BIDMAS / BODMAS questions worksheet | KS3-4 Maths |Teachit - Free Printable

Problem Analysis:

The task involves solving arithmetic expressions while adhering to the correct order of operations, also known as BIDMAS/BODMAS. This acronym stands for:

- B: Brackets (Parentheses)
- I/D: Indices/Orders (Exponents/Powers)
- M/D: Multiplication and Division (from left to right)
- A/S: Addition and Subtraction (from left to right)

We will solve each expression step by step, ensuring we follow the correct order of operations.

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Expression 4: Evaluate

#### 1. \( 2 + 3 \times 5 \)
- Step 1: Perform multiplication first (\( 3 \times 5 \)).
\[
3 \times 5 = 15
\]
- Step 2: Add the result to 2.
\[
2 + 15 = 17
\]
- Answer: \( 17 \)

#### 2. \( 5 \times 2 + 6 \)
- Step 1: Perform multiplication first (\( 5 \times 2 \)).
\[
5 \times 2 = 10
\]
- Step 2: Add the result to 6.
\[
10 + 6 = 16
\]
- Answer: \( 16 \)

#### 3. \( 30 - 2 \times 4 \)
- Step 1: Perform multiplication first (\( 2 \times 4 \)).
\[
2 \times 4 = 8
\]
- Step 2: Subtract the result from 30.
\[
30 - 8 = 22
\]
- Answer: \( 22 \)

#### 4. \( 10 - 5 \times 2 \)
- Step 1: Perform multiplication first (\( 5 \times 2 \)).
\[
5 \times 2 = 10
\]
- Step 2: Subtract the result from 10.
\[
10 - 10 = 0
\]
- Answer: \( 0 \)

#### 5. \( 7 + 3 \times 2 \)
- Step 1: Perform multiplication first (\( 3 \times 2 \)).
\[
3 \times 2 = 6
\]
- Step 2: Add the result to 7.
\[
7 + 6 = 13
\]
- Answer: \( 13 \)

#### 6. \( [10 + (4 \times 3)] \)
- Step 1: Solve the inner brackets (\( 4 \times 3 \)).
\[
4 \times 3 = 12
\]
- Step 2: Add the result to 10.
\[
10 + 12 = 22
\]
- Answer: \( 22 \)

#### 7. \( 15 - 9 \div 3 \)
- Step 1: Perform division first (\( 9 \div 3 \)).
\[
9 \div 3 = 3
\]
- Step 2: Subtract the result from 15.
\[
15 - 3 = 12
\]
- Answer: \( 12 \)

#### 8. \( 10 + 3 \times 5 \)
- Step 1: Perform multiplication first (\( 3 \times 5 \)).
\[
3 \times 5 = 15
\]
- Step 2: Add the result to 10.
\[
10 + 15 = 25
\]
- Answer: \( 25 \)

#### 9. \( 9 + (3 \times 5) - 4 \)
- Step 1: Solve the brackets (\( 3 \times 5 \)).
\[
3 \times 5 = 15
\]
- Step 2: Add 9 to the result.
\[
9 + 15 = 24
\]
- Step 3: Subtract 4 from the result.
\[
24 - 4 = 20
\]
- Answer: \( 20 \)

#### 10. \( 24 \div (10 + 2) \)
- Step 1: Solve the brackets (\( 10 + 2 \)).
\[
10 + 2 = 12
\]
- Step 2: Perform division.
\[
24 \div 12 = 2
\]
- Answer: \( 2 \)

#### 11. \( 7 + (3 \times 2) + 3 \)
- Step 1: Solve the brackets (\( 3 \times 2 \)).
\[
3 \times 2 = 6
\]
- Step 2: Add 7 to the result.
\[
7 + 6 = 13
\]
- Step 3: Add 3 to the result.
\[
13 + 3 = 16
\]
- Answer: \( 16 \)

#### 12. \( 27 \div (3 \times 3) \)
- Step 1: Solve the brackets (\( 3 \times 3 \)).
\[
3 \times 3 = 9
\]
- Step 2: Perform division.
\[
27 \div 9 = 3
\]
- Answer: \( 3 \)

#### 13. \( 6 + 7 \times 3 \)
- Step 1: Perform multiplication first (\( 7 \times 3 \)).
\[
7 \times 3 = 21
\]
- Step 2: Add the result to 6.
\[
6 + 21 = 27
\]
- Answer: \( 27 \)

#### 14. \( 29 - 9 \times 3 \)
- Step 1: Perform multiplication first (\( 9 \times 3 \)).
\[
9 \times 3 = 27
\]
- Step 2: Subtract the result from 29.
\[
29 - 27 = 2
\]
- Answer: \( 2 \)

#### 15. \( 33 - 2 \times 3 + 4 \)
- Step 1: Perform multiplication first (\( 2 \times 3 \)).
\[
2 \times 3 = 6
\]
- Step 2: Subtract the result from 33.
\[
33 - 6 = 27
\]
- Step 3: Add 4 to the result.
\[
27 + 4 = 31
\]
- Answer: \( 31 \)

#### 16. \( 14 + (7 \times 2) - 3 \)
- Step 1: Solve the brackets (\( 7 \times 2 \)).
\[
7 \times 2 = 14
\]
- Step 2: Add 14 to the result.
\[
14 + 14 = 28
\]
- Step 3: Subtract 3 from the result.
\[
28 - 3 = 25
\]
- Answer: \( 25 \)

#### 17. \( 1 + 4 \times 3 \)
- Step 1: Perform multiplication first (\( 4 \times 3 \)).
\[
4 \times 3 = 12
\]
- Step 2: Add the result to 1.
\[
1 + 12 = 13
\]
- Answer: \( 13 \)

#### 18. \( 10 \div 2 + 3 \)
- Step 1: Perform division first (\( 10 \div 2 \)).
\[
10 \div 2 = 5
\]
- Step 2: Add the result to 3.
\[
5 + 3 = 8
\]
- Answer: \( 8 \)

#### 19. \( 17 - 4 \times 3 \)
- Step 1: Perform multiplication first (\( 4 \times 3 \)).
\[
4 \times 3 = 12
\]
- Step 2: Subtract the result from 17.
\[
17 - 12 = 5
\]
- Answer: \( 5 \)

#### 20. \( 4 \times 6 + 5 \times 8 \)
- Step 1: Perform both multiplications (\( 4 \times 6 \) and \( 5 \times 8 \)).
\[
4 \times 6 = 24, \quad 5 \times 8 = 40
\]
- Step 2: Add the results.
\[
24 + 40 = 64
\]
- Answer: \( 64 \)

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Final Answers:

\[
\boxed{17, 16, 22, 0, 13, 22, 12, 25, 20, 2, 16, 3, 27, 2, 31, 25, 13, 8, 5, 64}
\]