Standard chemistry worksheet featuring 37 unbalanced chemical equations for students to solve.

Final Answer:
1) 1 H₃PO₄ + 3 KOH → 1 K₃PO₄ + 3 H₂O
2) 6 K + 1 B₂O₃ → 3 K₂O + 2 B
3) 1 HCl + 1 NaOH → 1 NaCl + 1 H₂O
4) 2 Na + 2 NaNO₃ → 2 Na₂O + 1 N₂
5) 1 C + 2 S₈ → 1 CS₂ (Note: S₈ is a molecule; to balance realistically, use S, but per worksheet format, likely expects 1 C + 2 S₈ → 1 CS₂ — however, that’s chemically incorrect. Correct balancing with S atoms: CS₂ needs 2 S atoms, so better to treat as S: 1 C + 2 S → 1 CS₂. Since worksheet writes S₈, assume they want smallest whole numbers using S₈ as given — but no integer solution exists unless we use 8 CS₂ and 1 S₈. Standard approach in such worksheets: treat S₈ as 8 S, so equation becomes C + 8S → CS₂ — still not balanced. Most likely, the intended answer is 1 C + 2 S → 1 CS₂, but since it's written S₈, many textbooks use: 1 C + ½ S₈ → 1 CS₂, then multiply by 2: 2 C + S₈ → 2 CS₂. So final: 2 C + 1 S₈ → 2 CS₂)
→ Let’s follow common worksheet convention: 2 C + 1 S₈ → 2 CS₂

But since instructions say *only final answer*, and multiple equations, I must provide all 37 balanced equations concisely.

Given the length, and that only Final Answer is requested (ExplainAnswer, etc. are false), I will list all 37 balanced equations with smallest whole-number coefficients:

1) 1 H₃PO₄ + 3 KOH → 1 K₃PO₄ + 3 H₂O
2) 6 K + 1 B₂O₃ → 3 K₂O + 2 B
3) 1 HCl + 1 NaOH → 1 NaCl + 1 H₂O
4) 10 Na + 2 NaNO₃ → 6 Na₂O + 1 N₂
5) 2 C + 1 S₈ → 2 CS₂
6) 4 Na + 1 O₂ → 2 Na₂O
7) 2 N₂ + 1 O₂ → 2 N₂O
8) 2 H₃PO₄ + 3 Mg(OH)₂ → 1 Mg₃(PO₄)₂ + 6 H₂O
9) 2 NaOH + 1 H₂CO₃ → 1 Na₂CO₃ + 2 H₂O
10) 1 KOH + 1 HBr → 1 KBr + 1 H₂O
11) 2 Na + 1 O₂ → 1 Na₂O
12) 2 Al(OH)₃ + 3 H₂CO₃ → 1 Al₂(CO₃)₃ + 6 H₂O
13) 16 Al + 3 S₈ → 8 Al₂S₃
14) 2 Cs + 1 N₂ → 2 Cs₃N? Wait—Cs₃N implies 3 Cs per N, so: 6 Cs + 1 N₂ → 2 Cs₃N
15) 1 Mg + 1 Cl₂ → 1 MgCl₂
16) 2 Rb + 2 RbNO₃ → 2 Rb₂O + 1 N₂
17) 2 C₆H₆ + 15 O₂ → 12 CO₂ + 6 H₂O
18) 1 N₂ + 3 H₂ → 2 NH₃
19) 1 C₁₈H₃₈ + 27.5 O₂ → 18 CO₂ + 19 H₂O → multiply by 2: 2 C₁₈H₃₈ + 55 O₂ → 36 CO₂ + 38 H₂O
20) 1 Al(OH)₃ + 3 HBr → 1 AlBr₃ + 3 H₂O
21) 2 CH₃CH₂CH₂CH₃ + 13 O₂ → 8 CO₂ + 10 H₂O
22) 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
23) 3 Li + 1 AlCl₃ → 3 LiCl + 1 Al
24) 2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
25) 3 NH₄OH + 1 H₃PO₄ → 1 (NH₄)₃PO₄ + 3 H₂O
26) 3 Rb + 1 P → 1 Rb₃P
27) 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
28) 2 Al(OH)₃ + 3 H₂SO₄ → 1 Al₂(SO₄)₃ + 6 H₂O
29) 2 Na + 1 Cl₂ → 2 NaCl
30) 16 Rb + 1 S₈ → 8 Rb₂S
31) 2 H₃PO₄ + 3 Ca(OH)₂ → 1 Ca₃(PO₄)₂ + 6 H₂O
32) 1 NH₃ + 1 HCl → 1 NH₄Cl
33) 2 Li + 2 H₂O → 2 LiOH + 1 H₂
34) 2 Ca₃(PO₄)₂ + 6 SiO₂ + 10 C → 6 CaSiO₃ + 10 CO + 1 P₄? Wait—product says P (atomic), but phosphorus is P₄. Worksheet says “P”, so assume atomic P → unbalanced. Standard reaction: Ca₃(PO₄)₂ + 3 SiO₂ + 5 C → 3 CaSiO₃ + 5 CO + 2 P. So: 2 Ca₃(PO₄)₂ + 6 SiO₂ + 10 C → 6 CaSiO₃ + 10 CO + 4 P
35) 4 NH₃ + 3 O₂ → 2 N₂ + 6 H₂O
36) 4 FeS₂ + 11 O₂ → 2 Fe₂O₃ + 8 SO₂
37) 5 C + 2 SO₂ → 1 CS₂ + 4 CO

However, due to strict instruction: *Provide only the final correct answer*, and the format requires just the answer block — and since this is a long list, the expected output is the fully balanced set.

But to comply precisely with the format (only “Final Answer:” section, no extra text), I will output the 37 equations in compact form as a single block, using minimal spacing:

Final Answer:
1) 1,3,1,3
2) 6,1,3,2
3) 1,1,1,1
4) 10,2,6,1
5) 2,1,2
6) 4,1,2
7) 2,1,2
8) 2,3,1,6
9) 2,1,1,2
10) 1,1,1,1
11) 2,1,1
12) 2,3,1,6
13) 16,3,8
14) 6,1,2
15) 1,1,1
16) 2,2,2,1
17) 2,15,12,6
18) 1,3,2
19) 2,55,36,38
20) 1,3,1,3
21) 2,13,8,10
22) 2,25,16,18
23) 3,1,3,1
24) 2,7,4,6
25) 3,1,1,3
26) 3,1,1
27) 1,2,1,2
28) 2,3,1,6
29) 2,1,2
30) 16,1,8
31) 2,3,1,6
32) 1,1,1
33) 2,2,2,1
34) 2,6,10,6,10,4
35) 4,3,2,6
36) 4,11,2,8
37) 5,2,1,4