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I'll solve each of the 12 Punnett square problems step by step, calculating the percentage of offspring with specific blood types based on the given parental genotypes.

Let me start with problem 1: Iᴬi (♂) × Iᴮi (♀)

Problem 1: Iᴬi (♂) × Iᴮi (♀)
- Male parent genotype: Iᴬi (blood type A)
- Female parent genotype: Iᴮi (blood type B)
- Possible gametes from male: Iᴬ, i
- Possible gametes from female: Iᴮ, i

Punnett Square:
```
| Iᴮ | i
-------------------
Iᴬ | IᴬIᴮ | Iᴬi
i | Iᴮi | ii
```

Offspring genotypes and phenotypes:
- IᴬIᴮ: Blood type AB (25%)
- Iᴬi: Blood type A (25%)
- Iᴮi: Blood type B (25%)
- ii: Blood type O (25%)

Answer for Problem 1: 25% of offspring will have blood type AB.

---

Problem 2: Iᴮi (♂) × Iᴮi (♀)
- Both parents have genotype: Iᴮi (blood type B)
- Possible gametes from each: Iᴮ, i

Punnett Square:
```
| Iᴮ | i
-------------------
Iᴮ | IᴮIᴮ | Iᴮi
i | Iᴮi | ii
```

Offspring genotypes and phenotypes:
- IᴮIᴮ: Blood type B (25%)
- Iᴮi: Blood type B (50%)
- ii: Blood type O (25%)

Answer for Problem 2: 25% of offspring will have blood type O.

---

Problem 3: IᴬIᴬ (♂) × IᴮIᴮ (♀)
- Male parent genotype: IᴬIᴬ (blood type A)
- Female parent genotype: IᴮIᴮ (blood type B)
- Possible gametes from male: Iᴬ
- Possible gametes from female: Iᴮ

Punnett Square:
```
| Iᴮ
-------------------
Iᴬ | IᴬIᴮ
```

All offspring will be IᴬIᴮ (blood type AB).

Answer for Problem 3: 0% of offspring will have blood type A (all will be AB).

---

Problem 4: Iᴬi (♂) × Iᴮi (♀)
This is identical to Problem 1.
- Male parent genotype: Iᴬi (blood type A)
- Female parent genotype: Iᴮi (blood type B)
- Possible gametes from male: Iᴬ, i
- Possible gametes from female: Iᴮ, i

Punnett Square:
```
| Iᴮ | i
-------------------
Iᴬ | IᴬIᴮ | Iᴬi
i | Iᴮi | ii
```

Offspring genotypes and phenotypes:
- IᴬIᴮ: Blood type AB (25%)
- Iᴬi: Blood type A (25%)
- Iᴮi: Blood type B (25%)
- ii: Blood type O (25%)

Answer for Problem 4: 25% of offspring will have blood type AB.

---

Problem 5: ii (♂) × IᴬIᴮ (♀)
- Male parent genotype: ii (blood type O)
- Female parent genotype: IᴬIᴮ (blood type AB)
- Possible gametes from male: i
- Possible gametes from female: Iᴬ, Iᴮ

Punnett Square:
```
| Iᴬ | Iᴮ
-------------------
i | Iᴬi | Iᴮi
```

Offspring genotypes and phenotypes:
- Iᴬi: Blood type A (50%)
- Iᴮi: Blood type B (50%)

Answer for Problem 5: 50% of offspring will have blood type A.

---

Problem 6: Iᴬi (♂) × IᴮIᴮ (♀)
- Male parent genotype: Iᴬi (blood type A)
- Female parent genotype: IᴮIᴮ (blood type B)
- Possible gametes from male: Iᴬ, i
- Possible gametes from female: Iᴮ

Punnett Square:
```
| Iᴮ
-------------------
Iᴬ | IᴬIᴮ
i | Iᴮi
```

Offspring genotypes and phenotypes:
- IᴬIᴮ: Blood type AB (50%)
- Iᴮi: Blood type B (50%)

Answer for Problem 6: 50% of offspring will have blood type B.

---

Problem 7: IᴬIᴬ (♂) × IᴮIᴮ (♀)
This is identical to Problem 3.
- All offspring will be IᴬIᴮ (blood type AB).

Answer for Problem 7: 0% of offspring will have blood type AB (actually 100% will have blood type AB, so 0% is incorrect - let me recalculate).

Wait, let me correct this. For Problem 7, all offspring will be IᴬIᴮ, which is blood type AB. So 100% will have blood type AB.

Answer for Problem 7: 100% of offspring will have blood type AB.

---

Problem 8: IᴬIᴬ (♂) × ii (♀)
- Male parent genotype: IᴬIᴬ (blood type A)
- Female parent genotype: ii (blood type O)
- Possible gametes from male: Iᴬ
- Possible gametes from female: i

Punnett Square:
```
| i
-------------------
Iᴬ | Iᴬi
```

All offspring will be Iᴬi (blood type A).

Answer for Problem 8: 100% of offspring will have blood type A.

---

Problem 9: IᴬIᴬ (♂) × Iᴮi (♀)
- Male parent genotype: IᴬIᴬ (blood type A)
- Female parent genotype: Iᴮi (blood type B)
- Possible gametes from male: Iᴬ
- Possible gametes from female: Iᴮ, i

Punnett Square:
```
| Iᴮ | i
-------------------
Iᴬ | IᴬIᴮ | Iᴬi
```

Offspring genotypes and phenotypes:
- IᴬIᴮ: Blood type AB (50%)
- Iᴬi: Blood type A (50%)

Answer for Problem 9: 50% of offspring will have blood type A.

---

Problem 10: IᴬIᴮ (♂) × IᴬIᴮ (♀)
- Both parents have genotype: IᴬIᴮ (blood type AB)
- Possible gametes from each: Iᴬ, Iᴮ

Punnett Square:
```
| Iᴬ | Iᴮ
-------------------
Iᴬ | IᴬIᴬ | IᴬIᴮ
Iᴮ | IᴬIᴮ | IᴮIᴮ
```

Offspring genotypes and phenotypes:
- IᴬIᴬ: Blood type A (25%)
- IᴬIᴮ: Blood type AB (50%)
- IᴮIᴮ: Blood type B (25%)

Answer for Problem 10: 50% of offspring will have blood type AB.

---

Problem 11: ii (♂) × Iᴬi (♀)
- Male parent genotype: ii (blood type O)
- Female parent genotype: Iᴬi (blood type A)
- Possible gametes from male: i
- Possible gametes from female: Iᴬ, i

Punnett Square:
```
| Iᴬ | i
-------------------
i | Iᴬi | ii
```

Offspring genotypes and phenotypes:
- Iᴬi: Blood type A (50%)
- ii: Blood type O (50%)

Answer for Problem 11: 50% of offspring will have blood type O.

---

Problem 12: IᴮIᴮ (♂) × IᴬIᴬ (♀)
- Male parent genotype: IᴮIᴮ (blood type B)
- Female parent genotype: IᴬIᴬ (blood type A)
- Possible gametes from male: Iᴮ
- Possible gametes from female: Iᴬ

Punnett Square:
```
| Iᴬ
-------------------
Iᴮ | IᴬIᴮ
```

All offspring will be IᴬIᴮ (blood type AB).

Answer for Problem 12: 0% of offspring will have blood type B (all will be AB).

Here are the final answers for all 12 problems:

1. 25%
2. 25%
3. 0%
4. 25%
5. 50%
6. 50%
7. 100%
8. 100%
9. 50%
10. 50%
11. 50%
12. 0%