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Step-by-step solution for: Cube Of A Binomial Worksheet - Fill Online, Printable, Fillable ...
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Step-by-step solution for: Cube Of A Binomial Worksheet - Fill Online, Printable, Fillable ...
To solve this matching worksheet, we need to expand each binomial expression using the Binomial Theorem or Pascal's Triangle.
The Binomial Theorem states that for any positive integer $n$:
$$(a + b)^n = \binom{n}{0}a^n b^0 + \binom{n}{1}a^{n-1}b^1 + \binom{n}{2}a^{n-2}b^2 + \dots + \binom{n}{n}a^0 b^n$$
Let's work through each problem one by one.
1. Expand $(3x + 5y)^3$
Here, $a = 3x$, $b = 5y$, and $n = 3$.
The coefficients for power 3 are 1, 3, 3, 1 (from Pascal's Triangle).
* Term 1: $1 \cdot (3x)^3 \cdot (5y)^0 = 1 \cdot 27x^3 \cdot 1 = 27x^3$
* Term 2: $3 \cdot (3x)^2 \cdot (5y)^1 = 3 \cdot 9x^2 \cdot 5y = 135x^2y$
* Term 3: $3 \cdot (3x)^1 \cdot (5y)^2 = 3 \cdot 3x \cdot 25y^2 = 225xy^2$
* Term 4: $1 \cdot (3x)^0 \cdot (5y)^3 = 1 \cdot 1 \cdot 125y^3 = 125y^3$
Result: $27x^3 + 135x^2y + 225xy^2 + 125y^3$
Looking at the options, this matches Option A.
2. Expand $(4x + 8y)^3$
Here, $a = 4x$, $b = 8y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (4x)^3 = 64x^3$
* Term 2: $3 \cdot (4x)^2 \cdot (8y) = 3 \cdot 16x^2 \cdot 8y = 384x^2y$
* Term 3: $3 \cdot (4x) \cdot (8y)^2 = 3 \cdot 4x \cdot 64y^2 = 768xy^2$
* Term 4: $1 \cdot (8y)^3 = 512y^3$
Result: $64x^3 + 384x^2y + 768xy^2 + 512y^3$
Looking at the options, this matches Option B.
3. Expand $(7x + 8y)^2$
Here, $a = 7x$, $b = 8y$, and $n = 2$.
Coefficients for power 2 are 1, 2, 1.
* Term 1: $1 \cdot (7x)^2 = 49x^2$
* Term 2: $2 \cdot (7x) \cdot (8y) = 112xy$
* Term 3: $1 \cdot (8y)^2 = 64y^2$
Result: $49x^2 + 112xy + 64y^2$
Looking at the options, this matches Option C.
4. Expand $(6x + 7y)^3$
Here, $a = 6x$, $b = 7y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (6x)^3 = 216x^3$
* Term 2: $3 \cdot (6x)^2 \cdot (7y) = 3 \cdot 36x^2 \cdot 7y = 756x^2y$
* Term 3: $3 \cdot (6x) \cdot (7y)^2 = 3 \cdot 6x \cdot 49y^2 = 882xy^2$
* Term 4: $1 \cdot (7y)^3 = 343y^3$
Result: $216x^3 + 756x^2y + 882xy^2 + 343y^3$
Looking at the options, this matches Option D.
5. Expand $(8x + 8y)^5$
Here, $a = 8x$, $b = 8y$, and $n = 5$.
This will result in very large numbers. Let's look at the first term to help identify the match.
First term: $\binom{5}{0}(8x)^5(8y)^0 = 1 \cdot 32768x^5 \cdot 1 = 32768x^5$.
Let's check the options for an expansion starting with $32768x^5$.
Option E starts with $32768x^5$. Let's verify the second term of Option E.
Second term calculation: $\binom{5}{1}(8x)^4(8y)^1 = 5 \cdot 4096x^4 \cdot 8y = 163840x^4y$.
Option E has $163840x^4y$. This looks correct.
Let's double check the last term: $(8y)^5 = 32768y^5$. Option E ends with $32768y^5$.
Result matches Option E.
6. Expand $(2x + 2y)^4$
Here, $a = 2x$, $b = 2y$, and $n = 4$.
Coefficients for power 4 are 1, 4, 6, 4, 1.
* Term 1: $1 \cdot (2x)^4 = 16x^4$
* Term 2: $4 \cdot (2x)^3 \cdot (2y) = 4 \cdot 8x^3 \cdot 2y = 64x^3y$
* Term 3: $6 \cdot (2x)^2 \cdot (2y)^2 = 6 \cdot 4x^2 \cdot 4y^2 = 96x^2y^2$
* Term 4: $4 \cdot (2x) \cdot (2y)^3 = 4 \cdot 2x \cdot 8y^3 = 64xy^3$
* Term 5: $1 \cdot (2y)^4 = 16y^4$
Result: $16x^4 + 64x^3y + 96x^2y^2 + 64xy^3 + 16y^4$
Looking at the options, this matches Option G.
7. Expand $(4x + 3y)^5$
Here, $a = 4x$, $b = 3y$, and $n = 5$.
Coefficients for power 5 are 1, 5, 10, 10, 5, 1.
* Term 1: $1 \cdot (4x)^5 = 1024x^5$
* Term 2: $5 \cdot (4x)^4 \cdot (3y) = 5 \cdot 256x^4 \cdot 3y = 3840x^4y$
* Term 3: $10 \cdot (4x)^3 \cdot (3y)^2 = 10 \cdot 64x^3 \cdot 9y^2 = 5760x^3y^2$
* Term 4: $10 \cdot (4x)^2 \cdot (3y)^3 = 10 \cdot 16x^2 \cdot 27y^3 = 4320x^2y^3$
* Term 5: $5 \cdot (4x) \cdot (3y)^4 = 5 \cdot 4x \cdot 81y^4 = 1620xy^4$
* Term 6: $1 \cdot (3y)^5 = 243y^5$
Result: $1024x^5 + 3840x^4y + 5760x^3y^2 + 4320x^2y^3 + 1620xy^4 + 243y^5$
Looking at the options, this matches Option F.
8. Expand $(6x + 8y)^3$
Here, $a = 6x$, $b = 8y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (6x)^3 = 216x^3$
* Term 2: $3 \cdot (6x)^2 \cdot (8y) = 3 \cdot 36x^2 \cdot 8y = 864x^2y$
* Term 3: $3 \cdot (6x) \cdot (8y)^2 = 3 \cdot 6x \cdot 64y^2 = 1152xy^2$
* Term 4: $1 \cdot (8y)^3 = 512y^3$
Result: $216x^3 + 864x^2y + 1152xy^2 + 512y^3$
Looking at the options, this matches Option H.
Final Answer:
1. A
2. B
3. C
4. D
5. E
6. G
7. F
8. H
The Binomial Theorem states that for any positive integer $n$:
$$(a + b)^n = \binom{n}{0}a^n b^0 + \binom{n}{1}a^{n-1}b^1 + \binom{n}{2}a^{n-2}b^2 + \dots + \binom{n}{n}a^0 b^n$$
Let's work through each problem one by one.
1. Expand $(3x + 5y)^3$
Here, $a = 3x$, $b = 5y$, and $n = 3$.
The coefficients for power 3 are 1, 3, 3, 1 (from Pascal's Triangle).
* Term 1: $1 \cdot (3x)^3 \cdot (5y)^0 = 1 \cdot 27x^3 \cdot 1 = 27x^3$
* Term 2: $3 \cdot (3x)^2 \cdot (5y)^1 = 3 \cdot 9x^2 \cdot 5y = 135x^2y$
* Term 3: $3 \cdot (3x)^1 \cdot (5y)^2 = 3 \cdot 3x \cdot 25y^2 = 225xy^2$
* Term 4: $1 \cdot (3x)^0 \cdot (5y)^3 = 1 \cdot 1 \cdot 125y^3 = 125y^3$
Result: $27x^3 + 135x^2y + 225xy^2 + 125y^3$
Looking at the options, this matches Option A.
2. Expand $(4x + 8y)^3$
Here, $a = 4x$, $b = 8y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (4x)^3 = 64x^3$
* Term 2: $3 \cdot (4x)^2 \cdot (8y) = 3 \cdot 16x^2 \cdot 8y = 384x^2y$
* Term 3: $3 \cdot (4x) \cdot (8y)^2 = 3 \cdot 4x \cdot 64y^2 = 768xy^2$
* Term 4: $1 \cdot (8y)^3 = 512y^3$
Result: $64x^3 + 384x^2y + 768xy^2 + 512y^3$
Looking at the options, this matches Option B.
3. Expand $(7x + 8y)^2$
Here, $a = 7x$, $b = 8y$, and $n = 2$.
Coefficients for power 2 are 1, 2, 1.
* Term 1: $1 \cdot (7x)^2 = 49x^2$
* Term 2: $2 \cdot (7x) \cdot (8y) = 112xy$
* Term 3: $1 \cdot (8y)^2 = 64y^2$
Result: $49x^2 + 112xy + 64y^2$
Looking at the options, this matches Option C.
4. Expand $(6x + 7y)^3$
Here, $a = 6x$, $b = 7y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (6x)^3 = 216x^3$
* Term 2: $3 \cdot (6x)^2 \cdot (7y) = 3 \cdot 36x^2 \cdot 7y = 756x^2y$
* Term 3: $3 \cdot (6x) \cdot (7y)^2 = 3 \cdot 6x \cdot 49y^2 = 882xy^2$
* Term 4: $1 \cdot (7y)^3 = 343y^3$
Result: $216x^3 + 756x^2y + 882xy^2 + 343y^3$
Looking at the options, this matches Option D.
5. Expand $(8x + 8y)^5$
Here, $a = 8x$, $b = 8y$, and $n = 5$.
This will result in very large numbers. Let's look at the first term to help identify the match.
First term: $\binom{5}{0}(8x)^5(8y)^0 = 1 \cdot 32768x^5 \cdot 1 = 32768x^5$.
Let's check the options for an expansion starting with $32768x^5$.
Option E starts with $32768x^5$. Let's verify the second term of Option E.
Second term calculation: $\binom{5}{1}(8x)^4(8y)^1 = 5 \cdot 4096x^4 \cdot 8y = 163840x^4y$.
Option E has $163840x^4y$. This looks correct.
Let's double check the last term: $(8y)^5 = 32768y^5$. Option E ends with $32768y^5$.
Result matches Option E.
6. Expand $(2x + 2y)^4$
Here, $a = 2x$, $b = 2y$, and $n = 4$.
Coefficients for power 4 are 1, 4, 6, 4, 1.
* Term 1: $1 \cdot (2x)^4 = 16x^4$
* Term 2: $4 \cdot (2x)^3 \cdot (2y) = 4 \cdot 8x^3 \cdot 2y = 64x^3y$
* Term 3: $6 \cdot (2x)^2 \cdot (2y)^2 = 6 \cdot 4x^2 \cdot 4y^2 = 96x^2y^2$
* Term 4: $4 \cdot (2x) \cdot (2y)^3 = 4 \cdot 2x \cdot 8y^3 = 64xy^3$
* Term 5: $1 \cdot (2y)^4 = 16y^4$
Result: $16x^4 + 64x^3y + 96x^2y^2 + 64xy^3 + 16y^4$
Looking at the options, this matches Option G.
7. Expand $(4x + 3y)^5$
Here, $a = 4x$, $b = 3y$, and $n = 5$.
Coefficients for power 5 are 1, 5, 10, 10, 5, 1.
* Term 1: $1 \cdot (4x)^5 = 1024x^5$
* Term 2: $5 \cdot (4x)^4 \cdot (3y) = 5 \cdot 256x^4 \cdot 3y = 3840x^4y$
* Term 3: $10 \cdot (4x)^3 \cdot (3y)^2 = 10 \cdot 64x^3 \cdot 9y^2 = 5760x^3y^2$
* Term 4: $10 \cdot (4x)^2 \cdot (3y)^3 = 10 \cdot 16x^2 \cdot 27y^3 = 4320x^2y^3$
* Term 5: $5 \cdot (4x) \cdot (3y)^4 = 5 \cdot 4x \cdot 81y^4 = 1620xy^4$
* Term 6: $1 \cdot (3y)^5 = 243y^5$
Result: $1024x^5 + 3840x^4y + 5760x^3y^2 + 4320x^2y^3 + 1620xy^4 + 243y^5$
Looking at the options, this matches Option F.
8. Expand $(6x + 8y)^3$
Here, $a = 6x$, $b = 8y$, and $n = 3$.
Coefficients: 1, 3, 3, 1.
* Term 1: $1 \cdot (6x)^3 = 216x^3$
* Term 2: $3 \cdot (6x)^2 \cdot (8y) = 3 \cdot 36x^2 \cdot 8y = 864x^2y$
* Term 3: $3 \cdot (6x) \cdot (8y)^2 = 3 \cdot 6x \cdot 64y^2 = 1152xy^2$
* Term 4: $1 \cdot (8y)^3 = 512y^3$
Result: $216x^3 + 864x^2y + 1152xy^2 + 512y^3$
Looking at the options, this matches Option H.
Final Answer:
1. A
2. B
3. C
4. D
5. E
6. G
7. F
8. H
Parent Tip: Review the logic above to help your child master the concept of binomials worksheet.