49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable
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Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
To solve the problem of balancing chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for each problem:
- Balance Al: 1 Al on both sides.
- Balance Br: 3 Br on the left, so we need 3 KBr on the right.
- Balance K: 3 K on the right, so we need 3 K on the left.
Balanced equation:
\[ \boxed{1 \text{AlBr}_3 + 3 \text{K} \rightarrow 3 \text{KBr} + 1 \text{Al}} \]
- Balance Fe: 1 Fe on both sides.
- Balance O: 1 O on both sides.
- Balance Pd: 1 Pd on both sides.
- Balance F: 2 F on the left and 2 F on the right.
Balanced equation:
\[ \boxed{1 \text{FeO} + 1 \text{PdF}_2 \rightarrow 1 \text{FeF}_2 + 1 \text{PdO}} \]
- Balance P: 4 P on the left, so we need 4 PBr₃ on the right.
- Balance Br: 3 Br in each PBr₃, so 4 PBr₃ requires 12 Br. We have 2 Br in each Br₂, so we need 6 Br₂.
Balanced equation:
\[ \boxed{1 \text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3} \]
- Balance Li: 1 Li on both sides.
- Balance Cl: 1 Cl on the left, so we need 1 Cl₂ on the right.
- Balance Br: 2 Br on the left, so we need 2 LiBr on the right.
Balanced equation:
\[ \boxed{2 \text{LiCl} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{Cl}_2} \]
- Balance Pb: 1 Pb on both sides.
- Balance Br: 2 Br on the left, so we need 2 HBr on the right.
- Balance H: 2 H in 2 HBr, so we need 2 HCl on the left.
- Balance Cl: 2 Cl in PbCl₂, so we need 2 HCl on the left.
Balanced equation:
\[ \boxed{1 \text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + 1 \text{PbCl}_2} \]
- Balance Co: 2 Co on the right, so we need 2 CoBr₃ on the left.
- Balance Br: 3 Br in each CoBr₃, so 2 CoBr₃ gives 6 Br. We need 2 CaBr₂ on the right.
- Balance Ca: 2 Ca on the right, so we need 2 CaSO₄ on the left.
- Balance S: 3 S on the right, so we need 3 SO₄²⁻ from 3 CaSO₄.
- Balance O: 12 O on the right, so we need 12 O from 3 CaSO₄.
Balanced equation:
\[ \boxed{2 \text{CoBr}_3 + 3 \text{CaSO}_4 \rightarrow 2 \text{CaBr}_2 + 1 \text{Co}_2(\text{SO}_4)_3} \]
- Balance Na: 3 Na in Na₃P, so we need 3 NaF on the right.
- Balance P: 2 P in Ca₃P₂, so we need 2 Na₃P on the left.
- Balance Ca: 3 Ca in Ca₃P₂, so we need 3 CaF₂ on the left.
- Balance F: 2 F in each CaF₂, so 3 CaF₂ gives 6 F. We need 6 NaF on the right.
Balanced equation:
\[ \boxed{2 \text{Na}_3\text{P} + 3 \text{CaF}_2 \rightarrow 6 \text{NaF} + 1 \text{Ca}_3\text{P}_2} \]
- Balance Mn: 1 Mn on both sides.
- Balance I: 3 I in MnI₃, so we need 3 HI on the left.
- Balance H: 2 H in H₂, so we need 2 HI on the left (already balanced with 3 HI).
Balanced equation:
\[ \boxed{1 \text{Mn} + 3 \text{HI} \rightarrow 1 \text{H}_2 + 1 \text{MnI}_3} \]
- Balance Li: 3 Li in Li₃PO₄, so we need 3 LiBr on the right.
- Balance P: 1 P on both sides.
- Balance O: 4 O on both sides.
- Balance Na: 3 Na in Na₃PO₄, so we need 3 NaBr on the left.
Balanced equation:
\[ \boxed{1 \text{Li}_3\text{PO}_4 + 3 \text{NaBr} \rightarrow 1 \text{Na}_3\text{PO}_4 + 3 \text{LiBr}} \]
- Balance Ca: 1 Ca on both sides.
- Balance F: 2 F in CaF₂, so we need 2 LiF on the right.
- Balance Li: 2 Li in Li₂SO₄, so we need 2 LiF on the right.
- Balance S: 1 S on both sides.
- Balance O: 4 O on both sides.
Balanced equation:
\[ \boxed{1 \text{CaF}_2 + 1 \text{Li}_2\text{SO}_4 \rightarrow 1 \text{CaSO}_4 + 2 \text{LiF}} \]
- Balance Mg: 1 Mg on both sides.
- Balance Br: 2 Br in MgBr₂, so we need 2 HBr on the left.
- Balance H: 2 H in each H₂O, so we need 2 H₂O on the right.
- Balance O: 2 O in Mg(OH)₂, so we need 2 H₂O on the right.
Balanced equation:
\[ \boxed{2 \text{HBr} + 1 \text{Mg(OH)}_2 \rightarrow 1 \text{MgBr}_2 + 2 \text{H}_2\text{O}} \]
- Balance Li: 2 Li in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance Ca: 1 Ca on both sides.
- Balance N: 2 N in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance O: 6 O in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance Br: 2 Br in CaBr₂, so we need 2 LiBr on the right.
Balanced equation:
\[ \boxed{2 \text{LiNO}_3 + 1 \text{CaBr}_2 \rightarrow 1 \text{Ca(NO}_3)_2 + 2 \text{LiBr}} \]
- Balance Ag: 1 Ag on both sides.
- Balance Li: 1 Li on both sides.
- Balance N: 1 N on both sides.
- Balance O: 3 O on both sides.
Balanced equation:
\[ \boxed{1 \text{AgNO}_3 + 1 \text{Li} \rightarrow 1 \text{LiNO}_3 + 1 \text{Ag}} \]
- Balance Si: 1 Si on both sides.
- Balance Br: 4 Br in SiBr₄, so we need 4 NaBr on the left.
- Balance Na: 4 Na in 4 NaBr, so we need 4 NaOH on the right.
- Balance O: 4 O in Si(OH)₄, so we need 4 NaOH on the right.
- Balance H: 4 H in Si(OH)₄, so we need 4 NaOH on the right.
Balanced equation:
\[ \boxed{1 \text{Si(OH)}_4 + 4 \text{NaBr} \rightarrow 1 \text{SiBr}_4 + 4 \text{NaOH}} \]
- Balance Na: 2 Na in Na₂CO₃, so we need 2 NaCN on the left.
- Balance C: 1 C in CuCO₃, so we need 1 CuCO₃ on the left.
- Balance N: 2 N in Cu(CN)₂, so we need 2 NaCN on the left.
- Balance O: 3 O in Na₂CO₃, so we need 1 CuCO₃ on the left.
- Balance Cu: 1 Cu in Cu(CN)₂, so we need 1 CuCO₃ on the left.
Balanced equation:
\[ \boxed{2 \text{NaCN} + 1 \text{CuCO}_3 \rightarrow 1 \text{Na}_2\text{CO}_3 + 1 \text{Cu(CN)}_2} \]
- Balance N: 2 N in (NH₄)₂SO₄, so we need 2 NH₃ on the left.
- Balance H: 8 H in (NH₄)₂SO₄, so we need 2 NH₃ and 1 H₂SO₄ on the left.
- Balance S: 1 S on both sides.
- Balance O: 4 O in H₂SO₄, so we need 1 H₂SO₄ on the left.
Balanced equation:
\[ \boxed{2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 (\text{NH}_4)_2\text{SO}_4} \]
\[ \boxed{
\begin{aligned}
1. & \ 1 \text{AlBr}_3 + 3 \text{K} \rightarrow 3 \text{KBr} + 1 \text{Al} \\
2. & \ 1 \text{FeO} + 1 \text{PdF}_2 \rightarrow 1 \text{FeF}_2 + 1 \text{PdO} \\
3. & \ 1 \text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3 \\
4. & \ 2 \text{LiCl} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{Cl}_2 \\
5. & \ 1 \text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + 1 \text{PbCl}_2 \\
6. & \ 2 \text{CoBr}_3 + 3 \text{CaSO}_4 \rightarrow 2 \text{CaBr}_2 + 1 \text{Co}_2(\text{SO}_4)_3 \\
7. & \ 2 \text{Na}_3\text{P} + 3 \text{CaF}_2 \rightarrow 6 \text{NaF} + 1 \text{Ca}_3\text{P}_2 \\
8. & \ 1 \text{Mn} + 3 \text{HI} \rightarrow 1 \text{H}_2 + 1 \text{MnI}_3 \\
9. & \ 1 \text{Li}_3\text{PO}_4 + 3 \text{NaBr} \rightarrow 1 \text{Na}_3\text{PO}_4 + 3 \text{LiBr} \\
10. & \ 1 \text{CaF}_2 + 1 \text{Li}_2\text{SO}_4 \rightarrow 1 \text{CaSO}_4 + 2 \text{LiF} \\
11. & \ 2 \text{HBr} + 1 \text{Mg(OH)}_2 \rightarrow 1 \text{MgBr}_2 + 2 \text{H}_2\text{O} \\
12. & \ 2 \text{LiNO}_3 + 1 \text{CaBr}_2 \rightarrow 1 \text{Ca(NO}_3)_2 + 2 \text{LiBr} \\
13. & \ 1 \text{AgNO}_3 + 1 \text{Li} \rightarrow 1 \text{LiNO}_3 + 1 \text{Ag} \\
14. & \ 1 \text{Si(OH)}_4 + 4 \text{NaBr} \rightarrow 1 \text{SiBr}_4 + 4 \text{NaOH} \\
15. & \ 2 \text{NaCN} + 1 \text{CuCO}_3 \rightarrow 1 \text{Na}_2\text{CO}_3 + 1 \text{Cu(CN)}_2 \\
16. & \ 2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 (\text{NH}_4)_2\text{SO}_4 \\
\end{aligned}
} \]
1. \( \text{AlBr}_3 + \text{K} \rightarrow \text{KBr} + \text{Al} \)
- Balance Al: 1 Al on both sides.
- Balance Br: 3 Br on the left, so we need 3 KBr on the right.
- Balance K: 3 K on the right, so we need 3 K on the left.
Balanced equation:
\[ \boxed{1 \text{AlBr}_3 + 3 \text{K} \rightarrow 3 \text{KBr} + 1 \text{Al}} \]
2. \( \text{FeO} + \text{PdF}_2 \rightarrow \text{FeF}_2 + \text{PdO} \)
- Balance Fe: 1 Fe on both sides.
- Balance O: 1 O on both sides.
- Balance Pd: 1 Pd on both sides.
- Balance F: 2 F on the left and 2 F on the right.
Balanced equation:
\[ \boxed{1 \text{FeO} + 1 \text{PdF}_2 \rightarrow 1 \text{FeF}_2 + 1 \text{PdO}} \]
3. \( \text{P}_4 + \text{Br}_2 \rightarrow \text{PBr}_3 \)
- Balance P: 4 P on the left, so we need 4 PBr₃ on the right.
- Balance Br: 3 Br in each PBr₃, so 4 PBr₃ requires 12 Br. We have 2 Br in each Br₂, so we need 6 Br₂.
Balanced equation:
\[ \boxed{1 \text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3} \]
4. \( \text{LiCl} + \text{Br}_2 \rightarrow \text{LiBr} + \text{Cl}_2 \)
- Balance Li: 1 Li on both sides.
- Balance Cl: 1 Cl on the left, so we need 1 Cl₂ on the right.
- Balance Br: 2 Br on the left, so we need 2 LiBr on the right.
Balanced equation:
\[ \boxed{2 \text{LiCl} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{Cl}_2} \]
5. \( \text{PbBr}_2 + \text{HCl} \rightarrow \text{HBr} + \text{PbCl}_2 \)
- Balance Pb: 1 Pb on both sides.
- Balance Br: 2 Br on the left, so we need 2 HBr on the right.
- Balance H: 2 H in 2 HBr, so we need 2 HCl on the left.
- Balance Cl: 2 Cl in PbCl₂, so we need 2 HCl on the left.
Balanced equation:
\[ \boxed{1 \text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + 1 \text{PbCl}_2} \]
6. \( \text{CoBr}_3 + \text{CaSO}_4 \rightarrow \text{CaBr}_2 + \text{Co}_2(\text{SO}_4)_3 \)
- Balance Co: 2 Co on the right, so we need 2 CoBr₃ on the left.
- Balance Br: 3 Br in each CoBr₃, so 2 CoBr₃ gives 6 Br. We need 2 CaBr₂ on the right.
- Balance Ca: 2 Ca on the right, so we need 2 CaSO₄ on the left.
- Balance S: 3 S on the right, so we need 3 SO₄²⁻ from 3 CaSO₄.
- Balance O: 12 O on the right, so we need 12 O from 3 CaSO₄.
Balanced equation:
\[ \boxed{2 \text{CoBr}_3 + 3 \text{CaSO}_4 \rightarrow 2 \text{CaBr}_2 + 1 \text{Co}_2(\text{SO}_4)_3} \]
7. \( \text{Na}_3\text{P} + \text{CaF}_2 \rightarrow \text{NaF} + \text{Ca}_3\text{P}_2 \)
- Balance Na: 3 Na in Na₃P, so we need 3 NaF on the right.
- Balance P: 2 P in Ca₃P₂, so we need 2 Na₃P on the left.
- Balance Ca: 3 Ca in Ca₃P₂, so we need 3 CaF₂ on the left.
- Balance F: 2 F in each CaF₂, so 3 CaF₂ gives 6 F. We need 6 NaF on the right.
Balanced equation:
\[ \boxed{2 \text{Na}_3\text{P} + 3 \text{CaF}_2 \rightarrow 6 \text{NaF} + 1 \text{Ca}_3\text{P}_2} \]
8. \( \text{Mn} + \text{HI} \rightarrow \text{H}_2 + \text{MnI}_3 \)
- Balance Mn: 1 Mn on both sides.
- Balance I: 3 I in MnI₃, so we need 3 HI on the left.
- Balance H: 2 H in H₂, so we need 2 HI on the left (already balanced with 3 HI).
Balanced equation:
\[ \boxed{1 \text{Mn} + 3 \text{HI} \rightarrow 1 \text{H}_2 + 1 \text{MnI}_3} \]
9. \( \text{Li}_3\text{PO}_4 + \text{NaBr} \rightarrow \text{Na}_3\text{PO}_4 + \text{LiBr} \)
- Balance Li: 3 Li in Li₃PO₄, so we need 3 LiBr on the right.
- Balance P: 1 P on both sides.
- Balance O: 4 O on both sides.
- Balance Na: 3 Na in Na₃PO₄, so we need 3 NaBr on the left.
Balanced equation:
\[ \boxed{1 \text{Li}_3\text{PO}_4 + 3 \text{NaBr} \rightarrow 1 \text{Na}_3\text{PO}_4 + 3 \text{LiBr}} \]
10. \( \text{CaF}_2 + \text{Li}_2\text{SO}_4 \rightarrow \text{CaSO}_4 + \text{LiF} \)
- Balance Ca: 1 Ca on both sides.
- Balance F: 2 F in CaF₂, so we need 2 LiF on the right.
- Balance Li: 2 Li in Li₂SO₄, so we need 2 LiF on the right.
- Balance S: 1 S on both sides.
- Balance O: 4 O on both sides.
Balanced equation:
\[ \boxed{1 \text{CaF}_2 + 1 \text{Li}_2\text{SO}_4 \rightarrow 1 \text{CaSO}_4 + 2 \text{LiF}} \]
11. \( \text{HBr} + \text{Mg(OH)}_2 \rightarrow \text{MgBr}_2 + \text{H}_2\text{O} \)
- Balance Mg: 1 Mg on both sides.
- Balance Br: 2 Br in MgBr₂, so we need 2 HBr on the left.
- Balance H: 2 H in each H₂O, so we need 2 H₂O on the right.
- Balance O: 2 O in Mg(OH)₂, so we need 2 H₂O on the right.
Balanced equation:
\[ \boxed{2 \text{HBr} + 1 \text{Mg(OH)}_2 \rightarrow 1 \text{MgBr}_2 + 2 \text{H}_2\text{O}} \]
12. \( \text{LiNO}_3 + \text{CaBr}_2 \rightarrow \text{Ca(NO}_3)_2 + \text{LiBr} \)
- Balance Li: 2 Li in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance Ca: 1 Ca on both sides.
- Balance N: 2 N in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance O: 6 O in Ca(NO₃)₂, so we need 2 LiNO₃ on the left.
- Balance Br: 2 Br in CaBr₂, so we need 2 LiBr on the right.
Balanced equation:
\[ \boxed{2 \text{LiNO}_3 + 1 \text{CaBr}_2 \rightarrow 1 \text{Ca(NO}_3)_2 + 2 \text{LiBr}} \]
13. \( \text{AgNO}_3 + \text{Li} \rightarrow \text{LiNO}_3 + \text{Ag} \)
- Balance Ag: 1 Ag on both sides.
- Balance Li: 1 Li on both sides.
- Balance N: 1 N on both sides.
- Balance O: 3 O on both sides.
Balanced equation:
\[ \boxed{1 \text{AgNO}_3 + 1 \text{Li} \rightarrow 1 \text{LiNO}_3 + 1 \text{Ag}} \]
14. \( \text{Si(OH)}_4 + \text{NaBr} \rightarrow \text{SiBr}_4 + \text{NaOH} \)
- Balance Si: 1 Si on both sides.
- Balance Br: 4 Br in SiBr₄, so we need 4 NaBr on the left.
- Balance Na: 4 Na in 4 NaBr, so we need 4 NaOH on the right.
- Balance O: 4 O in Si(OH)₄, so we need 4 NaOH on the right.
- Balance H: 4 H in Si(OH)₄, so we need 4 NaOH on the right.
Balanced equation:
\[ \boxed{1 \text{Si(OH)}_4 + 4 \text{NaBr} \rightarrow 1 \text{SiBr}_4 + 4 \text{NaOH}} \]
15. \( \text{NaCN} + \text{CuCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{Cu(CN)}_2 \)
- Balance Na: 2 Na in Na₂CO₃, so we need 2 NaCN on the left.
- Balance C: 1 C in CuCO₃, so we need 1 CuCO₃ on the left.
- Balance N: 2 N in Cu(CN)₂, so we need 2 NaCN on the left.
- Balance O: 3 O in Na₂CO₃, so we need 1 CuCO₃ on the left.
- Balance Cu: 1 Cu in Cu(CN)₂, so we need 1 CuCO₃ on the left.
Balanced equation:
\[ \boxed{2 \text{NaCN} + 1 \text{CuCO}_3 \rightarrow 1 \text{Na}_2\text{CO}_3 + 1 \text{Cu(CN)}_2} \]
16. \( \text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \)
- Balance N: 2 N in (NH₄)₂SO₄, so we need 2 NH₃ on the left.
- Balance H: 8 H in (NH₄)₂SO₄, so we need 2 NH₃ and 1 H₂SO₄ on the left.
- Balance S: 1 S on both sides.
- Balance O: 4 O in H₂SO₄, so we need 1 H₂SO₄ on the left.
Balanced equation:
\[ \boxed{2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 (\text{NH}_4)_2\text{SO}_4} \]
Final Answer:
\[ \boxed{
\begin{aligned}
1. & \ 1 \text{AlBr}_3 + 3 \text{K} \rightarrow 3 \text{KBr} + 1 \text{Al} \\
2. & \ 1 \text{FeO} + 1 \text{PdF}_2 \rightarrow 1 \text{FeF}_2 + 1 \text{PdO} \\
3. & \ 1 \text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3 \\
4. & \ 2 \text{LiCl} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{Cl}_2 \\
5. & \ 1 \text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + 1 \text{PbCl}_2 \\
6. & \ 2 \text{CoBr}_3 + 3 \text{CaSO}_4 \rightarrow 2 \text{CaBr}_2 + 1 \text{Co}_2(\text{SO}_4)_3 \\
7. & \ 2 \text{Na}_3\text{P} + 3 \text{CaF}_2 \rightarrow 6 \text{NaF} + 1 \text{Ca}_3\text{P}_2 \\
8. & \ 1 \text{Mn} + 3 \text{HI} \rightarrow 1 \text{H}_2 + 1 \text{MnI}_3 \\
9. & \ 1 \text{Li}_3\text{PO}_4 + 3 \text{NaBr} \rightarrow 1 \text{Na}_3\text{PO}_4 + 3 \text{LiBr} \\
10. & \ 1 \text{CaF}_2 + 1 \text{Li}_2\text{SO}_4 \rightarrow 1 \text{CaSO}_4 + 2 \text{LiF} \\
11. & \ 2 \text{HBr} + 1 \text{Mg(OH)}_2 \rightarrow 1 \text{MgBr}_2 + 2 \text{H}_2\text{O} \\
12. & \ 2 \text{LiNO}_3 + 1 \text{CaBr}_2 \rightarrow 1 \text{Ca(NO}_3)_2 + 2 \text{LiBr} \\
13. & \ 1 \text{AgNO}_3 + 1 \text{Li} \rightarrow 1 \text{LiNO}_3 + 1 \text{Ag} \\
14. & \ 1 \text{Si(OH)}_4 + 4 \text{NaBr} \rightarrow 1 \text{SiBr}_4 + 4 \text{NaOH} \\
15. & \ 2 \text{NaCN} + 1 \text{CuCO}_3 \rightarrow 1 \text{Na}_2\text{CO}_3 + 1 \text{Cu(CN)}_2 \\
16. & \ 2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 (\text{NH}_4)_2\text{SO}_4 \\
\end{aligned}
} \]
Parent Tip: Review the logic above to help your child master the concept of balancing simple chemical equations worksheet.
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