Solved Balancing Equations Worksheet 1) 2) 3) 4) 5) 1 Na3PO4 ... - Free Printable
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Step-by-step solution for: Solved Balancing Equations Worksheet 1) 2) 3) 4) 5) 1 Na3PO4 ...
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Show Answer Key & Explanations
Step-by-step solution for: Solved Balancing Equations Worksheet 1) 2) 3) 4) 5) 1 Na3PO4 ...
Let’s go through each equation one by one and balance them. Balancing means making sure the number of atoms of each element is the same on both sides of the arrow.
We’ll start from #1 to #20, checking each carefully.
---
1) Na₃PO₄ + KOH → NaOH + K₃PO₄
Left: Na=3, P=1, O=4+1=5? Wait — let’s count properly.
Actually, better to list elements:
Na₃PO₄ has: Na=3, P=1, O=4
KOH has: K=1, O=1, H=1
→ Total left: Na=3, P=1, O=5, K=1, H=1
Right: NaOH → Na=1, O=1, H=1
K₃PO₄ → K=3, P=1, O=4
→ Total right: Na=1, K=3, P=1, O=5, H=1
So we need 3 NaOH on right to match Na=3 → then H=3, so need 3 KOH on left → then K=3 on left → matches K₃PO₄ on right.
✔ Balanced: 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
---
2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
Left: Mg=1, F=2, Li=2, C=1, O=3
Right: Mg=1, C=1, O=3, Li=1, F=1 → need 2 LiF
✔ Balanced: 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
---
3) P₄ + O₂ → P₂O₅
Left: P=4, O=?
Right: P=2, O=5 → need 2 P₂O₅ to get P=4 → then O=10 → so need 5 O₂ (since 5×2=10)
✔ Balanced: 1 P₄ + 5 O₂ → 2 P₂O₅
Wait — user wrote “3” for O₂? That would be wrong. Let me check again.
P₄ → 4 P atoms
Each P₂O₅ has 2 P → so need 2 P₂O₅ → total P=4 ✔️
O in 2 P₂O₅ = 2×5 = 10 → so need 5 O₂ molecules (each gives 2 O) → 5×2=10 ✔️
So correct is: 1 P₄ + 5 O₂ → 2 P₂O₅
But user filled in “3” for O₂ — that’s incorrect. We must fix it.
✔ Corrected: 1 P₄ + 5 O₂ → 2 P₂O₅
---
4) RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
Left: Rb=1, N=1, O=3, Be=1, F=2
Right: Be=1, N=2, O=6, Rb=1, F=1 → need 2 RbF → then Rb=2 on right → so need 2 RbNO₃ on left → then N=2, O=6 → matches Be(NO₃)₂
✔ Balanced: 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
User had this correct.
---
5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
Left: Ag=1, N=1, O=3, Cu=1
Right: Cu=1, N=2, O=6, Ag=1 → need 2 AgNO₃ on left → then Ag=2 → so need 2 Ag on right
✔ Balanced: 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
User had this correct.
---
6) CF₄ + Br₂ → CBr₄ + F₂
Left: C=1, F=4, Br=2
Right: C=1, Br=4, F=2 → need 2 F₂ on right → then F=4 ✔️
Need 2 Br₂ on left → Br=4 ✔️
✔ Balanced: 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
User had this correct.
---
7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Left: H=1, C=1, N=1, Cu=1, S=1, O=4
Right: H=2, S=1, O=4, Cu=1, C=2, N=2 → need 2 HCN on left → then H=2, C=2, N=2 → matches
✔ Balanced: 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
User had this correct.
---
8) GaF₃ + Cs → CsF + Ga
Left: Ga=1, F=3, Cs=1
Right: Cs=1, F=1, Ga=1 → need 3 CsF → then Cs=3 → so need 3 Cs on left
✔ Balanced: 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
User had this correct.
---
9) BaS + PtF₂ → BaF₂ + PtS
Check atoms:
Left: Ba=1, S=1, Pt=1, F=2
Right: Ba=1, F=2, Pt=1, S=1 → already balanced!
✔ Balanced: 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
User left blanks — should be all 1s.
---
10) N₂ + H₂ → NH₃
Left: N=2, H=2
Right: N=1, H=3 → need 2 NH₃ → then N=2, H=6 → so need 3 H₂ (3×2=6)
✔ Balanced: 1 N₂ + 3 H₂ → 2 NH₃
---
11) NaF + Br₂ → NaBr + F₂
Left: Na=1, F=1, Br=2
Right: Na=1, Br=1, F=2 → need 2 NaF → then F=2 → but then Na=2 → so need 2 NaBr → then Br=2 → matches Br₂
Wait: If 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
Check: Left: Na=2, F=2, Br=2
Right: Na=2, Br=2, F=2 ✔️
✔ Balanced: 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
---
12) Pb(OH)₂ + HCl → H₂O + PbCl₂
Left: Pb=1, O=2, H=2+1=3? Wait — Pb(OH)₂ has Pb, 2O, 2H; HCl has H, Cl
Better: Pb(OH)₂ → Pb=1, O=2, H=2
HCl → H=1, Cl=1 per molecule
Right: H₂O → H=2, O=1; PbCl₂ → Pb=1, Cl=2
To balance Cl: need 2 HCl → then H from HCl = 2, plus H from Pb(OH)₂ = 2 → total H=4 → so need 2 H₂O (each has 2H → 4H total) → O: 2 from Pb(OH)₂ → 2 H₂O needs 2O ✔️
✔ Balanced: 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
---
13) AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
Left: Al=1, Br=3, K=2, S=1, O=4
Right: K=1, Br=1, Al=2, S=3, O=12 → need 2 AlBr₃ → Al=2, Br=6
Need 3 K₂SO₄ → K=6, S=3, O=12
Then right: need 6 KBr → K=6, Br=6
And 1 Al₂(SO₄)₃ → Al=2, S=3, O=12
✔ Balanced: 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
---
14) CH₄ + O₂ → CO₂ + H₂O
Left: C=1, H=4, O=2
Right: C=1, O=2+1=3? Wait — CO₂ has O=2, H₂O has O=1 → total O=3 if one H₂O, but H=2 → need 2 H₂O → then H=4, O=2 (from CO₂) + 2 (from 2 H₂O) = 4 → so need 2 O₂ (2×2=4)
✔ Balanced: 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
---
15) Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO₄)₂
Left: Na=3, P=1, O=4, Ca=1, Cl=2
Right: Na=1, Cl=1, Ca=3, P=2, O=8 → need 2 Na₃PO₄ → Na=6, P=2, O=8
Need 3 CaCl₂ → Ca=3, Cl=6
Then right: need 6 NaCl → Na=6, Cl=6
And 1 Ca₃(PO₄)₂ → Ca=3, P=2, O=8
✔ Balanced: 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
---
16) K + Cl₂ → KCl
Left: K=1, Cl=2
Right: K=1, Cl=1 → need 2 KCl → then K=2 → so need 2 K on left
✔ Balanced: 2 K + 1 Cl₂ → 2 KCl
---
17) Al + HCl → H₂ + AlCl₃
Left: Al=1, H=1, Cl=1
Right: H=2, Al=1, Cl=3 → need 2 Al → then Al=2 → need 2 AlCl₃ → Cl=6 → so need 6 HCl → H=6 → need 3 H₂ (3×2=6)
✔ Balanced: 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
---
18) N₂ + F₂ → NF₃
Left: N=2, F=2
Right: N=1, F=3 → need 2 NF₃ → N=2, F=6 → so need 3 F₂ (3×2=6)
✔ Balanced: 1 N₂ + 3 F₂ → 2 NF₃
---
19) SO₂ + Li₂Se → SSe₂ + Li₂O
Left: S=1, O=2, Li=2, Se=1
Right: S=1, Se=2, Li=2, O=1 → need 2 Li₂O → then O=2, Li=4 → so need 2 Li₂Se → then Se=2, Li=4
Then right: SSe₂ → S=1, Se=2 ✔️
Left: SO₂ → S=1, O=2 ✔️
Wait — if 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
Check: Left: S=1, O=2, Li=4, Se=2
Right: S=1, Se=2, Li=4, O=2 ✔️
✔ Balanced: 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
---
20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
Left: N=1, H=3+2=5? Wait — NH₃ has N=1, H=3; H₂SO₄ has H=2, S=1, O=4
Total left: N=1, H=5, S=1, O=4
Right: (NH₄)₂SO₄ → N=2, H=8, S=1, O=4 → need 2 NH₃ → then N=2, H=6 from NH₃ + 2 from H₂SO₄ = 8 ✔️
✔ Balanced: 2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
---
Now, compiling all corrected answers:
Note: Some were already correct in the image, some needed fixing (like #3 and #9).
Final Answer:
1) 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
2) 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
3) 1 P₄ + 5 O₂ → 2 P₂O₅
4) 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
5) 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
6) 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
7) 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
8) 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
9) 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
10) 1 N₂ + 3 H₂ → 2 NH₃
11) 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
12) 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
13) 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
14) 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
15) 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
16) 2 K + 1 Cl₂ → 2 KCl
17) 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
18) 1 N₂ + 3 F₂ → 2 NF₃
19) 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
20) 2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
We’ll start from #1 to #20, checking each carefully.
---
1) Na₃PO₄ + KOH → NaOH + K₃PO₄
Left: Na=3, P=1, O=4+1=5? Wait — let’s count properly.
Actually, better to list elements:
Na₃PO₄ has: Na=3, P=1, O=4
KOH has: K=1, O=1, H=1
→ Total left: Na=3, P=1, O=5, K=1, H=1
Right: NaOH → Na=1, O=1, H=1
K₃PO₄ → K=3, P=1, O=4
→ Total right: Na=1, K=3, P=1, O=5, H=1
So we need 3 NaOH on right to match Na=3 → then H=3, so need 3 KOH on left → then K=3 on left → matches K₃PO₄ on right.
✔ Balanced: 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
---
2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
Left: Mg=1, F=2, Li=2, C=1, O=3
Right: Mg=1, C=1, O=3, Li=1, F=1 → need 2 LiF
✔ Balanced: 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
---
3) P₄ + O₂ → P₂O₅
Left: P=4, O=?
Right: P=2, O=5 → need 2 P₂O₅ to get P=4 → then O=10 → so need 5 O₂ (since 5×2=10)
✔ Balanced: 1 P₄ + 5 O₂ → 2 P₂O₅
Wait — user wrote “3” for O₂? That would be wrong. Let me check again.
P₄ → 4 P atoms
Each P₂O₅ has 2 P → so need 2 P₂O₅ → total P=4 ✔️
O in 2 P₂O₅ = 2×5 = 10 → so need 5 O₂ molecules (each gives 2 O) → 5×2=10 ✔️
So correct is: 1 P₄ + 5 O₂ → 2 P₂O₅
But user filled in “3” for O₂ — that’s incorrect. We must fix it.
✔ Corrected: 1 P₄ + 5 O₂ → 2 P₂O₅
---
4) RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
Left: Rb=1, N=1, O=3, Be=1, F=2
Right: Be=1, N=2, O=6, Rb=1, F=1 → need 2 RbF → then Rb=2 on right → so need 2 RbNO₃ on left → then N=2, O=6 → matches Be(NO₃)₂
✔ Balanced: 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
User had this correct.
---
5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
Left: Ag=1, N=1, O=3, Cu=1
Right: Cu=1, N=2, O=6, Ag=1 → need 2 AgNO₃ on left → then Ag=2 → so need 2 Ag on right
✔ Balanced: 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
User had this correct.
---
6) CF₄ + Br₂ → CBr₄ + F₂
Left: C=1, F=4, Br=2
Right: C=1, Br=4, F=2 → need 2 F₂ on right → then F=4 ✔️
Need 2 Br₂ on left → Br=4 ✔️
✔ Balanced: 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
User had this correct.
---
7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Left: H=1, C=1, N=1, Cu=1, S=1, O=4
Right: H=2, S=1, O=4, Cu=1, C=2, N=2 → need 2 HCN on left → then H=2, C=2, N=2 → matches
✔ Balanced: 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
User had this correct.
---
8) GaF₃ + Cs → CsF + Ga
Left: Ga=1, F=3, Cs=1
Right: Cs=1, F=1, Ga=1 → need 3 CsF → then Cs=3 → so need 3 Cs on left
✔ Balanced: 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
User had this correct.
---
9) BaS + PtF₂ → BaF₂ + PtS
Check atoms:
Left: Ba=1, S=1, Pt=1, F=2
Right: Ba=1, F=2, Pt=1, S=1 → already balanced!
✔ Balanced: 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
User left blanks — should be all 1s.
---
10) N₂ + H₂ → NH₃
Left: N=2, H=2
Right: N=1, H=3 → need 2 NH₃ → then N=2, H=6 → so need 3 H₂ (3×2=6)
✔ Balanced: 1 N₂ + 3 H₂ → 2 NH₃
---
11) NaF + Br₂ → NaBr + F₂
Left: Na=1, F=1, Br=2
Right: Na=1, Br=1, F=2 → need 2 NaF → then F=2 → but then Na=2 → so need 2 NaBr → then Br=2 → matches Br₂
Wait: If 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
Check: Left: Na=2, F=2, Br=2
Right: Na=2, Br=2, F=2 ✔️
✔ Balanced: 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
---
12) Pb(OH)₂ + HCl → H₂O + PbCl₂
Left: Pb=1, O=2, H=2+1=3? Wait — Pb(OH)₂ has Pb, 2O, 2H; HCl has H, Cl
Better: Pb(OH)₂ → Pb=1, O=2, H=2
HCl → H=1, Cl=1 per molecule
Right: H₂O → H=2, O=1; PbCl₂ → Pb=1, Cl=2
To balance Cl: need 2 HCl → then H from HCl = 2, plus H from Pb(OH)₂ = 2 → total H=4 → so need 2 H₂O (each has 2H → 4H total) → O: 2 from Pb(OH)₂ → 2 H₂O needs 2O ✔️
✔ Balanced: 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
---
13) AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
Left: Al=1, Br=3, K=2, S=1, O=4
Right: K=1, Br=1, Al=2, S=3, O=12 → need 2 AlBr₃ → Al=2, Br=6
Need 3 K₂SO₄ → K=6, S=3, O=12
Then right: need 6 KBr → K=6, Br=6
And 1 Al₂(SO₄)₃ → Al=2, S=3, O=12
✔ Balanced: 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
---
14) CH₄ + O₂ → CO₂ + H₂O
Left: C=1, H=4, O=2
Right: C=1, O=2+1=3? Wait — CO₂ has O=2, H₂O has O=1 → total O=3 if one H₂O, but H=2 → need 2 H₂O → then H=4, O=2 (from CO₂) + 2 (from 2 H₂O) = 4 → so need 2 O₂ (2×2=4)
✔ Balanced: 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
---
15) Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO₄)₂
Left: Na=3, P=1, O=4, Ca=1, Cl=2
Right: Na=1, Cl=1, Ca=3, P=2, O=8 → need 2 Na₃PO₄ → Na=6, P=2, O=8
Need 3 CaCl₂ → Ca=3, Cl=6
Then right: need 6 NaCl → Na=6, Cl=6
And 1 Ca₃(PO₄)₂ → Ca=3, P=2, O=8
✔ Balanced: 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
---
16) K + Cl₂ → KCl
Left: K=1, Cl=2
Right: K=1, Cl=1 → need 2 KCl → then K=2 → so need 2 K on left
✔ Balanced: 2 K + 1 Cl₂ → 2 KCl
---
17) Al + HCl → H₂ + AlCl₃
Left: Al=1, H=1, Cl=1
Right: H=2, Al=1, Cl=3 → need 2 Al → then Al=2 → need 2 AlCl₃ → Cl=6 → so need 6 HCl → H=6 → need 3 H₂ (3×2=6)
✔ Balanced: 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
---
18) N₂ + F₂ → NF₃
Left: N=2, F=2
Right: N=1, F=3 → need 2 NF₃ → N=2, F=6 → so need 3 F₂ (3×2=6)
✔ Balanced: 1 N₂ + 3 F₂ → 2 NF₃
---
19) SO₂ + Li₂Se → SSe₂ + Li₂O
Left: S=1, O=2, Li=2, Se=1
Right: S=1, Se=2, Li=2, O=1 → need 2 Li₂O → then O=2, Li=4 → so need 2 Li₂Se → then Se=2, Li=4
Then right: SSe₂ → S=1, Se=2 ✔️
Left: SO₂ → S=1, O=2 ✔️
Wait — if 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
Check: Left: S=1, O=2, Li=4, Se=2
Right: S=1, Se=2, Li=4, O=2 ✔️
✔ Balanced: 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
---
20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
Left: N=1, H=3+2=5? Wait — NH₃ has N=1, H=3; H₂SO₄ has H=2, S=1, O=4
Total left: N=1, H=5, S=1, O=4
Right: (NH₄)₂SO₄ → N=2, H=8, S=1, O=4 → need 2 NH₃ → then N=2, H=6 from NH₃ + 2 from H₂SO₄ = 8 ✔️
✔ Balanced: 2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
---
Now, compiling all corrected answers:
Note: Some were already correct in the image, some needed fixing (like #3 and #9).
Final Answer:
1) 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
2) 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
3) 1 P₄ + 5 O₂ → 2 P₂O₅
4) 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
5) 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
6) 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
7) 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
8) 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
9) 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
10) 1 N₂ + 3 H₂ → 2 NH₃
11) 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
12) 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
13) 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
14) 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
15) 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
16) 2 K + 1 Cl₂ → 2 KCl
17) 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
18) 1 N₂ + 3 F₂ → 2 NF₃
19) 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
20) 2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
Parent Tip: Review the logic above to help your child master the concept of balancing equations worksheet answers.
