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Balancing Equations Worksheet with 20 chemical equations to balance.

Balancing Equations Worksheet with 20 chemical equations to balance, including reactants and products.

Balancing Equations Worksheet with 20 chemical equations to balance, including reactants and products.

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Show Answer Key & Explanations Step-by-step solution for: Chapter 7 Worksheet #1 Balancing Chemical Equations | Lecture ...
To solve the problem of balancing chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for each problem:

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1. \( \text{Na}_3\text{PO}_4 + \text{KOH} \rightarrow \text{NaOH} + \text{K}_3\text{PO}_4 \)



- Balance Na: There are 3 Na atoms on the left and 1 on the right. Add a coefficient of 3 to NaOH.
- Balance K: There is 1 K atom on the left and 3 on the right. Add a coefficient of 3 to KOH.

Balanced equation:
\[ \text{Na}_3\text{PO}_4 + 3\text{KOH} \rightarrow 3\text{NaOH} + \text{K}_3\text{PO}_4 \]

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2. \( \text{MgF}_2 + \text{Li}_2\text{CO}_3 \rightarrow \text{MgCO}_3 + \text{LiF} \)



- Balance Mg: There is 1 Mg atom on both sides.
- Balance F: There are 2 F atoms on the left and 1 on the right. Add a coefficient of 2 to LiF.
- Balance Li: There are 2 Li atoms on the left and 1 on the right. Add a coefficient of 2 to LiF.
- Balance C and O: There is 1 C and 3 O atoms on both sides.

Balanced equation:
\[ \text{MgF}_2 + \text{Li}_2\text{CO}_3 \rightarrow \text{MgCO}_3 + 2\text{LiF} \]

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3. \( \text{P}_4 + \text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \)



- Balance P: There are 4 P atoms on both sides.
- Balance O: There are 2 O atoms on the left and 10 on the right. Add a coefficient of 5 to O₂.

Balanced equation:
\[ \text{P}_4 + 5\text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \]

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4. \( \text{RbNO}_3 + \text{BeF}_2 \rightarrow \text{Be(NO}_3)_2 + \text{RbF} \)



- Balance Be: There is 1 Be atom on both sides.
- Balance Rb: There is 1 Rb atom on the left and 1 on the right.
- Balance N and O: There is 1 N and 3 O atoms on the left and 2 N and 6 O atoms on the right. Add a coefficient of 2 to RbNO₃.
- Balance F: There are 2 F atoms on the left and 1 on the right. Add a coefficient of 2 to RbF.

Balanced equation:
\[ 2\text{RbNO}_3 + \text{BeF}_2 \rightarrow \text{Be(NO}_3)_2 + 2\text{RbF} \]

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5. \( \text{AgNO}_3 + \text{Cu} \rightarrow \text{Cu(NO}_3)_2 + \text{Ag} \)



- Balance Cu: There is 1 Cu atom on the left and 1 on the right.
- Balance Ag: There is 1 Ag atom on the left and 1 on the right.
- Balance N and O: There is 1 N and 3 O atoms on the left and 2 N and 6 O atoms on the right. Add a coefficient of 2 to AgNO₃.

Balanced equation:
\[ 2\text{AgNO}_3 + \text{Cu} \rightarrow \text{Cu(NO}_3)_2 + 2\text{Ag} \]

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6. \( \text{ClF}_3 + \text{Br}_2 \rightarrow \text{ClBr}_3 + \text{F}_2 \)



- Balance Cl: There is 1 Cl atom on the left and 1 on the right.
- Balance Br: There are 2 Br atoms on the left and 3 on the right. Add a coefficient of 3 to Br₂ and 2 to ClBr₃.
- Balance F: There are 3 F atoms on the left and 2 on the right. Add a coefficient of 3 to F₂.

Balanced equation:
\[ 2\text{ClF}_3 + 3\text{Br}_2 \rightarrow 2\text{ClBr}_3 + 3\text{F}_2 \]

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7. \( \text{HCN} + \text{CuSO}_4 \rightarrow \text{H}_2\text{SO}_4 + \text{Cu(CN)}_2 \)



- Balance H: There is 1 H atom on the left and 2 on the right. Add a coefficient of 2 to HCN.
- Balance C and N: There is 1 C and 1 N atom on the left and 2 C and 2 N atoms on the right. The coefficients are already correct.
- Balance Cu, S, and O: There is 1 Cu, 1 S, and 4 O atoms on both sides.

Balanced equation:
\[ 2\text{HCN} + \text{CuSO}_4 \rightarrow \text{H}_2\text{SO}_4 + \text{Cu(CN)}_2 \]

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8. \( \text{GaF}_3 + \text{Cs} \rightarrow \text{CsF} + \text{Ga} \)



- Balance Ga: There is 1 Ga atom on both sides.
- Balance F: There are 3 F atoms on the left and 1 on the right. Add a coefficient of 3 to CsF.
- Balance Cs: There is 1 Cs atom on the left and 3 on the right. Add a coefficient of 3 to Cs.

Balanced equation:
\[ \text{GaF}_3 + 3\text{Cs} \rightarrow 3\text{CsF} + \text{Ga} \]

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9. \( \text{BaS} + \text{PF}_3 \rightarrow \text{BaF}_2 + \text{PS} \)



- Balance Ba: There is 1 Ba atom on both sides.
- Balance S: There is 1 S atom on both sides.
- Balance P: There is 1 P atom on the left and 1 on the right.
- Balance F: There are 3 F atoms on the left and 2 on the right. Add a coefficient of 2 to PF₃ and 3 to BaF₂.

Balanced equation:
\[ 3\text{BaS} + 2\text{PF}_3 \rightarrow 3\text{BaF}_2 + 2\text{PS} \]

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10. \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \)



- Balance N: There are 2 N atoms on the left and 1 on the right. Add a coefficient of 2 to NH₃.
- Balance H: There are 2 H atoms on the left and 3 on the right. Add a coefficient of 3 to H₂.

Balanced equation:
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]

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11. \( \text{NiF}_2 + \text{Br}_2 \rightarrow \text{NiBr}_2 + \text{F}_2 \)



- Balance Ni: There is 1 Ni atom on both sides.
- Balance F: There are 2 F atoms on the left and 2 on the right.
- Balance Br: There are 2 Br atoms on the left and 2 on the right.

Balanced equation:
\[ \text{NiF}_2 + \text{Br}_2 \rightarrow \text{NiBr}_2 + \text{F}_2 \]

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12. \( \text{Pb(OH)}_2 + \text{HCl} \rightarrow \text{PbCl}_2 + \text{H}_2\text{O} \)



- Balance Pb: There is 1 Pb atom on both sides.
- Balance O: There are 2 O atoms on the left and 1 on the right. Add a coefficient of 2 to H₂O.
- Balance H: There are 2 H atoms on the left and 2 on the right in H₂O, but we need 2 more H from HCl. Add a coefficient of 2 to HCl.
- Balance Cl: There is 1 Cl atom on the left and 2 on the right. Add a coefficient of 2 to HCl.

Balanced equation:
\[ \text{Pb(OH)}_2 + 2\text{HCl} \rightarrow \text{PbCl}_2 + 2\text{H}_2\text{O} \]

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13. \( \text{AlBr}_3 + \text{K}_2\text{SO}_4 \rightarrow \text{KBr} + \text{Al}_2(\text{SO}_4)_3 \)



- Balance Al: There is 1 Al atom on the left and 2 on the right. Add a coefficient of 2 to AlBr₃.
- Balance Br: There are 3 Br atoms on the left and 1 on the right. Add a coefficient of 6 to KBr.
- Balance K: There are 2 K atoms on the left and 1 on the right. Add a coefficient of 3 to K₂SO₄.
- Balance S and O: There is 1 S and 4 O atoms on the left and 3 S and 12 O atoms on the right. The coefficients are already correct.

Balanced equation:
\[ 2\text{AlBr}_3 + 3\text{K}_2\text{SO}_4 \rightarrow 6\text{KBr} + \text{Al}_2(\text{SO}_4)_3 \]

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14. \( \text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)



- Balance C: There is 1 C atom on both sides.
- Balance H: There are 4 H atoms on the left and 2 on the right. Add a coefficient of 2 to H₂O.
- Balance O: There are 2 O atoms on the left and 3 on the right. Add a coefficient of 2 to O₂.

Balanced equation:
\[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]

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15. \( \text{Na}_3\text{PO}_4 + \text{CaCl}_2 \rightarrow \text{NaCl} + \text{Ca}_3(\text{PO}_4)_2 \)



- Balance Na: There are 3 Na atoms on the left and 1 on the right. Add a coefficient of 3 to NaCl.
- Balance Ca: There is 1 Ca atom on the left and 3 on the right. Add a coefficient of 3 to CaCl₂.
- Balance P and O: There is 1 P and 4 O atoms on the left and 2 P and 8 O atoms on the right. The coefficients are already correct.

Balanced equation:
\[ 2\text{Na}_3\text{PO}_4 + 3\text{CaCl}_2 \rightarrow 6\text{NaCl} + \text{Ca}_3(\text{PO}_4)_2 \]

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16. \( \text{K} + \text{Cl}_2 \rightarrow \text{KCl} \)



- Balance K: There is 1 K atom on both sides.
- Balance Cl: There are 2 Cl atoms on the left and 1 on the right. Add a coefficient of 2 to KCl.

Balanced equation:
\[ 2\text{K} + \text{Cl}_2 \rightarrow 2\text{KCl} \]

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17. \( \text{Al} + \text{HCl} \rightarrow \text{H}_2 + \text{AlCl}_3 \)



- Balance Al: There is 1 Al atom on the left and 1 on the right.
- Balance H: There are 2 H atoms on the right and 1 on the left. Add a coefficient of 2 to HCl.
- Balance Cl: There is 1 Cl atom on the left and 3 on the right. Add a coefficient of 3 to HCl.

Balanced equation:
\[ 2\text{Al} + 6\text{HCl} \rightarrow 3\text{H}_2 + 2\text{AlCl}_3 \]

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18. \( \text{N}_2 + \text{F}_2 \rightarrow \text{NF}_3 \)



- Balance N: There are 2 N atoms on the left and 1 on the right. Add a coefficient of 2 to NF₃.
- Balance F: There are 2 F atoms on the left and 3 on the right. Add a coefficient of 3 to F₂.

Balanced equation:
\[ \text{N}_2 + 3\text{F}_2 \rightarrow 2\text{NF}_3 \]

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19. \( \text{SO}_2 + \text{Li}_2\text{Se} \rightarrow \text{SSe}_2 + \text{Li}_2\text{O} \)



- Balance S: There is 1 S atom on the left and 2 on the right. Add a coefficient of 2 to SO₂.
- Balance Se: There is 1 Se atom on the left and 2 on the right. Add a coefficient of 2 to Li₂Se.
- Balance Li: There are 2 Li atoms on the left and 2 on the right.
- Balance O: There are 2 O atoms on the left and 1 on the right. Add a coefficient of 2 to Li₂O.

Balanced equation:
\[ 2\text{SO}_2 + 2\text{Li}_2\text{Se} \rightarrow \text{SSe}_2 + 4\text{Li}_2\text{O} \]

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20. \( \text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \)



- Balance N: There is 1 N atom on the left and 2 on the right. Add a coefficient of 2 to NH₃.
- Balance H: There are 6 H atoms on the left and 8 on the right. Add a coefficient of 2 to NH₃.
- Balance S and O: There is 1 S and 4 O atoms on both sides.

Balanced equation:
\[ 2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \]

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Final Answer:



\[
\boxed{
\begin{array}{l}
1. \text{Na}_3\text{PO}_4 + 3\text{KOH} \rightarrow 3\text{NaOH} + \text{K}_3\text{PO}_4 \\
2. \text{MgF}_2 + \text{Li}_2\text{CO}_3 \rightarrow \text{MgCO}_3 + 2\text{LiF} \\
3. \text{P}_4 + 5\text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \\
4. 2\text{RbNO}_3 + \text{BeF}_2 \rightarrow \text{Be(NO}_3)_2 + 2\text{RbF} \\
5. 2\text{AgNO}_3 + \text{Cu} \rightarrow \text{Cu(NO}_3)_2 + 2\text{Ag} \\
6. 2\text{ClF}_3 + 3\text{Br}_2 \rightarrow 2\text{ClBr}_3 + 3\text{F}_2 \\
7. 2\text{HCN} + \text{CuSO}_4 \rightarrow \text{H}_2\text{SO}_4 + \text{Cu(CN)}_2 \\
8. \text{GaF}_3 + 3\text{Cs} \rightarrow 3\text{CsF} + \text{Ga} \\
9. 3\text{BaS} + 2\text{PF}_3 \rightarrow 3\text{BaF}_2 + 2\text{PS} \\
10. \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \\
11. \text{NiF}_2 + \text{Br}_2 \rightarrow \text{NiBr}_2 + \text{F}_2 \\
12. \text{Pb(OH)}_2 + 2\text{HCl} \rightarrow \text{PbCl}_2 + 2\text{H}_2\text{O} \\
13. 2\text{AlBr}_3 + 3\text{K}_2\text{SO}_4 \rightarrow 6\text{KBr} + \text{Al}_2(\text{SO}_4)_3 \\
14. \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \\
15. 2\text{Na}_3\text{PO}_4 + 3\text{CaCl}_2 \rightarrow 6\text{NaCl} + \text{Ca}_3(\text{PO}_4)_2 \\
16. 2\text{K} + \text{Cl}_2 \rightarrow 2\text{KCl} \\
17. 2\text{Al} + 6\text{HCl} \rightarrow 3\text{H}_2 + 2\text{AlCl}_3 \\
18. \text{N}_2 + 3\text{F}_2 \rightarrow 2\text{NF}_3 \\
19. 2\text{SO}_2 + 2\text{Li}_2\text{Se} \rightarrow \text{SSe}_2 + 4\text{Li}_2\text{O} \\
20. 2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of balancing chemical equations chapter 7 worksheet 1 answers.
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