Balancing Equations Worksheet #2 featuring 20 chemical equations to balance, with a note about coefficients and a copyright notice from 2004 Cavalcade Publishing.
Balancing Equations Worksheet #2 with 20 chemical equations to balance, featuring a note about coefficients and a copyright notice from 2004 Cavalcade Publishing.
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Show Answer Key & Explanations
Step-by-step solution for: Balancing Equations 44 | PDF | Inorganic Chemistry | Metallic Elements
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Show Answer Key & Explanations
Step-by-step solution for: Balancing Equations 44 | PDF | Inorganic Chemistry | Metallic Elements
Let's solve each of these chemical equations by balancing them. The goal is to ensure the number of atoms of each element is the same on both sides of the equation.
---
Step-by-step:
- Left: 3 Li, 1 P, 4 O from PO₄, plus Na and O/H from NaOH.
- Right: 1 Li, 1 O, 1 H in LiOH; 3 Na, 1 P, 4 O in Na₃PO₄.
We need:
- 3 Li on right → 3 LiOH
- 3 Na on right → 3 NaOH
So:
→ Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄
✔ Balanced.
---
- Left: 1 Mg, 2 F, 2 Li, 1 C, 3 O
- Right: 1 Mg, 1 C, 3 O, 1 Li, 1 F
Need:
- 2 LiF → 2 Li, 2 F
So:
→ MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF
✔ Balanced.
---
- P₄ has 4 P atoms → need 2 P₂O₃ (to get 4 P)
- 2 P₂O₃ has 6 O → need 3 O₂
→ P₄ + 3O₂ → 2P₂O₃
✔ Balanced.
---
- Right: Mg(NO₃)₂ → needs 2 NO₃⁻ → so need 2 RbNO₃
- Then: 2 Rb → need 2 RbF
- So: 2 RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF
Check:
- Left: 2 Rb, 2 N, 6 O, 1 Mg, 2 F
- Right: 1 Mg, 2 N, 6 O, 2 Rb, 2 F
✔ Balanced.
---
- Cu(NO₃)₂ has 2 NO₃ → need 2 AgNO₃
- Then: 2 Ag → 2 Ag on right
- Cu → 1 Cu
→ 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
✔ Balanced.
---
- C: 1 on both sides
- F: 4 left → need 2 F₂ on right
- Br: 2 Br₂ = 4 Br → CBr₄ has 4 Br
So:
→ CF₄ + 2Br₂ → CBr₄ + 2F₂
✔ Balanced.
---
- Cu(CN)₂ has 2 CN → need 2 HCN
- Then: 2 H → H₂SO₄ has 2 H → good
- SO₄: 1 on each side
→ 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
✔ Balanced.
---
- GaF₃ → 1 Ga, 3 F
- Need 3 CsF → 3 Cs, 3 F
- Ga → 1 Ga
→ GaF₃ + 3Cs → 3CsF + Ga
✔ Balanced.
---
- Sr: 1 each side
- S: 1 each side
- Pt: 1 each side
- F: 2 each side
→ SrS + PtF₂ → SrF₂ + PtS
✔ Already balanced.
---
- N₂ → 2 N → need 2 NH₃
- 2 NH₃ → 6 H → need 3 H₂
→ N₂ + 3H₂ → 2NH₃
✔ Balanced.
---
- Br₂ → 2 Br → need 2 LiBr
- 2 LiBr → 2 Li → need 2 LiF
- F: 2 F from 2 LiF → F₂ on right
→ 2LiF + Br₂ → 2LiBr + F₂
✔ Balanced.
---
- Pb: 1 each
- Cl: 2 on right → need 2 HCl
- H: left: 2 from OH + 2 from HCl = 4 H
- Right: 2 H₂O → 4 H, 2 O
But OH from Pb(OH)₂ gives 2 O and 2 H, HCl gives 2 H → total 4 H, 2 O
Right: 2 H₂O → 4 H, 2 O
→ Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂
✔ Balanced.
---
- Right: Ga₂(CO₃)₃ → 2 Ga, 3 CO₃²⁻
- So need 2 GaBr₃ → 6 Br
- Need 6 NaBr → 6 Na
- Na₂CO₃ → each has 2 Na → need 3 Na₂CO₃ → 3 CO₃
Now check:
- Left: 2 Ga, 6 Br, 6 Na, 3 C, 9 O
- Right: 2 Ga, 6 Br, 6 Na, 3 C, 9 O
→ 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃
✔ Balanced.
---
- CH₄ → 1 C, 4 H
- CO₂ → 1 C
- H₂O → 2 H per molecule → need 2 H₂O for 4 H
- But 2 H₂O → 2 O, CO₂ → 2 O → total 4 O → need 2 O₂
→ CH₄ + 2O₂ → CO₂ + 2H₂O
✔ Balanced.
---
- Right: Ca₃(PO₄)₂ → 3 Ca, 2 PO₄
- So need 2 Li₃PO₄ → 6 Li
- 2 Li₃PO₄ → 6 Li, 2 PO₄
- Need 3 CaCl₂ → 3 Ca, 6 Cl
- Right: 6 LiCl → 6 Li, 6 Cl
→ 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂
✔ Balanced.
---
- Cl₂ → 2 Cl → need 2 NaCl → 2 Na
- So: 2Na + Cl₂ → 2NaCl
✔ Balanced.
---
- GaCl₃ → 3 Cl → need 3 HCl
- 3 HCl → 3 H → H₂ → need 3/2 H₂ → better use whole numbers
- Multiply by 2: 2Ga + 6HCl → 3H₂ + 2GaCl₃
→ 2Ga + 6HCl → 3H₂ + 2GaCl₃
✔ Balanced.
---
- N₂ → 2 N → need 2 NF₃ → 6 F
- F₂ → 3 F₂ → 6 F
→ N₂ + 3F₂ → 2NF₃
✔ Balanced.
---
- S: 1 each side
- Se: Li₂Se → 1 Se → SSe₂ → 2 Se → need 2 Li₂Se
- O: SO₂ → 2 O → need 2 Li₂O → 2 O
- Li: 2 Li₂Se → 4 Li → 2 Li₂O → 4 Li
So:
→ SO₂ + 2Li₂Se → SSe₂ + 2Li₂O
✔ Balanced.
---
- (NH₄)₂SO₄ → 2 N, 8 H, S, 4 O
- NH₃ → 1 N, 3 H → need 2 NH₃ → 2 N, 6 H
- H₂SO₄ → 2 H, S, 4 O → total H: 6+2=8 → perfect
→ 2NH₃ + H₂SO₄ → (NH₄)₂SO₄
✔ Balanced.
---
## ✔ Final Answers:
1) Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄
2) MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF
3) P₄ + 3O₂ → 2P₂O₃
4) 2RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF
5) 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
6) CF₄ + 2Br₂ → CBr₄ + 2F₂
7) 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
8) GaF₃ + 3Cs → 3CsF + Ga
9) SrS + PtF₂ → SrF₂ + PtS
10) N₂ + 3H₂ → 2NH₃
11) 2LiF + Br₂ → 2LiBr + F₂
12) Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂
13) 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃
14) CH₄ + 2O₂ → CO₂ + 2H₂O
15) 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂
16) 2Na + Cl₂ → 2NaCl
17) 2Ga + 6HCl → 3H₂ + 2GaCl₃
18) N₂ + 3F₂ → 2NF₃
19) SO₂ + 2Li₂Se → SSe₂ + 2Li₂O
20) 2NH₃ + H₂SO₄ → (NH₄)₂SO₄
---
Let me know if you'd like a printable version or explanation for any specific problem!
---
1) Li₃PO₄ + NaOH → LiOH + Na₃PO₄
Step-by-step:
- Left: 3 Li, 1 P, 4 O from PO₄, plus Na and O/H from NaOH.
- Right: 1 Li, 1 O, 1 H in LiOH; 3 Na, 1 P, 4 O in Na₃PO₄.
We need:
- 3 Li on right → 3 LiOH
- 3 Na on right → 3 NaOH
So:
→ Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄
✔ Balanced.
---
2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
- Left: 1 Mg, 2 F, 2 Li, 1 C, 3 O
- Right: 1 Mg, 1 C, 3 O, 1 Li, 1 F
Need:
- 2 LiF → 2 Li, 2 F
So:
→ MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF
✔ Balanced.
---
3) P₄ + O₂ → P₂O₃
- P₄ has 4 P atoms → need 2 P₂O₃ (to get 4 P)
- 2 P₂O₃ has 6 O → need 3 O₂
→ P₄ + 3O₂ → 2P₂O₃
✔ Balanced.
---
4) RbNO₃ + MgF₂ → Mg(NO₃)₂ + RbF
- Right: Mg(NO₃)₂ → needs 2 NO₃⁻ → so need 2 RbNO₃
- Then: 2 Rb → need 2 RbF
- So: 2 RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF
Check:
- Left: 2 Rb, 2 N, 6 O, 1 Mg, 2 F
- Right: 1 Mg, 2 N, 6 O, 2 Rb, 2 F
✔ Balanced.
---
5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
- Cu(NO₃)₂ has 2 NO₃ → need 2 AgNO₃
- Then: 2 Ag → 2 Ag on right
- Cu → 1 Cu
→ 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
✔ Balanced.
---
6) CF₄ + Br₂ → CBr₄ + F₂
- C: 1 on both sides
- F: 4 left → need 2 F₂ on right
- Br: 2 Br₂ = 4 Br → CBr₄ has 4 Br
So:
→ CF₄ + 2Br₂ → CBr₄ + 2F₂
✔ Balanced.
---
7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
- Cu(CN)₂ has 2 CN → need 2 HCN
- Then: 2 H → H₂SO₄ has 2 H → good
- SO₄: 1 on each side
→ 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
✔ Balanced.
---
8) GaF₃ + Cs → CsF + Ga
- GaF₃ → 1 Ga, 3 F
- Need 3 CsF → 3 Cs, 3 F
- Ga → 1 Ga
→ GaF₃ + 3Cs → 3CsF + Ga
✔ Balanced.
---
9) SrS + PtF₂ → SrF₂ + PtS
- Sr: 1 each side
- S: 1 each side
- Pt: 1 each side
- F: 2 each side
→ SrS + PtF₂ → SrF₂ + PtS
✔ Already balanced.
---
10) N₂ + H₂ → NH₃
- N₂ → 2 N → need 2 NH₃
- 2 NH₃ → 6 H → need 3 H₂
→ N₂ + 3H₂ → 2NH₃
✔ Balanced.
---
11) LiF + Br₂ → LiBr + F₂
- Br₂ → 2 Br → need 2 LiBr
- 2 LiBr → 2 Li → need 2 LiF
- F: 2 F from 2 LiF → F₂ on right
→ 2LiF + Br₂ → 2LiBr + F₂
✔ Balanced.
---
12) Pb(OH)₂ + HCl → H₂O + PbCl₂
- Pb: 1 each
- Cl: 2 on right → need 2 HCl
- H: left: 2 from OH + 2 from HCl = 4 H
- Right: 2 H₂O → 4 H, 2 O
But OH from Pb(OH)₂ gives 2 O and 2 H, HCl gives 2 H → total 4 H, 2 O
Right: 2 H₂O → 4 H, 2 O
→ Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂
✔ Balanced.
---
13) GaBr₃ + Na₂CO₃ → NaBr + Ga₂(CO₃)₃ *(Tough one)*
- Right: Ga₂(CO₃)₃ → 2 Ga, 3 CO₃²⁻
- So need 2 GaBr₃ → 6 Br
- Need 6 NaBr → 6 Na
- Na₂CO₃ → each has 2 Na → need 3 Na₂CO₃ → 3 CO₃
Now check:
- Left: 2 Ga, 6 Br, 6 Na, 3 C, 9 O
- Right: 2 Ga, 6 Br, 6 Na, 3 C, 9 O
→ 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃
✔ Balanced.
---
14) CH₄ + O₂ → CO₂ + H₂O
- CH₄ → 1 C, 4 H
- CO₂ → 1 C
- H₂O → 2 H per molecule → need 2 H₂O for 4 H
- But 2 H₂O → 2 O, CO₂ → 2 O → total 4 O → need 2 O₂
→ CH₄ + 2O₂ → CO₂ + 2H₂O
✔ Balanced.
---
15) Li₃PO₄ + CaCl₂ → LiCl + Ca₃(PO₄)₂ *(Tough)*
- Right: Ca₃(PO₄)₂ → 3 Ca, 2 PO₄
- So need 2 Li₃PO₄ → 6 Li
- 2 Li₃PO₄ → 6 Li, 2 PO₄
- Need 3 CaCl₂ → 3 Ca, 6 Cl
- Right: 6 LiCl → 6 Li, 6 Cl
→ 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂
✔ Balanced.
---
16) Na + Cl₂ → NaCl
- Cl₂ → 2 Cl → need 2 NaCl → 2 Na
- So: 2Na + Cl₂ → 2NaCl
✔ Balanced.
---
17) Ga + HCl → H₂ + GaCl₃ *(Last tough one)*
- GaCl₃ → 3 Cl → need 3 HCl
- 3 HCl → 3 H → H₂ → need 3/2 H₂ → better use whole numbers
- Multiply by 2: 2Ga + 6HCl → 3H₂ + 2GaCl₃
→ 2Ga + 6HCl → 3H₂ + 2GaCl₃
✔ Balanced.
---
18) N₂ + F₂ → NF₃
- N₂ → 2 N → need 2 NF₃ → 6 F
- F₂ → 3 F₂ → 6 F
→ N₂ + 3F₂ → 2NF₃
✔ Balanced.
---
19) SO₂ + Li₂Se → SSe₂ + Li₂O
- S: 1 each side
- Se: Li₂Se → 1 Se → SSe₂ → 2 Se → need 2 Li₂Se
- O: SO₂ → 2 O → need 2 Li₂O → 2 O
- Li: 2 Li₂Se → 4 Li → 2 Li₂O → 4 Li
So:
→ SO₂ + 2Li₂Se → SSe₂ + 2Li₂O
✔ Balanced.
---
20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
- (NH₄)₂SO₄ → 2 N, 8 H, S, 4 O
- NH₃ → 1 N, 3 H → need 2 NH₃ → 2 N, 6 H
- H₂SO₄ → 2 H, S, 4 O → total H: 6+2=8 → perfect
→ 2NH₃ + H₂SO₄ → (NH₄)₂SO₄
✔ Balanced.
---
## ✔ Final Answers:
1) Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄
2) MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF
3) P₄ + 3O₂ → 2P₂O₃
4) 2RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF
5) 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
6) CF₄ + 2Br₂ → CBr₄ + 2F₂
7) 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
8) GaF₃ + 3Cs → 3CsF + Ga
9) SrS + PtF₂ → SrF₂ + PtS
10) N₂ + 3H₂ → 2NH₃
11) 2LiF + Br₂ → 2LiBr + F₂
12) Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂
13) 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃
14) CH₄ + 2O₂ → CO₂ + 2H₂O
15) 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂
16) 2Na + Cl₂ → 2NaCl
17) 2Ga + 6HCl → 3H₂ + 2GaCl₃
18) N₂ + 3F₂ → 2NF₃
19) SO₂ + 2Li₂Se → SSe₂ + 2Li₂O
20) 2NH₃ + H₂SO₄ → (NH₄)₂SO₄
---
Let me know if you'd like a printable version or explanation for any specific problem!
Parent Tip: Review the logic above to help your child master the concept of balancing equations chemistry worksheet.
![49 Balancing Chemical Equations Worksheets [with Answers]](/images2/balancing-equations-chemistry-worksheet/balancing-equations-chemistry-worksheet-0.jpg)
