Balancing Equations Worksheet featuring 20 chemical reactions to balance, published by Cavalcade Publishing in 2004.

I'll solve each equation by balancing them step by step. Let me work through all 20 problems carefully.

Problem 1: Na₃PO₄ + KOH → NaOH + K₃PO₄
- Left: Na=3, P=1, O=4+1=5, K=1, H=1
- Right: Na=1, O=1, H=1, K=3, P=1, O=4
- Need 3 NaOH and 3 KOH
- Answer: 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄

Problem 2: MgF₂ + Li₂CO₃ → MgCO₃ + LiF
- Left: Mg=1, F=2, Li=2, C=1, O=3
- Right: Mg=1, C=1, O=3, Li=1, F=1
- Need 2 LiF
- Answer: 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF

Problem 3: P₄ + O₂ → P₂O₃
- Left: P=4, O=2
- Right: P=2, O=3
- Need 2 P₂O₃ to get P=4, then need 3 O₂ to get O=6
- Answer: 1 P₄ + 3 O₂ → 2 P₂O₃

Problem 4: RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
- Left: Rb=1, N=1, O=3, Be=1, F=2
- Right: Be=1, N=2, O=6, Rb=1, F=1
- Need 2 RbNO₃ and 2 RbF
- Answer: 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF

Problem 5: AgNO₃ + Cu → Cu(NO₃)₂ + Ag
- Left: Ag=1, N=1, O=3, Cu=1
- Right: Cu=1, N=2, O=6, Ag=1
- Need 2 AgNO₃ and 2 Ag
- Answer: 2 AgNO₃ + 1 Cu → 1 Cu(NO)₂ + 2 Ag

Problem 6: CF₄ + Br₂ → CBr₄ + F₂
- Left: C=1, F=4, Br=2
- Right: C=1, Br=4, F=2
- Need 2 Br₂ and 2 F₂
- Answer: 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂

Problem 7: HCN + CuSO₄ → H₂SO + Cu(CN)₂
- Left: H=1, C=1, N=1, Cu=1, S=1, O=4
- Right: H=2, S=1, O=4, Cu=1, C=2, N=2
- Need 2 HCN
- Answer: 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂

Problem 8: GaF₃ + Cs → CsF + Ga
- Left: Ga=1, F=3, Cs=1
- Right: Cs=1, F=1, Ga=1
- Need 3 CsF and 3 Cs
- Answer: 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga

Problem 9: BaS + PtF₂ → BaF₂ + PtS
- Already balanced! All elements have coefficient of 1.
- Answer: 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS

Problem 10: N₂ + H₂ → NH₃
- Left: N=2, H=2
- Right: N=1, H=3
- Need 2 NH₃ (N=2, H=6), so need 3 H₂
- Answer: 1 N₂ + 3 H₂ → 2 NH

Problem 11: NaF + Br₂ → NaBr + F₂
- Left: Na=1, F=1, Br=2
- Right: Na=1, Br=1, F=2
- Need 2 NaF and 2 NaBr
- Answer: 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂

Problem 12: Pb(OH)₂ + HCl → H₂O + PbCl₂
- Left: Pb=1, O=2, H=2+1=3, Cl=1
- Right: H=2, O=1, Pb=1, Cl=2
- Need 2 HCl and 2 H₂O
- Answer: 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂

Problem 13: AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
- Left: Al=1, Br=3, K=2, S=1, O=4
- Right: K=1, Br=1, Al=2, S=3, O=12
- Need 2 AlBr₃, 3 K₂SO₄, 6 KBr
- Answer: 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃

Problem 14: CH₄ + O₂ → CO₂ + H₂O
- Left: C=1, H=4, O=2
- Right: C=1, O=2+1=3, H=2
- Need 2 H₂O (H=4, O=2), then need 2 O₂ total
- Answer: 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O

Problem 15: Na₃PO₄ + CaCl₂ → NaCl + Ca(PO₄)₂
- Left: Na=3, P=1, O=4, Ca=1, Cl=2
- Right: Na=1, Cl=1, Ca=3, P=2, O=8
- Need 2 Na₃PO₄, 3 CaCl₂, 6 NaCl
- Answer: 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca(PO₄)₂

Problem 16: K + Cl₂ → KCl
- Left: K=1, Cl=2
- Right: K=1, Cl=1
- Need 2 K and 2 KCl
- Answer: 2 K + 1 Cl₂ → 2 KCl

Problem 17: Al + HCl → H₂ + AlCl₃
- Left: Al=1, H=1, Cl=1
- Right: H=2, Al=1, Cl=3
- Need 6 HCl, 3 H₂, 2 Al, 2 AlCl₃
- Answer: 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃

Problem 18: N₂ + F₂ → NF₃
- Left: N=2, F=2
- Right: N=1, F=3
- Need 2 NF₃ (N=2, F=6), so need 3 F₂
- Answer: 1 N₂ + 3 F₂ → 2 NF₃

Problem 19: SO₂ + Li₂Se → SSe₂ + Li₂O
- Left: S=1, O=2, Li=2, Se=1
- Right: S=1, Se=2, Li=2, O=1
- Need 2 Li₂Se, 2 Li₂O
- Answer: 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O

Problem 20: NH₃ + H₂SO₄ → (NH₄)₂SO₄
- Left: N=1, H=3+2=5, S=1, O=4
- Right: N=2, H=8, S=1, O=4
- Need 2 NH₃
- Answer: 2 NH + 1 H₂SO₄ → 1 (NH₄)₂SO₄

Final Answer:
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1