Science 9 worksheet titled "Balancing Equations Worksheet" by Mr. Belvedere, featuring 20 chemical equations to balance.
Balancing Equations Worksheet with 20 chemical equations to balance, including reactants and products with blank spaces for coefficients.
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers ...
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers ...
To solve the problem of balancing chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for each problem:
---
- Balance carbon (C): 3 C atoms on the left, so we need 3 CO₂ on the right.
- Balance hydrogen (H): 8 H atoms on the left, so we need 4 H₂O on the right.
- Balance oxygen (O): 2 O atoms in O₂, and we need a total of 10 O atoms (6 from 3 CO₂ and 4 from 4 H₂O), so we need 5 O₂ on the left.
Balanced Equation:
\[ \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \]
---
- Balance aluminum (Al): 1 Al on the left, so we need 1 AlN on the right.
- Balance iron (Fe): 3 Fe on the left, so we need 3 Fe on the right.
- Balance nitrogen (N): 2 N on the left, so we need 2 AlN on the right (which gives 2 N).
Balanced Equation:
\[ 2\text{Al} + \text{Fe}_3\text{N}_2 \rightarrow 2\text{AlN} + 3\text{Fe} \]
---
- Balance sodium (Na): 1 Na on the left, so we need 1 NaCl on the right.
- Balance chlorine (Cl): 2 Cl on the left, so we need 2 NaCl on the right.
Balanced Equation:
\[ 2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl} \]
---
- Balance hydrogen (H): 2 H on the left, so we need 1 H₂O on the right.
- Balance oxygen (O): 2 O on the left, so we need 1 O₂ on the right and 1 O in H₂O.
Balanced Equation:
\[ 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \]
---
- Balance carbon (C): 6 C on the left, so we need 6 CO₂ on the right.
- Balance hydrogen (H): 12 H on the left, so we need 6 H₂O on the right.
- Balance oxygen (O): 6 O in C₆H₁₂O₆ and 2 O in each O₂, so we need 6 O₂ on the left (total 18 O) to match 6 O in 6 H₂O and 12 O in 6 CO₂.
Balanced Equation:
\[ \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{H}_2\text{O} + 6\text{CO}_2 \]
---
- This is a photosynthesis-like reaction. Balance carbon (C): 1 C on the left, so we need 7 CO₂ on the left.
- Balance hydrogen (H): 2 H on the left, so we need 16 H₂O on the left.
- Balance oxygen (O): 2 O in H₂O and 2 O in CO₂, so we need 16 O₂ on the right.
Balanced Equation:
\[ 16\text{H}_2\text{O} + 7\text{CO}_2 \rightarrow \text{C}_7\text{H}_{16} + 16\text{O}_2 \]
---
- Balance sodium (Na): 1 Na on the left, so we need 1 NaCl on the right.
- Balance chlorine (Cl): 1 Cl on the left, so we need 1 NaCl on the right.
- Balance oxygen (O): 3 O on the left, so we need 1.5 O₂ on the right. Multiply everything by 2 to eliminate the fraction.
Balanced Equation:
\[ 2\text{NaClO}_3 \rightarrow 2\text{NaCl} + 3\text{O}_2 \]
---
- Balance lead (Pb): 4 Pb on the left, so we need 3 Pb₃(PO₄)₄ on the right.
- Balance phosphorus (P): 1 P on the left, so we need 4 PO₄ on the right.
- Balance nitrogen (N): 3 N in (NH₄)₃PO₄ and 4 N in Pb(NO₃)₄, so we need 12 NH₄NO₃ on the right.
- Balance oxygen (O): 4 O in (NH₄)₃PO₄ and 12 O in Pb(NO₃)₄, so we need 12 O in NH₄NO₃.
Balanced Equation:
\[ 3(\text{NH}_4)_3\text{PO}_4 + 4\text{Pb(NO}_3)_4 \rightarrow \text{Pb}_3(\text{PO}_4)_4 + 12\text{NH}_4\text{NO}_3 \]
---
- Balance boron (B): 1 B on the left, so we need 2 BF₃ on the left.
- Balance lithium (Li): 2 Li on the left, so we need 6 LiF on the right.
- Balance sulfur (S): 1 S on the left, so we need 3 Li₂SO₃ on the left.
- Balance fluorine (F): 3 F on the left, so we need 6 LiF on the right.
Balanced Equation:
\[ 2\text{BF}_3 + 3\text{Li}_2\text{SO}_3 \rightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF} \]
---
- Balance carbon (C): 7 C on the left, so we need 7 CO₂ on the right.
- Balance hydrogen (H): 17 H on the left, so we need 8.5 H₂O on the right. Multiply everything by 2 to eliminate the fraction.
- Balance oxygen (O): 2 O in O₂, so we need 11 O₂ on the left.
Balanced Equation:
\[ 2\text{C}_7\text{H}_{17} + 23\text{O}_2 \rightarrow 14\text{CO}_2 + 17\text{H}_2\text{O} \]
---
- Balance calcium (Ca): 1 Ca on the left, so we need 3 CaCO₃ on the left.
- Balance phosphorus (P): 1 P on the left, so we need 2 H₃PO₄ on the left.
- Balance hydrogen (H): 3 H in H₃PO₄, so we need 6 H₂CO₃ on the right.
- Balance oxygen (O): 3 O in CaCO₃ and 4 O in H₃PO₄, so we need 6 O in H₂CO₃.
Balanced Equation:
\[ 3\text{CaCO}_3 + 2\text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{CO}_3 \]
---
- Balance silver (Ag): 2 Ag on the left, so we need 2 Ag on the right.
- Balance sulfur (S): 1 S on the left, so we need 1/8 S₈ on the right. Multiply everything by 8 to eliminate the fraction.
Balanced Equation:
\[ 8\text{Ag}_2\text{S} \rightarrow 16\text{Ag} + \text{S}_8 \]
---
- Balance potassium (K): 1 K on the left, so we need 3 KOH on the right.
- Balance bromine (Br): 1 Br on the left, so we need 3 Br in FeBr₃ on the right.
- Balance iron (Fe): 1 Fe on the left, so we need 1 FeBr₃ on the right.
- Balance oxygen (O): 3 O in Fe(OH)₃, so we need 3 OH⁻ on the right.
Balanced Equation:
\[ 3\text{KBr} + \text{Fe(OH)}_3 \rightarrow 3\text{KOH} + \text{FeBr}_3 \]
---
- Balance potassium (K): 1 K on the left, so we need 2 KNO₃ on the left.
- Balance carbon (C): 1 C on the left, so we need 1 K₂CO₃ on the right.
- Balance hydrogen (H): 2 H on the left, so we need 2 HNO₃ on the right.
- Balance oxygen (O): 3 O in KNO₃ and 3 O in H₂CO₃, so we need 3 O in HNO₃.
Balanced Equation:
\[ 2\text{KNO}_3 + \text{H}_2\text{CO}_3 \rightarrow \text{K}_2\text{CO}_3 + 2\text{HNO}_3 \]
---
- Balance lead (Pb): 1 Pb on the left, so we need 1 PbO₂ on the right.
- Balance copper (Cu): 2 Cu on the left, so we need 2 Cu(OH)₂ on the right.
- Balance oxygen (O): 4 O in Pb(OH)₄ and 1 O in Cu₂O, so we need 2 O in PbO₂ and 4 O in Cu(OH)₂.
Balanced Equation:
\[ \text{Pb(OH)}_4 + 2\text{Cu}_2\text{O} \rightarrow \text{PbO}_2 + 4\text{Cu(OH)}_2 \]
---
- Balance chromium (Cr): 1 Cr on the left, so we need 1 CrSO₄ on the right.
- Balance nitrogen (N): 2 N in Cr(NO₂)₂ and 2 N in (NH₄)₂SO₄, so we need 4 NH₄NO₂ on the right.
- Balance oxygen (O): 4 O in Cr(NO₂)₂ and 4 O in (NH₄)₂SO₄, so we need 4 O in NH₄NO₂.
Balanced Equation:
\[ \text{Cr(NO}_2)_2 + (\text{NH}_4)_2\text{SO}_4 \rightarrow \text{CrSO}_4 + 4\text{NH}_4\text{NO}_2 \]
---
- Balance potassium (K): 1 K on the left, so we need 3 KOH on the left.
- Balance cobalt (Co): 3 Co on the left, so we need 3 Co(OH)₂ on the right.
- Balance phosphorus (P): 2 P on the left, so we need 2 K₃PO₄ on the right.
- Balance oxygen (O): 8 O in Co₃(PO₄)₂, so we need 8 O in K₃PO₄ and Co(OH)₂.
Balanced Equation:
\[ 6\text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow 2\text{K}_3\text{PO}_4 + 3\text{Co(OH)}_2 \]
---
- Balance tin (Sn): 1 Sn on the left, so we need 3 Sn(NO₂)₄ on the left.
- Balance platinum (Pt): 3 Pt on the left, so we need 3 Pt(NO₂)₄ on the right.
- Balance nitrogen (N): 4 N in Sn(NO₂)₄ and 4 N in Pt₃N₄, so we need 4 N in Sn₃N₄.
- Balance oxygen (O): 8 O in Sn(NO₂)₄, so we need 8 O in Pt(NO₂)₄.
Balanced Equation:
\[ 3\text{Sn(NO}_2)_4 + \text{Pt}_3\text{N}_4 \rightarrow \text{Sn}_3\text{N}_4 + 3\text{Pt(NO}_2)_4 \]
---
- Balance boron (B): 2 B on the left, so we need 2 B(NO₃)₃ on the right.
- Balance bromine (Br): 6 Br on the left, so we need 6 HBr on the right.
- Balance hydrogen (H): 1 H on the left, so we need 6 HNO₃ on the left.
- Balance oxygen (O): 3 O in HNO₃, so we need 6 O in B(NO₃)₃.
Balanced Equation:
\[ \text{B}_2\text{Br}_6 + 6\text{HNO}_3 \rightarrow 2\text{B(NO}_3)_3 + 6\text{HBr} \]
---
- Balance zinc (Zn): 1 Zn on the left, so we need 3 ZnS on the left.
- Balance aluminum (Al): 1 Al on the left, so we need 2 AlP on the left.
- Balance phosphorus (P): 1 P on the left, so we need 2 Zn₃P₂ on the right.
- Balance sulfur (S): 1 S on the left, so we need 3 Al₂S₃ on the right.
Balanced Equation:
\[ 3\text{ZnS} + 2\text{AlP} \rightarrow \text{Zn}_3\text{P}_2 + \text{Al}_2\text{S}_3 \]
---
\[
\boxed{
\begin{aligned}
1. & \quad \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \\
2. & \quad 2\text{Al} + \text{Fe}_3\text{N}_2 \rightarrow 2\text{AlN} + 3\text{Fe} \\
3. & \quad 2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl} \\
4. & \quad 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \\
5. & \quad \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{H}_2\text{O} + 6\text{CO}_2 \\
6. & \quad 16\text{H}_2\text{O} + 7\text{CO}_2 \rightarrow \text{C}_7\text{H}_{16} + 16\text{O}_2 \\
7. & \quad 2\text{NaClO}_3 \rightarrow 2\text{NaCl} + 3\text{O}_2 \\
8. & \quad 3(\text{NH}_4)_3\text{PO}_4 + 4\text{Pb(NO}_3)_4 \rightarrow \text{Pb}_3(\text{PO}_4)_4 + 12\text{NH}_4\text{NO}_3 \\
9. & \quad 2\text{BF}_3 + 3\text{Li}_2\text{SO}_3 \rightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF} \\
10. & \quad 2\text{C}_7\text{H}_{17} + 23\text{O}_2 \rightarrow 14\text{CO}_2 + 17\text{H}_2\text{O} \\
11. & \quad 3\text{CaCO}_3 + 2\text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{CO}_3 \\
12. & \quad 8\text{Ag}_2\text{S} \rightarrow 16\text{Ag} + \text{S}_8 \\
13. & \quad 3\text{KBr} + \text{Fe(OH)}_3 \rightarrow 3\text{KOH} + \text{FeBr}_3 \\
14. & \quad 2\text{KNO}_3 + \text{H}_2\text{CO}_3 \rightarrow \text{K}_2\text{CO}_3 + 2\text{HNO}_3 \\
15. & \quad \text{Pb(OH)}_4 + 2\text{Cu}_2\text{O} \rightarrow \text{PbO}_2 + 4\text{Cu(OH)}_2 \\
16. & \quad \text{Cr(NO}_2)_2 + (\text{NH}_4)_2\text{SO}_4 \rightarrow \text{CrSO}_4 + 4\text{NH}_4\text{NO}_2 \\
17. & \quad 6\text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow 2\text{K}_3\text{PO}_4 + 3\text{Co(OH)}_2 \\
18. & \quad 3\text{Sn(NO}_2)_4 + \text{Pt}_3\text{N}_4 \rightarrow \text{Sn}_3\text{N}_4 + 3\text{Pt(NO}_2)_4 \\
19. & \quad \text{B}_2\text{Br}_6 + 6\text{HNO}_3 \rightarrow 2\text{B(NO}_3)_3 + 6\text{HBr} \\
20. & \quad 3\text{ZnS} + 2\text{AlP} \rightarrow \text{Zn}_3\text{P}_2 + \text{Al}_2\text{S}_3 \\
\end{aligned}
}
\]
---
1. \( \text{C}_3\text{H}_8 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)
- Balance carbon (C): 3 C atoms on the left, so we need 3 CO₂ on the right.
- Balance hydrogen (H): 8 H atoms on the left, so we need 4 H₂O on the right.
- Balance oxygen (O): 2 O atoms in O₂, and we need a total of 10 O atoms (6 from 3 CO₂ and 4 from 4 H₂O), so we need 5 O₂ on the left.
Balanced Equation:
\[ \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \]
---
2. \( \text{Al} + \text{Fe}_3\text{N}_2 \rightarrow \text{AlN} + \text{Fe} \)
- Balance aluminum (Al): 1 Al on the left, so we need 1 AlN on the right.
- Balance iron (Fe): 3 Fe on the left, so we need 3 Fe on the right.
- Balance nitrogen (N): 2 N on the left, so we need 2 AlN on the right (which gives 2 N).
Balanced Equation:
\[ 2\text{Al} + \text{Fe}_3\text{N}_2 \rightarrow 2\text{AlN} + 3\text{Fe} \]
---
3. \( \text{Na} + \text{Cl}_2 \rightarrow \text{NaCl} \)
- Balance sodium (Na): 1 Na on the left, so we need 1 NaCl on the right.
- Balance chlorine (Cl): 2 Cl on the left, so we need 2 NaCl on the right.
Balanced Equation:
\[ 2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl} \]
---
4. \( \text{H}_2\text{O}_2 \rightarrow \text{H}_2\text{O} + \text{O}_2 \)
- Balance hydrogen (H): 2 H on the left, so we need 1 H₂O on the right.
- Balance oxygen (O): 2 O on the left, so we need 1 O₂ on the right and 1 O in H₂O.
Balanced Equation:
\[ 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \]
---
5. \( \text{C}_6\text{H}_{12}\text{O}_6 + \text{O}_2 \rightarrow \text{H}_2\text{O} + \text{CO}_2 \)
- Balance carbon (C): 6 C on the left, so we need 6 CO₂ on the right.
- Balance hydrogen (H): 12 H on the left, so we need 6 H₂O on the right.
- Balance oxygen (O): 6 O in C₆H₁₂O₆ and 2 O in each O₂, so we need 6 O₂ on the left (total 18 O) to match 6 O in 6 H₂O and 12 O in 6 CO₂.
Balanced Equation:
\[ \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{H}_2\text{O} + 6\text{CO}_2 \]
---
6. \( \text{H}_2\text{O} + \text{CO}_2 \rightarrow \text{C}_7\text{H}_{16} + \text{O}_2 \)
- This is a photosynthesis-like reaction. Balance carbon (C): 1 C on the left, so we need 7 CO₂ on the left.
- Balance hydrogen (H): 2 H on the left, so we need 16 H₂O on the left.
- Balance oxygen (O): 2 O in H₂O and 2 O in CO₂, so we need 16 O₂ on the right.
Balanced Equation:
\[ 16\text{H}_2\text{O} + 7\text{CO}_2 \rightarrow \text{C}_7\text{H}_{16} + 16\text{O}_2 \]
---
7. \( \text{NaClO}_3 \rightarrow \text{NaCl} + \text{O}_2 \)
- Balance sodium (Na): 1 Na on the left, so we need 1 NaCl on the right.
- Balance chlorine (Cl): 1 Cl on the left, so we need 1 NaCl on the right.
- Balance oxygen (O): 3 O on the left, so we need 1.5 O₂ on the right. Multiply everything by 2 to eliminate the fraction.
Balanced Equation:
\[ 2\text{NaClO}_3 \rightarrow 2\text{NaCl} + 3\text{O}_2 \]
---
8. \( (\text{NH}_4)_3\text{PO}_4 + \text{Pb(NO}_3)_4 \rightarrow \text{Pb}_3(\text{PO}_4)_4 + \text{NH}_4\text{NO}_3 \)
- Balance lead (Pb): 4 Pb on the left, so we need 3 Pb₃(PO₄)₄ on the right.
- Balance phosphorus (P): 1 P on the left, so we need 4 PO₄ on the right.
- Balance nitrogen (N): 3 N in (NH₄)₃PO₄ and 4 N in Pb(NO₃)₄, so we need 12 NH₄NO₃ on the right.
- Balance oxygen (O): 4 O in (NH₄)₃PO₄ and 12 O in Pb(NO₃)₄, so we need 12 O in NH₄NO₃.
Balanced Equation:
\[ 3(\text{NH}_4)_3\text{PO}_4 + 4\text{Pb(NO}_3)_4 \rightarrow \text{Pb}_3(\text{PO}_4)_4 + 12\text{NH}_4\text{NO}_3 \]
---
9. \( \text{BF}_3 + \text{Li}_2\text{SO}_3 \rightarrow \text{B}_2(\text{SO}_3)_3 + \text{LiF} \)
- Balance boron (B): 1 B on the left, so we need 2 BF₃ on the left.
- Balance lithium (Li): 2 Li on the left, so we need 6 LiF on the right.
- Balance sulfur (S): 1 S on the left, so we need 3 Li₂SO₃ on the left.
- Balance fluorine (F): 3 F on the left, so we need 6 LiF on the right.
Balanced Equation:
\[ 2\text{BF}_3 + 3\text{Li}_2\text{SO}_3 \rightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF} \]
---
10. \( \text{C}_7\text{H}_{17} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)
- Balance carbon (C): 7 C on the left, so we need 7 CO₂ on the right.
- Balance hydrogen (H): 17 H on the left, so we need 8.5 H₂O on the right. Multiply everything by 2 to eliminate the fraction.
- Balance oxygen (O): 2 O in O₂, so we need 11 O₂ on the left.
Balanced Equation:
\[ 2\text{C}_7\text{H}_{17} + 23\text{O}_2 \rightarrow 14\text{CO}_2 + 17\text{H}_2\text{O} \]
---
11. \( \text{CaCO}_3 + \text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{CO}_3 \)
- Balance calcium (Ca): 1 Ca on the left, so we need 3 CaCO₃ on the left.
- Balance phosphorus (P): 1 P on the left, so we need 2 H₃PO₄ on the left.
- Balance hydrogen (H): 3 H in H₃PO₄, so we need 6 H₂CO₃ on the right.
- Balance oxygen (O): 3 O in CaCO₃ and 4 O in H₃PO₄, so we need 6 O in H₂CO₃.
Balanced Equation:
\[ 3\text{CaCO}_3 + 2\text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{CO}_3 \]
---
12. \( \text{Ag}_2\text{S} \rightarrow \text{Ag} + \text{S}_8 \)
- Balance silver (Ag): 2 Ag on the left, so we need 2 Ag on the right.
- Balance sulfur (S): 1 S on the left, so we need 1/8 S₈ on the right. Multiply everything by 8 to eliminate the fraction.
Balanced Equation:
\[ 8\text{Ag}_2\text{S} \rightarrow 16\text{Ag} + \text{S}_8 \]
---
13. \( \text{KBr} + \text{Fe(OH)}_3 \rightarrow \text{KOH} + \text{FeBr}_3 \)
- Balance potassium (K): 1 K on the left, so we need 3 KOH on the right.
- Balance bromine (Br): 1 Br on the left, so we need 3 Br in FeBr₃ on the right.
- Balance iron (Fe): 1 Fe on the left, so we need 1 FeBr₃ on the right.
- Balance oxygen (O): 3 O in Fe(OH)₃, so we need 3 OH⁻ on the right.
Balanced Equation:
\[ 3\text{KBr} + \text{Fe(OH)}_3 \rightarrow 3\text{KOH} + \text{FeBr}_3 \]
---
14. \( \text{KNO}_3 + \text{H}_2\text{CO}_3 \rightarrow \text{K}_2\text{CO}_3 + \text{HNO}_3 \)
- Balance potassium (K): 1 K on the left, so we need 2 KNO₃ on the left.
- Balance carbon (C): 1 C on the left, so we need 1 K₂CO₃ on the right.
- Balance hydrogen (H): 2 H on the left, so we need 2 HNO₃ on the right.
- Balance oxygen (O): 3 O in KNO₃ and 3 O in H₂CO₃, so we need 3 O in HNO₃.
Balanced Equation:
\[ 2\text{KNO}_3 + \text{H}_2\text{CO}_3 \rightarrow \text{K}_2\text{CO}_3 + 2\text{HNO}_3 \]
---
15. \( \text{Pb(OH)}_4 + \text{Cu}_2\text{O} \rightarrow \text{PbO}_2 + \text{Cu(OH)}_2 \)
- Balance lead (Pb): 1 Pb on the left, so we need 1 PbO₂ on the right.
- Balance copper (Cu): 2 Cu on the left, so we need 2 Cu(OH)₂ on the right.
- Balance oxygen (O): 4 O in Pb(OH)₄ and 1 O in Cu₂O, so we need 2 O in PbO₂ and 4 O in Cu(OH)₂.
Balanced Equation:
\[ \text{Pb(OH)}_4 + 2\text{Cu}_2\text{O} \rightarrow \text{PbO}_2 + 4\text{Cu(OH)}_2 \]
---
16. \( \text{Cr(NO}_2)_2 + (\text{NH}_4)_2\text{SO}_4 \rightarrow \text{CrSO}_4 + \text{NH}_4\text{NO}_2 \)
- Balance chromium (Cr): 1 Cr on the left, so we need 1 CrSO₄ on the right.
- Balance nitrogen (N): 2 N in Cr(NO₂)₂ and 2 N in (NH₄)₂SO₄, so we need 4 NH₄NO₂ on the right.
- Balance oxygen (O): 4 O in Cr(NO₂)₂ and 4 O in (NH₄)₂SO₄, so we need 4 O in NH₄NO₂.
Balanced Equation:
\[ \text{Cr(NO}_2)_2 + (\text{NH}_4)_2\text{SO}_4 \rightarrow \text{CrSO}_4 + 4\text{NH}_4\text{NO}_2 \]
---
17. \( \text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow \text{K}_3\text{PO}_4 + \text{Co(OH)}_2 \)
- Balance potassium (K): 1 K on the left, so we need 3 KOH on the left.
- Balance cobalt (Co): 3 Co on the left, so we need 3 Co(OH)₂ on the right.
- Balance phosphorus (P): 2 P on the left, so we need 2 K₃PO₄ on the right.
- Balance oxygen (O): 8 O in Co₃(PO₄)₂, so we need 8 O in K₃PO₄ and Co(OH)₂.
Balanced Equation:
\[ 6\text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow 2\text{K}_3\text{PO}_4 + 3\text{Co(OH)}_2 \]
---
18. \( \text{Sn(NO}_2)_4 + \text{Pt}_3\text{N}_4 \rightarrow \text{Sn}_3\text{N}_4 + \text{Pt(NO}_2)_4 \)
- Balance tin (Sn): 1 Sn on the left, so we need 3 Sn(NO₂)₄ on the left.
- Balance platinum (Pt): 3 Pt on the left, so we need 3 Pt(NO₂)₄ on the right.
- Balance nitrogen (N): 4 N in Sn(NO₂)₄ and 4 N in Pt₃N₄, so we need 4 N in Sn₃N₄.
- Balance oxygen (O): 8 O in Sn(NO₂)₄, so we need 8 O in Pt(NO₂)₄.
Balanced Equation:
\[ 3\text{Sn(NO}_2)_4 + \text{Pt}_3\text{N}_4 \rightarrow \text{Sn}_3\text{N}_4 + 3\text{Pt(NO}_2)_4 \]
---
19. \( \text{B}_2\text{Br}_6 + \text{HNO}_3 \rightarrow \text{B(NO}_3)_3 + \text{HBr} \)
- Balance boron (B): 2 B on the left, so we need 2 B(NO₃)₃ on the right.
- Balance bromine (Br): 6 Br on the left, so we need 6 HBr on the right.
- Balance hydrogen (H): 1 H on the left, so we need 6 HNO₃ on the left.
- Balance oxygen (O): 3 O in HNO₃, so we need 6 O in B(NO₃)₃.
Balanced Equation:
\[ \text{B}_2\text{Br}_6 + 6\text{HNO}_3 \rightarrow 2\text{B(NO}_3)_3 + 6\text{HBr} \]
---
20. \( \text{ZnS} + \text{AlP} \rightarrow \text{Zn}_3\text{P}_2 + \text{Al}_2\text{S}_3 \)
- Balance zinc (Zn): 1 Zn on the left, so we need 3 ZnS on the left.
- Balance aluminum (Al): 1 Al on the left, so we need 2 AlP on the left.
- Balance phosphorus (P): 1 P on the left, so we need 2 Zn₃P₂ on the right.
- Balance sulfur (S): 1 S on the left, so we need 3 Al₂S₃ on the right.
Balanced Equation:
\[ 3\text{ZnS} + 2\text{AlP} \rightarrow \text{Zn}_3\text{P}_2 + \text{Al}_2\text{S}_3 \]
---
Final Answer:
\[
\boxed{
\begin{aligned}
1. & \quad \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \\
2. & \quad 2\text{Al} + \text{Fe}_3\text{N}_2 \rightarrow 2\text{AlN} + 3\text{Fe} \\
3. & \quad 2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl} \\
4. & \quad 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \\
5. & \quad \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{H}_2\text{O} + 6\text{CO}_2 \\
6. & \quad 16\text{H}_2\text{O} + 7\text{CO}_2 \rightarrow \text{C}_7\text{H}_{16} + 16\text{O}_2 \\
7. & \quad 2\text{NaClO}_3 \rightarrow 2\text{NaCl} + 3\text{O}_2 \\
8. & \quad 3(\text{NH}_4)_3\text{PO}_4 + 4\text{Pb(NO}_3)_4 \rightarrow \text{Pb}_3(\text{PO}_4)_4 + 12\text{NH}_4\text{NO}_3 \\
9. & \quad 2\text{BF}_3 + 3\text{Li}_2\text{SO}_3 \rightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF} \\
10. & \quad 2\text{C}_7\text{H}_{17} + 23\text{O}_2 \rightarrow 14\text{CO}_2 + 17\text{H}_2\text{O} \\
11. & \quad 3\text{CaCO}_3 + 2\text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{CO}_3 \\
12. & \quad 8\text{Ag}_2\text{S} \rightarrow 16\text{Ag} + \text{S}_8 \\
13. & \quad 3\text{KBr} + \text{Fe(OH)}_3 \rightarrow 3\text{KOH} + \text{FeBr}_3 \\
14. & \quad 2\text{KNO}_3 + \text{H}_2\text{CO}_3 \rightarrow \text{K}_2\text{CO}_3 + 2\text{HNO}_3 \\
15. & \quad \text{Pb(OH)}_4 + 2\text{Cu}_2\text{O} \rightarrow \text{PbO}_2 + 4\text{Cu(OH)}_2 \\
16. & \quad \text{Cr(NO}_2)_2 + (\text{NH}_4)_2\text{SO}_4 \rightarrow \text{CrSO}_4 + 4\text{NH}_4\text{NO}_2 \\
17. & \quad 6\text{KOH} + \text{Co}_3(\text{PO}_4)_2 \rightarrow 2\text{K}_3\text{PO}_4 + 3\text{Co(OH)}_2 \\
18. & \quad 3\text{Sn(NO}_2)_4 + \text{Pt}_3\text{N}_4 \rightarrow \text{Sn}_3\text{N}_4 + 3\text{Pt(NO}_2)_4 \\
19. & \quad \text{B}_2\text{Br}_6 + 6\text{HNO}_3 \rightarrow 2\text{B(NO}_3)_3 + 6\text{HBr} \\
20. & \quad 3\text{ZnS} + 2\text{AlP} \rightarrow \text{Zn}_3\text{P}_2 + \text{Al}_2\text{S}_3 \\
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of balancing equations worksheet 2 answers.
![49 Balancing Chemical Equations Worksheets [with Answers]](/images2/balancing-equations-worksheet-2-answers/balancing-equations-worksheet-2-answers-4.jpg)
![49 Balancing Chemical Equations Worksheets [with Answers]](/images2/balancing-equations-worksheet-2-answers/balancing-equations-worksheet-2-answers-18.jpg)
