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Unbalanced chemical equations for practice or study.

A list of 10 unbalanced chemical equations, numbered 10 through 19, displayed in a clear, black-and-white format.

A list of 10 unbalanced chemical equations, numbered 10 through 19, displayed in a clear, black-and-white format.

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The task involves identifying the type of chemical reaction for each given equation. Here is a detailed explanation of each reaction and its classification:

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10) \( \text{KClO}_3 \rightarrow \text{KCl} + \text{O}_2 \)



- Type of Reaction: Decomposition
- Explanation: A single compound (\( \text{KClO}_3 \)) breaks down into two simpler substances (\( \text{KCl} \) and \( \text{O}_2 \)). This is characteristic of a decomposition reaction.

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11) \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \)



- Type of Reaction: Synthesis (Combination)
- Explanation: Two elements (\( \text{N}_2 \) and \( \text{H}_2 \)) combine to form a single compound (\( \text{NH}_3 \)). This is a synthesis or combination reaction.

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12) \( \text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \)



- Type of Reaction: Single Displacement
- Explanation: Sodium (\( \text{Na} \)), a metal, displaces hydrogen (\( \text{H}_2 \)) from water (\( \text{H}_2\text{O} \)). The products are sodium hydroxide (\( \text{NaOH} \)) and hydrogen gas (\( \text{H}_2 \)). This is a single displacement reaction.

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13) \( \text{Cu} + \text{AgNO}_3 \rightarrow \text{Ag} + \text{Cu(NO}_3\text{)}_2 \)



- Type of Reaction: Single Displacement
- Explanation: Copper (\( \text{Cu} \)), a more reactive metal, displaces silver (\( \text{Ag} \)) from silver nitrate (\( \text{AgNO}_3 \)). The products are silver metal (\( \text{Ag} \)) and copper(II) nitrate (\( \text{Cu(NO}_3\text{)}_2 \)). This is a single displacement reaction.

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14) \( \text{HCl} + \text{Cu(OH)}_2 \rightarrow \text{CuCl}_2 + \text{H}_2\text{O} \)



- Type of Reaction: Acid-Base Neutralization
- Explanation: Hydrochloric acid (\( \text{HCl} \)) reacts with copper(II) hydroxide (\( \text{Cu(OH)}_2 \)), an alkali base, to form a salt (\( \text{CuCl}_2 \)) and water (\( \text{H}_2\text{O} \)). This is an acid-base neutralization reaction.

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15) \( \text{ZnCl}_2 + \text{H}_2\text{S} \rightarrow \text{ZnS} + \text{HCl} \)



- Type of Reaction: Double Displacement
- Explanation: Zinc chloride (\( \text{ZnCl}_2 \)) and hydrogen sulfide (\( \text{H}_2\text{S} \)) exchange ions to form zinc sulfide (\( \text{ZnS} \)) and hydrochloric acid (\( \text{HCl} \)). This is a double displacement reaction.

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16) \( \text{O}_2 + \text{H}_2 \rightarrow \text{H}_2\text{O} + \text{S} \)



- Type of Reaction: Combustion
- Explanation: Oxygen (\( \text{O}_2 \)) reacts with hydrogen (\( \text{H}_2 \)) to form water (\( \text{H}_2\text{O} \)). This is a combustion reaction involving a fuel (hydrogen) and oxygen.

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17) \( \text{Cr}_2\text{O}_3 \rightarrow \text{Cr}_2\text{O}_3 + \text{O}_2 \)



- Type of Reaction: Decomposition
- Explanation: Chromium(III) oxide (\( \text{Cr}_2\text{O}_3 \)) decomposes into chromium(III) oxide (\( \text{Cr}_2\text{O}_3 \)) and oxygen gas (\( \text{O}_2 \)). This is a decomposition reaction.

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18) \( \text{Cl}_2 + \text{O}_2 \rightarrow \text{CO}_2 + \text{SO}_2 \)



- Type of Reaction: Combination (Synthesis)
- Explanation: Chlorine (\( \text{Cl}_2 \)) and oxygen (\( \text{O}_2 \)) combine to form carbon dioxide (\( \text{CO}_2 \)) and sulfur dioxide (\( \text{SO}_2 \)). This is a combination or synthesis reaction.

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19) \( \text{NaHSO}_4 \rightarrow \text{Na}_2\text{SO}_4 + \text{SO}_3 + \text{H}_2\text{O} \)



- Type of Reaction: Decomposition
- Explanation: Sodium bisulfate (\( \text{NaHSO}_4 \)) decomposes into sodium sulfate (\( \text{Na}_2\text{SO}_4 \)), sulfur trioxide (\( \text{SO}_3 \)), and water (\( \text{H}_2\text{O} \)). This is a decomposition reaction.

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20) \( \text{O}_2 + \text{H}_2\text{S} \rightarrow \text{H}_2\text{O} + \text{SO}_2 \)



- Type of Reaction: Oxidation-Reduction (Redox)
- Explanation: Oxygen (\( \text{O}_2 \)) oxidizes hydrogen sulfide (\( \text{H}_2\text{S} \)) to form water (\( \text{H}_2\text{O} \)) and sulfur dioxide (\( \text{SO}_2 \)). This is an oxidation-reduction reaction because there is a transfer of electrons.

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Final Answer:



| Equation Number | Type of Reaction |
|------------------|-------------------|
| 10 | Decomposition |
| 11 | Synthesis |
| 12 | Single Displacement |
| 13 | Single Displacement |
| 14 | Acid-Base Neutralization |
| 15 | Double Displacement |
| 16 | Combustion |
| 17 | Decomposition |
| 18 | Combination |
| 19 | Decomposition |
| 20 | Oxidation-Reduction |

Boxed Final Answer:
\[
\boxed{
\begin{array}{c|c}
\text{Equation Number} & \text{Type of Reaction} \\
\hline
10 & \text{Decomposition} \\
11 & \text{Synthesis} \\
12 & \text{Single Displacement} \\
13 & \text{Single Displacement} \\
14 & \text{Acid-Base Neutralization} \\
15 & \text{Double Displacement} \\
16 & \text{Combustion} \\
17 & \text{Decomposition} \\
18 & \text{Combination} \\
19 & \text{Decomposition} \\
20 & \text{Oxidation-Reduction} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of balancing chemical reactions worksheets.
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