Colorful bar chart illustrating population statistics in lakhs from 2005 to 2010, showing a significant rise and peak in 2008.
Bar chart showing population growth in lakhs from 2005 to 2010.
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Show Answer Key & Explanations
Step-by-step solution for: Worksheet on Bar Graph | Bar Graph Home Work | Questions on Bar Graph
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Show Answer Key & Explanations
Step-by-step solution for: Worksheet on Bar Graph | Bar Graph Home Work | Questions on Bar Graph
Problem Analysis:
The image provided is a bar chart showing the population (in lakhs) over several years. The task likely involves analyzing the data presented in the chart and answering specific questions related to it. Since no explicit question is mentioned, I will infer common types of questions that could be asked based on such a chart and provide a general solution.
Key Observations from the Chart:
1. Years Represented: The chart shows data for the years 2005, 2006, 2007, 2008, 2009, and 2010.
2. Population Values:
- 2005: Approximately 160 lakhs
- 2006: Approximately 210 lakhs
- 2007: Approximately 350 lakhs
- 2008: Approximately 400 lakhs
- 2009: Approximately 300 lakhs
- 2010: Approximately 370 lakhs
3. Trends:
- The population generally increases from 2005 to 2008.
- There is a significant drop in population from 2008 to 2009.
- The population rises again from 2009 to 2010 but does not reach the peak of 2008.
Possible Questions and Solutions:
#### 1. What is the population in the year 2008?
- From the chart, the population in 2008 is approximately 400 lakhs.
#### 2. Which year had the highest population?
- The highest population is observed in the year 2008, with approximately 400 lakhs.
#### 3. Which year had the lowest population?
- The lowest population is observed in the year 2005, with approximately 160 lakhs.
#### 4. What is the percentage increase in population from 2005 to 2008?
- Step 1: Population in 2005 = 160 lakhs
- Step 2: Population in 2008 = 400 lakhs
- Step 3: Increase in population = \( 400 - 160 = 240 \) lakhs
- Step 4: Percentage increase = \( \left( \frac{\text{Increase}}{\text{Initial Population}} \right) \times 100 \)
\[
\text{Percentage increase} = \left( \frac{240}{160} \right) \times 100 = 150\%
\]
- Answer: The population increased by 150% from 2005 to 2008.
#### 5. What is the percentage decrease in population from 2008 to 2009?
- Step 1: Population in 2008 = 400 lakhs
- Step 2: Population in 2009 = 300 lakhs
- Step 3: Decrease in population = \( 400 - 300 = 100 \) lakhs
- Step 4: Percentage decrease = \( \left( \frac{\text{Decrease}}{\text{Initial Population}} \right) \times 100 \)
\[
\text{Percentage decrease} = \left( \frac{100}{400} \right) \times 100 = 25\%
\]
- Answer: The population decreased by 25% from 2008 to 2009.
#### 6. What is the average population over the given years?
- Step 1: Sum of populations over all years:
\[
160 + 210 + 350 + 400 + 300 + 370 = 1790 \text{ lakhs}
\]
- Step 2: Number of years = 6
- Step 3: Average population = \( \frac{\text{Total Population}}{\text{Number of Years}} \)
\[
\text{Average population} = \frac{1790}{6} \approx 298.33 \text{ lakhs}
\]
- Answer: The average population over the given years is approximately 298.33 lakhs.
Final Answer:
Depending on the specific question asked, the answers are as follows:
- Highest population: 2008
- Lowest population: 2005
- Population in 2008: 400 lakhs
- Percentage increase from 2005 to 2008: 150%
- Percentage decrease from 2008 to 2009: 25%
- Average population: 298.33 lakhs
If you have a specific question in mind, please clarify, and I can refine the answer accordingly!
$$
\boxed{400 \text{ lakhs}}
$$ (if the question is about the population in 2008).
Parent Tip: Review the logic above to help your child master the concept of bar graph worksheet 6th grade.