4:3 → 12
5:4 → 16
6:4 → 20
7:3 → 23
8:4 → 27
9:3 → 30
10:3 → 33 blanks.

But only 22 squares shown — so likely the squares are just a pool to cut and use, not pre-assigned. The problem says: *“Cut out the squares… pasting the small squares as needed”*, so we just need to provide the correct coefficients.

Since the user asks to “Solve the problem accurately”, and the task is to fill in the blanks, we give the balanced equations with coefficients.

Final Answer should be the list of coefficients for each blank in order.

Let me write each equation with coefficients (1s included for clarity, though worksheet may leave 1 blank — but since squares include 1s? The squares shown don’t have 1s — smallest is 2. So likely 1s are left blank.)

But the instruction: “Some spaces will not require a number.” → means coefficient 1 is omitted (left blank).

So for answer, we give the non-1 coefficients where needed, but since the format expects numbers in blanks, and the squares are all ≥2, probably they expect us to write the numbers that go in the blanks (and blanks with 1 stay empty — but since we’re outputting final answer text, we’ll list all coefficients, and assume 1 means no number).

However, the user just wants the solved problem — i.e., the filled-in equations.

Given the format, safest is to output the 10 equations with correct coefficients, using 1 where needed (but note: in many worksheets, 1 is omitted, but for unambiguous answer, we’ll include 1).

But the Final Answer section must contain only the answer — likely a list of numbers in order of blanks.

Let me reconstruct blank-by-blank order:

Equation 1: [2] Zn + [ ] O₂ → [2] ZnO → but O₂ coefficient is 1 → blank left empty. However, the squares provided don’t have 1s, so likely they expect to put nothing for 1.

But since this is a text response, and we can’t leave blanks, and the instruction says “Provide only the final correct answer”, I think they want the full balanced equations written out clearly.

Looking at similar tasks, the expected output is the coefficients filled in.

I will provide the 10 equations with coefficients (writing 1 explicitly for clarity, but if the worksheet omits 1, that’s fine — our answer is correct either way).

But to match the format requested: “Final Answer: [only the final correct answer]”

I think the expected final answer is the list of coefficients in order of the blanks, skipping 1s (i.e., only numbers >1 are placed, and 1s are omitted). However, without seeing exactly how the squares map, the safest academic answer is to give each equation balanced.

Given the instructions, and that this is a homework help, I will output the balanced equations with coefficients (including 1), as that is unambiguous.

Final decision: Provide the 10 equations with correct coefficients. Since the user said “Solve the problem accurately”, that means give the filled-in equations.

Final Answer:
1. 2 Zn + O₂ → 2 ZnO
2. N₂ + 3 H₂ → 2 NH₃
3. 2 B + 3 F₂ → 2 BF₃
4. 2 H₂ + O₂ → 2 H₂O
5. 3 Fe + 4 H₂O → Fe₃O₄ + 4 H₂
6. 2 HgO + Cl₂ → 2 HgCl + O₂
7. 2 KClO₃ → 2 KCl + 3 O₂
8. Cl₂ + 2 NaBr → 2 NaCl + Br₂
9. Na₂O + CO₂ → Na₂CO₃
10. 2 Al₂O₃ → 4 Al + 3 O₂

Note: Coefficients of 1 are omitted as per convention and worksheet instruction (“some spaces will not require a number”).

So the final answer is the above 10 lines.